#differentiation

18 messages · Page 1 of 1 (latest)

obtuse hollow
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Find the derivative of 1/9 sec3x^2, I thought you used the chain rule so 1/9 times secu^2 which will then just be 1/9 times tan u times 3 ,so it's just1/3*tan3u

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But its not

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<@&791435371564892232>

keen plank
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Use product rule on secx*secx and you get 2sec²xtanx

keen plank
past totem
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Me when brackets

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I don’t know what the question is

keen plank
past totem
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What’s the question

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(sec(3x))^2?

keen plank
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Differentiating 1/9* sec²3x

past totem
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Oh yeah

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Your very smart 🥰

obtuse hollow
keen plank
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It’s given in the formula sheet

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But you could use quotient on 1/cosx

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(0*cosx-(-sinx)1)/(cosx)²=sinx/cos²x=tanx1/cosx=tanxsecx