Axes question

[austere haven]

i presume if its just a sketch u need to complete the square to find turning point

wait nvm

💀 didnt see x^3

[small ingot]

if it's in the form x(x-a)^2

then one solution is 0

and the other solution repeats

so the graph only intersects twice

[red monolith]

but how u figure it out

[small ingot]

take out an x first

and then complete the square on the quadratic

[red monolith]

so i should do a quadratic equation

[small ingot]

if you take out the x from the equation

you get x(x^2-4x+4)

and then complete the square on the bracket

x(x-2)^2-4+4

= x(x-2)^2

[austere haven]

so the turning point is (2,2) >

?

[small ingot]

(2,0) i think

[austere haven]

why:

[small ingot]

why would it be (2,2)

what's ur reasoning for that

[austere haven]

well u completed the square and then to get the coords of turning point wouldnt u just flip whats in the bracket and thats ur x coord

and then y is the one outside

[small ingot]

careful

the y is only the one outside if it's a - or a + term

with no x

so the turning point would have been (2,2) if the equation was x(x-2)^2 +2

[austere haven]

OH

Wait

IM STUPID

i thought the ^2 was -2

💀

[small ingot]

lol

[austere haven]

i might need glasses

[small ingot]

ur fine dw