#modelling follow on
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a = deltaV / deltaT you can find speed and you know time
How would u do it in tbis case
you know your constant A and B so you sub in t to find velocity at t = 5 then you know speed and you know thats the speed when t = 5 so you can do a = your value for V / 5
Why V / 5
And when u sub in all the values, isn't that just finding V . Like how do u differentiate it
yeah v is velocity, acceleration = velocity / time, when you find velocity thats the velocity at t=5 so you do V / 5
if you look at marks they wouldnt make you differentiate for 2 marks
i would argue they would seen as its very easy to differentiate and then sub in t=5
@celest pagoda you differentiate the -be^-0.17t seen as thats the only bit you can differentiate
i mean you could differentiate it works maybe im just biased
and then sub in t=5
too physics minded ๐
๐ญ
just see e and dont wanna differentiate tbh
even if it is easy
cmon now its just 0.17be^-0.17t
yeah im deffo biased
Wb the A
Or like are we skipping A
How do u dodderenciate it
Index ร interger
Index - 1
thats for powers of x
Like if I asked you to differentiate 2 what would you say it is
Nth
exactly
So would thT mean that it becomes 0!?
Wb the right side
if you expand the bracket you get B -Be^-0.17t
the second bit is the bit you need to differentiate and B differentiated is just 0 as it is just anumber like A was
Wait could u like write it like visually
A = 11
B = 7
Ok so V= 11 +7(1-e^-0.17t)
expand it V=11 +7 -7e^-0.17t
V=18- 7e^-0.17t
differentiating e^-0.17t is -0.17e^-0.17t then you multiply that by -B which is -7 so you get 1.19e^-0.17t
sub in t=5 you get 1.19e^-0.85
which is 0.509
I don't get this part
Did u like separate them
And differentiated the e part
And then ร 7
Giw did it become -0.17e^-0.17t
Ohhh wait I think I get that part. But doesn't the power decrease by 1
oh have you never differentiated e^x before
well e^x differentiates to e^x and therefore if theres a number like -0.17 infront of the x you use chain rule and multiply by -0.17