#just show the steps of the ans dont give explanation

24 messages · Page 1 of 1 (latest)

tall token
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<@&791435371564892232>

past totem
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factorise

still crag
normal viper
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(2x+3)(2x-3)/3(2x+3) is the first fraction

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so that's (2x-3)/3

tall token
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i got until 2x(4x^2 -9)/3x(2x^2-3x-9)

past totem
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factorise

still crag
tall token
alpine abyss
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There is an identity for a general expression in the form (a^2 - b^2)

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a^2 - b^2 = (a + b)(a - b)

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The numerator of the first fraction is in that form

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Where a = 2x and b = 3
So you can factorise the numerator of the first fraction to be (2x + 3)(2x - 3)

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Because if you expand that out you will get:
4x^2 - 9

tall token
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yep

carmine swiftBOT
tall token
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i get that

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yep

carmine swiftBOT
tall token
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yep

carmine swiftBOT