#Factorising

53 messages · Page 1 of 1 (latest)

meager agate
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can someone explain how to do this please <@&791435371564892232>

deep coral
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is this a mock question

meager agate
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its from a past paper

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2019

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question 14

deep coral
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alr

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so we can see that theres an x+y in both terms

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so we can factor that out

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(x+y)[(x+y)+3]

meager agate
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i dont get how we can just do that

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is that just a rule u have to knoww

deep coral
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well

meager agate
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or is there like an explanation

deep coral
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how would u factorise x^2 + x

meager agate
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x(x+1)

deep coral
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so now if x = x+y?

meager agate
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wait how dos x go from x(x+1) to x=x+y

deep coral
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i think it was a bad example

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if u had z^2 + z

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ud make it z(z+1)

meager agate
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yh

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yh

deep coral
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so if z = x+y

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just change all the z's to x+y

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so youd have
(x+y)^2 + (x+y)
(x+y)[(x+y)+1]

meager agate
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x+y(x+y+1)

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ooh

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yhh

deep coral
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yeah

meager agate
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so wait if we go back to the question

deep coral
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you just factor out the x+y

meager agate
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so wait

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what do u get when u do that

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which x+y are we factoring out

rigid ermine
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SpongeBob hear me out

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Start off by timesing out everything

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What do u get

deep coral
deep coral
meager agate
meager agate
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expand those

deep coral
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for the question lets say z = x+y
then we have z^2 +3z
so z(z+3) and we just sub back in x+y
(x+y)(x+y+3)

deep coral
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waste of time

meager agate
meager agate
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but isnt that different to the question

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do u happen to know the name of that topic i think i need to watch a few videos on it 😭

deep coral
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its just factorising

meager agate
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do u know any videos that go through that type of factorising

deep coral
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no

meager agate
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nws thanks for ur help