difficult log questi

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<@&791435371564892232>

[spring pelican]

Do it in ur head ez

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easy

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wheres the q from

that was fun

wait

hmm

im tryan think if i did it right

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what does that show tho

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ok i red the queestion wrong

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it doesnt show anything

ygm

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i thought we were comparing vaslues mb

we are comparing the x and y values

mb

il redo

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ye

i got both into this form it looks semi useful

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OK DID it

so we got a number where a =63 so 63^x-y= 392

x>y as the rhs is not a fraction

hmm

oh wait

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ye i thought

i was wondering sthat

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well that sucks

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idk if it works then cuz we just have a random 3^k

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actually theyre x

not k

lol my writing sucks

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lol

any way i can show this is < 0 or > 0

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is this an oxf question

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ye

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looks like it tbh

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its some like course

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w where did you get it from

looks like its from mat

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nah

its a course oxford run they have problem sets every few weeks

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theyve got really fun questions

like the one youve got here

i enjoy them alot lol

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this is alright

its just like

idk a bit repeptiive

after abit

idk how to shoiw this

its the only 1 im stuck on

i think if i just put everytrhing as close as base 2 as i can and approximate it works

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im still doing it lol

is it meant to be the hardest?

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no

[worthy jacinth]

Compos

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ye

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r u doing it or just looking at the assignments

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im on it

i didnt know if assignments are public

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why u doing like 2 weeks ago assignment ??

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cuz i stopped doing them for as

im cathcing up

[worthy jacinth]

oh fair

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its more like 2 month ago

u think thats good enough

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What group/who’s ur tutor

Yeah I meant like last assignment x2

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idk group

but tutor is called max

i think group 4

[worthy jacinth]

It’s just the number in the classroom

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ye 4 thne

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Also I can send u my solution for that problem if u want another one

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ye sure

its not like ill get the chance to go over real solution

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yh yh I get u

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what group r u in

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1

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is it bsaed on skill or not ?

like the numbers

what u get assignment 1

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yh i think so

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like % 's

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Full marks on both

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fair enough

i got like 95% 95%

must be skill then

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was my solution for that

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wym that question

ye

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ye

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i tried that approach a few times

the powers

i never used this tho

thats what i was missing in my other solutions

i literally had this aswell

fair enough

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haha yeah it was a weird one cos so many ways of doing it

so u dont wanna commit too bad to one

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ye

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cos u can just see another method

like i kept switching my method

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ima just submit my approximate method

i think ifucked up the last q anyway

i got that but it defo shouldnt be 5000

[worthy jacinth]

ye omg that one was tough

most of the tutors couldn’t do it

so they told their group not to do it

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nice

is that right form what i did

u dont have to check idm

it seems right but my numberrs are wrong like the r and c values

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wait for which one the first or 2nd part of it

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2nd

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like 17 ?

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ye

this was my 16 part a answer alspo

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yh that’s right format for 17 but idt numbers r what i got

and yh 16 is right

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i thnk it is right then

cuz my tutor gave us the answer to 17b nothing else

but with my equation i get nothing close to it

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what?

16 is defo right yeah

but 17 no but right formal=t

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i mean like

we were given the answer to 17b in teh review or whatever its like 2400 or something

but with my equation that i got from 17a i dont get anything close to that

my kettle dont even boil

[worthy jacinth]

yh 2554s

oh wait

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what eq did u get for 17a then ?

thats my 17a

[worthy jacinth]

yh not that

think about it in terms of physics not maths

think about the limiting condition when all the energy goes to surroundings from the kettle

then u can find an equation and figure out the asymptote form that

and then bang in the same rate of change as 16 obv

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so is this not the right first step

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it could be, idk how to solve it by doing that

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how did u

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i just did it by deducing the asymptote

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using this

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= 0 ?

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nah right so

as t -> infinity all the energy from the source is gonna go to surroundings cos the kettle will reach its limiting temperature

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ye

makes snese

so

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so think about what u know about dQ/dt and stuff because of that

at the limiting tempo

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dT/dt = 0 ? cuz it no longer increases or is negative

not sure

[worthy jacinth]

no use dQ/dt

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i meant that

[worthy jacinth]

yeah no dont think of it like that

what acc is dQ/dt

?

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-C dT/dt

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think about it in terms of physics

no

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oh

its

rate of change of energy with respect to tiem ?

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yeah which is…

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power

so u literallyjust set 200 = r(T-Tr)

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yes

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i cant see how u get into a form of T(t)now

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u don’t need it

just think about what I said before and what I did

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the q asks for T(t) tho

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Yh

but

u don’t need to think about how to conver

Just think about the physical behaviour of the system and the model and fiddle around with it

cos now u know something about the behaviour

And that’s everything u need to know to work out the curve

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Yh but I mean think abo it what I said earlier cos I gtg but all the info is what I’ve said before

u will be able to figure it out

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alright tahnk you

have a good ady