#is this right?
11 messages · Page 1 of 1 (latest)
Shouldnt it be +-4?
p^2 - 4(2)(-2p) < 0
p^2 + 16p < 0
p(p+16) < 0
graph that
and its the area between -16 and 0
so i'm right
ye
11 messages · Page 1 of 1 (latest)
<@&791435371564892232>
Shouldnt it be +-4?
p^2 - 4(2)(-2p) < 0
p^2 + 16p < 0
p(p+16) < 0
graph that
and its the area between -16 and 0
so i'm right
ye