differentiation | Revision Server | Page 1

flat umbra Mar 8, 2023, 2:24 PM

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help

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<@&791435371564892232>

rancid swallow Mar 8, 2023, 3:41 PM

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what is the exercise

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find dy/dx ?

quartz socket Mar 8, 2023, 4:41 PM

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1/y dy/dx = 9sin^2(3x+4)cos(3x+4)
Dy/dx=9ysin^2(3x+4)cos(3x+4)

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Sin^3(3x+4)=(sin(3x+4))^3

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Use chain rule from there

flat umbra Mar 8, 2023, 8:32 PM

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Could you explain how you differentiated sin^3(3x + 4)

#differentiation