equation of circul idk WTF THIS IS

[frigid lantern]

ok

whyd u plug in -4

how do you know D is directly under the centre

ok so basically

u see y=2x+6

u plug that in for y in the equation of the circle

so now you only have one variable x

and then you jst solve

yw

u get two solutions and also this is a dumb question because how do you know where D is and where E is

i guess its interchangeable

yeah you get 2 solutions

so u get 2 coordinates where the line DE intersects the circle

but in your diagram D could be anywhere on the circle and E anywhere

you're assuming D is on the bottom half of the circle and E on the top half

np so yea D has two possible coordinates and E has two possible coordinates

usually they would have something that makes it clearer like D is above the x axis or something so you only get one possible solution for each

[civic bloom]

Hmm can u do this by using distance formula and then u will get a equation in form of x^2 +y^2 ig then u can do simulatneous equation with the equation of the circle?

Like u cam find the radius and find point D and do the same for point E

@frigid lantern will u get the right answer doing this ?

[frigid lantern]

No because u dont know the distance DE, the length of a chord is not equal to the radius unless it goes through the centre which you cannot assyme

[civic bloom]

Nah but

[civic bloom]

What about DC

We can take DC (length ) and prolly we will get an equation for an imaginary line passing through point D and u can combine the equation of the circle and the equation for D then u get solutions for D

[frigid lantern]

You need the coordinates of D for distance formula though?

[civic bloom]

Yea so what I'm saying

[civic bloom]

Hollon I'll show

[civic bloom]

Forgot to show 💀💀lol

[frigid lantern]

If u were gonna do it the way i thought you would u would have two variables x and y so you cant solve since youll only have one equation

[civic bloom]

No so basically if u use distance formula u can just plug in the coordinates of d as x and y so basically u get a equation for D then u can plug that equation into the equation of circle cuz they meet at D then u will get the values for D