#just show the steps of the ans dont give explanation
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factorise
Factorise everything u can then multiply the fractions then cancel common factors
i got until 2x(4x^2 -9)/3x(2x^2-3x-9)
what do i do next
factorise
There's difference of 2 squared
can u explain step by step
There is an identity for a general expression in the form (a^2 - b^2)
a^2 - b^2 = (a + b)(a - b)
The numerator of the first fraction is in that form
Where a = 2x and b = 3
So you can factorise the numerator of the first fraction to be (2x + 3)(2x - 3)
Because if you expand that out you will get:
4x^2 - 9
yep
-Znar
yep