#logstiehms

45 messages · Page 1 of 1 (latest)

undone ginkgo
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I’m stuck idk what to do next

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<@&791435371564892232>

muted jungle
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i think

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ln is base e

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so e^-1 = x/2

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2 e^-1 =x

undone ginkgo
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Uh

muted jungle
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is that right

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im a bit fizzy on logs

undone ginkgo
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I don’t get the step after the one I’m on

muted jungle
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basically

undone ginkgo
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Where does e^-1 come from

muted jungle
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here right

undone ginkgo
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Yeah

muted jungle
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so

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you ln?

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you know ln

undone ginkgo
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Yeah

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Log e

muted jungle
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ln is the same as log base e

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yeah

undone ginkgo
muted jungle
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so if you had log base 2 (x) = 8 then x would be 3 right

undone ginkgo
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Ohhhhhhhh

muted jungle
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woops did i do that right

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uhh

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i mean

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log base 2 (8) = x

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yeah

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and thats equal to 2^x = 8

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and then x = 3

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so

undone ginkgo
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Ok that makes a lot more sense

muted jungle
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log base e(x/2) = -1

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e^-1 = x/2

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2 e^-1 = x

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got it?

undone ginkgo
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Yes

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Thanks a lot

muted jungle
gloomy wadi
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Smh

muted jungle