#WORK DONE ENERGY QUESTION
167 messages · Page 1 of 1 (latest)
oh mb
i did a
how to do B?
EK=GPE+EK i think or
im not sure whats happening
i see EK
Hold up
BRUH
I wrote tan = 3/7 😭
I legit can’t read
2/7*
- was reading the wrong thing
Wait I’ll show u in a second I’m just redoing it
I’m sending it now
@sage mirage
oh my bad
16G
where did 16g come from
why is the reaction force 16g
i found what alpha was
26.8
36.8
Using the triangle
3 4 5 triangle
U don’t need it
i used it to find the reaction force
Ure not meant to do it like that
hmm
how do you know what alpha is tho
why is alpha 4/5
Wdym
wait is that 3 or 5
R=4gcosa
yep
5
whats a then?
Wdym a
in here
Ure substituting exact values for cos
Cosa=4/5 from here
Find missing length using Pythagoras
Cosa=a/h
Wdym
tan a = 3/4
ohhh wait
i see what you did
nvm
im used to find the angles way to much
nvm just substituet
KE=GPE+WDF
kinetic energy = work done + gravitational potential energy
yea
Good
wait why is it WDF
work done for the friction is 22.6
ye
Yh
ah 2.5(3/5)
h= 2.5(3/5)
where did these numbers come from
oh wait
what are the components
It’s the vertical component for the height
yeah
sin a = x/2.5
yeah
Then put that in GPE
but then it would be 2.5sina x 4g +22.4
YH
where is 3 and 5 in this
Edexcel Further Mechanics 1
Fri 3/4/20
WE said that h = 2.5sina
You’ll understand it after u watch this