#Quadratic Inequalities
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What did u get as the area of the rectangle?
X^2
The rectangle???
5x^2-11x+6
So u now have 5x^2-11x+6>x^2
4x^2-11x+6>0
Let y=4x^2-11x+6
Since y>0 x must lie outside of the roots ie x<root1 or x>root2 where root2>=root1
Y=(4x-3)(x-2)
So the roots of y are 3/4 and 2
Therefore x<3/4 or x>2