#critical region

89 messages · Page 1 of 1 (latest)

robust ruin
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wats the answer to part b?

image.png
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help

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pls

pseudo estuary
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which q

robust ruin
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part b

pseudo estuary
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OK

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1 SEC

robust ruin
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i asnwered it but some1 else got a different answer

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tell me wat u got

pseudo estuary
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BASICALLY

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as it is a two tailed test

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sorry for caps

robust ruin
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its alr

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this is wat i did ik how to do it but im confused cus some1 else got a different answer

pseudo estuary
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we need to spli the significane level of 5% (o.05) equally

robust ruin
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this is their answer

pseudo estuary
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the each tail has a probability of 0.025 (2.5%)

robust ruin
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can u work it out pls

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and tell me ur critical regions

pseudo estuary
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To find the critical region, we need to determine the z-scores corresponding to the tail probabilities.

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alr im doing it now

robust ruin
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ok ok ty

pseudo estuary
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np

robust ruin
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just gotta make sure im not doing anything wrong

pseudo estuary
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The critical z-score for the lower tail can be found using a standard normal distribution table

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i used calc tho

robust ruin
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wait wat

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y r u using standard normal

pseudo estuary
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the z-score with a cumulative probability of 0.025 in the lower tail is approximately -1.96.

pseudo estuary
robust ruin
# pseudo estuary wdym

u can split it into <0. 0025 on each side and then change upper tail to > 0.975 and enter ltos of values in list and see which ones match up

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with binomial cd

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and then go from there

pseudo estuary
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ive only learned the formula way

robust ruin
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oh ok

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ok clm tell me wat u get

pseudo estuary
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and the upper tail is the negative of the lower tail

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so its is 1.96

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so the lower region is

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z ≤ -1.96

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and the upper is the same without the negative

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so its

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z ≥ 1.96

robust ruin
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thats for normal standard tho

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theyre asking to give critical region in terms of students

pseudo estuary
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ohhh

robust ruin
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part b)

pseudo estuary
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ok so

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first calc margain of error

robust ruin
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so 0.025

pseudo estuary
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E = 1.96 * √((0.28 * (1 - 0.28)) / 60)

robust ruin
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on each side

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wait wth

pseudo estuary
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i got 0.108

robust ruin
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y r u doing normal approximation

pseudo estuary
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wdym what did you use

robust ruin
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here

pseudo estuary
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because basically

robust ruin
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basically since its 2 tailed u split sl into 2

pseudo estuary
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for lower you can do 1.28 - 0.108

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and for upper

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0.28 + 0.108

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so lower is 17.2%

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and upper is 23.28%

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so lower is 0-17 and upper is 24-36

pseudo estuary
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this is all from youtube knowledge ive gathered so its may be wrong

robust ruin
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oh ok cus u were doing standard normal distribution for no reason

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thats not even gonna work cus the q is binomial distribution

pseudo estuary
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ohhh

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i see

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the whole size = 60

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for the lower the critical value is approx 16

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and for upper it is approx 31

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so 0-16 and 31-60

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for upper and loweer

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mabye

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idk

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this is killing me

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<@&791435371564892232>

robust ruin
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i realised it shud be x <=10 and x >= 24 not 25

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cus it sed closest to 0.025

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doesnt matter if in cr or not