#mechanics 4 mark question
11 messages · Page 1 of 1 (latest)
Do u have the speed when B hits the floor
I'm not sure if it's right tho
But so far I got
S= ?
U= speed of B
V =0
A=0.8
T=/
But I'm not sure about the acceleration
As B is falling the string is taut so there is tension pulling A so A is accelerating but when B hits the ground the string becomes slack so there is no force pulling A forwards so A just moves a bit further because of the speed it gained while B was falling
So you want to get the speed A gained using v^2= u^2+2as
Then use f=ma to get the deceleration on A due to resistance
Then use v^2=u^2+2as again but using the deceleration and the u as the speed you got in the first step then solve for s
i forgot to mention that i tried it before i posted this and i got 0.648/0.649 (depending on if i used the actual value or rounded the decimal)
but i wasn’t sure if the answer was right or not
but i’ll try what you just said
i got 2.19 for the speed of b!