Complex Numbers

[heavy jetty]

sub in -i for z and do the mod ( youll get 4 )

if the half line passes theough the centre then sub in the centre ( as a complex number ) as z and show that it = π/6

thus the circle passed through the point z=-i as it satisfies the equation and then same idea for the half line

[willow ruin]

it doesnt satisfy the eq tho

for ai

[mystic arrow]

this stopped me from doing A level further maths next year 👍

[meager galleon]

it does

[willow ruin]

how

i got i +root3 -4

[meager galleon]

|-i - 2sqrt(3) - i| = |2 sqrt(3) + 2i|

which is sqrt(4 * 3 + 4)

by squaring each individually

which is sqrt(16) = 4

[heavy jetty]

It definitely satisfies it sir

[heavy jetty]

Interesting

[willow ruin]

how have u got |2 sqrt(3) +2i| to sqrt(4*3+4)

[meager galleon]

|a + bi| = sqrt(a^2 + b^2)

here a is 2sqrt(3) and b is 2

2sqrt(3) squared is 4*3

[willow ruin]

oh shit

okay thanks

[meager galleon]

nw!