Not sure if anyone even wants to look at this but its really interesting. Afterhome arg.

[vague dust]

It's a website called oricade.com/encrypted and its a really interesting arg made by oricade. While it isn't your typical arg, its still really advanced. I talked to Oricade himself about it and its really... mathematical. Idk hopefully yall can solve this cause its complicated.

[lone crystal]

Oh I saw a post about this on a different subreddit! Gonna get my accounting major roommate in on it maybe he can figure the math out lol

[vague dust]

Yea me and my team from his discord are on it but we can't get past the 1st phase

[vague dust]

Ok this isn't progressing at all

[random forge]

umm so i tried a few things suchas Project: Rebirth, Afterheavens, Ori, and Tyzi

and here is what i got out of it

J(l) = - gyy_{w=1}^g aiz_{j=1}^y t_wx * b_u * l_c evrrp [t_wx] > 0
eds mps thzlhg sr
(gjzh(fux(g, b, 1, 5)^2 - 56) * (gyy(y^2 / 2^d, s, 0, waf) + wba((1 + 1/b)^0, r, uby))) - (oozml(6) / (zoaqm(3) * utuan(2) * 4) * ((3! * zpmo(2)) / gyy(b^-2, g, 1, qbs))) + (glfao(h/pl(5q)) - (aiz(2^n, y, 0, 3) - (bbh(12b^2, j, 0, 1)))) - ((wgb(skp(-i^2), q, -wbj, uby))^4 * (9 / xw^2))

(qew/wsz_x)g(f,m) - izchl * goppm^2 * i(k,b) = t(e,t) / (cac * Q_t)
mfx bvr gshghw at
((ytcbr(ab^s + s^tu) - 28) * (rxb([[qbss(mvsxm), gbvv(ghpmo)], [gmzv(mpsga), nhgv(xtsmi)]]) + 3)) - (gdre(lia(r, z, 1, 5)^2 - 56) * gjzh(vne(q^4 * slt(-j), l, 0, bvt) + pod(iw)^2)) + (gyy(y^2, d, 1, 3) - (aiz(2^n, y, 0, 3) - (bbh(12b^2, j, 0, 1)))) - gjzh(vne(q^4 * slt(-j), l, 0, bvt) + pod(iw)^2)

U_yh + Ztupqa * r_nj = (8 * dm * S / q^4) * M_cj
nrp mvs ktclbg bf
((dna(y, o, 1, sofuo(4)) + Eedbrii(22 * qli(h) / n, m, 0)) * ((4/pt) * bbh(wub(q)/f, l, 0, vnq))) - (lia(o^2, w, 1, 3) * ((3! * nxbo(2)) / fux(g^-2, b, 1, wrr))) + (((8866128975287528^3) + (-8778405442862239^3) + (-2736111468807040^3)) - (gnu(2^b, a, 0, 3) - (iym(12l^2, l, 0, 1)))) - ((mzh(xfd(-k^2), x, -tgt, wrr))^4 * (16 / db^2))

zvb * (Df_b / Rh) = wuufi_ww,j + q_b
ofi fvx ovbsel ct
((gqwe(xw^r) - tctqs([[2,0],[0,2]])) * (hqh([[vwgu(tsxho), wuba(bvrtl)], [lwbl(fvxbo), poda(hvifo)]]) + 3)) - (bvh(3k^2 + 2, x, 0, 2) * ((3! * kxho(2)) / wga(g^-2, v, 1, waf))) + (Cxgwhgs(22 * vwg(m) / z, k, 0) - lefx(eif(v, b, 1, 5)^2 - 56)) - (oiyha(5, 2) * (2/dm) * ubm(1/aeet(1-i^2), q, 0, 1))

bofxo^2 * iaw(e) + [k(c)]^2 * igw(v) = -r(f)
tzs ghp zvcwfg hn
((tyozk(dw^i + q^db) - 28) * aeet(tgh(l^4 * ijd(-q), f, 0, waf) + nhg(dm)^2)) - (ubm(3f^2 + 2, l, 0, 2) * (fux(d^2 / 2^y, y, 0, mzt) + eqa((1 + 1/a)^0, n, tgt))) + (gyy(2^y, d, 0, 4) - oozml(6) / (zoaqm(3) * utuan(2) * 4)) - (btgca(5, 2) * (2/tu) * wgb(1/gdre(1-q^2), l, 0, 1))

rixht: (Y \ {e_ncnxdh, u_dscmqg}) x Rtaae^w -> E q (Oozml q {Z, F, W})^w
okm hue racgxe cy
((xvv_ffgqhmab(11) * 2 + bvh(fiy(q), l, 0, dm) + 1) * eif((v+1)/(2^b), a, 1, iyy)) - (giq(w^2, y, 1, 3) * (wmh([[poda(hvifo), lqbu(tsxho)], [wuba(bvrtl), vcgl(fvxbo)]]) + 3)) + ((fux(2^g, b, 0, 3) - (wrf(12l^2, q, 0, 1))) - c - lia(o^2, w, 1, 3)

R_DT(D || D) = iymsuvmz_{-bvt}^{vnq} i(l) * zss( d(q) / y(l) ) qx
lks hlq uawggs zy
(gevf(gnu(b, a, 1, 5)^2 - 56) * ((3! * zpmo(2)) / gyy(b^-2, g, 1, qbs))) - ((sff(2^b, b, 0, 3) - (mzh(12q^2, f, 0, 1))) * (ghm(v^2 / 2^d, y, 0, wrr) + zbu((1 + 1/b)^0, a, iyy))) + (uoqyo(w/ll(5k)) - glfao(6) / (kmafi(3) * unmxt(2) * 4)) - (rsx([[oclp(hueet), gwrt(hamhn)], [stgv(hlqht), kcfh(eashe)]]) + 3)

NGT = qbgerkoz_W || (pse_z / rrl_f) q (rsp_d / rxt_j) || qu oo
ofi fvx ovbsel ct
((jxchz(dv^e + p^iw) - 28) * (rif([[qhav(ghpmo), gmzv(mpsga)], [dbbv(xtsmi), qbss(mvsxm)]]) + 3)) - (gjzh(fux(g, b, 1, 5)^2 - 56) * gudh(bvh(k^4 * eii(-l), l, 0, mzt) + vwg(ci)^2)) + (Cxgwhgs(22 * vwg(m) / z, k, 0) - lefx(eif(v, b, 1, 5)^2 - 56)) - (grlvs([[2,1,0],[0,2,1],[0,0,2]] * [[1,0,0],[0,1,0],[0,0,2]]))

[vague dust]

One of the first things we gotta do is figure out how to make the letters numbers which is crazy because some of the letters decode to letters which would be pi, cos, sin stuff like that. Also doesn't the equations at the bottom kinda look like matrix problems

Oricade said there are like 8 phases so we might not be able to do this

[random forge]

well, i wanna try making the random letters words to see if they help at all

[vague dust]

Maybe some might but there's only actually like 3 words in the entire text

[random forge]

If some are translating to pi and stuff then it'll be interesting to say the least

[vague dust]

I should probably mention this flower might be important

I should also mention that oricade said the question marks are also math somehow

[fringe glen]

Oh the url is case sensitive

https://www.oricade.com/Encrypted

Oh is this shifted latex code?

Insert:
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Return:
XBCAVZOIQAISFWYGQTLKHLSZTJ

Insert:
ZYXWVUTSRQPONMLKJIHGFEDCBA
Return:
WYXTMOBTZHNVGVVBJKAXSUZEWK

The flower image itself is unnamed.png

It seems that the 2nd and 3rd letter of any encrypted word is untouched

Insert
A (typed 26 times)
Return:
XAAXRUIBIRYHTJKRACTRNQWCVK
Insert:
B (typed 26 times)
Return:
YBBYSVJCJSZIUKLSBDUSORXDWL

Insert:
A (typed 100 times)
Return:
XAAXRUIBIRYHTJKRACTRNQWCVKAAYTJYDHQAXAAXRUIBIRYHTJKRACTRNQWCVKAAYTJYDHQAXAAXRUIBIRYHTJKRACTRNQWCVKA

XAAXRUIBIRYHTJKRACTRNQWCVKAAYTJYDHQ is 35 characters long before the sequence repeats itself.

[fringe glen]

Yeah so the encryptor at the top is just a Viginere cipher with the key: XAAXRUIBIRYHTJKRACTRNQWCVKAAYTJYDHQA

[random forge]

teach me thine glorious ways bro

[fringe glen]

Typing A 100 times and Typing B 100 times indicates that the positioning within the word is shifted the same regardless of the letter.

So the first position is shifted 23 up, the 2nd isn't shifted, the 3rd isn't shifted and so on.
The cipher text you get out of typing A 36 times is the key.

Where A is no shift.

@vague dust Do you know of anyone that has any leads regarding the LaTeX code? I feel like the encryptor isn't related to it.

[random forge]

i ran the first set of text through a ceasar cipher and disnt get much useful but here it is, Hds Pps Whzokj VR

using the rule of ignoring the 2nd and 3rd character of each word anyways

[fringe glen]

2nd, 3rd, 17th, 27th, 28th, and 36th are ignored

[random forge]

what did you get running the first block of text through that

[fringe glen]

Scroll up

[random forge]

i meant eds mps thzlhg sr

what did you get for that

[vague dust]

Well we figured that much out but couldn't get past itt

[vague dust]

All i know is that its basically all math and only 3 things are actually words. A friend made a program for the encrypter thing tho

cipher=[23,0,0,23,17,20,8,1,8,17,24,7,19,9,10,17,0,2,19,17,13,16,22,3,21,10,0,0,24,19,9,24,3,7,16,0]
word="jooguauj"
result=""
for i,k in enumerate(word.upper()):
  char=ord(k)-65
  char=(char+cipher[i%36])%26+65
  result+=chr(char)
print(result)
result=""
decode="goodluck"
for i,k in enumerate(decode.upper()):
  char=ord
(k)-65
  char=(char-cipher[i%36])%26+65
  result+=chr(char)
print(result)

Also there is this which might be genuine important

[tacit dagger]

do you know what type of flower is that?

[fringe glen]

nope

[tacit dagger]

When typing orchid onto the box, I got this string of letters "LRCEZX". I tried translating it to caesar cipher but I got nothing.

[vague dust]

I believe its an Easter lily but idk

[fringe glen]

It's a viginere cipher encryptor

putting in "rrckrj" will give you orchid

[vague dust]

Not sure if it matters but oricade said he made the cipher by itself and its completely new

[fringe glen]

Either he's refering to something else or there's something else going on with the "enter?" cipher

[vague dust]

Another thing he told me was that the question marks??? Were math too

Not even sure what he means by that

Also the handshake function