help

[vocal nymph]

idk how to even start his question

[fallen jasper]

first one, expand the bracket and show LHS =/= RHS

and thus this is true forall a

[fallen jasper]

make sense so far?

[vocal nymph]

yup

[fallen jasper]

second one use pthag on both

so setting up a system

a^2+b^2 = c^2

(a+1)^2 + (b+1)^2 = (c+1)^2

expand (2) and then you can go from there

[vocal nymph]

i got a^2+2a+1+b^2+2b+1=c^2+2c+1

i cancelled 1 from both sides

to get a^2+2a+1+b^2+2b=c^2+2c

what do i do from there?

[fallen jasper]

you can now use the fact that a^2 + b^2 = c^2

then the c^2 will cancel

and then you're done

will leave you with 2a+2b+1=2c

[vocal nymph]

ohhhhh i see

[icy wyvern]

I remember this queshtion, one@fo the hardest questions in gcse

[vocal nymph]

thank you so much

[icy wyvern]

Cause people didn’t know where to start from…

[vocal nymph]

yeah 0.2% got full marks

[fallen jasper]

It's easy in principal

but

I think more guidance is needed

bit harsh the lack of guidance for this level

[vocal nymph]

what would i write for c)

[fallen jasper]

hmmm

so you have 2a, 2b, and 2c

by default, they are even numbers

(this is by assumption for integers btw)

but then 2a + 2b + 1 always an odd number

so odd = even

is not true for integers ofc

therefore they cannot be integers and must be by assumption real numebers

[vocal nymph]

thank you so much!

[fallen jasper]

np