Gradients... i guess

[sullen lark]

.

what e bisects b at (x value)

and the y value

so

TLDR got one part =7/2, NEED TO GET EXPRESSION FOR AREA OF TRAPEZIUM IN TERMS OF C

[sullen lark]

everything past here i lose confidence with

[sullen lark]

for me to do that, im trying to find perpendicular distance between lines a and b and then multiply by mean of (a+b)

but then it gets messy

distance between lines a and b using pythagoras uses the last 4 or so images

it is meant to be non calc

and then to find mean (a+b)

to find b, i need to find where b intercepts d

and where b intercepts the x axis

perhaps i use the fact that the midpoint of b goes through the perpendicular line to make another equation for c so maybe solve simultaneously????????

[sullen lark]

a completely alternate method which someone else came up with

using similar shapes and so scale factor ratios for the 2 highlighted shapes here....