#PLS HELP WITH PART C
32 messages · Page 1 of 1 (latest)
oh hell nah
I cba for vectors I'm always going off of gcse knowledge bc my teacher was shit 😭 give me a sec to actually get the answers and I'll guide you through them
I can send ms here
I can send a ss, one sec
Alr
Okay so you can see that the coefficient of a is 0, because ON is parallel to OB / is (a scalar constant) × OB.
Using that, they found λ to be 4/3. Plugging that into the equation, the vector of ON would be 2/3 b or 2/3 × OB. That means that the distance from O to N would be 2/3 times the distance from O to B
Putting this on a line, that would mean the distance from N to B would be 1/3 times the distance from O to B, and so the ratio between the distances ON and OB would be 2:1
If you need me to go over any of that then just ask
dk if that makes a lot of sense
but u need to find 2 routes of ON
and make the coefficients equal to each other to find lambda
theres a bunch of different ways of doing these types of vector questions
2 marks for this is ridiculous tho. what paper is this from
anyone know how the vector line equation works
swear it can be used for these type of qs
isnt that for 3d vectors?
Why are you equaling 2-3/2 lambda to 0?
Ong
Pmt vectors
they’re the coefficients of a
there's 3d ones at a level