#mechanics 4 mark question

11 messages · Page 1 of 1 (latest)

brittle zealot
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can someone help me with part d? i only need help with part d.

quaint pebble
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I'm not sure if it's right tho
But so far I got
S= ?
U= speed of B
V =0
A=0.8
T=/

                 But I'm not sure about the acceleration
radiant breach
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As B is falling the string is taut so there is tension pulling A so A is accelerating but when B hits the ground the string becomes slack so there is no force pulling A forwards so A just moves a bit further because of the speed it gained while B was falling

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So you want to get the speed A gained using v^2= u^2+2as

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Then use f=ma to get the deceleration on A due to resistance

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Then use v^2=u^2+2as again but using the deceleration and the u as the speed you got in the first step then solve for s

brittle zealot
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but i wasn’t sure if the answer was right or not

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but i’ll try what you just said

brittle zealot