quick question | Revision Server | Page 1

azure bobcat Jan 25, 2023, 6:11 PM

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So if they get c correct and have 4 marks per, then 4c would be their points for the correct questions

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To get the ones they got wrong you would have (a - c) since a is every question they did and c is just the right ones

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And they lose 1 mark for each of those, so you'd just subtract (a-c) from 4c

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For part 2 you simply plug in the values you're given and the only thing you actually need to find is 3/4 of 20 to plug in for a

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@rich meteor

coarse idol Jan 25, 2023, 6:21 PM

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a) 4a-c?

azure bobcat Jan 25, 2023, 6:21 PM

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No?

coarse idol Jan 25, 2023, 6:22 PM

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b) 3/4 of 20 is 15. 4x15 = 60. 60+c = 80. c = 20

azure bobcat Jan 25, 2023, 6:22 PM

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4c - (a-c) (brackets unnecessary but helps with understanding it)

coarse idol Jan 25, 2023, 6:22 PM

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are u actually a year 8?

azure bobcat Jan 25, 2023, 6:22 PM

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Yeah that's just my expression simplified

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Helps to understand it when you spell it out

azure bobcat Jan 25, 2023, 6:22 PM

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coarse idol are u actually a year 8?

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azure bobcat Jan 25, 2023, 6:23 PM

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coarse idol b) 3/4 of 20 is 15. 4x15 = 60. 60+c = 80. c = 20

You saying they got 20 question correct and attempted 15?

coarse idol Jan 25, 2023, 6:23 PM

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ye cos it says each correct ans u get 4 marks

azure bobcat Jan 25, 2023, 6:24 PM

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Your formula is incorrect

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a is attempted and c is correct

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In your formula you've got 4a

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But some of the attempted are wrong

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You want 4c

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And then subtract the wrong ones (a-c)

coarse idol Jan 25, 2023, 6:36 PM

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oh yeah

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that makes sense

#quick question