#Parametric
4 messages · Page 1 of 1 (latest)
y=cos2t+1 = 1-2sin^2t + 1 = 2-2sin^2t = 2-2x^2
range: 0≤y≤2
so 0≤k≤2 as y=k is a horizontal line
so you can use the cartesian form of the equation
4 messages · Page 1 of 1 (latest)
why did they make the y part equal to k
i thought you needed the whole equation to be equal to k
y=cos2t+1 = 1-2sin^2t + 1 = 2-2sin^2t = 2-2x^2
range: 0≤y≤2
so 0≤k≤2 as y=k is a horizontal line
so you can use the cartesian form of the equation