#Parametric equations
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hm
x/a = sinΘ
so sin²Θ = (x/a)²
so then y/b = cosΘ
so cos²Θ= (y/b)²
Using --> sin²Θ + cos²Θ = 1
so (x/a)² + (y/b)² = 1
so x²/a² + y²/b² = 1
And I believe its an ellipse
cause its +
so it should look like a stretched out circle
like this @balmy inlet
The curve is an ellipse yh
but if it’s a cartesian equation shouldn’t it be in terms of x and y only?
yeah it is
a and b are constants