#Ant
996 messages · Page 1 of 1 (latest)
HI
hello ok
what have u done
i’m trying this too
i’ve drawn out the like sides yh
and if i break it into triangles
can i find the lengths?
r u doing it on paper send a pic
ok one sec
@oblique kelp i have no clue if this even makes sense tho
i see what you’ve done but i think u drew the first triangles wrong so it’s confused u , i did it like this
i did a straight line and then another one equal in length just 30 degrees lower
and again and again
ohhhhh
yh i see what u did
and then i made little triangle with the sides
and then i labelled the angles
what would u do after that tho
i’m thinking phythagoras
with the side 3+root3
and we make a new triangle like this
to find the displacement
yeah but how is that linked to the triangles
basically u know the yellow side can be found by adding the yellow sides of the amal triangles
also i need to do my geo hw that’s due tmr so i’ll be back in a bit
come back tho don’t go missing
i’ll try this q myself then 😒
@somber sparrow
oh yes i put in an extra x
doubt it’s got anything to do with interior angles
i formed a triangle
And now i’m trying pythagoras
hmmmm this shape is strange... 5 sides, so 540
540-180
360 =2 angles 
do u have the q in front of u
nah
ill@send
why don’t u make little triangles like me and see where u end up
ill just work off your pic
ah i have an idea
so if u extend the bottom right corner of the 2 small triangles u drew so that it touches the line of displacement
aka the line thats 3(root3)
then the hypotenuse of the new triangle forrmed is ON THE LINE of the 3 root 3
u get me?
u want kme to deraw it?
yes
ok
hmmmm
nvm i think im wrong
i was intending something like this
but then u dont know the angle
oh rigjt
i see what u tryna do
why don’t we do pythagoras wit the big triangle i made
so we can find displacement
is there a way to get these 2 red cross angles btw?
yeahh if we can find the vertical and horizontal component
like ifwe just consider the folloiwng shape:
the dark blue
the displacement is just from start to finish
yes
but to get the following a and b
we need to find the dark blue shape height and width i think
the horizontal is y+ xcos60
we can find c
the veritcal ix xsin30 + xsin60
wait i got an idea
u know the triangles we made we can add all the lengths to make one side of the triangle
vertical side and horizontal side
ur really still doing this
shush
so the vertical component is xsin90=xcos30 (or however u remember it)=x(root3/2)
it’s a rlly hard question so i wanna try it
ye thats what im saying
thats what i mean by horizontal and vertical component
this is the vertical
x(root3/2)
i didnt say anything ages ago cuz ud bascially alr done it...
horizontal is xcos60+y labelled here
horizontal side we can add xcos60 + xcos30 + x
i’m stuck icl
vertical is xsin60 plus xsin30 plus x ??
cos90 = 0 though right??
why u made a blue triangle
noit this
then ||get vertical height in terms of x||
then just ||pythagoras to solve for x||
its not a triangle, dw about it , it was me trying to show how to get unknown valuesto get horizontal and vetical component
ye we done that - it was about realising it
tbh i wouldve never though ab the big triangle
big brain for that
yes this is right
how? isnt th ehorizontal just x
its xcos60+xcos30+x
=xcos90+x
wut
u cant add cos like that
this what i did idk tho
these numbers r so hard to do pythagoras with
if u did pythagoras right then its correct. i didnt actually owrk it out
x=2, dimension cannot be negative
magnitude*
u mean root 2
yes
oh
the one i discarded was negative so ima say it’s the ant going backwards but i’m guessing
but i may be off
yeah... that sounds right... that the ant could have done it all but reflected
an ant cant walk -2cm
ye
so what do u think the answer is then
so 'what is meant by the solution'?
if i ever saw that id jsut skip icl
i assume mscheme costs money? @oblique kelp
just say it going backwards
but i agree with u - it cant.... x is a distance, not a vector quantity (i.e. it is a magnitude)
this was from my school so i’ll ask my teacher
U CAME JUST NOW
😭
it’s fine u can see how you would have done the q if you tried it
hardest part imo is deciding to draw the large right angle triangle
u think?
i cba to do maths anymore
it’s ok there’s always tmrw
what do u think it is?
these questions are too much
can u send another tmr tho
the hardest thing for me was forming the diagram correctly and funding the lengths of the small triangles and knowing to add them up
ok
ah
tbf
i agree
bcs i got the angles wrong
like i thought the interiors were 30 at first...
and i wouldnt have thought to write these pencil angles (30 60 90)
yeah u started tryna make it interior angles 😭
i wuld have just written it as 30 each time with a different normal
for me it just came to mind
wtf how
?
i don’t get the angles
sooo
just so natural at maths 😍
u turn 30 degrewes each time, so 30 adds each time
so 30 60 90
and the reason it isnt 30 each time
is because the normal (the daughbted nine) is in the same direction
what
so the tilt (direction of ant) is getting further and further away each time it rotates
daughbted?
thats the legnth
whats wrong with ur apps
nothing they are awesome 😉 thats why i have them
pls do lmk the answer to the worded part
ok
the vector question in that booklet is crazy
need atleast 2 hours to fully understand it
usually i love vectors but these ones 💀
spent like 40 minutes on it last week and gave up
my teacher rlly tried to tell me ‘it’s doable with gcse knowledge’
halp
\
i used 2 routes: GA and HE
OHH i think i kno wwhat i did wrong
haven’t done this q but i annotated the octagon
i wrote 3b instead of 2b
before i gave up
oh i see
label HC as na bc it’s parallel to AB
and AB is a
nope, doesnt change it....still got x=0
that’s what i did first
What are the 2 routes
that u used
um wdym two routes
like how i used GA and HE
real
so easy q
didn’t u refuse to help me with it the other day
vectors is the best maths topic
...
i’m being fr
no
what’s so bad abt it
fr x-a1/b1 = y-a2/b2 = z-a3/b3 😍
r u gonna help us with this q or
maybe
tell me the 2 routes pls
if not then go
id rather do that than revise for my physics test for tomorrow
i did GA and HE
physics is w subject
like its just cool
how the universe works
r u sure abt that
idk man electromagnetism is a disgusting topic
with all the generator effects and stuff
and motor effect
ah so we are both on that atm lol
real
a level physics is cold
anyways, help pls freesniper
i don’t even understand it
💀
cant promise anything
ofc
ok
do u agree
those are defo the 2 routes to use
X does not lie on any other lines
= to what i said
and added them
see dotted lines
u drew a whole watermelon* rectangle last question
ok
shall i say what i did
magnitudally💀
what u mean by that
idk if it is a word, but u get what i mean
nvm just vertical component
idk why i said magnitudally
hm ok
defo over complicating things
what i did was i made a line HC
labelled it na
bc it’s parallel to vector AB
me making a mistake is goodnews
labelled HE nb
bcs u defo need to find GA and HE
bc it’s parallel to GF
yea i’m getting to that
okk
Wait icl idek if i should have made parallel lines
do we start getting angles in there
angles 💀
every interior is 135 😉
no angles needed
probs u righyt
what paper is rhis from??
god knows my teacher gave it to me
i can send it to you
lemme continue
let’s find HG and HA
too much maths today ffs
aha
WE GOT HC AND WE GOT HE bc their parallel ok
i made the line HC
and i labelled them na and nb bc their multiples
do u get that
i’m gonna reprint this question once sec so i can draw
just peutting an idea outthere
we dont need to use their vectors
yes pls
we can make our own vector quantities
if u get me?
. LETS SAY HG = a GF=b
fjkds;lkfjlsdfg
nvm
wed need 3 equations
which we dont have
@midnight otter help us get HE and GA please
HE=n(b) oui
is the vertical ccomponent of BC = vertical component of CD <@&791435371564892232>
this is the original
dont use n for bothj
if this is true then this question is a cake walk - except it cannot be true otherwise x=0 😩
ok we can find HA the same way by adding the path
HG=b(n-1)-a
Hence
HE= b(n)
Anddd
we a re back
to square 1
idk what i was expecting
lmao
this is funni
gcse photography
💀
who knows 😉
is what i’m doing right
maybe
howd u get Ha???
actually u probs don’t even know
fr
added AB BC and HC
u still have 3 variables and 2 equations
i think he's just tryna compensate for the fact that he cant do this either
i can use n
brilliant mentor
real
u cant use it twice
u dont know that x(AB)=HA
y(BC)=HE
u dont know that x=y
but thats what u stated
they are 2 separate fractions of the lines
whend i get GA
yeah thats wrong
thats when i was assuming that
the vertical component of the diagonal segment=vertical component of vertical segment... if u get me...
BUT acc explain why i cannot use n twice
.
what’s the vector ur on about
no vector just vertical component... like here, the diagonal dotted red is probably longer than BC is in reality
not probably - it is longer than BC is in reality
bcs since regular octagon
then same legnths
then because diagonal is at an angle
it wont cover the same vertical distance
u get me?
its like pythagoras
no i don’t get u
kindve an abstract link
think of these 3 lines
as separate
the vertical component of the hypotenuse is only = to the vertical component of the a
because it is longer
if it were the same length then the vertical component would be less.
vertical component of c=a here.....
chaos boutta solve it all 😍
if length of c = length of a.
then b would have a vertical compoonent (assuming a has no horizontal component)
... but.... you are reusing n....
can i not use n for two separate parallel lines
fr🥶
the method itself is fine, but like sniper said, there are then 3 variables (assuming u do it correctly) - correctly being where you have 2 constants, n and (E.g.) m
physics is horrible i’m not choosing it for a levels btw
n is just a placeholder for a multiple it can be anything
probably can cuz its regular
it wont come up
who says
me
how do you know
cuz im very smart
ok ill change it
if it does come up
(it wont)
nobody will get it right anyway
thats not how u r using it though
i can
good night plebs i love yall
see growth mindset
uve spent probably longer than an exam is trying so far 🥶
no finish this q before u go
that’s true but i wanna have the accomplishment of getting a hard vector question right
ive summoned people from math discussion
now its just if anyone cba
u should become an english nentor
no
why
why u think that
it is way better than maths i agree
😧
@bitter bough halpp
actually
sorry for ping
just bcs he said to i shuldnt have
💀
🥴no
ur feedback was super helpful
english over maths any day
that’s so nice to hear i’m glad
what is it
how tf r u good at everything
remember the original question
Pls 😭
what is HE and GA
at first I thought the vertical component of BC = vertical component of CD
but that isnt right - if it was i end up with negative values of the constants
im saying that u cant use n for both expressions
this is wat i’ve done
u can find n
idek if HX is -GH + some amt of GA
with some trig
once u get HE and GA
udo
x(HE)=y(GA)
equate coefficients of a and b to solve for x and y simultaneously
the hard part imo is getting HE and GA
if i can do mental maths, it should be that n=1 + sqrt(2)
hmmmm remember the answer is an integer
can u see if what i’ve done is right or have i done it all wrong
nvm that shouldnt effect it
.
ignore what i said
alright gn
sleep tight
dont let the bed bugs bite
dont close this pls
or send me explanation
u need to see the other ways to do it (my way)
seems good
k(HE)
is it -GH and a some part of GA
oh ok
is this the right WO i tried to find k
or should i have called it a different letter
i’ll continue this another time it’s too long
i wrote working out for n twice oops
Mb 💀
💀
HE=n(b)
GA=n(a)-n(b)
HX=x(n(b))
GX=y(n(a)-n(b))
GX=GH+HX
WHAT IS GH? <@&791435371564892232>
GH=b+a+n(-b)
HX=x(n(b))
GHX=GX=b+a+n(-b)+x(n(b))
.**FROM THE 2 LINES ABOVE, **equating coefficients
xn=1-n+xn
so n=1...
that cannot be correct... what did i do wrong
<@&791435371564892232>
I suppose because i equated the 2 equations of HE
@oblique kelp the ant thing part ii) might just be, the ant travels negative distance
its not a correct statement - this is why we disregarded it
so it sounds like a correct answer
wait have u found the answer yet or u still stuck
yeah i thought so
we can work from this since ik it’s right so far
Will help when I can
no, will try in approx 1 hr
i’m doing it i changed my mind i nearly there tho
soo
we need GA and HE
HE=n(BC)=n(b)
GA=GD+DA=n(AB)+n(-BC)=n(a)+n(-b)
HE=n(b)
GA=n(a-b)
HX=x(n(b))
GX=y(n(a-b))
HX=GX+GH
GH=GF+FE+EH=b+a-n(b)
HX+GH=y(n(a-b))+b+a-n(b)
HX=GX+GH
x(n(b))=y(n(a-b))+b+a-n(b)
HX= 0a+xn(b)
GX+GX (which is = to HX) = (yn+1)a (-yn+1-n)b
Hence, equating coefficients:
yn+1=0
-yn+1-n=xn
. **need a third equation in terms of x **
is it possible to get the answer just from this?
@oblique kelp
perhaps we can input that yn=-1 from the first equ into the second
-(-1)+1-n=xn
2-n=xn
xn+n=2
n(x+1)=2
n=2/(x+1)
hello lemme read this
shall i send what i’ve done bc i’ve got an answer to the question it’s just maybe i’ve gone wrong somewhere
i’ve got some equations
did u use the same constants
i used n and y
u need 3
the final ans?
no
can u show me the methods? for this?
i mean idk what i was doing but i think my method is right take a look
i got my y and my n
and i worked out what they both were
if u got these values then u got the final answer
sure
wait can u use the same variables as me
what variables did u use?
I made hx=x(HE) and gx=y(GA)
and i used n the same a su
as u
ok so i used y as a scalar amt for HX
wait
i made HX = y x nb
bc HX is obvs a part of the line nb and we wanna find that
damn i’m lost
we need GA and HE
HE=n(BC)=n(b)
GA=GD+DA=n(AB)+n(-BC)=n(a)+n(-b)
HE=n(b)
GA=n(a-b)
HX=x(n(b))
GX=y(n(a-b))
HX=GX+GH
GH=GF+FE+EH=b+a-n(b)
HX+GH=y(n(a-b))+b+a-n(b)
HX=GX+GH
x(n(b))=y(n(a-b))+b+a-n(b)
HX= 0a+xn(b)
GX+GX (which is = to HX) = (yn+1)a (-yn+1-n)b
Hence, equating coefficients:
yn+1=0
-yn+1-n=xn
. need a third equation in terms of x
is it possible to get the answer just from this?
perhaps we can input that yn=-1 from the first equ into the second
-(-1)+1-n=xn
2-n=xn
xn+n=2
n(x+1)=2
n=2/(x+1)
1:(HE/HX) -1
1:(1/x)-1
upated method
- we either need a third equation
<@&791435371564892232>
can a math mentor pls go over my method
see if its all valid
There's no way that last line is correct, but algebraically i see no error
(1/x)-1 is not an integer
ok now we can make equations
help. or tell us that you dont know how.
i still haven’t actually done the ant one yet💀
soo HX = y x HE
and HX = nb
so now i can say that the amt of a’s in xn-1 is 0 so we can say xn -1=0. ??
no he did some of it and dipped
didnt he tell you n
yeah
i thought it was easy from there
no way look at the q there’s so many things we need to find apart from n
we gotta find k and y
whats y
do you have HG and HA
yes
then since you have n its easy from there right
cuz u just have two lines through x
im not reading that icl
yeah
compare coefficients then u have lambda and mu
lambda what
can i not do HX = HG + fGA
yes thats the second line
if u have GA u dont have to do the simplifying that i was doing
i just went off you having only HA and HG
if i wanna do the path HG and fGA shall i just add them up and i’ll get (fn-1)a and (fn-n-1)b or nah
also is lampda supposed to be used in maths
its used a lot in vectors
yes
u have the identity in the 3rd line of what i have done
so you simplify everything to be some multiple of a and some multiple of b
then you compare things
and get simultaneous eqs
i got fn-1=0 😭 and i can rearrange to get fn=1??
ur trying to find f
u said u have n so thats means u have f
so you can work out hx
for HE i got nb
for GA i got na- nb
for HG i got -a - (n-1) b
for n i got root2+1
and then i got k = HX / XE
i know HX = yn
actually idk
i got 3-2root2 for y
so if ik that HX = yn i just do 3-root2 x root2 + 1
i have hx = -nb
how did u get that
i just got HX = n x nb
oh i get it so is that ur final answer?
cause i got smthing diff
also we gotta find K
so do we do HX / XE
@somber sparrow did u get somewhere
thats just hx
u need to find the other thing in the ratio
did u get y
nah the way i’m doing it makes so much sense then using lampda
oh y is something i made
look at what i sent earlier if u wanna understand but u said i’m not reading all that
i got a final answer just do the q and tell me if it’s the same
if u can be asked took me days to do this
no thanks
why i thought u like to do maths
this doesnt count
why cause it’s vectors
exactly
this is can be done with gcse level skills yk
so can most things
nah bc some things have alevel topics
what’s lampda units for again
anyways i got K = root2 - 2 / 2
lambda
why r u using wave speed units
or is it wavelength
idek
its conventional
always in vectors we use lambda and mu
r = a1i + a2j + a3k + lambda(b1i + b2j + b3k)
always lambda
in planes too
crazy
fr
i’m never using lampda for vectors
just gonna use x and y
can one of u explain a question pleaseeeeee
depends what it is
it’s a cool word icl
probability
r u agreeing to do it
no
fill in the table
am i meant to multiply it
no
then what
what if they’re the same
then see how many 1's there are
then its 0 either way
8?
no
how many
9
so it’s 9
maybe
i don’t understand why though
oh it’s asking the prob for it being 1
im gonna try another challenge type of q but this one is easier wanna try @oblique kelp after u done w ur probability
it’s more doable
lol
since u said u wanted to try a q today
yh i’m done with probability
hopefully i can acc do it😭
u can
defo
,rotate
i tried smth but i highly doubt its right
ok
tell me what u did
first find speed of them both
or find an expression for it
I got d(1-1/n)
im pretty sure its right
imo only hard part is removing s
like i used s=dt
so fast kid n(s)=d/t
so t=d/ns
slow kid s=dt
so t=d/s
por sorry 2d
bcs its there and back
so 2d/ns vs d/s
take out common s
2d/n aand d
2d/kn and 2d/k?
and bc he’s n times faster u multiply the second one by n? so u can equate them? @oblique kelp
idrk
nah andy = k and ben=kn
so ur right u need to multiply by n
u get it ?
time for ben to get to the end of path is d/kn
,rotate
i just wrote that but how if that meant to show the answer
How are there so much people writing on this thread
lol idk it was open for ages
@somber sparrow what u get for vector i got an answer 2
what i wrote is not 2
4root2-4/8 = (roo2-1)/2
thats the simplified
this what i got can u eeee
see
is that the same
i’m guessing we did it very diff ways
i got this using parallel lines yk
u used angles 💀
how else do u get root 2
i did it ina way that didn’t need angles except to find n by using trig
found out my n and y and then subbed them in equations i made
that
doesn’t count tho
anyways this question has caused me too much stress
how long did u spend on it
9 hours is crazy 😭 i mean i started this a few days ago and left it and came back to it yesterday and then came back to it today and then spent like 2 hours
i probs spent the same amt of time all together
this would never come in gcses trust me
lmao
it’s just challenge questions
😭
but some of these will
it’s supposed to be doable for gcse but idk man
imagine if this was in a paper
ok i’m gonna try another q tmrw @somber sparrow i’ll ping u
<@&791435371564892232>
Put 2 into vertical bisect B
split AC into x and 6-x
get expressions for AB and BC in terms of x using pythagoras
multiply the 2 squared values of AB and BC in terms of x and half them and set them as = 36 (because Area of triangle =6, 6^2=36)
@somber sparrow im did something similar what i did was i said 1/2ab= 6 and then i said 2ab=24
then i did pythagoras a^2+b^2=36
then i added 2ab to both sides and said
a^2+2ab+b^2= 36 + 2ab
i know 2ab= 24 so i just did 24+36
so now i have (a+b)^2 = 60
and i square rooted
and got a+b = 2root15
then
we know a-b= 2root 3 i forgot to say
this is so@confusing lemme write it out
this what i did @somber sparrow
how do u go from a-b=2root3
to a+b=2root15
the line a-b-a+b =2b
towards the end- like 7 ish lines from bottom, maybe 6
that is just 0=2b,which is false
i made two equations
oh yea ur right
i did a mistake somewhere
yeah... i dont think its valid to take 1 equation and make it into 2 by adding different values if you know whatr i mean
lemme explain what i did it’s profs wrong but
the first thing i did was do pythagoras = a^2 + b^ 2 = 36
and i know 1/2 ab= 6
and i made it easier for myself and made 2ab=24
thenn
now i got a^2 + b^2 = 36 and ima add 2ab to both sides bc i know 2ab is 24
so then it just becomes a^2+ 2ab+ b^2 = 2ab which is (24) + 36
so we get a^2 + 2ab+ b^2= 60
then i can simply to make (a-b)^2 = 60
+- 2 root 15?
then i square root and i got (a-b) = 2root15
yeah, +-
yeah but let’s jus use positive
so now we got (a+b) = 2 root 15
now we wanna find what a-b is
so we make a similar eq
oh yeah a+b not a-b
oops yes
a^2-2ab+b^2 = 36 - 2ab (which is 24)
so a^2-2ab+b^2 = 12
and then we simplify
and get (a-b) = 12
i mean squared
and we get (a-b) = root12
which is 2root3
do u get how i did that
then i wanna find 2a which is (a+b) + (a-b)
and it’s equal to root3+ root 15
acc
wait
i made a mistake to find the b’s
riad just dont even try icl
my screenshot button brock again smh
where u come from
my computer
why
i was doing just fine working this out
also is there a faster way but i swear it’s alevel
I was gnna but then I won’t decide to now
damn ok
ye and then the perimeter is a + b+ 6
so we add them all up
and u get 6+ 2root3
right?? idk
just only use positive
wait
nvm
it’s the same thing either way
did u get the final ans
thats my b
ill do for a
i get the same list
bcs its +-
wdym
ur only supposed to get one a not 2
yeah
u were right
no +-
@oblique kelp
yeah that’s right i accidentally wrote 2root3 cuz i used the wrong number but yeah
if u look at the numbers i added i just added them wrong cuz i didn’t have a calc 😭😭