#simultaneous equations
16 messages · Page 1 of 1 (latest)
solve simultaniously then set discriminant to 0
yh the solving simultaneously is what i cant do
wait do i solve it in terms of kx
then use discriminant
so from the second equation y = 1 + kx/2 then sub that into the first one
oh i think i got it
wait this is dumb but
if i have - x (1+x) would i multiply terms in the braquet by minus x or posotive x then just subtract what i get
@daring plume
do -x