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gilded turret Apr 9, 2023, 3:04 PM

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How to do part b

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I’ve done part a

gilded turret Apr 9, 2023, 4:03 PM

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<@&791435371564892232>

hollow flame Apr 9, 2023, 7:56 PM

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gilded turret <@&791435371564892232>

So sub in your entire expression for g−¹(x) as your “x” term for g(x)

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i.e. replace the x in 6 - 2x with (x-6)/-2

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Actually you dont need that because its always x for any function and its inverse

wanton shoal Apr 9, 2023, 11:48 PM

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gilded turret

Part b) ok so what I like to do first and what u should do is find inverse g and so essentially that would be 6-x/2 u then wanna sub this back in g and it would be 6-2(6-x/2) so 6-(12-2x/2) which can be simplified to 6–x and then 6-6-x =-x

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