#range of values
10 messages · Page 1 of 1 (latest)
this question is just about doing trial and errors using calculator, i would recommend using very closest values to figure out these conditions [for example : -2 < a < 0 just for first try use -1.9 and b as -0.9 then use other closest side of inequality] (i cant really explain this q however this might help)
Not really
Firstly the question is saying that GIVEN THAT -2<a<0 and -1<b<1 deduce some information
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squaring a (or any real number) gives a²≥0 so the statement a²<0 is NEVER TRUE
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squaring b again gives b²≥0 and applying the fact that b<1 gives b²<1 so 0≤b²<1 which falls inside of -1<b²<1 so id ALWAYS TRUE
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We know a is a negative number but b is either negative or positive so b/a is either negative or positive so it is SOMETIMES TRUE that b/a<0
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This one you could find when a-b is positive and negative as inequalities but since it is the "sometimes true" case is the weakest we can just give an example of when the statement is true and when it is not e.g -1.9-0.9=-1<0 and -0.1-(-0.9)=0.8>0 so is SOMETIMES TRUE
I can't really explain it but I got this question right in the mock.
I don't mean that its necessarily wrong but its more that its unreliable
Like there's some luck involved
Yeah,I get it but your explanation is great.