Help

[cyan narwhal]

Help please. I think I'm overcomplicating this. <@&791435371564892232>

[kind fog]

whats this

[stable sinew]

I’d recommend drawing a diagram to help you vision it

Then you’d find the gradient of CD by calculating the gradient of AB because they are parallel so they have the same gradient

And you’d sub in the x and y values from C to get the full equation

For D you can sub in the values into the equation to show it lies on the line but also create a new equation for AD by using the gradient as the negative reciprocal of the gradient for CD or AB

And sub in As coordinates to get the full equation

Then you could make them equal to each other to find out the x value they meet at

And sub that into either equation to get the y value

That should be (-1, 2)

And you’d use change in y/change in x for the gradient

or y2-y1/x2-x1

[cyan narwhal]

@stable sinew cheers bro