#equation of line
25 messages · Page 1 of 1 (latest)
sketch it
it's just asking you to write the line of anything that passes through (0,1)
so essentially y=mx+1
you can choose the gradient
y=-2x+1 passes through, y=1 passes through, y=79x+1 passes through
Assume that the line is perpendicular to line AB
Easier to get the gradient then
/jc, why does perpendicular lines matter here
It doesn't
I'm just saying that it helps to find the gradient
gradient of the the line is -1/gradient ab
I would've imagined m is irrelevant here, as the example given is 5. you could realistically get away with writing $y=mx+1, m \in \mathbb{R}$
shaun
and they would be inclined to mark you as correct, since you've specified that for any m, there exists a straight line going through coords (0,1)
Isn't that the answer?
what do you mean?
well not the only correct one, but I would imagine it's an example of a correct solution, yes
I did it in my way and the gradient is -2 ig it's wrong
having a gradient of -2 is fine, you would just have to have y=-2x+1
this still passes through (0,1)
No not the only answer, it can be any answer such that it follows the condition listed:
Aight
okay ty both for your help