#chapter 3
51 messages · Page 1 of 1 (latest)
for b, the line has y intercept -31/2 which is -15.5, not -16.5 btw
np
ill check d
you can see from the graph that the line p(x) is below the curve q(x) when x<1 and when x>11/2
using set notation, you’d write this as:
{x: x<1} U {x: x>11/2} i believe
no problem! happy to help
can you double check another question as well please lmao
sure
it doesnt intersect so i shouldnt equate but im not sure
is the left side working out enough for the awnser??
okay so
since they don’t intersect, it means that b^2 - 4ac < 0 i believe
p is a set of possible values not just a few values by the way
so would it be p<32/9
you solve 9p^2 - 20p + 8 = 0, then sketch the graph of 9p^2 - 20p + 8 < 0
i don’t think the left side is relevant but i’ll recheck
mhm
that’s true i’ll need to think a bit
alright no problem
i think it’s still helpful to find what the values of p would be where they intersect the realise if p is below that then they won’t intersect but let me graphically check rq
yeah i checked graphically and i was right so
you want to find the values of p for which 9p^2 - 20p + 8 < 0 is true
you do this by sketching the graph using the solutions for 9p^2 - 20p + 8 = 0 you calculated
so i sketch the grap with the two awnsers of +/-
yes
and then check where its below 0
yep
this graph of the functions for different values of p will help you understand your answer once you get it
{p: - root<p< + root}
alright
yeah