Differntiation

[opal cedar]

May someone pls help me with question 3, I'd appreciate it

[exotic blaze]

this is the method, i’ll then explain what i did:

so i used the product rule to differentiate y^4 ln(y)

i factorised out y^3 just to neaten it up you don’t have to

i then used the fact that the dy/dx is the reciprocal of dx/dy to find dy/dx

i then just substituted in y as e then simplified

[exotic blaze]

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[opal cedar]

ok thank u mate @exotic blaze