how do i do this

[minor nexus]

<@&791435371564892232>

[potent iris]

It’s using circle theorems

So the angle at the circumference is half that at the centre

So then it’s 150/360(pi r^2) - 1/2 r^2 sin150

=200

Rearrange for r

[minor nexus]

i get the first part, but why 1/2r^2 sin150

where did that come from

[potent iris]

1/2 abSin C

for the area of a triangle

A and b are both r

[minor nexus]

so ur subtracting the area of the triange from the sector?

to find the shaded region

[potent iris]

Yeah

[minor nexus]

Oh alr thankyou so much