<div id="Attacco" *ngFor="let i of moduli[index]">
{{i}}
<!--CREA ARRAY LUNGO QUANTO i-->
<p *ngFor="let j of i.length???">
<app-carta></app-carta>
</p>
</div>
#Need an array as long as a number in an ngFOr
crystal tiger
mellow patio
write a custom pipe that transforms a number to an iterable, then use pipe inside ngFor
stiff cape
a simple solution would be:
<p *ngFor="let j of [].constructor(i.length)">
<app-carta></app-carta>
</p>
but what is i? a string? a number? an array?
mellow patio
or use generator function inside component
protected *iterate(num: number) {
for (let i = 0; i < num; i++) {
yield i
}
}
i is a number
crystal tiger
a simple solution would be:
```html
<p *ngFor="let j of [].constructor(i.length)...
this worked tysm
crystal tiger
a simple solution would be:
```html
<p *ngFor="let j of [].constructor(i.length)...
could you explain how this works rq btw?
clear dune
could you explain how this works rq btw?
stiff cape
[].constructor(10) is the same as new Array(10) so it creates an array of 10 items but all empty.
then your *ngFor will iterate over the 10 empty elements
mellow patio
keep in mind, that it creates a new array every time change detection is run