finding ewuations of tangents to circle | Revision Server | Page 1

spark comet Apr 30, 2023, 10:03 AM

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Help

radiant apex Apr 30, 2023, 10:23 AM

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spark comet Apr 30, 2023, 10:24 AM

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isn’t the answer 2 coordinates

radiant apex Apr 30, 2023, 10:24 AM

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Wait that is the illustration

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so basically you need to differentiate x^2 + y^2 = 10

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After you get the dy/dx lets say i got 1/2(-x^2+10)^1/2

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Then you put the -1 into the dy/dx to get the gradient

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After you get the gradient you should get 1/6 then you use m1 x m2 = -1 which equals to -6

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So the -6 will be your new gradient for the two new tangent

#finding ewuations of tangents to circle