help plz

[pale axle]

Someone walk me through this thx

[vernal juniper]

The way you'd find AC is by using the angle and the calculated side BC. This equation would be BC / sin(BAC) (found by using SohCahToa)
As you want to find the lower bound of this, you want the answer to be the lowest it can be. The way to do that is to make BC as small as it can be, and to make sin(BAC) as big as it can be (by making BAC as big as it can be)
You have the things rounded, not truncated, to 2sf and 1dp each, so you can find the biggest/smallest values they would be to just round to the value shown

[pale axle]

Tysm

so do i find the bounds first

before using trig

like

8.15<x<8.25 for BC

[vernal juniper]

Yes find the bounds

Then do the trig

[pale axle]

51.5<x<5.25

do those

look right

[vernal juniper]

Those are correct yeah

[pale axle]

i was confused on the bounds for 2 sig fig

alr

tysm

[vernal juniper]

Np

[pale axle]

one more question, how do u know which one out of the angle and side to use the UB or the LB

Like how do u know to make the angle the UB and the side the LB

[vernal juniper]

So for both bounds, if you have a number on the numerator you want the same bound, and if you have a number on the denominator you want the opposite bounds

For instance if you want the largest speed, you'd want to cover the largest distance in the smallest time

That sort of thing

[pale axle]

Ohhhh

thanks would 10.3 be right then for LB of AC it doesnt have a markscheme

[vernal juniper]

Gimme a sec

Yes

[pale axle]

Thx sm