Angle Question

[deft shadow]

hey lads
I've got an angle question
I can't think of anyway on how to solve it
<@&791435371564892232>

Is 6x+41=90?

are the two lines perpendicular?

[kindred lotus]

to be perpendicular the gradient have to x to -1

wait nvm its not that type of question

byt 8y + 79 + 6x + 41 = 160

[deft shadow]

how do you know?

@kindred lotus

[kindred lotus]

6x + 41 and the angle in the circle (8y+79) are corresponding

[simple crane]

Isn’t it 360 then?

[grim palm]

what are you guys on about lmao

[deft shadow]

yea?

[grim palm]

give me a second

[simple crane]

ia have no idea

[deft shadow]

this

is the 67° useless?

[grim palm]

No you need all angles

67 is actually the one you need most

[deft shadow]

how so

[simple crane]

to work out x

[grim palm]

Im going to draw some lines on the pages, and youll see that this question isnt as bad as you think it is

[deft shadow]

k

[simple crane]

i think this is what x would be

Because if the lines are parallel

the two angles will add up to 180

[deft shadow]

Alternate angles?

[simple crane]

angles in a straight line add up to 180

but technically yea

[grim palm]

If you dont get it heres a (shitty) graphic for it

[deft shadow]

OHHHH

[grim palm]

Basically you use the rules for alternate/corresponding or whatever angles to find that

[simple crane]

yep

[deft shadow]

i see

[grim palm]

Alr, you know how to find them now?

[deft shadow]

yea lemme work it out

[grim palm]

I mean thats already how you find x but hopefully you know how to find y now

[simple crane]

yep

[deft shadow]

thanks guys

really helped

Just to make sure
X=12 y=21

how do I close this tab?

[grim palm]

thats what I got