#ive been stuck on these flippin ratios for hours anyone help me please itll make my day
129 messages · Page 1 of 1 (latest)
No it isn't
Yh
Bun that
Gimme 5 mins
Calm gn g
That's the answer I think
@steel musk
30
I think
12
12 penguins
30 monkey ppl
Hmm
Bro got sparxx at midnight
ðŸ˜
loool
💀
THEYRE LIKE YANKO WHERE DID YOU GO
Innit
yhyh
Let me try it
sn
THEY DONT WANR RHIS FORILLA ON ROAD SO THEY LCIKED ME UP IN THE Z DOUBLE O
so
man needs to go back jail luv
theres an app that does it for u
maths smthing
fairs
yhyh
use da
long
use ur marges phone
charge dat
wallahi
is the first one 40
It fits the number of adult tickets ðŸ˜
just google it bro
Wtf it reset
thank google not me
To who
yw ðŸ˜ðŸ˜ðŸ˜
💀💀💀💀
explanation if u need
Kasam se I'm dead
copy and paste
This guy man
what even is this A level bs 🤣
Akh do u do edexcel?
It came up similar to the tomato question and carrot
So it’s good to know this
Yhyh my pojnt
THATS WHAT U HAD TO DO
Goat question
ffs
BANGED THAT QUESTION
Yeah I got it right in the exam 🔥
what did he get muted for
What would you do if the number of child’s tickets changed
Whole question would be 10x harder
bruv i done gcse
@devout bough how do you prove that any open cover of a closed bounded set has a finite subcover
Since the set is bounded, we can choose a finite-sized ball that completely contains the set. Let's call this ball B. Now, since B is a closed set (closed balls are closed sets), it is also a closed bounded set.
Since B is closed and bounded, it is compact. Therefore, any open cover of B has a finite subcover. Since our original set is contained within B, any open cover of our original set is also an open cover of B.
Hence, any open cover of our original closed bounded set has a finite subcover, as it is a subset of the open cover of B.
This proves that any open cover of a closed bounded set has a finite subcover.
Did you just copy paste that? It doesn't make sense lol
g ting i did lool i was half asleep
wat subject is dis
Topology
yh wtf is dat
R u doing maths in uni or not lmao
is that about space
Ye
It's easyish topology. Real numbers only.
Point set topology is a required course isn't it?
mah