#multiplying out brackets
146 messages · Page 1 of 1 (latest)
sorry its cut off whats x =
@waxen sentinel
also for a) you can actually simplify x^0
x=6
but in the answer it says this for A)
mmm
0
X * 0 = 0
thats times not to the power of
if i went from 2^0 to 2^1
what must i have done
I’m not sure
No one
wdym by that soryr
for x^0?
Yeah
yeah x^0 = 1
Oh how
Oh I meant for 2^0 to 2^1 I don’t see why it’s multipled by 2 to reach 2^1
so do you know your index laws
Yeah the smaller version of numbers
Yeah
Forgot a bit of it tho
how would you simplify that
2
why
Wait
Oh so the fourth law of indices says x^0 = 1 but to me it doesn’t really make sense
But it is a law so should it just make sense like that
well we can use our other laws to show it
can we go back to like
how would you simplify 2^0 times 2
if you didnt know what 2^0 was
wheres 1 come from sorry
you cant do that
Oh
4^1
nop
heres a reminder of the laws
im interested in the last one on the left
x^n times x^m = x^(n+m)
2^1
perfect
so 2^0 * 2^1 = 2^1
so
you can see that multiplying by 2^0
hasnt changed our number
right?
Yeah
both sides of the =
from this
2^1 = 2^1 = 1?
nop
Oh
anything divided by itself is 1
2^1 is just some number so
2^1 / 2^1 = 1
right?
Yup
So I have to apply this strategy to the question I was given
cuz we have the same like
3^0 * 3^1 = 3^1
so 3^0 = 1
like its exactly the same
theres nothing special about the bottom number
Yep by memorising the laws would it be a quicker way of doing that bc you’d instantly know what 3^0 is
1
ohh ok I’ll do this question and show you what I get
epic
I got confused again, because in this occasion I’m not actually multiplying
yeah so
theres actually another way of writing 6^-1
without the power
if you remember?
yep
6/1?
other way round
1/6
now you gotta add fractions
7/6?
perfect
ohh, thank you so much!
nw!
Imo it shld be (x+1)/x