shapeshift's default with respect to surroundings

[static salmon]

s.object({
  name: s.enum("A", "B"),
  other: s.object({ name: s.string }).default(/** if name is "A", default is { name: "abc" }, if name is "B", default is { name: "cba" }

[tender pike]

@static salmon to help others find answers, you can mark your question as solved via Right Click Solution Message->Apps->✅ Mark Solution

[acoustic pulsar]

s.object({
  name: s.enum("A", "B"),
  other: s.object({ name: s.string }).default(/** if name is "A", default is { name: "abc" }, if name is "B", default is { name: "cba" }

With actual code block

[static salmon]

oh wait yea sorry

also can I make a recursive shape

[acoustic pulsar]

@ionic elbow might be able to answer quicker than me or @void sand

[void sand]

I don't think this is possible now it will be possible after adding when

[ionic elbow]

I don't fully understand the question

[static salmon]

basically if the name is "A", then the default is { name: "abc" }, if its "B", then the default is { name: "bca" }

[ionic elbow]

Oh, conditional defaults

[void sand]

Once we implement when, You'll be able to do it like this

s.object({
  name: s.enum("A", "B"),
  other: s.object({ name: s.string }).when('name', {
  is: (v) => v==='A',
  then: (s) => s.default({name: 'abc'}),
  else: (s) => s.default({name: 'bca'})
})

[static salmon]

and the recursive object thing, what I mean is

const v = s.object({
  name: "abc",
  option: v
});

[ionic elbow]

Iirc we do support recursivity

[void sand]

yeah

[static salmon]

how do I do it tho, cuz js doesn't allow using the variable before declaration

[ionic elbow]

It should work

I don't remember exactly how to do it

[void sand]

true. In general, if anything isn't possible in js won't be possible in shapeshift too. But u can do it using lazy

https://github.com/sapphiredev/shapeshift/blob/807666ef537c84d2e0f8bd9f4ce1a8060bfb3fb5/tests/validators/lazy.test.ts#L40

[static salmon]

oki, thanks