math-help

[cyan night]

did i correct

why not

it looks very easy

just

pythagorean to find ac

then divide by 2

then add that by the x,y coordinate to the coordinate of the midpoint

depending on the symbol -+ i can get abcd

🤔

ye

tahtss what i did

did i get it correct

[covert briar]

@left knoll is it possible if ye could send a pic of ur working
sry im new to coordinate geo

[cyan night]

the distance formula wasnt taught in alg 1

[covert briar]

its my hw from my classes
by new i mean i started it like 2 months back

[cyan night]

that seems fairly easy

[covert briar]

yea

[cyan night]

i got it wrong

[covert briar]

if its childs play for ye send ur workin

[cyan night]

ok 1 minute

ok im waiting for jay's solution

[covert briar]

wait is it possible to get 4 root 10 into something root 2

[cyan night]

yes it is 8 root 5

jay can u rotate

wait is it unknown

or are u not done

ok

[covert briar]

hmm

i didnt get it yet but ty for the help

[solid anvil]

james started stream?

[fiery coyote]

okay, so i'll try explaining it to you, first of all, your 1st step is not possible, you can go from the 1st to the third equation, but the second equation is not equal to your first equation

so that in mind, you could write 4 as 2^2, that's what you do in your 3rd equation, meaning that on both sides of the equal sign, you have 2^x

that makes it easy to get rid of the 2 in the base by applying a logaritm

so 2^(2x) = 4^x , and 2^(x+2) = (2^(x))*4

[ivory pumice]

1, a - use sin(x+y) = sinxcosy+cosxsiny
B - use part a

2. a- divide and multiply by 13 , then you will get the answer , Cos(alpha)= 12/13
   b , max value = 13 when cos(theta-alpha) = 1
   min when cos()= -1
   C. Solve

3, find Sin B &Cos A and remember sinB >0 and cosA<0 , then use identity

I assume your test is over now

[proven orchid]

it is and I got it

[ember kernel]

Ok I can provide help for each of them if you need

[cyan night]

quentin pro

quentin do u know chemistry

what is FR

[ember kernel]

In my curriculum I must use these concepts as much as addition and multiplication everyday. Hence I'm kinda used to them

[ember kernel]

FR stands for French

[cyan night]

ok sir

[dense wadi]

@left knoll what are you using to divide it, were you given any factor?

[left knoll]

hey is anybody good at cycle permutations?

I'm having a problem with C

[drowsy fog]

Im having problem solving this, if anyone know how, please help me

The topic about function,
I might have a clue what it wants, but im not sure if my answers is right

[azure yarrow]

Is there someone who can help me with a question of functions in mathematical analysis 1, it is a short question

[cyan night]

wwhats the question i might be able to help

[azure yarrow]

if I have this function the graph is linear
What about the asymptote?

ex i

Sorry if you don't understand my question, I don't speak English very well

[uncut mason]

@azure yarrow , this might help:
https://www.youtube.com/watch?v=58dVDrrvTCw

[azure yarrow]

Thank you very much. That was what I was looking for. I didnt find some thing like that in my idiom

[inland heath]

I often use the calculator for 1.1

[left knoll]

yo can someone teach me simultaneous equations pls ??

[cyan night]

wdym

[left knoll]

y r we multiplying it by 3 and 5?

@cyan night .

[last echo]

That's because v can cancel out x and then get the value of y

Afterwards v can substitute the value of y in eq 1 or 2 to get the value of x

[left knoll]

oh ok but what if the question was different, how would i know what to multiply it with

[cyan night]

to get the common multiple in order to cancel out

[cyan night]

find the least common multiple between the coefficients

of x or y to cancel either

[last echo]

See u multiply so that u can either cancel the x or y term

[left knoll]

got it ..thx

[last echo]

Np :)

[cyan night]

npnpnpnpnpnpnpnp

[left knoll]

Hi guys

Kahn's flight departed Orland at 12:53 and landed in city X at 15:37. Both cities are in the same time zone. If her flight took һ hours and m minutes, for 0 <m <60, then find h + m.

Do you know what the topic of this task is? Like what I should find or other examples like this question. I just need to find out the topic and then I'll solve for myself. Thank you in advance

[cyan night]

@opal rock do u know the (a+b)^2 and (a-b)^2 formulas

[opal rock]

Yeah I have

[cyan night]

do u know vieta's formula

its really helpful

[opal rock]

No I haven't learn't that yet

[cyan night]

u can search it up its pretty straightforward

so let me give u an example of using a+b)^2 and (a-b)^2

[opal rock]

Ok I'm watching

[cyan night]

suppose u need to factorise x^2-2x+7 or something

u cant really group and factorise

so u want to make it under the form of a-b)^2

so recall x-y)^2 = x^2 - 2xy + y^2

here we have x^2 as x

and we want 2xy

so 2* x * y = -2x in this case

so y = -1

and we want y^2 so instead of +7

we do -1^2 = 1 and then trade off for 7 so +6

x^2 - 2x + 1 +6

=> (x-1)^2 + 6

yeah kinda like that

[opal rock]

Wait so your trying to factorise x^2-2x+7

[cyan night]

yeah

it actually doesnt have a solution

because u then have (x-1)^2 = -6 which isnt posible

[opal rock]

Cause like I was confused with the equation cause it doesn't have a solution but you can plot it on a graph

[cyan night]

under imaginary number?

if its based on i then ye it does have solution

[opal rock]

I heard of imaginary numbers but I haven't learnt that yet I don't know the content which is pretty much what I'm saying

[cyan night]

ye

i have a trick that can help u to factorise

[opal rock]

how?

[cyan night]

so suppose u have ax^2 + bx + c

u want to factorise

[opal rock]

ok

yes

[cyan night]

so u should make bx = mx +nx or sth right

so u can group mx with ax^2 or nx with c

theres a trick which is

mx + nx = bx and mx*nx = ax^2 + c

trial and error

u find mx and nx hence u can group

u got it?

my grouping i meant like (x-2)(x-3) or sth like that u want it to be like that so u can solve for x

example x^2-12x+36

i want to make -12x = mx+nx

[opal rock]

Ok I'm just gonna do my work real quick and If i'm in trouble then I will tell you

[cyan night]

mx+nx = -12x and mx*nx = 36x^2

=> mx = nx = -6

thats it

(x-6)^2

thats the trick

but if u cannot factorise then u use the (a+b)^2 or (a-b)^2

[opal rock]

How do you even know all this information and know how to do it like how exactly?

[cyan night]

because i study math all day

but i still suck lol

and the last way is to use quadratic formula

or use vieta's formula

trial and error

quad formula is the easiest, do u know how to derive from ax^2+bx+c to the quadratic formula?

i just learnt it yesterday

[opal rock]

I'm just factorising trinomials right now

[cyan night]

ok

i can teach u how to draw parabola based on quadratic

[opal rock]

Well I really appreciate the time and effort into doing this Thank you man

[cyan night]

ok

do u understand the methods yet

1. is the mx and nx

2. is (a+b)^2 and (a-b)^2

3. is vieta

4. is quadratic formula

or 5. is u factor normally where u can easily find mx and nx

tonight ill try deriving quadratic again

[left knoll]

Can any1 explain me wy n.1 is 7q2 and n.2 is -12c ?

[fringe ibex]

can anyone solve this diff equation please

[cyan night]

1. is because 2 negative signs multiply to get a positive and 2) is because negative times positive is negative

[left knoll]

Ahhh got it tnx

[cyan night]

no problem sir

[left knoll]

@cyan night can u plz explain this one sir

[cyan night]

where do u need help?

9x*-3 = -27 => -27b^2

[left knoll]

. 9 is bigger

[cyan night]

but its multipled by a negative so it becomes negative

[left knoll]

Hmmm

[cyan night]

negative * positive = negative

pos * pos = pos

neg * neg = pos

[left knoll]

But the answes is -27

[cyan night]

ya

positve * negative

9 is pos -3 is neg

[left knoll]

Pos*neg = neg?

[cyan night]

yes

i mistype

[left knoll]

Oh

[cyan night]

ya sorry

[left knoll]

Ok.. tnx again

[left knoll]

No problem

[left knoll]

Can anyone solve this?

[oak solstice]

867

[left knoll]

Thanks!

[oak solstice]

no worries

[left knoll]

How did u solve it?

3(2(12x8+10x8)-63)=867

[oak solstice]

like we will not take base area

[hollow escarp]

I'll post an explanation in five

[left knoll]

Oh thank you a lot!

[hollow escarp]

No worries

[left knoll]

The geometric series a + ar + ar^2 + .. has the sum equal to 7, and the terms containing odd powers of r have the sum 5. Find the value of the sum a + r.

Anyone?

[foggy isle]

sum of a+r is 5

[hollow escarp]

Do you have the final answer ?

when i solved i got -8 😅

This is how I solved. You can refer to this. Not completely sure if this is correct or not. Please check with someone if possible @left knoll

[foggy isle]

actually i think u got a step right that i didnt for a = ar

[foggy isle]

yeah 8 final

[pearl tusk]

who cares abt math bro

[languid zenith]

Hey... Man. They are just trying to learn and do their best in Math.

[pearl tusk]

cool cool

[pearl tusk]

just kidding

[languid zenith]

Oh. Sorry. My bad.

[fringe timber]

please help me with b) i dont understand how to do it

[void badge]

hey is the answer 2,-1

[covert briar]

im not sure
idrk how to do it

howd u get it

[void badge]

also in the new equation the third term has to be 5y'2

x' = x-h and y'=y-k => x=x'+h and y=y'+k now in first equation replace x and y by x'+h and y'+k .After replacing you ll get a new equation in terms of x' and y' finally get h and k by just comparing the coeficients in the final equation you get and the new equation given in ques

[covert briar]

so then i convert the first eqn in terms of x' and y'
after that?

[waxen storm]

how is deltax = -20 here

and when i write delta do i consider - 7 or 7

[cyan night]

help me draw shape lol

given rectangle abcd. exist points p and q on the outside of the rectangle such that AP ⊥ DQ, BP ⊥ CQ

[void badge]

lets say your eqn is 1 and the eqn given in ques end is 2 so now equalize 1=2 compare the coefficients of each term eg x'2 x' x'y' etc

[dreamy depot]

can you help me with this?: how many positive integer values ​​of parameter m are there for the minimum value of the function y=|x^2-4x+3| + 4mx larger than 2

[craggy plume]

What does the highlighted equation do and how do i use it? I don't really get it

[cyan night]

@left knoll

[ember kernel]

Hi ! Could you send a picture of the question for context please ?

[cyan night]

how do i draw shape

[ember kernel]

What do you mean ?

[cyan night]

im struggling to draw

[glacial robin]

someone can me help to find algorithm for matrix?

[void badge]

what ans are you getting

i can confirm

[dreamy depot]

A.1 B.2 C.3 D.infinite and i think my answer is D

[ember kernel]

The derivative of x² - 5x + 4 at x = 3 is 1

Therefore, you know that the slope of the tangent is 1

You want the expression of that tangent : y = mx + p = x + p (since you know that m = slope = 1)

To get p, just plug in (x,y) = (3,-2) (since you want your tangent to go through those coordinates) and you get -2 = 3 + p, which returns p = -5

Then, you have the expression for your tangent : y = x - 5

The line you highlighted is just a shortcut for all that reasoning. Imagine you want the expression of a line that goes through (a,b) with a known slope m, you can just use the formula y-b = m (x-a) to get it, without having to actively look for the value of p and plug it in the expression)

[ember kernel]

^

[craggy plume]

wohw thank you so much! I get it now :D I have always used y=mx+c and plugem in lol

[ember kernel]

That's what I do too tbh, but that's another way of doing it

[mossy fjord]

What happens if i do ._.

{ Quentin.cheerUp; }

[ember kernel]

?

[mossy fjord]

I meant your bio :P

[ember kernel]

Yeah I got that part, but I just don't understand what you meant 😅

[azure yarrow]

Can someone help me with this question?
If I have this equation
By properties I concluded that x = 1
but the teacher wrote that x = 6
and the graphing app says that x = 5.13 ...

What's going on here?
Log √(x-5)+ log √2x_3=1
3. 3

[dim path]

how the hell is it 2???

the function repeats itself at 1...

[gritty agate]

Hi everyone, I am looking for a colleague (maths, physics, engineering) we can support each other, if anyone thinks, please write, thank you,

[uncut mason]

looks more like -cos(pi/2 * t) to me.

[oak solstice]

Answer is π

[ember kernel]

-2 cos(2x) - 2 actually

[timber violet]

Is this correct notation

So it’s not defined when y = 1 but when y is 1 there is no x solution, which I think means that the curve never passes that point in space and therefore will always exist

[covert briar]

tysmmm

[stoic sinew]

Sorry to bother yall but I’m stuck on part c of this question, any chance someone knows how to finish it off?

[ember kernel]

It is

[left knoll]

I don't know if I understand your problem, but just replace the x you found in the f(x) fonction and you will find the y (as f(x)=y)

[dry surge]

I think she already did that

In the coordinates

[left knoll]

last question, she got x but I don't see any y (I can do maths in french but some words change and I don't understand everything in english)

[stoic sinew]

do you mean the -2/6 and -1/3 part? if so thats just simplifying 1 x term

[ember kernel]

x = -1/3 is indeed correct

Now, according to the conventions I've been taught, this would be enough.

But if you need to give the complete coordinates, then it means you must also find the y-value at x = -1/3, which is f(-1/3)

Therefore, the answer is either x = -1/3 or (x,y) = (-1/3, f(-1/3))
(Simplify the f(...) part ofc)

[dry surge]

Don’t she needs to find concavity as part of the inflexion

[left knoll]

it is what I meant, coordonates are (x;y) and not just x

[stoic sinew]

ah so do I just sub x into the original equation and thats it?

no concavity or anything?

[ember kernel]

That'd be a different question, in my opinion

[ember kernel]

There's no mention of that in the question, so I would say that's enough.
Plus you already mentioned the concavity of each section of the graph in question (b)

[dry surge]

Ahhh ok

[stoic sinew]

ahh ok, thank you guys!

[stoic sinew]

Sooooo anyone know how to tackle this 🌝

[oak solstice]

first put
x = 0

where y = c = 1(as u can see frm graph)y=1 where x = 0```
then period sinx is 2(pie) now in sin function we have coefficient which is b 
now here we can see period sin also 2(pie) here so value of b must be 1 that means b =1
now range of sin function is from -1 to 1 as u know bt here in this graph as we can see sin is going from 1 to 4 that means value a must have to be 3 
so 
**a = 3 , b = 1 and c =1**

[stoic sinew]

wow that was quick, damn wish I could get it that quick lol, thank you though, it means a lot! :D

[fiery coyote]

isn't the period pi

so that means that b =2

bcs b=(2pi)/p

when p = the period

[oak solstice]

right b =2 @stoic sinew coz here in graph period is pie so value of b must have to be 2

[oak solstice]

thnx for correcting me 😃

mistakenly i took graph period 2 pie bt it is clearly pie 😅 ooof

[fiery coyote]

no probs, that's why we're here 🙂

[fiery coyote]

as long as that doesn't happen on a test 🙃

[stoic sinew]

ahh well tbh im still trying to process everything 😅

[fiery coyote]

do you get why and how you get these numbers?

[stoic sinew]

I mean, im trying to lol

[fiery coyote]

well, the function you were given really resembles the general sinus function

so if you look that up, i'm sure you'll find the right info

[stoic sinew]

ahh so is that the formula we put in?

[fiery coyote]

yeah, altho, in your exemple c would be d in the photo i send

[stoic sinew]

Ahhh oki

Thank you for the help

[fiery coyote]

you're welcome 🙂

[oak solstice]

yes

[left knoll]

Sorry

I deleted my ques

[oak solstice]

have you solved??

[left knoll]

No yet

three equal circles w1 (O1, r), w2 (O2, r), and w3 (O3, r) are tangent to the circle w (O, R) internally. Express r in terms of R

[left knoll]

Can you solve this

[oak solstice]

ohhhk let me try

[left knoll]

Thanks 🙏

[oak solstice]

r = root(3)r/(2+root(3))

@left knoll

is it correct ??

[left knoll]

Idk

Thank you anyway)

[oak solstice]

wait i m sending u soln in few mins

[oak solstice]

is it multiple choice question right ??

coz root3/2-roo3is also possible here

[left knoll]

Oh Thank you a lot!!

[oak solstice]

lol dont u want solution ???

[oak solstice]

I could'nt understand

[timid delta]

Nais

[oak solstice]

thnx

you have million different faces but they will never understand

unless you let them in

[dry summit]

can anyone explain this to me im confused aboutthis part

also why'd they use radians for x

[dry summit]

nvmnvm

[timid delta]

Radians is the SI unit of angle

[left knoll]

2x+5y=17 , 5x+3y=14 .. how do i solve this using substitution method

[timid delta]

y=17-2x/5

Put that in second eqn

@left knoll

[left knoll]

k thx

[pearl tusk]

how do you study a subject or chapter you don't like
if it's a very boring chapter but is pretty important from the test point of view @here

[cyan night]

what chapter is it

[pearl tusk]

a chapter called similar triangles and real numbers

i just hate them

i'm starting to not like trigonometry a bit as well

[cyan night]

similar triangles is pretty simple

its just ratio and relationship

whats boring about it

[pearl tusk]

yes exactly i feel i know it so i don't want to study it

[pearl tusk]

i'm too overconfident about it

[cyan night]

if u know it well then why study

[ember kernel]

YouTube videos summarising the content and introducing the rules and formulas through visual examples

Helps a lot

[pearl tusk]

so what i thought 'll do was i skip it and do some practice questions and see if i get them wrong @cyan night

[pearl tusk]

thanks i'll check it out

[cyan night]

yeah and also past papers maybe

[pearl tusk]

do you have any tips for real numbers
seems like there can be many MCQ's formed from that chapter since that is the format for our exam

[cyan night]

real numberes do u just mean domain

[ember kernel]

@cyan night is right. "Real numbers" in maths is as vague as "word" in literature. For what do you use real numbers in your course ?

[pearl tusk]

i'm still in my school educational system so i just have to study everything tho i don't like it...so i just have to learnt it

[ember kernel]

What I mean is that studying "real numbers" gives little to no information on how we could help you. What uses do you need to make of them ? What do you study especially about real numbers ?

[pearl tusk]

we are learning to prove if a number is irrational or not and surds and other stuff

[last echo]

Wait, u r in 10th?

[pearl tusk]

yeah why? are you in 10th too?

[last echo]

Bro- how?????

[last echo]

Topics coverd are:
Euclid's lemma
Hcf and lcm
Proving numbers irrational
That's pretty much it

[last echo]

Yes 😂
And triangles is the worst chp, I can't do sh*t in that chp

[pearl tusk]

the euclids part is deleted

[pearl tusk]

triangles is very dumb its just proving 2 triangle are similar that's so pointless and its very easy so i dont care about it and i'm not studying it lmao

[last echo]

Bro can v hv a study session?

[pearl tusk]

sure

[last echo]

Thxxxx

[cyan night]

i learnt similar triangles in 5th grade

[last echo]

yea now its pretty diff

[cyan night]

how is it different man

[last echo]

k wait, i'll give u a question

[cyan night]

ok

[cyan night]

ok wait

what do u mean by a b c have usual meaning @last echo

oh ok

[last echo]

a, b and c represent the value of each side

[cyan night]

ok

a is easy

[last echo]

did u make the diagram? otherwise it'll be hard to keep a track

[cyan night]

i did

are u struggling this questin

[last echo]

nope, this is the easiest of the lot

[cyan night]

ye

[last echo]

there r other proving questions which r way more stupid than this

[cyan night]

i can do proving questions

send me one @last echo

[last echo]

first solve this one lmao

[cyan night]

send me

a

proving

for

for a

ba/2 = cp/2 = s abc => ba=cp

:kekw:

for b

ab = cp

=> c = ab/p

=> c^2*p = a^2 * b^2

wait no

[left knoll]

Hey, what makes something a function in math-

[cyan night]

with 1 input only has 1 output

2 inputs can have 1 output

but 1 input cannot have 2 outputs

[left knoll]

This the x y thing right?? Which one cannot be repeated

[cyan night]

so f(x) = y

with every x function u put in

there can only be 1 answer of y

u get it?

[left knoll]

Yeeeee

I doo

Thank u :3

[cyan night]

okok

np

@last echo

1/a^2+1/b^2

= a^2+b^2/a^b^2

[last echo]

@cyan night u r rly a middle skooler?

[cyan night]

uh ye

one minute

i reasoned it wrongly for sum reason

cp = ab

oh wait i got it

c^2 * p^2 = a^2 * b^2

[last echo]

which country? im pretty sure its not india

[cyan night]

so c^2/a^2*b^2 = 1/p^2

c^2 = a^2+b^2

-> a^2+b^2/a^2*b^2 = 1/p^2

[last echo]

u could hv written than directly by using pt

[cyan night]

yeah

so => 1/a^2 + 1/b^2 = 1/p^2

proven

[last echo]

then put the value of c = ab/p using the first eq

[cyan night]

not really

i did

like cp = ab so c^2p^2 = a^2b^2

and then i make it a fraction

[last echo]

yea thats a long process

[cyan night]

not rlly

[edgy hinge]

hey can anyone help me with this: find the biggest value of this if we got a + 2b +3c = 6

[cyan night]

bruv ok

also @last echo send proving math im way better at that lol

1 more and i gotta go saka

saka..

[last echo]

dont do the first part, its pointless

[cyan night]

sorry saka i gtg

ok

here

similar triangles is ugh

wait

isnt it 3:1

wtf

@last echo

or am i hallucinated

[last echo]

9:1

[cyan night]

what

that doesnt look right

[last echo]

the ak says so

[cyan night]

what

[olive drum]

sup guys i'am new member

[cyan night]

those 2 triangles are similar in the case angle angle angle

[cyan night]

welcome

[last echo]

@cyan night

[last echo]

hey there!

[cyan night]

i wasnt introduced to the new theorem yet..

sorry

[last echo]

well, all this stuff is taught in 10th grade and considering that u r in ms thats not surprising

[cyan night]

i can still do the problem above-

and if u let me do both a and b then i can do b easily lol

[last echo]

wts the point of proving the theorem when the statement is already given to u?

[cyan night]

ok

sorry

[last echo]

wt? y r u apologizing?

[cyan night]

idk

[last echo]

honestly, u r pretty good at math

[cyan night]

yeah but i only know math lol

im not really used to similar triangles yet

anyway bye have a good day

[last echo]

u too!

[meager creek]

can anyone help me with this?

[left knoll]

How do you differentiate between an even and odd function?

[ember kernel]

Even function : f(x) = f(-x)
Odd function : f(x) = -f(-x)

@left knoll

[left knoll]

Whaaaaaat

Can u explain it like I'm stupid

[ember kernel]

Graphically :
Even : axial (vertical) symmetry
Odd : central symmetry

[left knoll]

Or maybe 3

[left knoll]

So odd is horizontal?

[ember kernel]

No

Wait a sec

[left knoll]

༎ຶ‿༎ຶ

[magic harness]

I failed maths last year, but still passed my year, which means I will work further with last years basics. I keep finding out there are some errors in my basics due some circumstances in the past....

Does someone know a way to pick up it a little, trying to fix the errors so I can save this year's maths in a relatively short amount of time? (since its pretty crucial to pass this year)

(my major is maths and science, 6 hours maths. And heading to my final year of highschool now.)

[cyan night]

There is this type of problem regarding polynomials and bezout theorem, for example, given P(1)=P(-1) P(2)=P(-2) find P(6)

[ember kernel]

@left knoll

[left knoll]

Ahhhhhh

[ember kernel]

Straight from my paint skills

[left knoll]

Omg really

U DIDNT HAVE TO DO THAT MUCH

WHY U BEING SO NICE

🥺🥺

Thank u sm

[ember kernel]

Just helping lol

[left knoll]

Ur too sweet bruh

I appreciate it

[ember kernel]

Thanks <3

[left knoll]

( ◜‿◝ )♡

[ember kernel]

I'm playing lol

Wait for 30ish minutes, sry

Lucian

(but that's off-topic)

[ember kernel]

Sry but nope

[left knoll]

What is a linear function

[mossy fjord]

The graph is a straight line.
It follows the following form
Y = mx + C
(m is the slope, c is the y axis interceptt)

[left knoll]

Ahh okay thank u smm

[mossy fjord]

Glad to help

[left knoll]

Mwah

[left knoll]

What's a polar function 😭

Sorry guys I'mma be asking alot today

[dusk adder]

Good evening to everybody, Are linear algebra and analytic geometry the same?

[left knoll]

Hi can someone explain to me how it got this answer???

[ember kernel]

Last line is actually +/- sqrt(25), not just sqrt(25)

Otherwise, the +/- would pop out of nowhere

[bronze marsh]

Ya.

✌🏻

[left knoll]

Ooooh I get it now thanks! : D

[ashen flint]

x = +/- sqrt(9+16) = +/- sqrt(25) = +/- 5

[olive trail]

Whats up guys has anyone taken the math accuplacer for college?

[inland oracle]

Translation: Find the lengths of the sides of the triangle with the vertices indicated, and determine if the triangle is a right triangle, isosceles triangle, or neither.
I need to do exercise 30, but I don't know how to solve it

[pastel helm]

You can find distance using distance formula square root[(x2-x1)^2 + (y2-y1)^2 + (z2-z1)^2]
I think 30 is isosceles 'cause distance between (0,6,2) and (3,5,6) & (3,4,1) and (3,5,6) are same

[timber violet]

How do you simplify from first pic to second pic

Anyone a master of simplification work your magic

[last echo]

use the distance formula and solve it

[timber violet]

guys nvm

they are not equal lol

miscalcuation

but wolframalpha did the trick

[inland oracle]

thx everyone

[olive trail]

@timber violet yo what math course is that problem from?

[timber violet]

math1072

ie multivariate calculus and ordinary differential equations

"advanced"

[olive trail]

Oh nice nice

Jus curious cuz I had no idea how to solve that problem lol

[timber violet]

ahh fair fair

yea multivariate

just means more than one

so the upgraded version of the f(x) function

ie f(x,y)

[agile trench]

yes

[olive trail]

Ahh dope dope.

[timber violet]

basically higher dimensions you will need it later

[agile trench]

does anyone here know about galois theory?

[timber violet]

nope

[olive trail]

Could anyone help me with his problem please. I do not really understand the explanation given and how they determine what would make the sine function the larges.

[agile trench]

the function sin u is maximum when u = pi/2 + 2.pi.n

so sin ( 2pi(t+1)/24) is maximum when what is inside equals to pi/2 + 2.pi.n

i don’t know if i helped

sorry

[olive trail]

No worries dont be sorry 🙂 To better phrase my question I don’t understand how they determined that pi/2+2piN would make it the largest?

Like how would I figure that out

[polar heron]

If you look at graph of sin(x), it has the maximum value when the variable x= pi/2 or (pi/2 + 2 n*pi , where n is some integer).

[olive trail]

@polar heron Hmmm I think I kind of understand what you mean. But in the original function aren’t there transformations applied to it? So wouldn’t that mean that it has a different maximum value than just sin(x)?

[polar heron]

sin(x) has maximum at x= pi/2 or (pi/2 + 2 npi), in the question we are given sin(2pi (t+1)/24). call T= (2pi (t+1)/24). now it becomes sin(T). sin(T) would be max when T=pi/2 or (pi/2 + 2 npi), this is what has been done in the solution.

[olive drum]

btw

how old are u guy?

guys*

[olive trail]

@polar heron So even tho the function T has a different period than Sin(x) it is still max when it is T=pi/2? Sorry it takes me awhile to understand

[agile trench]

21

[drifting lance]

Hey guys, does anyone know how i can find alpha in this system

I know angle betta and the one marked with blue (it goes to the center of the circle)

[left knoll]

how many grams in 1/4 moles of Ca (oh) 2 ?

[left knoll]

Thank you!!!!!

@left knoll ( ◜‿◝ )♡

[left knoll]

☺️♥️

[lapis yoke]

Calculate the modulus of the vector sum in the case below:

[ember kernel]

[[[FALSE FALSE FALSE]]]
[[[Was I drunk when I wrote this ?]]]
F1 and F2 horizontally cancel each other out. Therefore, F1+F2 is just a 200N vector pointing upwards.
Add F3, which is a 100N vector pointing downwards, and you get F1+F2+F3, which is a 100N vector going upwards.
Thus modulus = 100N

[obsidian sage]

how is f1 + f2= 200N

[slow cipher]

pretty sure it's zero, isn't it? They "cancel eachother out"

[outer tide]

can anybody help me with this?

[polar void]

I need some help 😭🪄
Ps. Unsigned integer is from C language, i guess it’s [0,65535]

[agile trench]

i have no ideia 😦

[polar void]

i try to do that by taking m and n with gcd and lcm first coz (gcd)(lcm) = mn so minimum value maybe m=20 and n= 50400 but now i have to solve the equation 2 :))

[tough elk]

I need help 😦
WHY IS THIS FALSE

it don't make sense

this is calc one btw

[hollow escarp]

yes, it's zero

[upbeat osprey]

can anyone help me out?

[tawdry dagger]

Find the sum of cos^ 3 A+cos^ 3 2A+cos^ 3 3A+..... to n terms.

[tawdry dagger]

Are u from iit home?

[polar void]

I try to do 2 ways , normal equation solve and use diff(calculus) and the answer is true 😂 (i think it should be true)

[tough elk]

my professor bout to have a whole lot of explaining to do lol

[ember kernel]

@slow cipher Oh wow I'm shocked at how wrong I was. I didn't see the pattern on the spot and didn't bother to use trigonometry, and didn't check and actually calculate before sending my answer unlike I often do. I'm really embarrassed by the level of the question it took me to be wrong 😆

[ember kernel]

Dude you're clearly showing it's an exam question. I advise you to go and read rule 5 once again. Good luck tho

[left knoll]

can anyone explain how to turn #1 into an equation?

[slow cipher]

It's ok hahaha, we all make mistakes

The important thing is to recognize our mistakes and better ourselves, just like you did :)

[soft patrol]

CAN SOMEONE ANTIDIFFERENTIATE THIS PLEASE

ok wait nvm I got it y is it so huge

[glass phoenix]

Hello, could someone help my with the first step of this equation (exponential) ? 5^x+1 = 3^x+1

[last echo]

cancel the 1 from both sides and then divide both sides with 3^x, x will come out to be zero

5^x+1 = 3^x+1
5^x = 3^x
5^x/3^x = 3^x/3^x
(5/3)^x = 1
therefore, x = 0 [x^0 = 1]

[left knoll]

hello maths people

i got part a right but am a bit puzzled about part b's solution

its short and simple but idk where the 0.1 came from can someone help me out

[glass phoenix]

thx

[cyan night]

uhhh i think x+1 is in parenthesis

[cyan night]

yeah

[cyan night]

so its 5^x*5^1 = 3^x * 3^1

5*5^x = 3 * 3^x

5 * 5^x - 3 * 3^x = 0

[obsidian sage]

i think you can use the exponential form of complex number

to create a gp

[glass phoenix]

i don't understand your method @cyan night

[cyan night]

A^m*A^n =A^(m+n)

[last echo]

Ohhhhh, yea then there would be a different answer

[cyan night]

Yeye

Saka can give me more geometry

[last echo]

Not now

Me is studying English

[cyan night]

Okok

[pastel helm]

Try taking log on both sides

[last echo]

quick question: diagonals of a parallelogram are always equal ri8?

[left knoll]

yeeeee

[last echo]

cool thx

[left knoll]

what is the expression equals to

[last echo]

ohkk so in this question: If (1, 2), (4, 6), (x, y) and (3, 5) are the vertices of a parallelogram taken in order, find x and y.
so can i just use distance formula instead of the section formula?

cuz in the textbook its given that v need to first find the point of intersection of the diagonals

[left knoll]

can be solved using distance formula but is lil bit lengthy

[last echo]

oh okay, thx

[glass phoenix]

i put x equal 0

[left knoll]

: (. I was thinking to solve it using log

[cyan night]

No

They never are unless they are special parallelograms which are rectangles or squares

Diagonals of a parallelogram only intersect at eachs midpoint

KittyKat they aren’t equal

[left knoll]

I just checked on google they said yes

[cyan night]

What

[left knoll]

I'm confused

[cyan night]

Parallelogram

Not isosceles trapezium

[last echo]

a rectangle is a parallelogram with each angle equal to 90

[cyan night]

That source is incorrect

[cyan night]

Yes

[left knoll]

ohh

[last echo]

and a square is a rectangle with all sides equal

[cyan night]

Yes

[last echo]

dude thats a verified source

[cyan night]

Here

[cyan night]

No I’m specialized in geometry

Check other sources they all said no

[last echo]

the diagonals form 2 congruent triangles

[left knoll]

I was taught in school diagonals of parallelogram simply intersect each other at mid points

[last echo]

by cpct they r equal

[left knoll]

that

[cyan night]

Yes

[left knoll]

that's it

[cyan night]

What

The diagonals are not equal there is no such property

I learn geometry all day I should know

[left knoll]

I was never good at geometry lol

[cyan night]

Saka they are not congruent

As a middle schooler I can confirm

[last echo]

yea ncert is bogus ri8

[left knoll]

using side -angle- side?

[cyan night]

That case is only valid if and only if angles a and b are congruent

Which they aren’t

[green bolt]

hello, does someone know how to estimate slope of curve like this

[left knoll]

opposite angles are equal

[cyan night]

Yes

[left knoll]

y2-y1/ x2- x1

[cyan night]

Which triangles are u considering

Kitty

[left knoll]

lemme check

[cyan night]

They should involve both diagonals

If they do then iirc they involve the angles that are supplementary, not equal

@last echo

I learn geometry all day xd

[last echo]

nvm, i'll just use the long way of solving

[cyan night]

What’s the problem I can help

[left knoll]

oops I was wrong

sorry

[cyan night]

Ya it’s ok

Saka can I try solving geometry

[green bolt]

idk how to find the other two points aside from 4 and 3

[left knoll]

y coordinate is zero not sure about x coordinate

[green bolt]

ohhh alright thanks

[cyan night]

Saka I can help

Should I ping

[left knoll]

she's afk

maybe later

[cyan night]

Oh it’s a she

I thought saka is boy

Sorry

[left knoll]

check her profile

*roles

[cyan night]

Ya

Anyone kitty kat do u have any geometry concerns

I can maybe ponder with you

[left knoll]

whole geometry is problematic to me lol

[cyan night]

Anything that ur wondering about

Like how to prove a property

Or anything

Ok bye

[left knoll]

ya sure

[cyan night]

Hi

I haven’t gone yet

[left knoll]

hola

nah

[cyan night]

What are u wondering

[left knoll]

Lemme solve some geometry questions, If I face some difficulty I'll @ you or Dm you : )

Cya soon

XD

Good bye and have a nice sleep

[ember kernel]

Using (y2-y1)/(x2-x1) for such a question, where you lack information, leads to nowhere.
Here, the only way to process is by elimination of the false answers.
a) If the slope was 0, the tangent would be horizontal, here it goes upwards ❌
c) If the slope was -1, the tangent would go downwards, here it goes upwards ❌
d) If the slope as undefined, there would be no way to draw the tangeant ❌

Then it's b

[green bolt]

ohhh now I understand it, thank you so much!!

[last echo]

No need, I was just asking cuz I wanted to try and solve the question using another method

[left knoll]

2x² + x - 6 = 0

Splitting the middle term

2x² + 4x -3x - 6 = 0

why are we writing 4x-3x

[ember kernel]

To extract in an easy way (x+2) to factorise the polynomial

[ember kernel]

This is just a thing that simplifies calculations, but can't work all the time as you need to actively see the trick

This is a shortcut, not a formula or rigorous way of solving

[olive trail]

Hey guys really simple question but would this be the correct way to write this fraction with only positive exponents?

[ember kernel]

No

[ember kernel]

Therefore

[ember kernel]

The reason you got this wrong is most likely that you used something like a²+b² = (a+b)² in the denominator (and with a negative exponent) which is incorrect

[olive trail]

Oh i see thank you so basically I need to turn it into a complex fraction then simplify

[ember kernel]

Yup

[olive trail]

Hey guys Im taking the accuplacer for college math placement soon and want to place into calc I. You really need to have your algebra fundamentals down because its a progressive test so if you get something wrong in the algebra section the test will not give you more difficult questions such as Precalculus ones and you will not place into calc. I took Alg-Precalculus in high school do you think I could just go through my precal course and be fine or should I study Algebra I first?

[tawdry dagger]

Thanks

[obsidian sage]

np :p

[red spruce]

pretty ez question but i was thinkin g of a approach of applying 1+cosa = 2cos^2(a/2) being applied but cant seem to solve it someone help

everywhere they apply by coversion of cosine to sine and then solve

[cyan night]

looks like its somewhat related to a^2 - b^2

it reminds me of this

u think so?

uh maybe not sorry

lol

actually it might be like that, good luck 😉

try deriving to get squares, using (a-b) (a+b)

hihi gl

[red spruce]

PLS MAN u are in 8th grade T.T this is of 11th

[weary arrow]

i mean you can just plug it into a calculator but maybe that's not the way you're supposed to do it

huh I get 16

[cyan night]

So what?

It is going to use (a-b)(a+b) at some point

Why aren’t you being appreciative because I’m trying to help

[red spruce]

read my question again ik the solution , i was askig if someone know and can solve with approach im tryi ng to do

[red spruce]

1/8

[cyan night]

But u didn’t have to be rude like that

[red spruce]

i was rude?

sorry then

[cyan night]

Yes

[red spruce]

didnt notice

[cyan night]

It’s ok

[red spruce]

uwu but nice thinking, u solved it

[cyan night]

It was somewhat this type of question that I recognized

[red spruce]

thats a gp

maybe

[cyan night]

But I can’t work with trigonometric identities yet

[red spruce]

u will get there

dont worry keep working

[weary arrow]

is it something else than simply the value of them multiplied together? cos(pi/8 )>0 so it's not possible for this to have a value below 1

[inland sigil]

I think you make it such that there are two pairs of (1+cos(theta))(1-cos(theta))

[red spruce]

yes

[inland sigil]

And then you convert it into 2(theta)

And you have an angle for which you know the exact value

[red spruce]

i want to use identity 1+costheta = 2cos2theta/2

[inland sigil]

It's kinda mushy F

3 years

But yeah, seems like a standard 2theta conversion

[red spruce]

its poretty ez but like i wanna apply the other approach js for fun yk

[inland sigil]

Basically if you're given half the angle of a standard angle

You should be looking to use 2Theta formual

[red spruce]

ye

thnx tho appreaciate u uwu

[weary arrow]

hold on nvm i was using deg

[gentle crow]

Having a brain melt, why is the derivative of y^2 wrt x = 2y(dy/dx)

[inland sigil]

Because of the product rule iirc

[gentle crow]

ah

I am seeing now I think

[rustic hedge]

sahil some questions can be solved in particular ways only .

[gentle crow]

thanks

[red spruce]

coz thats what u doing its not differentitaion but partial differentiation

u can google that up and ezily get the full lectures on that

[red spruce]

hmph

[rustic hedge]

you are 11 th class?

sahil...

[ruby tinsel]

https://www.doubtnut.com/question-answer/cospi-8cos3pi-8cos5pi-8cos7pi-8-2446185

I'm hoping this video would help?

[rustic hedge]

do you need any help to solve it easily?

[red spruce]

oh thnx , i did solved it and got more questions so ibetter get going

[rustic hedge]

okay

[red spruce]

ayy thnx

[terse fox]

can someone help me with some differentiation

[rustic hedge]

yup

[terse fox]

log{tan(pi/4 +x/2)}

please

i cant understand the solution

[rustic hedge]

we should differentiate it?

[terse fox]

uh yeah i forgot to mention it

[rustic hedge]

okay....you know how to diffrentiate sin2x?

[terse fox]

is it squared or just 2x

[rustic hedge]

just 2x

[terse fox]

umm no

is it possible if u cud solve and post it ill try to understand it ill let u know if i get stuck anywhere

[rustic hedge]

hmm okay....in diffrentiation there is a rule called chain rule

[red spruce]

SINX = COSX in differentitaion

[terse fox]

yeah i know it

[red spruce]

so live sin2x= 2sinx *cosx

chain rule applied

[rustic hedge]

YUP

[terse fox]

this wouldve been the case if it was sin^2x right?

[terse fox]

yeah i know this

[rustic hedge]

okay use this to solve your doubt

[red spruce]

1/x sec2ptan2p where p is pi/4 +x/2 now differentitate p and multiply to whole statement

[terse fox]

wait i got it

i used substituion to do it

[rustic hedge]

log derivative 1/x so, it would be 1/(tan(pi/4+x/2) but tan(pi/4+x/2 is a function so,again apply chain rule so tan derivative is sec^2x so.....

[terse fox]

thank you guys

[rustic hedge]

okay

[red spruce]

ye 1/x is that only i by mistake mentioned x there it should be the whole value

[terse fox]

pi/4 + x/2 again a fn so again chain rule.. i got it thank you

[red spruce]

ayy les o\go

[left knoll]

is there a diffrence between for eg y=2-5x and y =- 5x+2

[terse fox]

nope

the signs should be correct no matter where they are placed

[left knoll]

thank uu

but when how to make a general form from 5y=3x-1?

[last echo]

General form is: ax+by+c=0
-3x+5y+1=0

[left knoll]

chain rule lol

[olive trail]

Could anyone help me out with this please? Much appreciated.

[harsh dragon]

Well u plug it in

For about

V

[olive trail]

Idk am I doing something wrong?

Cuz I do that and get the wrong answer

[peak orchid]

My answer is 4 seconds, am I wrong?

[cyan night]

its just inputting numbers tho

[ember kernel]

There are 4 questions on this page, we don't know which one you're talking about.
Plus, none of them requires an answer in seconds, so you might be wrong

[cyan night]

and wdym answer is 4 seconds

[peak orchid]

Oh

Im being stupid

[cyan night]

its in ft

[peak orchid]

Sry I havent slept for like 16 hrs now I have been doing these exercises

I cant sleep @_@

This is embarassing lmao

[ember kernel]

Don't overwhelm yourself with exercises when you feel your focus is decreasing. Take a little break to go outside (if the weather's clear) or, after 16h, call it a day

[ember kernel]

Don't worry about that 😉

[peak orchid]

Today is a very bad day for me @__@

Thanks anyways I feel quite assured now

[ember kernel]

No problemo, have a good day

[cyan night]

help

how do i find the minimum value or maximum value of -x^2+6x-5

i made some progress

= -1 (x^2-6x+5)

= -1 (x-5)(x-1)

how to conitnue

@ember kernel

[cyan night]

wait nvm i got it

[ember kernel]

Derivative

[cyan night]

actually

i test out all the domains of x possible

2 of the domains result in a negative result

x = 5 or x = 1 results in 0

so domain of x is1<x<5 in order for the equation to have maximum

x = 4

and ihavent learnt derivatives yet

[dark sorrel]

Try to write the quadratic equation in the form of y = +-(x+d)^2 + e, with d and e constants

After that its a lot easier to find the maximum or minimum

[cyan night]

something was wrong with me ngl

i did it very wrongly

[upbeat osprey]

anyone knows how to answer letter b?

[lofty arch]

have you learned strictly dominated strategies yet?

or mixed strategies?

If you have, X is strictly dominated by a mixed strategy of Y and Z for both player A and player B, which means we can ignore X for both players, leaving us with only Y and Z for both players

[upbeat osprey]

@lofty arch i know some things about dominated strategies

[upbeat osprey]

btw i think i understand now what you were saying

thank you so much!

[pearl tusk]

all the doubts are here are so advanced
i don't know any of this xD

[olive trail]

Could someone please explain the steps to this answer? I got the same answer but with negatives in the wrong place.

[peak cradle]

To all the precalc ppl out there, I'm just starting the school year and I basically just don't remember any of this. I'm trying to skim through my old Algebra II notes but to no avail. Anyone know what these specific equations are?

[inland oracle]

3. An airplane that carries out the task of putting out fires, must have clear indications regarding the speed and direction that it must carry out to reach its destination and carry out the discharge of water that it carries. An airplane flight study shows that the relative speed of 200 mi / h is flying in the 50 ° direction and a 40 mi / h wind is blowing directly from the west. As seen in the figure. Calculate the true course and speed on the ground.

[ember kernel]

Use this :

[ember kernel]

And remember that :

[pastel helm]

Also use properties like nth root of a will be a^(1/n). (a^n)^m=a^(mn).
a^(n)×a^(m)=a^(m+n)

[olive trail]

Could anyone help me out with this?

[left knoll]

Hey guys, I don't understand this question:

" Express the side length of a square as a function of the length d of the square's diagonal. Then express the area as a function of the diagonal length."

[weary arrow]

Use the abc formula:

a=2, b=-1, c=-1

[left knoll]

For the first part, apply hypotenuse theorem, so for example for a square of side x and diagonal d , x as a function of d would eventually come as d/√2. For the 2nd part substitute the value of x from the first part in the formula for area of square, that would be area as a function of the diagonal length

[left knoll]

Ahh sorry I don't get, "substitute the value of x from the first part in the formula for area of square"

I just woke up

[left knoll]

Oh first part as in the first question, you get x = d/√2 so use this in the formula for area of square that is A=x^2

[left knoll]

Take your time zay !!!! You can do this a bit later tooo! Hope the answer helps you

[left knoll]

Wait so

How would thst look like

[left knoll]

I'm so bad at math 😭

Thank you I appreciate it

[cyan night]

i can help

[left knoll]

Lemme send you a picture instead

[left knoll]

Sure

Several explainations help 😂

[cyan night]

so u know the side lengths of the square are both equal right

[left knoll]

Yes

[cyan night]

do u know about the pythagorean theorem?

a^2+b^2 = c^2 in a right triangle

[left knoll]

Yeeee

[cyan night]

a,b, are the legs of the triangle that are adjacent to the right angle

and hypotenuse, which is c, is the side that is opposite to the right angle

[left knoll]

Okayy

True

[cyan night]

so u imagine there is a triangle formed from the diagonal and the 2 sides of the square

[left knoll]

Yepp!

[cyan night]

so do u know what a function is

[left knoll]

Yep

😂😂

[cyan night]

so here

d = f(x) = something u have to make

applying pythagorean theorem, the total of the squares of the sides of the square is equal to the diagonal's length squared

[left knoll]

Didn't it say function of d

[cyan night]

uhh wait

[left knoll]

So wouldn't it be f (d)

[cyan night]

no

i dont think so

[left knoll]

:0

[cyan night]

u want d to be the output here

[left knoll]

Zay hope this helps also whaa faygo's explanation is good!!!

[cyan night]

yes like that

function OF d, not function d

[left knoll]

Ahhh thank u so muuuch z sorry to put u guys through trouble

[cyan night]

and ye the diagonals of the square are equal in length

[left knoll]

Never done this before 💀

[left knoll]

Okayy

Thank uu blue and bii

( ◜‿◝ )♡

[cyan night]

so the answer is

[left knoll]

It's okay huhu this is a help channel for a reason XD

:3 y'all too sweet

[cyan night]

d = f(x) = x/sqrt 2

and d = a(y) = y^2/2

i think

is this correct bii

[left knoll]

Interesting

[left knoll]

No just reverse it

The question wants length and area as the function of diagonal

[cyan night]

wait my brain

should be

d = f(x) = sqrt.2 * x

this ^

[left knoll]

So that'll be x= d/√2

[cyan night]

isnt this the standard way they present functions tho

[left knoll]

And A=d^2/2

[left knoll]

That's a general way, you gotta see what the question wants

[cyan night]

yeah

[cyan night]

i did it that way

[left knoll]

This would be expressing diagonal as a function of length and area

[cyan night]

i thnk

oh

ya true

x = f(d) = x/SQRT. 2

[left knoll]

May I have ur brain

[cyan night]

no i just searched the internet

my brain is also not capable of doing that LOL

[left knoll]

Still smart

[cyan night]

i can help u

[left knoll]

Very

Oh dw I'm okay rn

:3

[cyan night]

okok

good luck zay

[left knoll]

You too !

https://c.tenor.com/J4WA4IXVeBQAAAAM/love-you.gif

[left knoll]

AHHHHHH

OKAY

[cyan night]

U get it yet?

[left knoll]

Okay, so basically the first part of the question is asking for the side of the square, and we had to do the hypotenuse thing cause there's a triangle

diagonal in the square

right?

[left knoll]

im waking up

haha

[left knoll]

basically it's one way to approach the problem so yes

AYEEEEE