#what is it asking
18 messages · Page 1 of 1 (latest)
find derivative, set equal to 0 and find turning points
For part c it is always decreasing
What?
U solve f'(x) < 0
So for part c f'(x) = -10x⁴-24x² < 0 but since x⁴ and x² are non-negative f(x) is decreasing for all values EXCEPT x=0
So the range is all values of x where x≠0
If fx) is decreasing then f'(x) <0 and if increasing f'(x) >0
you literally need to do what I said to find that
And then some the inequality
Not really
U gotta do that but that's not the point
when you find the turning points it's obvious where the function is decreasing/increasing
so is that the answer?
Why do u "need" to find the turning point to solve f'(x) < 0
And why do u "need" to set it equal to 0 to solve f'(x) < 0
Yep