#hidden quadratics

71 messages · Page 1 of 1 (latest)

mossy zealot
real stratus
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Rootx = y

elder sluice
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wait this is fm?

mossy zealot
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yessir

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i got 17 pages of this to do

elder sluice
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id rationalise the first fraction so they are both over x

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then u can add them and have one fraction over x

mossy zealot
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5root x/x

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right

elder sluice
steady hamlet
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💀

real stratus
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Lmao

elder sluice
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wait did i mess up

mossy zealot
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i think u did something wrong

real stratus
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Nope

mossy zealot
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no

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u didn't

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dw

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i now know what to do

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i times both sides by ex

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thx bots

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boys

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not bots

elder sluice
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also @mossy zealot is it aqa fm?

mossy zealot
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yeah

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wait

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i think i did something wrong

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i got thingy

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3 root x 2 -5 = 0

elder sluice
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this guy is amazing for aqa fm

mossy zealot
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i see

elder sluice
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he still needs to do 2 more videos on trig other than that hes done with everytrhing

mossy zealot
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but for the moment

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he don't do

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the thing i am doing

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can u help

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i get 3rootx 2 -5

west ingot
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One of u’s help me

elder sluice
mossy zealot
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cause i took it from the other side

elder sluice
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u cant do that

mossy zealot
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oh

elder sluice
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since on the other side its being multiplied with x

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not added with x

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if that makes any sence

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i can elaborate more if needed

mossy zealot
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oh i see

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so then it becomes 5x

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so i get

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3root 2 = 5x

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right

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now to take the root away

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multiply by x

elder sluice
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3rootx + 2 = 5x

mossy zealot
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gets u 3x +2x = 5x^2

mossy zealot
elder sluice
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if u do one thing on one side u have to do it to the other side

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tbh idk how to do this instantly give me a min to think

mossy zealot
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so i get 5x^2 -5x

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what do i do from there

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do u k @elder sluice

elder sluice
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wqait

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could it be 1

steady hamlet
# elder sluice 3rootx + 2 = 5x

Let root(x) = y
You’d then have
3y + 2 = 5y^2
5y^2 - 3y - 2 = 0
5y^2 - 3y - 10 = 0
(5y - 5)(5y + 2)
y = 1
y = -2/5
rootx = 1
rootx = -2/5
?

mossy zealot
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oh i see

mossy zealot
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ur gods

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both of u

green marten