#help physics gcse
12 messages · Page 1 of 1 (latest)
iirc there is some equation
Power 1 =power 2
and u can use p=vi
PD of primary x current of primary = PD of secondary x current of secondary
I believe this is the equation to be used
i did
5x10^5 x 1200
all over
160,000
got 3750 tho , and answer is 3600
ohhhhhhhh