math-help

[steel plover]

this is the question

[granite crow]

@bold dagger

@steel plover

The h is related to the First Principles definition

[dusky heart]

🔴 if someone has some🤌 integration problems, please DM. i'm practicing it 🔴

[steel plover]

thanks!

[bold dagger]

Thank you!

[covert anchor]

how do i do 6

[mental snow]

the second equation is (x-2) (x-3)
so x=2 or x=3 can be the common factor

put x = 2 in the 1st equation and you ll get 1 value for k
and then put x = 3 in the 1st equation you ll get another value for k

these will be the possible values of k

[covert anchor]

ok thanks

can i pm for u to ask another question ?

[mental snow]

sure no worries.

[echo wasp]

does anyone know how to answer this?

[ivory pumice]

Distance from centre should be >= radius

@echo wasp

[ivory pumice]

What you are doing is reducing the number of solutions

On the left part you assumed that y can't be 0 but one of the roots of the quadratic equation Is 0 as well so it's wrong .. you can cancel like that if y is not equal to 0

[ivory pumice]

Use remainder theorem and solve

[covert anchor]

i know but how to apply

[ivory pumice]

Umm after that it would be just solving for A&B

Remainder when f(x) is divided by (x-r) is f(r)

[covert anchor]

like how do i use remainder theorem

do i sub in -1 or 2 ?

[ivory pumice]

Yes

[covert anchor]

gosh i need to buck up

[ivory pumice]

For polynomials only

[ivory pumice]

^^

[covert anchor]

i got -a-3+7b

for subbing in -1

[ivory pumice]

Ok

-a-3+7b = 2R

[covert anchor]

ok so what then

[ivory pumice]

Now substitute 2

[covert anchor]

2 into fx

[ivory pumice]

Yes

You will get 2 equations

Multiply first one ( in which you substituted -1 ) by -3 & second one by 2 they both will be equal , that would give part A

[covert anchor]

wait so multiply the opposite of each r terms

since the first one i sent was 2r

[slate wolf]

got it thanks!

so if we put y=0 and divide it by zero do we get infinity or 0 or 1?

[ivory pumice]

Hmm first part had 0 on RHS. So we did this

[ivory pumice]

It's actually not defined

[slate wolf]

got it

thankss

[ivory pumice]

Np

[covert anchor]

ok how about ii

[ivory pumice]

Use part A

13a+47b = -3

13a-47b = √((13a+47b)²- 4×13×47ab)

Now solve for a and b

[covert anchor]

from here ?

hey im not sure how to simplify that

that is too complex

[ivory pumice]

√9+4×13×47×14 = 185

26a=182

a=7

b= -2

[ivory pumice]

I took +185 because a>b is given

Otherwise "a" would become -ve & b >0

@covert anchor

[mental snow]

true

[mental snow]

c has to be greater than 2 root 15 and smalled than - 2 root 15

[ivory pumice]

Including 2√15 & (-2√15)

[covert anchor]

How bout this

[mental snow]

i mean

does not intersect

well if u consider it as tangent

then only including

[echo wasp]

Ah thank you

[mental snow]

no worries

[left knoll]

https://gyazo.com/1cfaa1c0ce87a7cf74d12bf7e8e63159

https://gyazo.com/8147e3befb0f0b64d22766ab76f772e4

can anyone help me with these two

[zinc comet]

Have any of you taken Linear Algebra in college?

[ember kernel]

Yup

What's your question ?

[zinc comet]

I was just wondering what was your best method for studying it? I hear there are a lot of new terms you learn. Obviously doing practice problems helps. Did you ever do flashcards?

[ember kernel]

@zinc comet Gilbert Strang is very good lecturer. Here's the entire playlist of his course (extremely helpful) :
https://m.youtube.com/playlist?list=PL49CF3715CB9EF31D

To answer your question, I'd say that you must be willing to spend time on actually understanding what's going on. Flashcards could help you memorise the few formulas there are, but it isn't a necessity. On the contrary, understanding what each concept does and is for is crucial. Why ? Because linear algebra is heavily based on theory, and it consists in many small concepts with little in common (put aside vectors and matrix) : system solving, bases, orthogonality, linear operations, etc.

So yeah, make sure you understand what each concept consists in and is used for. Then, as there aren't many formulas, you can easily get used to them with some training. Regarding the technical terms, there are quite a lot but, again, it should be no problem once you've understood the concepts

[wary geyser]

Can anyone help me with the B.P.T theorem (Thales theorem)

Ping me pls

[dusky heart]

can someone explain what 'base 10' means?

[ivory pumice]

Logarithm?

[mild anchor]

can anyone help me with this?

[ivory pumice]

-2 & -3

[last echo]

yea i can, its coming for my mid terms

and can u help me with other topics related to triangles?

[ivory pumice]

Use substitution method

[ivory pumice]

You will get this

[mild anchor]

got it, thanks! ^^

[ember kernel]

"Logarithm of A in base B equals C" means that C = logB(A) <=> A = B^C

So, in a logarithm, base 10 means that you're looking for the exponent you need to apply to 10 to get a certain number (A)

[red spruce]

so for solving this the calc is pretty time consuming any tips for doing it fastconsidering they give 3 mins for each question

[sharp ferry]

In what context number system? Logarithms?

[sharp ferry]

It's in chemistry?

[red spruce]

yes

[sharp ferry]

For the universal gas constant you can write 1/12

And you can round off 303 as 302 approx

And cancel out stuff

[red spruce]

oh alrit got it

thnx

[tardy crown]

hi, i need help with the limits of this multi integral.

https://cdn.discordapp.com/attachments/310219120589275136/860900156245016606/unknown.png

for the question 2 i made this

the purple area is the area limit (right?) but is a little zone

the red area is not part, of the integrate area. how i can solve this?

(and sorry for my draw in paint :P)

to all the person I have asked, no one has been able to reach the answers to questions 2 and 3, I think they are very advanced

more clean 😄

[dusky heart]

dis, this seemed like a cauchy eqn first, but it's not 🥤

[dusky heart]

just a hint, please🥤

i found f(x)(1 + f(x)) = f(1/x)(f(1/x) + 1)

maybe i'm right, idk :(((

[tawdry hazel]

by plugging x = 1 and y = 1 in, you will find f(1) = 1 or f(1) = -1. then divide the question into two parts. First assume that f(1) = 1 and try to solve f(x), then assume f(1) = -1 and see what will happen. if u need more hints let me know.
you will find two separate answers for f(x)

[ivory pumice]

x=-1

m(t)= 20 t^5/2

dy/dx = 1/y . Sin2x/2

dy/dx = 1/1 . 1/2 = 1/2

[winter sigil]

why do you divide by 5 in the second step?

[ivory pumice]

du= 5dx , dx= du/5@winter sigil

[naive forum]

help

[ember kernel]

@naive forum

[naive forum]

im sorry but i cant see it rly clearly

[ember kernel]

Click on the image to make it go full screen

If that's not the problem, I can take another picture

[naive forum]

yeah its not the problem, pls take another picture

[ember kernel]

Is it better ?

[naive forum]

yes, thanks

[mild hill]

Hello guys ,can you solve this please?

[crystal mural]

use trig substitution

x = 2sin(t)

[mild hill]

Thank you

[ivory sparrow]

Hi

Can you guys solve the indefinite integral of a secant squared?

[ivory pumice]

sec²x?

tanx+c

[rare sorrel]

heyyy, can someone help me with this one please :c

(the exercise is in spanish so i had to translate it)

[rare sorrel]

ohh thanks a loot 😄 😄

i was very confused with that one

[left knoll]

You’re welcome✨

[potent peak]

heyy can anyone lend help

[granite crow]

@potent peak I wrote the relevant rules on the side

[potent peak]

okie thank you so much!!

[granite crow]

no worries

[left knoll]

Is anyone REALLY good at functions and is willing to help me with a few questions and understanding ?

[ember kernel]

Yup

[left knoll]

Ty again HAHAH I’ll dm you

[solid anvil]

someone help with maths

[last echo]

Send ur question, if I can then I'll ans it 🙂

[solid anvil]

can someone solve any 1 of the following question

[ember kernel]

For a)
Area of shaded region = Area of ABCD - Area of AEB

[solid anvil]

will i get both or only 1??

i mean the area of aed and bce or only 1 of them

[ember kernel]

Take the parallelogram ABCD, and then remove the region covered by the triangle AEB.

What remains is the two triangles ADE and ECB

[solid anvil]

ohh im stupid

[ember kernel]

Nah you're not

Plus, you now know how to proceed for the last two :D

[solid anvil]

:D

[solid anvil]

ayo someone help me again

(i) no.

someone

:(
help

[left knoll]

Guys I too need some halp plz

[left knoll]

Can anyone explain this whole sum pls 😭

[solid anvil]

question not clear :)

omg jesus

seen no reply :)

[left knoll]

Yo

[ember kernel]

[I used • as the multiplication operator]

By rearranging the two initial expressions (which I named A and B for clarity) :
A = 10(x²-1) = 2**• 5•(x+1)** •(x-1)
B = 15•(x+1)⁴•(2x+3) = ** 5•(x+1) **•3•(x+1)³•(2x+3)

You want to get the Highest Common Factor (HFC) of A and B, which are already expressed with factors.

The factors that you find in both A and B are 5 and (x+1). Thus, if you want to get the HFC, multiply them all (as they are factors of A and B), which gives you 5•(x+1)

@left knoll Does it help ?

[left knoll]

Oh my god THANK U SO MUCH 😭

[ember kernel]

Glad I could help 😁

[ember kernel]

Sorry, geometry is a weakness of mine

[ivory pumice]

20

Join QN , PM &QS , Area of PQN= area of PQS = area of PSM = 5×8/2 = 20

&angle PSM = 90°

[stone raft]

could someone help me with this problem

thanks

[flat hatch]

Sup people, hope you are having a beautiful day

I'm having my head burnt my this problem, can anyone find a solution to it??

-7^2+14.7-156

I'm finding 20, but not shure at all about it

[ember kernel]

The order to follow is always :

• Parenthesis
• Exponents
• Multiplication/Division
• Addition/Substraction
  Also known as "PEMDAS" to remember it easily

Thus :
-7² + 14.7 - 156
= -49 + 14.7 - 156 (exponent first)
= -49 + 98 - 156 (then multiplication)
And finally you can do the sum.

I took into account that the minus sign of -7 isn't included in the square as well. If you meant "the square of -7" instead of "the opposite of the square of 7", be clear about that by writing (-7)²

[flat hatch]

THXXX

[cinder olive]

r

[fringe narwhal]

Hii I'm doing a optimization exercise but I don't really understand the topic

This is one of the exercises would someone please help me how to realise it🙏

I know that I have to derivate the function and then... Make a supposition to get the values to make the f'(x)= 0...?

[left knoll]

Hope this helps

[last echo]

thats the exact same thing that i told u xd
well sometimes being stupid is actually good, u do learn a lot

[solid anvil]

thx i learned how to do it :)

[peak gale]

are you still on this problem?

[abstract latch]

hey guys can someone help me with the problem number 4?? im stuck for a couple of minutes now :((

[pulsar turret]

Can anyone help me understand as to why D is the answer? I’d really appreciate it

[left knoll]

hi does anyone know how to do q10

[crystal mural]

Think about it, the bigger x becomes thr faster it will grow, making it narrower

To move the whole graph you change the constant factor

Graph the function with desmos and try playing around with it, that helps immensely

[pulsar turret]

I see

[ember kernel]

You get dy/dx = 5x^4 - 15 x^2 - 20 = 0
Use z = x^2 and to be able to use the quadratic formula and get the values of z. You can them get the x-values where dx/dy = 0 using x = +/- sqrt(z)

The rest of the answer should be the same as the previous questions

[abstract latch]

ohhh got it thank you very much! :))

[ember kernel]

No worries

[acoustic delta]

What is your favorite geometry channel on YouTube?

[left knoll]

Hey! Anyone has any experience with the kernel methods? (Kernel Trick)

[fallen dock]

Can someone check this ?

[left knoll]

I think it is true

[plucky gorge]

This is true!

[left knoll]

Write an arithmetic progression of three terms so that its sum equals -3 and its product equals 8. PLSS

[rustic shuttle]

X-R, X, X+R
sum is 3X=-3, therefore X=-1,
(-1-R)(-1)(-1+R)=8
(1+R)(-1+R)=8
-1+R^2=8
R^2=9
R=3
Therefore, (-1-3),(-1),(-1+3), or -4, -1, 2

[rustic shuttle]

^

[steel plover]

can someone explain how both sides are equal here please?

[left knoll]

@steel plover find the value of a and put it in both sides and you eill see the result on both sides will be same.

[steel plover]

that's the ans I get when I evaluate the LHS

[wary pulsar]

how do you find the magnitude and direction ?

of a vector

[sharp ibex]

Can someone help me on #38? It has graphs on the other page to go along with it. It's a SAT question.

[north widget]

wanna ask that if my tan(theta)=5/18 , 180<theta < 270, find sin(theta)

[bold atlas]

Ping me if u get it

[green root]

is the answer 30.5?

I did by adding up the volume of hemisphere and cylinder, presuming the lid doesn't overlap the cylinder

[bold atlas]

yea it is

btw i cant understand the question

the lid part

[green root]

Here’s the diagram, sorry the dimensions arent drawn to scale, but here’s the shape of it

if 30.5 is correct, you can imagine the lid part(hemisphere) is attached to the upper surface of the cylinder, so now the interior volume would be the total of volume of both

[bold atlas]

cool

thanks!

[left knoll]

the magnitude just means the size of the vector (regardless of direction). In this case it would be the 4.5 lb.

The direction here is measured as an angle, i believe you can just say the direction is 110°to the horizontal or something like that

[wary pulsar]

ty!!

[lofty arch]

In my experience with linear algebra, angles should be measured counterclockwise from the positive x-axis unless specified otherwise

So the angle is either 250° or 110° clockwise

[left knoll]

i see, thanks

[last echo]

In a PQR, N is a point on PR such that QN ⊥ PR. If PN  NR = QN^2 , prove that NPQ ~  NQR.

that box is triangle

[lofty arch]

PN*NR=QN^2, we can get from that PN/QN = QN/NR

calling angle PQN theta, tan(R) = QN/NR, tan(theta)=PN/QN,

so tan(R) = tan(theta), and since R and theta are strictly less than 90° (from angle sum of a triangle), R = theta, and you have SAS similarity

that was like 3 different iterations for 3 lines of working smh

[solid anvil]

i guess you know both <qnp and <qnr are 90 perpendicular so we got one (a)

[solid anvil]

using rhs would be better i guess

[last echo]

no trigo

v need to use bpt and similarities only

[last echo]

and no rhs similarity too

plz let me know if it cant be solved by any bpt and similarities(AA and SAS) only

cuz it wont be tested

so i can move on to the next one

[last echo]

can someone explain this asap

[red cradle]

omg

[peak gale]

perhaps use vectors and the Chasle's relationship for deriving the

eqality

[left knoll]

obrigado ❤️

or thanks kkkk

[rustic shuttle]

xD

[vivid kindle]

Hola, alguien aquí que entienda español y me pueda sacar de duda ,si la desviación estándar en medidas de variabilidad es diferente en una muestra y en una población?

[lofty arch]

you first use PN*NR = QN^2 to show that angle PQR is 90, then set angle QPN = alpha, which leads to angle PQN = 90- alpha, and hence angle NQR = alpha, so you have AA similarity

[gleaming monolith]

hola, busqué el tema porque no lo se y encontré esta página, espero que te sirva

https://matemovil.com/varianza-y-desviacion-estandar-ejemplos-y-ejercicios/

[lofty arch]

This is just a few steps realising that BMC and EMD are congruent and then using properties of a parallelogram

[last echo]

ohkk thx

[last echo]

thx a lot again :)

thx @frank sleet and @peak gale

[flint trout]

hey @everyone does anyone know how to solve this question?

[lofty arch]

You need to calculate the error for sin and cos first, and then you can find the maximum error in quadrature

Or you can choose to use these formulas instead, which are essentially the same thing but require a little bit of calculus to understand intuitively

[celest quarry]

can someone help with this? the answer is 49 but im not sure how to get there

[lofty arch]

Are you working with complex numbers?

wait no that won't work

[ember kernel]

Because a^101 = 1, maybe you could start by rewriting a^200 = a^99, a^102 = a, ...

[celest quarry]

why would that work? im a bit confused

[ember kernel]

I don't know. I'm not home so I have no access to my pen and paper and I can't work on that problem. I'm just trying to find ways that could help us start solving the problem

[celest quarry]

ah alright, ill keep trying. thankyou though!

[lofty arch]

this implies that a^202 is also 1

Also denominators are all differences of two squares, you can take a factor of (a-1) out of each of them

[celest quarry]

how does that apply into that though?

sorry im kinda completely clueless about this ;-;

[lofty arch]

yeah not 100% sure about this one tbh

just trying to brainstorm as many things as possible

[lofty arch]

this is probably the right way to do it though

[celest quarry]

ah alright

i dont really know how to go from there though

id assume theres something to do w factorising the denominator too

[lofty arch]

a^200/(a^100-1) = (a^99 + 1 -1)/[(a-1)(a^99 + 1)]

[celest quarry]

OH

OKAY

thankyou omg

[lofty arch]

yeah i think that's what you gotta do for everything

[celest quarry]

okayy thankyou so so so much!!

[lofty arch]

hopefully that works!

[inland oracle]

Summation
PG= geometric progression

[acoustic delta]

Do you need to find a_15?

Or wat

[inland oracle]

yes yes

[acoustic delta]

@inland oracle

[inland oracle]

thanks!! 🥰

[upper mountain]

How can I calculate this summation exercise

[lapis sand]

break it into a telescopic series

1-1/2+1/2-1/3+1/3-1/4+1/4-1/5.....

[upper mountain]

Thanks uwu

[rustic shuttle]

What app did u use to write like this?

[celest quarry]

ok still need help haha

[obtuse pike]

can someone help with alg 2

i need to find the translation

[lapis sand]

x---->x-3

[acoustic delta]

Graphic tablet + pdf element

[inland oracle]

Firm A has an initial production of 1,500 units and decreases at the rate of 15 units per year. Company B has an initial production of 300 units (the initial year is the same for both companies) and increases its production by 10 units for each year.
a) When will both productions of A and B be the same?
B) When will the production of A be zero?

[steep scaffold]

@inland oracle I think this is the answer for both questions, if anything's wrong let me know

[inland oracle]

THANKSSS

[steep scaffold]

ur welcome!!

[solid anvil]

a no

ans is 3/2 right??

yes

[left knoll]

i got 1????

[solid anvil]

can you send process

[idle olive]

x=1/2-√3 find x^3-2x^2 - 7x + 5

[solid anvil]

i think its 3

[idle olive]

umm

[solid anvil]

wth hell is that

its indices

[left knoll]

see

[solid anvil]

:)

sned process

[left knoll]

just expand and take 2^x common

[idle olive]

what do u mean

[left knoll]

wha 10th is this tho

[solid anvil]

3 remains up as 2 and -2 cancel each other

and i dont understand down

10th :)

[left knoll]

try to solve the polynomial itself and find factors, then put the value of x?

[left knoll]

i did 10th last year this isnt ncert idjsnk

[idle olive]

umm ok

[solid anvil]

imbad in maths

can someone send process

[left knoll]

Ah I didn’t read it dndjjs

I tried to make it as simple as possible

💀

[left knoll]

@solid anvil

[solid anvil]

nvm i forgot the first rule

i canceled 2 x and -2 x

[solid anvil]

i sloved all now it was easy :)

[covert anchor]

How do I solve

[lapis sand]

Use vanishing method

guess a solution first say n then factor x-n out

after that it's a simple quadratic

[lofty arch]

that's such a nice way of solving these cubics without having to go through the pain of polynomial long division

might steal that myself, thanks!

[covert anchor]

how did this happen

u split the 46x into 22x and 24x

[lofty arch]

(x-a)(x^2+bx+c) = x^3 -13x^2 + 46x - 48, so you're looking for -a + b = -13, ab + c = 46 and -ac = -48

[lofty arch]

and you can find a=2 pretty easily by substitution

it's just a matter of understanding how the expansion works and then rearranging your stuff so that you can see how it all comes together, it would've made more sense to write -48 as -2*24 if that helps you see it better

[lapis sand]

I knew that 2 is a root so I manipulated the polynomial to take out x-2 common

[lapis sand]

[small canyon]

guys can someone help me with the 12th question, kinda stuck on it

[weary zodiac]

use gauss-jordan inverse

[small canyon]

i have no idea what that is 😅

[lofty arch]

You're basically solving A*A^-1 = I (the identity matrix)

There's a neat trick for it that you'll eventually learn, but elementary transformations means you're gonna have to do this the long way

So you need to make the top one look like the bottom one to find the inverse

Essentially you're rearranging it to reach the equation A^-1*I = A^-1

[small canyon]

thx alot

[cobalt rapids]

???

[lofty arch]

that fraction on the right will go to zero as n increases

the denominator must diverge faster than the numerator

so it just becomes 1

[opal flint]

1. Write the (...)^n as exp(nln(...)) 2) Use Taylor series to conclude. (You should get a limit of 1)

[left knoll]

anyone know how to do dis

[cobalt rapids]

like this?taylor series on what

[cobalt rapids]

i dont get it🤷‍♂️
im at 12th grade level, if that helps

what does 'Hn' mean

[opal flint]

Oh sorry, I think taylor series are undergraduate stuff right?

[cobalt rapids]

idk where i live people use undergraduate stuff in school too

wait

this is the official answer

but i dont get it

@opal flint

[opal flint]

The answer on your screen is quite contrived: the author also uses the Taylor series like me, so that's how they get L = lim exp((1+1/2+...+1/n)/n)). With this expression, the author tries to find an upper bound of the term within the exp so that it tends to 0

The term inside the exp can be cleverly (and rather unintuitively) upper-bounded by (n+1/2^n) which has a limit of 0

I prefer my answer: it is easy to show, and quite known that the harmonic series is equal to log(n)+ O(1)

[cobalt rapids]

okkayy. i def get it better than before. and yours is easier anyways. thanks a lot. :)

[mellow bramble]

someone speak spanish?

[left knoll]

can someone help me with this question?

[ancient thunder]

Someone could help me solve this is set and relationships.

[dusky mesa]

Bruhh.. I remember this problem when I was preparing for JEEE.. such nostalgia

[cobalt rapids]

glad we could share the misery

[dusky mesa]

Haha.. all the best.. hope you do well 👍

[cobalt rapids]

ty:)

did you make it in?

[dusky mesa]

Nahh bruhh.. my chemistry sucked.. I was decent at Maths tho..

[cobalt rapids]

damn bro okayy. is there still hope if i dont make it coz it looks like i wont do that well at this point

[dusky mesa]

Haha.. I had same thoughts at the time.. But after almost 3 and a half year.. I'm in my final semester of my college and have 2 Job offer letters.. the pay isn't humongous but it's enough for me.. don't loose hope.. give your best. There's always a way

[ember kernel]

That's what I have

It may contains some mistakes, I'm quite tired tbh. Could someone check and confirm my answer pls ?

[ancient thunder]

I don't know if its okay, but thank you very much

[sterile hare]

can someone help me with this question?

[cobalt rapids]

okayy

[craggy plume]

Why does the square root 6x-1 not get cancelled?

[ember kernel]

Because both terms of the numerator have to be divisible by sqrt(6x-1) :

5(6x-1) is divisible, but 3(5x+1) isn't

If you did cancel the sqrt, you'd be back to the step 3 lines starting from the end of the solution

[plain terrace]

What is combinatorics

[lofty arch]

That's a deep question lmao

[ember kernel]

In a nutshell, it is the study of how many possible outcomes/arrangements a problem that involves sorting items given specified conditions has.

Example 1 : If you shuffle a deck of 13 cards, how many arrangements (combinations) of cards could you possibly get ?

Example 2 (harder) : Knowing that :

• Volley-ball teams are made of 6 players (with specific positions named from A to F)
• 11 students are members of the school team
• Student n°6 can't play at position B for some reason
• The order in which non-playing members are sat on the bench next to the terrain doesn't matter

As the coach, how many possible arrangements of all 11 members can you make ?

[plain terrace]

@ember kernel thankyou soo much

[left knoll]

Can anyone give me answers for the questions which marked pls

[proper sail]

The passage and the question 81.Please help in this question!!

[ember kernel]

The one you circled, (a), seems good to me, as there is no guarantee that the trio GJK is linked to the trio MSP

[ruby tinsel]

Could someone please helpppp

[left knoll]

AAAAAA OMG THANK U 😭😭😭❤️

Thank u very much 😭

[weary arrow]

First find the volume of a sphere with r=10 cm. Then find the volume of a cylinder with r=2 cm (diameter=2r). Substract the second value from the first value, and you should get the answer

The height of the cylinder will be 20* cm

[ruby tinsel]

If the height of the cylinder is 20cm, we're kind of over-estimating if that makes sense... The two curvy plates?... like lids need to be considered

[weary arrow]

I assumed the lids would be ignored for simplicity's sake, wasn't sure how advanced the math was supposed to be

[ruby tinsel]

I have my working out but I just am not sure if I'm right

There were two different solutions and answers given to me so I'm shooo confused...

np thank u

Ahhh I will double check with my teacher but thank you!

[alpine escarp]

How do you get to the equation from the given set

[thick pine]

You show that the three vectors in the set are a generator of R3: https://en.wikipedia.org/wiki/Generator_(mathematics)

Solve this equation for lambda1, 2 and 3

[alpine escarp]

Thank you so much! @thick pine

[thick pine]

Sure, no problem!

[thick pine]

Haha thank you but that was the answer to @alpine escarp question on how to get the equation in his picture

[ember kernel]

Oh mb

Thanks for notifying me

[proper sail]

Please help with this question!!!

[novel wigeon]

That's hard but P is 3,14 you probably know that so devide it by 2

@proper sail

[steel plover]

anyone know how to do c? I already finished the other 3

[rustic shuttle]

1/2 ?

[steel plover]

thanks

[left knoll]

Heya can u halp me now...ehehehe

[solid anvil]

can anyone help me understand

i didnt understand what teacher did

i have the question as well ig

yes i have someone help

[mossy fjord]

The 2nd term was multipled by b^-1 both in the neumeratorr and denominator (so ultimately it cancels out )
In tge denominator , b^-1.c^-1 is -a
(abc =-1
a= -1/b.c
-a = b^-1 .c^-1)
Similarly , -a is multiplied both in the neumer.. and the denomin.. In the 3rd term Also a.c is
-b^-1(abc = -1
ac = -1/b
-ac = 1/b
ac = -b^-1)

[solid anvil]

feel like im getting it

[solid anvil]

thx

@mossy fjord

[mossy fjord]

If you r still confuse i can explain it better :)

[solid anvil]

ill ask for help if i dont understand :) again

[solid anvil]

can you explain 3g

[modest ice]

Yall if h is tending towards 0 then shouldn’t that be the left hand limit and when dealing with LHL shouldn’t the function say f(x-h) ....like is there sth m assuming wrong in here?

[tacit frost]

@left knoll

[left knoll]

Heya can u help me in these sums

@tacit frost

[solid anvil]

how will i understand if you skipped steps

[tacit frost]

send em let me see

which package

[high nexus]

Hello, this is the definition of derivative

[warm surge]

Sorry I am too bad in english to be able to explain😅

[solid anvil]

oh

[left knoll]

I want pearl package
Emerald package passage type questions
And diamond....

[tacit frost]

the picture is too blurry i cant see

[left knoll]

Oh noo

[left knoll]

Pearl package I'll write the rest of the q's

[modest ice]

Ahh ahh wait so this ain’t got nothing to do with the calc ic it’s the principle 😭m dumb ✋ but like ummmgenerally if we see x tending towards zero it will be considered LHL?

[left knoll]

Here's the emerald package

[high nexus]

not necessarily

the theorem explains the existence of a limit, so you have to do it from both left and right

there simply has to be that limit

[brave wing]

Is this formula applicable for fractional increase (v2-v1)/v(average) rather than (v2-v1)/original v

[left knoll]

Spamming these pics for the 4th time....HALP MEEE 😭😭😭😭😭

[ember kernel]

Statement A is false because (x+1) is not a factor of f(x), but (x-1) is [using quadratic formula]

Statement B is true (that's what I used in all the answers)

[modest ice]

Ah ahhh got it thanks!

[left knoll]

AAAAAAAAAAAAAAAAAAAAAH
THANK U SO MUCH 😭

[solar summit]

Can anyone help me with q2 perimeter?

[ember kernel]

9 + 6 + 9 + 1 + 1 + 2pi* 2/2 = 26 + 2pi

You get the 2 via radius = (6-2*1)/2

And it's obviously in cm

[solar summit]

oo tyvm

[ember kernel]

Wait

There, I corrected the answer

[solar summit]

why 2/2 again?

[ember kernel]

2 is the radius of the circle
/2 because you only have half a circle

[solar summit]

Ok, I appreciate it sir

thanks once again

[ember kernel]

Np

[flat bolt]

Help

[lofty arch]

you know that they form an equilateral triangle in a unit circle

wait no this is worse that i thought

[lofty arch]

Ok i've got something

The radius of the small circles must be chosen such that the lines connecting the circles tangent to the unit circle must be equal to 2r(n-1)

[thick pine]

Equilateral triangle -> 60° in corners, distance to each corner from the middle = 1, trig. functions give you the length of the sides

[craggy plume]

May i know how can i get the correct answer? I keep getting the answer wrong…

Its about product rule in calculus-differentiation

[pastel helm]

Derivative of root(x+3) is 1/2root(x+3)

[lofty arch]

and the distance from the centre of the tangent circles to the centre of the unit circle is (1-r), and you can use cosine rule to get that the lines connecting the centre of the tangent circles is sqrt(3)*(1-r)

[thick pine]

Maybe I have some mistakes somewhere haha

Or did I misread the question somehow haha

[lofty arch]

so we have sqrt(3)(1-r)/[2r(n-1)] = 1, which solves to r = sqrt(3)/[2n-2+sqrt(3)]

[flat bolt]

Thx dud

[novel wigeon]

Anyone know how to solve this

An annual pass to the gym cost SEK 2,500. The price is increased by 6 %. What does the annual card cost after the increase

[solid anvil]

help

4h

[solid anvil]

2650

[left knoll]

do 2500 x 1.06

decimal multiplier for 6% is 1.06

gives 2650

[novel wigeon]

Thanks

[solid anvil]

that makes no sense

[left knoll]

wym

[solid anvil]

its like 6/100*2500

[left knoll]

maybe you learnt it differently

[solid anvil]

oh yea sry

[novel wigeon]

Yeah I live in Sweden

[solid anvil]

can you help me with my prob

[novel wigeon]

That's not how you learn it here

But thanks

[left knoll]

idk how to do it lol

sorry

[solid anvil]

;(

[novel wigeon]

@solid anvil I think i can

[solid anvil]

rlly?

[novel wigeon]

But its probably gonna be differently from how you learnt it

[solid anvil]

this question looks like 7th grade

[solid anvil]

yea nvm can you teach me

[novel wigeon]

Are you in the 7th grade?

[solid anvil]

no 10

[novel wigeon]

Okay wait a minute

But which one should i solve there is many a or b ?

[solid anvil]

i took lcm from down but idk what to do

[solid anvil]

4h

the one above 5

[novel wigeon]

Can you take a better picture of it its blurry

[left knoll]

this one right?

lemme try

[solid anvil]

yes

[novel wigeon]

I know that a^2+b^2+c^2 is used in the pythagorean theorem

So the answer of that is c^5

[left knoll]

isnt pythagoras' theorem a^2+b^2=c^2

rather than a^2+b^2+c^2

ok ive worked it out

answer is a^2b^2c^2

all multiplied

[novel wigeon]

That's right

[covert quest]

yep

[left knoll]

yeah thats right

[solid anvil]

damn

thx

[vale wyvern]

Can anybody help me

How to find the minimum value of cos(2x) + cos x

Ty

[opal flint]

Take the derivative of cos(2x)+cos(x) and find where it is equal to 0

[rancid copper]

Someone help me please
The sides of a triangle are 3 consecutive integers. A perpendicular is drawn on the second largest side. If it divides the second largest side into two parts of lengths p and q respectively, then find the value of (p – q)^2

And also this one too please

[rustic shuttle]

lets say we have a triangle with x-1, x, x+1 as sides, if we draw the perpendicular in x, we get two triangles with a 90ª

And one side shared

If you apply pythagoras theorem in both squares, and isolate the value of the shared side you get an equation that will have (p~q)^2

Idk if i made myself clear

[rancid copper]

ohkayy!!

[rancid copper]

yes u very much did! tysm!!

@rustic shuttle lol sorry im tagging u rn bt cud u help me with the second one aswell?

[rustic shuttle]

well, idk what is inradius, english is not my first language

[rancid copper]

its basically the radius of a circle formed inside a triangle(the circle touches all the three sides)

[rustic shuttle]

k, let me see

[rustic shuttle]

well, idk how to do it lol xD

[rancid copper]

lmaoo its okayyy!! thnks fr the help overall tho!

someone free to help me with some more maths questions? i hv 3-4 doubts

idk no one responding ill post them here...hope ill get some kind of response

1. Let ABCD be a convex quadrilateral with ∠BAC = 30°, ∠CAD = 20°, ∠ABD = 50° and ∠DBC = 30°. If the diagonals intersect at P, then find ∠PDC (in degree measure)?

2. Let a=π/494. Find the smallest positive integer n such that 2[cos(a)sin(a) + cos(4a)sin(2a) + cos(9a)sin(3a) + ………+cos(n2a)sin(na)] is an integer.

3. In rectangle ABCD, AB = 50. Let E be the mid-point of AD. Given that the line AC and the line BE are perpendicular, find the greatest integer less than AD. (take √2 = 1.414)

4. The perimeter of triangle APM is 152 and ∠PAM = 90°. A circle of radius 19 with centre O is drawn with diameter on AP so that it is tangent to AM and PM. Find AM.

[last echo]

so basically u hv to find 6% of 2500 and add it to the original amt i.e. 2500

6% of 2500 is 150
=6/100*2500
so amt after increase is 2500+150
=2650

[lofty arch]

Quadrilaterals need to have an angle sum of 360 degrees, this doesn't make sense

Just draw out 3 and 4 and you should be able to see the proof without too much work, give labels to everything

And 2 is disgusting

[left knoll]

Hello, anyone know how to unwrap this?

[glad cave]

Can someone help me with this?

My class test is going on T T

[rancid copper]

u should try making the diagram once...ull understand that 2 angles mentioned there are not made by 2 sides and rather by a side and a diagonal

[rancid copper]

i tried it already...i still couldn't do it nd that is why i asked these questions here

[rancid copper]

okay and?

[lofty arch]

ohhh true mb

[high nexus]

194

[glad cave]

Tysmm

[modest ice]

Hey can someone solve this please thanks in advance …

[ebon igloo]

I have to calculate the domain of this function, I got the answer 3/4<x, however, when I checked the answers, it was 3/4<x<=1, where did the 1 come from?

[rustic shuttle]

I think there is no log in the 0.5 base that goes to something bigger than 1

in this case it would result in negative values so you cant take the square root

[ebon igloo]

ahh oki ty

[abstract valve]

Hi I have a question.
I can't understand how the professor went from the first line to the second. What was the process?

[ember kernel]

4x/3 = 3x/3 + x/3 = x + x/3
x = (4/3)^k and he did the same for (5/4)^k

@abstract valve

[abstract valve]

Thank you

What is the name of that process/attribute so I can look further into it?

[ember kernel]

I don't think it has a name, as it is as simple as a sum. But the first equality of my demonstration implies the distributive property (a+b)x = ax + bx

[verbal estuary]

hi guys, how can i check if a funcion is continuous?
exercise 26

all i know is that we have to use limits but i don't know how to start

[rustic shuttle]

The limits from left and right in x=1 must be the same to the limit in x=1

if it is the same the function is continuous

[verbal estuary]

and what about the middle one ( 1 x=1 )

what am i supposed to do there?

[rustic shuttle]

Also apply the limit

[tidal galleon]

the idea is that the first part has to approach 1 as x approach 1 from the left and the third part approach 1 when x approach 1 from the right, if those ¿branches? (i don't know the word in english) go to the same point, and the middle one is that exact point, then the function is continuous

[rustic shuttle]

that ^

[verbal estuary]

thank you

i resolved the exercise and the first and the third limits give a different results so they are not continuous

and the ex. book says that the result is : R - (1)

the first limit gives 1, the third one gives 2

so, that "1" in the result, where does it come from?

[tidal galleon]

i graph it in geogebra and the first and third go to the same point but it is (2,1) instead of (1,1)

[tidal galleon]

the 1 means that the function is continuos in all R except in 1

[tidal galleon]

any ways the answer is the same, the function is continuous in all R except in 1, if we take your answer it's bc the function makes a "jump" and if we take mine it's bc there is a point that isn't in the right place (technically is also a jump but :p )

[verbal estuary]

and how could you find that "1" without using geogebra to see the graph?

[tidal galleon]

it's the point where the functions should connect

in a random exercise you should look for discontinuities in the points where the branches meet. Also you should check (if they are in the domain) the points where strange things could happen like something/0 or square roots from negatives

and you prove the discontinuity by showing a) that the function is not defined or b) the laterals limits are different between them or with the actual value of the function

the last case is the one in this exercise

[verbal estuary]

thank you so much for the help ❤️

math is too difficult for me

[left knoll]

can someone please share their solution for this question? Class 11 ; Relations & Functions

[tidal galleon]

you could check 3blue1brown videos on youtube, he made some series about calculus and linear algebra that are awesome, super graphic and clear, they helped me a lot to understand completely some concepts

[verbal estuary]

thank you so much, i will check his videos later on or tomorrow
Have a nice day bro ❤️

[tidal galleon]

you too!!

[naive cape]

in general you can use the definition of an identity fuction (f(f(x))-x=0) or f°f(x)=x

[proper sail]

Please help in this question!!

[scenic nest]

Guys

https://links.easya.io/links/gp-2

This app is actually really good

I used to use photomath before and would usually not understand why the method was as it was

But you can actually download this app for free with this link and talk to tutors who will help you

deffo recommend

[wraith geyser]

Oh it's not available for me

[opal flint]

The answer is 2: the sum of the geometric series with the common ratio being 1/2 is 1(1-1/2)

[opal flint]

You want to show that f(f(x)) is an identity fonction, so for x in R (with 5/4 excluded), you have to show that f(f(x))=x. Write f(f(x)) and you should verify that easily

[opal flint]

You should apply the tan function to the left part of the equality (we can do that since arctan is bijective on the interval considered), then simplify a bit and you should get there by using the formula of tan(a+b).

[formal stag]

does anyone know how to do these

[rustic shuttle]

Pardon my paint skills

I forgot to calculate the fraction but u got the idea

The third is kinda like the second one

but with perimeter instead of area

[azure bolt]

help me with this question, I already solved it but I don't know if I did it right.

[solid anvil]

open image in new tab and zoom its not quite that clear but zoom and see youll get it

[distant walrus]

that looks very familar

[left knoll]

which ques tho

[solid anvil]

4a

the first one

[left knoll]

what help do u need in a constructions question

[solid anvil]

i mean i cant understand

i can construct the quadrilateral measure the arc but dont know what do i do afterwards

[left knoll]

do u know if u need to draw the triangle in the quadrilateral or separately

[solid anvil]

in the quadrilateral

lemme send a pic real quick

It looks like this only quadrilateral

[left knoll]

Draw a line parallel to the diagonal QS through point P

[solid anvil]

I did that and made an arc I don't know what to do afterwards

I'm stuck

[formal stag]

thank you

sorry i know this question isnt too hard but my brain just isnt working right now.. does anyone know how to solve this?

[solid anvil]

It's indices

[formal stag]

yea but going through a brain lag and cant get the solution

[solid anvil]

Let me try

[formal stag]

thank you so much

from the mark scheme the answer is 4/5 but i want to know the working to it

[left knoll]

I made a demonstration see if it helps i don't think drawing arc is needed here

[left knoll]

triangle SOR is the req. triangle

[solid anvil]

My brain is defused now

[formal stag]

felt

thank you for trying

[solid anvil]

I still don't understand how you did that

[solid anvil]

Still don't understand 😭😭😭

[left knoll]

https://socratic.org/questions/how-do-we-construct-a-triangle-equal-in-area-to-a-given-triangle-or-quadrilatera#:~:text=We are to construct a triangle equal in area to this quadrilateral.&text=Principle followed-,The areas of all triangles of same base are same,between two parallel sraight lines.&text=The diagonal BD is,a ruler and a compass.

[left knoll]

Hmm this link should help you

[solid anvil]

We haven't been taught like this I don't get it

[left knoll]

I am sorry i wasn't of any help but someone here must be able to help you the other way

[solid anvil]

But thx for help

[left knoll]

Hmm taking log on both sides should help for b)

[cloud girder]

hey can anyone help me out

[tacit frost]

hey guys! i need some math help.

thats the question and here's the answer but idk how

[tacit frost]

nvm i got it ...

[proper sail]

Please help in this question!!

[ember kernel]

One property of hyperbolic trigonometric functions is that (sinh x)' = cosh x and (cosh x)' = sinh x

Thus, via the chain rule : ( sinh(x²) )' = cosh(x²) * (x²)' = 2x cosh(x²)

@proper sail

Don't mistake it with trigonometric functions, with which a - appears when derivating a cosine

[proper sail]

@ember kernel thanks man

[ember kernel]

You're welcome buddy

[proper sail]

Please help in this question!!!

[rustic shuttle]

y=e^(sinx cosx)
y'=e^(sinx cosx) * (sinx cosx)'
y'= e^(sinx cosx) * (sinx*(-sinx) + (cosx) *cosx)
y'=e^(sinx cosx) * ((cosx)^2 - (sinx)^2)
y'=e^(sinx cosx) * cos2x
(a)

[proper sail]

@rustic shuttle thanks bro

[sharp totem]

could i get some help on this if possible? i've been stuck here for a while 🥲

[ember kernel]

Tell me if that works

For my answer, I used a vectorial parametrised function C(t) = (x(t), 150) to be the position of the car. Thus, both x and y act as outputs of C(t), while t (which is not represented by an axis in my sketch) is the actual variable of the function C, and thus of the function d (the distance Car-Observer)

[sharp totem]

that worked!! thank you so much and thank you for showing your work and explaining. T__T have been stuck on this for at least an hour so i really appreciate it ;; @ember kernel

[ember kernel]

I'm glad I could help you ^^

[steel plover]

does anyone know how it got (3x^2 +1)

that's the question btw

[rustic shuttle]

x^10(x^2+1)^10
10x^9(x^2+1)^10 + x^10 (10(x^2+1)^9 (2x))
[10 x^9 (x^2+1)^9 (x^2+1)] + [10 x^9 (x^2+1)^9 2x^2]
10 x^9 (x^2+1)^9 [(x^2+1)+ (2x^2)]
10x^9(x^2+1)^9 (3x^2+1)

let me know if u understand

basically there is one (x^2+1) in the left part and (2(x^2)) in the right part

[rustic shuttle]

^

[winged coyote]

new to the topic(says pi/8 at the end btw

[steel plover]

ohh got it. thank you!

[polar quiver]

try to do it from there 🙂 just product rule it

[winged coyote]

thanks for the help

[polar quiver]

all good mate. if you need more help feel free to let me know @winged coyote

[blissful narwhal]

plsh elp

[left knoll]

Ans is 2

[blissful narwhal]

thank you! 🙂

[proper sail]

Please help in this question!!

[ember kernel]

arctanh(x) = 0.5 * ( ln(1+x) - ln(1-x) )

Proof and used method in this video : https://m.youtube.com/watch?v=dpnqhIVd-pg

From there, you can use (ln x)' = 1/x and chain rule to calculate your way to the answer

[unreal mirage]

100a + 10b + c = 2a + b³ + c³

100a + 10b + c is a even number

What is a, b, c??

I've worked on this all day. Just can't solve it

[peak gale]

did you find at least b and c are even numbers?

[ember kernel]

I guess it is implied that a, b and c are integers ?

[ember kernel]

If it can help, here is the list of all the solutions such that -200 <= a,b,c <= 200 :

(-174, 14, -27), (-150, -10, -24), (-150, 10, -25), (-138, -24, 4), (-135, -14, -22), (-117, -18, -18), (-108, -14, -20), (-30, -14, -7), (-18, 196, -196), (-9, 98, -98), (0, -4, 3), (0, 0, -1), (0, 0, 0), (0, 0, 1), (0, 4, -3), (9, -98, 98), (18, -196, 196), (30, 14, 7), (108, 14, 20), (117, 18, 18), (135, 14, 22), (138, 24, -4), (150, -10, 25), (150, 10, 24), (174, -14, 27)

[I obtained them numerically]

[solid anvil]

someone help me how do i make a parallelogram from a triangle

i mean explain idk what to do after pulling the parallel

[stray elk]

Can you find a angle

[atomic cipher]

why is this wrong?
http://0x0.st/-OIp.png

[proper sail]

@ember kernel thanks man

[left knoll]

https://gyazo.com/2ad18249111cfeba1560c0071a9a05b9

can anyone help me

[open wolf]

türksun galiba o yuzden bole yaziyorum
e ile a arasindaki nokta ic teget cemberinin merkezi oluyor gerisi gelir heralde

[open wolf]

2(12x+11) + (80+13×-1) = 360
24x + 22 +79 + 13× = 360
37x = 360 - 101
37×=259
x=7

[left knoll]

oh okay

thanks

[open wolf]

np

[proper sail]

Please help in this question!!

[nimble sand]

Take logs on both sides

And then solve

[left knoll]

Here's your answer

[stray elk]

Gerisi gelmedi ama sağol

[left knoll]

Use natural log, I didn't use natural log 😅

[open wolf]

kusura bakma musai degilimtam cozum yapip atamiyorum

[proper sail]

OK but I don't know in Answer key in my book it's written option D

[left knoll]

Option C is right, maybe printing error

[proper sail]

Or I think it's wrong in Answer key

OK

There is still some confusion in my mind when I applied product rule I didnot get 1/y at the left side of equation

But you got 1/y

[left knoll]

You need to use amplicit differentiation method

[stray elk]

D ve c doğrusu açıortaysa dediğini anladım sanırım

[left knoll]

Umm angle B is of 30°

And maybe we can solve further by similar triangle

Or something like that

[left knoll]

Sir, you just differentiated LHS what about RHS

For RHS differentiation you need to use amplicit differentiation method

[stray elk]

Yes how you find it ?@left knoll

[left knoll]

Angle A + Angle B + Angle C = 180° property of triangles

[proper sail]

I think amplicit will be just the left side of product rule multiplied by derivative of lny am I right is it the only thing I was missing?

[left knoll]

Yea using amplicit method on 'ln (theta)' side

[proper sail]

Ooh OK thanks

[left knoll]

I have few similar question, if you wish to solve them I can send you the questions 😊

[wraith pilot]

Hey guys

could anyone help me with this math question please

[left knoll]

X= 3/2

@wraith pilot

[proper sail]

@left knoll sure

[wraith pilot]

how did u get there??

[left knoll]

@wraith pilot

[wraith pilot]

THANK U!!!

life saver ❤️

[left knoll]

You can cross verify by substituting any value of 'm' and solving LHS and RHS separately

[wraith pilot]

oooh okay

thanks for the help!

[left knoll]

@wraith pilot did you cross verify the answer

[mystic python]

How do you differentiate 4 + (x-5)^6. I am confused by the constant outside

It has something to do with chain rule I think

[steel plover]

can someone explain how y^n = x implies ny^n-1 y' = 1? super sleep deprived rn so I might be missing smth obvious

[steel plover]

just realised after staring at the page for a solid few minutes that this is literally just the power rule fml 👍

[inland oracle]

translation:
Determine the functions to be able to construct the shear force and bending moment diagram for the structure

[torpid tiger]

help pls

[swift quest]

@left knoll maybe can be like this, i hope it helps

[glad sierra]

https://www.youtube.com/channel/UC3tFZR3eL1bDY8CqZDOQh-w

came across this channel when studying MLEs and the guy does help in understanding the concepts better

[left knoll]

What question you're talking about?

d(4)/dx + d(x-5)*6 / dx this is how it gets differentiated

Chain rule is used when we have to differentiate functions like sin(3x)..

[mystic python]

Hmmm... okay Thanks @left knoll

[left knoll]

Or a function containing function in itself

[swift sleet]

hello

[left knoll]

i am having a lot trouble understanding any of this
i would be very grateful if guys could help me out here

[swift sleet]

Hi, I am currently taking a linear class and fell behind by a lot. Any tips on how to catch up on 30 hours missed?
or just general tips to catch up, how much studying should I be doing and practice

[ember kernel]

I would say my linear algebra class had a theory/practice ratio of about 70-30, so it is important to not rush it. Here are 2 ytchannels thatcould help

Strang's whole course (18.06 if I recall correctly) has been updated on YouTube. This lecturer is competent and makes his topic very understandable. There are 30-ish one-hour-long lectures, but you can just focus the parts you struggle the most with

3brown1blue's playlist on linear algebra helps a lot visualising what you're doing but doesn't go into the details and formulas (takes less than 2 hours to watch)

[swift sleet]

Okay perfect, thanks a lot!

ill check em out

[peak gale]

Not all the series admitt a limite, even an infinite one; you can consider: An= (-1)^n and that is easy to find that series does do converge; for your example, it is assumed theta is rational but more generally, you can prove if theta is not null, then f(n) doesn't not converge because of the periodicity of the sine

[peak gale]

I tried by assuming p as: unknown coeff× sqrt(q)/ r
By using the pieces of information, for finding out the coeff (by submitting), I found m, and then the required value

[left knoll]

thank you!!

[peak gale]

for (-1)^n, that does NOT coverge (sorry for the tipo)

[covert anchor]

Hi

Given that : a is -3
b is 6

How do I find X

[open wolf]

is there anything given other than this

[swift quest]

No problem 😁

[covert anchor]

Hi did I make any mistakes

[dense cliff]

could i have some help with this question pleeease

[proper sail]

OK I have problems with the point of inflexion the f'(x) part of the defination in the second page so when I attempted the question I am constantly getting option D which is wrong answer I checked Answer key.So please help me in this question!!!

[rustic shuttle]

170 girls
2 girls for 7 boys -> 1707/2 boys
595 boys -> 595 + 170 children
765 children
3/5 children, then 2/5 is adults
765(2/5) /(3/5)
510 adults

[rustic shuttle]

if you get x=0, f(x) would bee 100, then i think point of inflection would be (0,100)

[proper sail]

OK thanks

[deep horizon]

guys ive asked the mods if they would be able to add this bot! what do you guys think?

It'll be hard to type bigger expressions...but it does the job good in the end!

[peak eagle]

great idea, I use it on another server and it's way better than reading the written code without it being TeXed 🙂

[ember kernel]

Is it LaTeX way of encoding ? I think it wouldn't be very used, as it requires effort to learn how to write the code. Plus, the message the bot sends seems quite big, and it's easier to just write a whole development on a sheet of paper that you photograph rather than writing the whole code, which isn't very visual

But idk, it could be useful for short answers that need equations

[peak eagle]

yes it is. Well sometime I am more lazy to write it on a paper and then take my phone to take picture. Like this I can just TeX it and for some it's easier if they are already working with it. Also maybe easier to read than some handwriting or bad taken pictures 🙈

[deep horizon]

yes! i hope they respond. i texted in the help ticket thing. will work right?

[humble bobcat]

There are 3 possible values for x, you would have to find a & b in order to get x. Or else you will end up getting the answer in terms of a or b

[steel plover]

can someone help me out with this one?

[steel plover]

thanks for answering!

just to be clear, does this answer match that?

(the answer sheet was given, I was just confused as to how it was done)

[left knoll]

using the division rule for differentiation ans is matching.
will check the another process again

[lofty arch]

wolfram gives this

[steel plover]

ohh I see, really appreciate the help mate

[heavy zenith]

+1 for Ben Lambert. His econometrics series is fantastic

[edgy hinge]

Hey guys can you help me please

[tawdry dagger]

please help 🙂

[tardy moth]

Consider two cases for x. Case 1: x=(2n+1) Case 2: x=2n

where n is any natural number

[tawdry dagger]

😮

[tawdry dagger]

thanks !!

find the truth and justify why

[glad sierra]

Granted some basics will help but if you get his flow it’s amazing 😩

[formal stag]

can anyone help me out with this

[mental snow]

the value of 1st statement for given conditions is True and the second statement is False

[tawdry dagger]

thanks man ! @mental snow

[mental snow]

😄 cheers mate!

[mental snow]

the equation of curve i am getting is

e^2x + 3/2 x^2 + 8x - 6

[formal stag]

oh really? can you tell me where i went wrong with my working

[tidal galleon]

I think this is correct

[formal stag]

thank you

[mental snow]

oh m sorry i took dy/dx as 5

my bad

[mental snow]

yeah its perfect

[mental snow]

3x^2
10x
-3 x^-4
cosx - sinx
0

[deep horizon]

We are probably getting the TeXit bot!

should help the channel!

[tawdry dagger]

thanks man

[left knoll]

what class?

[proper sail]

@left knoll that was a middle calculation in this question please help me with this question!!

[left knoll]

Are you trying to make partial fractions?

[proper sail]

I guess

[left knoll]

What class is it exactly

Calc 1? Calc 2? 3?

[proper sail]

Wait let me check

Unit 6 in calculus AB

[left knoll]

It's currently 5:00 AM and I haven't slept yet so I'm really tired lol. I don't have paper with me... But umm

So calc 1

hold on

okay so

just by looking at it

id say it's either A or B

Leaning on the side of A

But don't quote me

i just had to do some serious mental math lol

[proper sail]

Please explain me too how did you find it in your mind

I think you must have slept

[ember kernel]

@tawdry dagger nononono last one is 0 because sin(pi) = -1 is a constant !

[worn mist]

Ill be looking for some info on a latex bot today so no need to open any tickets on it!😌

[tawdry dagger]

😮

[stuck pewter]

Hiii i wanted to ask if you guys have any tips for proofs and theorems because those really drive me crazy I can't like proof smt without looking at the solution once if u get what I mean so please share some tips if you have, it will really help me a lot
Thank you:)

[tardy moth]

Looking at the solutions is not a bad thing when you're just starting to learn proofs. Developing mathematical maturity takes time and you just need to have enough exposure. Kenneth Ross- Elementary Analysis is a really good book for understanding the logic behind proofs.

[balmy sand]

Heyy, can someone help me with additional mathematic ??

This is the question :/

[rustic shuttle]

Is it 20,57?

[balmy sand]

there is no answer scheme..

[mental snow]

oh sorry that looked like x when i saw it

my bad

[tardy moth]

Hint: 3^(x-2)=(3^x)(3^-2)

try to separate like this

[balmy sand]

wow tqvm!

[stuck pewter]

Ok thank you but like if a new proof that I've never solved before comes up in the test my mind just goes blank like I can't seem to get myself to solve it it just is too complicated so I wanted to know how you train yourself to think about the proofs

[solid anvil]

can someone help me

[covert anchor]

how th do i find x

like do i square the whole expression

[rustic shuttle]

it's not even an equation lol xD

[covert anchor]

ok how do i find x

the whole thing is = 0

[rustic shuttle]

oh now i get it

[covert anchor]

sorry this is it

[ember kernel]

Maybe you could use z = sqrt(x), to solve 9z³ - 30z² - 23z - 4 = 0

Then, you just solve and find all values for z, and from there you get the x values via x = z²

@covert anchor

Note that x >= 0

[covert anchor]

i will get 4 as my ans

which is wrong

the ans shld be 16

[ember kernel]

well x = z²

[rustic shuttle]

yeah...

[covert anchor]

How do I do ii

[left knoll]

Is 2x *4 - 8x *3- 12x *2+ 22x- 4 the answer of first sub questions

@covert anchor

[worn mist]

$sin(x)$

the latex bot doesn't seem to work for some reason

=tex n^2

[worn mist]

oh

[ember kernel]

Yep, works perfectly. Thanks a lot !

[worn mist]

it's not as easy as the texit bot but for some reason that one doesn't seem to work here

I made a little info channel for the bot to make it easier #how-to-use-math-bot

[worn mist]

example^

Should be a little easier if you already know how to use LaTeX but it's not hard to get the concept if you google it a bit

[ember kernel]

Maybe you could mention it also works with multiple lines, using \\ as line-breaker

*in #how-to-use-math-bot

[worn mist]

gotcha!

gonna add it rn

[ember kernel]

Thanks a lot 😁

[worn mist]

how did u do the \ \ cuz discord tripping 😦

[ember kernel]

If you want to actually display, type 3 's
For MathBot use, only 2 's does the job (only one will be displayed, but that doesn't matter as our message will be deleted)

[worn mist]

true

but in the how to it doesn't delete 👀

[ember kernel]

Since the bot can't delete your message, write it as \ (one is deleted), wait for the bot to send its message, then modify to \\ for the permanent example

[worn mist]

yup that is smart

haha

[ember kernel]

Because you're an admin, the bot's rights are weaker than yours

[worn mist]

nono i made it that way

so the channel actually shows how to code it for people who don't know how how to type it

[ember kernel]

It doesn't seem to like you :p

[worn mist]

the bot doesn't do anything anymore rip

ye haha