math-help

[open mango]

OFC

oh shoot

that looks way more complicated

[hollow escarp]

6(x^4+5) x 4x^3 = (6x^4+30) * 4x^3

= 24x^7 + 120x^3

[eager falcon]

well that's how i would do it

[open mango]

ah

[left knoll]

Thanks! do you know the reasoning for why that's the answer tho?

i went the long way around for it

I found out how many possibilities were in the 9000s and multiplied that times 10

Which im pretty sure there's an easier way

Usually I cna do these but this one has me stumped

[hollow escarp]

if it's odd , the final digit should be 1,3,5,7 or 9

[left knoll]

right

[hollow escarp]

so the 4th digit can only be chosen from these 5 digits.

[left knoll]

So we would have smth like : __* _ * _ * 5

right???

And like 0 can't go in the first slot so is the first slot 9 ?

[hollow escarp]

actually no number can be repeated either

so , when three digits are fixed , and we are doing the first digit , we cant use the two digits used before and zero

there must be plenty of solution videos . let me find one for you real quick

[vast vapor]

Hallo

Can me i help me

[left knoll]

What's up?

[hollow escarp]

I'll explain on DM ?

[left knoll]

Sure!

[left knoll]

do you need help?

[scenic garnet]

Can you guys tell me some differences between series and power series? I cant think in a phrase to explain it easily

[latent siren]

There is a very specific form for a power series. It's always of the form

A series, in general, is just that, a finite or infinite summation of numbers.

Note that a power series also has a variable in it, you can think of it as a function (provided that you know the radius of convergence)

@scenic garnet

[scenic garnet]

thx @latent siren 😄

[chilly lava]

heyo can someone tell me how to calculate antilog?

[dusk skiff]

The antilog of any number is just the base raised to that number. So antilog10(3.5) = 10^(3.5) = 3,162.3. This applies to any base; for example, antilog7(3) = 7^3 = 343. Hope it help 😄

[primal sedge]

can someone help me with this question please? any help would be greatly appreciated ^^

[halcyon summit]

=sinx/cosx =y/x = -3/-5 = 0.6

[chilly lava]

Thanks

[glad grove]

does anyone know how to calculate this integral using complex integration? i dont need the full answer just someone to tell me where is my mistake. pm pls

[random flame]

Hi can someone help me with part b? Ping if you do and thanks in advance!

[inland oracle]

How can I solve for T in this equation?
It is the Rutherford model, regarding radioactive decay.

[covert anchor]

Anyone knows how to solve ?

[peak jay]

^indices

[peak jay]

base on your histogram, anything below 24 shld be fine

[random flame]

Ah alright thank you!!

[digital moth]

Does anyone know how to do conditional probability

There is a quiz show that is composed of three rounds. A contestant solves Question 1 first and if she gets the right answer, then she will move on to next round to answer Question 2, and if she also answers correctly, then she will go to final round to answer Question 3. If she fails to answer correctly, then she is not allowed to go on to the next round. The probability that she knows the answer to Question 1 is 0.9, to Question 2 is 0.8 and to Question 3 is 0.7.

1. What is the probability that she will win this quiz show?
   2.Given that she did not win this quiz show, what is the conditional probability that she failed to answer

[lucid quartz]

Could someone help with this? It says: “Find x in terms of O (theta angle) and r (radius)”

I would really appreciate 🥺

[tawdry hazel]

i hope this helps ;)

[lucid quartz]

Thank you so much @tawdry hazel

This is the last one 🙏🏻

[left knoll]

I think i was wrong

[tawdry hazel]

you need L in terms of theta and r?

[tawdry hazel]

wrong with what?

[left knoll]

I mean, i did the same
But i think i was wrong
(Sorry, i'm learning english)

[tawdry hazel]

oh i see ;) no no need to apologize

[left knoll]

I thought*

[lucid quartz]

I feel I can do this one for myself (I’m learning English)

[left knoll]

xd

[lucid quartz]

Thanks 😊

[tawdry hazel]

oh ok ;)

[tawdry hazel]

no worries

[peak jay]

Find x in terms of what?

[royal marsh]

anyone able to solve this? i get stuck at weird values like -lnx+2ln2=1 and i highly doubt that's the answer

[granite crow]

@royal marsh you're on the right track! You just need to keep going to solve for x

I haven't fully solved it, try to keep going from there :)

[royal marsh]

:o ty so much

[mild idol]

Can anyone help me solve this

[granite crow]

@mild idol

I've started you off, but I'll let you work out the recurrence relationship of the coefficients. Let me kmow if you have any issues :)

[mild idol]

thank you so much I'll try solving the rest
if its not an issue may i ask another problem as well?

[granite crow]

Of course

[mild idol]

how do i integrate this?

[covert anchor]

Anyone can help with this what should I start with

[granite crow]

@mild idol

[mild idol]

oh my I understand now
Thank you so much💙

[granite crow]

No problem <3

@covert anchor

For part i) you just need to visualise what it would look like from the side. Then it should be clear what to do

[covert anchor]

What did u use with i

[granite crow]

Basic trigonometry. Remember that tan(Θ) = opp/adjacent. BT is opposite and BA is adjacent. Θ = 24

BA = 80

So tan(24) = BT/80

[covert anchor]

Ok trigo ratio basics rhen

[granite crow]

Exactly

[covert anchor]

can you please guide me with part iii

idru

[mystic python]

what are the differences between trig functions and identities

I need to make formula sheets on these but I forgot what the differences were

[granite crow]

The trig functions are just sin, cos, tan, cot, sec, etc. No need to write those down.
The identities are what you want to write down in your formula sheet @mystic python

[mystic python]

Kk Thanks @granite crow

[left knoll]

could someone help me, please

q9

[granite crow]

@left knoll

The wording is a bit tricky

I've started you off, try to solve for p% :)

[left knoll]

aah tysm omg

[potent flint]

Hello

Does anybody here have some background on Convex Optimization?

If you do have some background, please ping me here. I just have a few questions.

[modest ice]

Ok can someone tell me what would be the derivative of 8z^3/dz

[umbral spear]

Would this book be appropriate for a rising 8th grader to learn Geometry (i have it in my room)

[modest ice]

I assume so...

[random flame]

Hi can someone help me with Q6a? Ping if you do and thanks in advance!!

[chrome cypress]

ln - lnx + 1 = lne^2 - ln4

ln + ln4 -lnx + 1 = 2

lnx = ln + ln4 -1 i think

x = 1.47

because lne^2 = loge(e)^2 = 2(loge(e)) = 2(1) = 2

in exact form x = 4/e

[royal marsh]

dont have my notes, but i ended it with x=4e^(-1) i think

[chrome cypress]

yes

thats the same as 4/e so its right

[royal marsh]

aight. tyty :)))

[chrome cypress]

pretty sure they just want u to square the entire original function

[random flame]

I kinda did, but I got the answer wrong

Not sure where I went wrong

[chrome cypress]

what was the answer

u didnt square it im pretty sure lol

@random flame

[random flame]

Hold on

[chrome cypress]

oki

[random flame]

Just look at Q6a

[chrome cypress]

u did it right

ur answer can just simplify to that

16x/2x+4 = 8x/x+2

@random flame

[random flame]

Ohh

Okie thanks!!

[chrome cypress]

AC is just Pythagoras' theorem, the rest is just trig and angle rules

[teal bay]

please help me find positive integer solutions of the equation x^2y+2xy+y = 32x

[teal bay]

ok thanks

[potent pewter]

No that’s not the answer

I was tryna ask a question for my thing

I meant I got one for my question and I was asking if that was correct

[bitter rune]

No

[rocky adder]

well

you can rearrange the equation

such that it gives you

(x² + 1)/x

• 2

= 32/y

[potent pewter]

How do you do this?

[rocky adder]

nvm, I tried to do something but it doesn't work out necessarily kkkkkk

[potent pewter]

I forgot 😦

[rocky adder]

oh, volume of cylinder

take the circle area and times the height

[silk quiver]

pir^2 h

[rocky adder]

so

pi*r² * h

[rocky adder]

yeah, exactly

[potent pewter]

Ok thanks a lot ❤️😭

[hidden forge]

a good way to remember how to get the slope is "rise over run", meaning how high (y) you go, divided by how wide (x) you go. The points are (2, 5) and (8, -4), so here's how you do this: pick one point (let's say you like (8, -4) better for whatever reason), so you do this: (-4 - 5) / (8 - 2); you get -9/6 = -3/2 as a slope. Just make sure the first "y" you take is from the same point you take the first "x" (so i took -4 from the same point I took 8; an alternative is you start with 5 in the numerator, then you'd have to start with x in the denominator).

[potent pewter]

Ok thanks a lot

[rocky adder]

you can rearrange the equation by factoring y to get

x² + 2x + 1 = 32x/y

then you get some hints of possibility

because the left side must be an integer

such that the right hand side must aswell

[hidden forge]

I know you already got the answer, but I think this will still be useful: think of volume as area moved along some axis. The volume of a cylinder is the area of any of the circles that make it, but moved along the "height". How many "circles" can you have along the height?
If this is confusing (because of how I phrased it), just ignore what I said. I was just trying to give some intuition behind the formula; it's how most things stay in my head 🙂

[sudden quiver]

hello sir

i have a small doubt

[potent pewter]

I got 388 after I rounded to a whole number

[sudden quiver]

pls help me solving this

[rocky adder]

alright

calm down sir

[sudden quiver]

:>

[rocky adder]

gosh, this takes some weird math as far as I remember

[sudden quiver]

:<

[rocky adder]

yeah, for each integral

you need to separate into two integral each

[potent pewter]

I got 388 is that correct?

[rocky adder]

idk, if you used the formula it MUST be correct then

let me see there

[potent pewter]

Ok 👍

[hidden forge]

I think a faster way would be to try to unify the denominators

or find some "common form" for them

[rocky adder]

idk, but pi(6.5ft)² * 19ft
gives me

2520,635 ft³

[hidden forge]

think of how you can make e^-4x turn into e^4x and it ends up being a very simple problem

[potent pewter]

Oh I didn’t square it

[rocky adder]

yeah xD

[potent pewter]

🤣

[hidden forge]

a hint (after looking at the solutions, you'll still have to do some work after this): multiply J by e^4x, and the denominators will become the same; then the subtraction they want you to do becomes naive. The remainder is to just figure out what your result would look like in terms of the answers (this is pretty straightforward)

[potent pewter]

Pls help

[rocky adder]

just like messiah said

earlier

slope is defined as the "rise" over "width'

or within an interval:

deltaY/deltaX

= (y2 - y1)/(x2 - x1)

or just the derivative of the function

[potent pewter]

Ok so the slope is what?

[rocky adder]

it's the tangent of the line

@potent pewter

[potent pewter]

Oh ok 🧐

So the slope is -1/3?

[rocky adder]

show me your calculations

or logic

[potent pewter]

Wait nvm

I need my note book

[rocky adder]

because it's not btw 😅

[potent pewter]

Ya ik

I figured it out

I had to watch a video

😊👍

[bitter rune]

Please help me solve this system of equations , thank you so much !!!

[chrome cypress]

is this simultaneous equations? if not whats the question

oh wait "voi" prolly means find or something so prolly is then lol

[bitter rune]

Don't attention to it

[potent pewter]

Someone pls help

😭

[left knoll]

Z angle

[potent pewter]

OMG your the best tysm ❤️❤️

[left knoll]

You’re welcome🌟

[mystic python]

X-3 / x+2 is larger than or equal to 0

Why can’t x = -1

Nah allg I figured out

[jagged urchin]

Can someone help me with this ive been working on it for some time but im really stuck.

[pure garden]

The reason is that angles in a straight line adds up to 180

and alternate angles are the same

or you could say co interior angles adds up to 180

[modest compass]

Idk if it's correct but yeah, lmk if any numbers are unclear

[twin knoll]

On the right side it's not -1, it's 1; (13-12=1) which means that b=302/256

[modest compass]

Ah shit yeah, typo, but would the rest be correct? The general method i mean

[steel plover]

is anyone here familliar with truth tables? Not sure why that question is incorrect

[desert sluice]

I have used truth tables in semiconductors

Not sure if that same for mathematics

[steel plover]

could you help me out with that question?

[desert sluice]

Plugging in the initial values of particles and no. Of undecayed particles at time t [N(t)] and knowing the decay constant you can find the value of time

[steel plover]

nvm! I worked out the mistake

[desert sluice]

Oh really that’s great

[desert sluice]

Was that prb from mathematical reasoning

[steel plover]

introduction to mathematical thinking, it's a coursera course

[inland oracle]

thaaanks !! 😦 so much

[raw mica]

any idea, i know it has to do with harmonic oscillator system

[gritty ether]

Someone pls help

[jagged urchin]

can someone help me with this ?

[hollow spear]

Need help with questions 4

[left knoll]

Even I wanna know the answer pls ping me

[royal marsh]

I'm having a problem with probability. Heres a rough translation of the problem: "If you jog one day, there is a 60% chance you will jog the next day. If you don't jog one day, there's a 30% chance that you jog the next day.
If you jog one day, what is the probability that you jog the day after tomorrow?"

i would assume it's P(jogging given that you jogged the day before) * P(jogging given that you didn't jog the day before) but none of the formulas i have seem to fit this way of solving it.

[granite crow]

@royal marsh

[royal marsh]

ooo so i actually did the math right. ty very much

[granite crow]

Np :)

[covert anchor]

can someone help me with b ?

[granite crow]

I'm having a hard time reading, could you resend?

[mental dragon]

7^(2x+3-x^2) = 1
x^2-2x-3 = 0
(x-3)(x+1) = 0
x = 3 or -1

[granite crow]

I've started you off, try to solve the quadratic :)

[covert anchor]

easy

did not think bout that

my big prob is that idk how to apply rules etc

[minor rapids]

can i get help

[granite crow]

Yeah there's a bit of a learning curve when you're starting, but it starts to come quickly after you practice many questions

@minor rapids

Look at the sin graph between 0 and 2Pi

For what angle does the graph reach 1?

There's only 1 point in that domain

[upper sable]

pi/2

[jagged urchin]

@granite crow can you dm me rq

[granite crow]

Sure thing, I sent a fr

[covert anchor]

b how do i draw d graph ?

[granite crow]

@covert anchor

It's going to have this general shape

Find the y-intercept by making ×=0 in your calculator

What do you get?

[covert anchor]

hold on

4 ?

[granite crow]

yep

[covert anchor]

how did u know the shape ?

[granite crow]

You know it's an exponential function because it follows the general formula y = k(a)^x

[covert anchor]

ok

[granite crow]

An typical exponential function looks like that, but other factors will shift it around

[covert anchor]

oki !! thks

this i dont get

i learnt it but was absent

would be nice for explanation

[gritty ether]

Sr about my handwriting😅.I will resend right now

[rugged imp]

Is this fine?

[covert anchor]

an1 can help with ii ??

[rugged imp]

This is a rough sketch

I can give the general shape only

[covert anchor]

np thats the point of the qs hahah

btw how di u get 1,0

[gritty ether]

Thank you so much :00

[rugged imp]

your'e welcome

[rugged imp]

at x=1, lox(base 3) will give 0

*logx(base 3)

[covert anchor]

how did u get 4 qand 8 too

[rugged imp]

ok

So x has to be greater than 9 as it's an increasing function

[rugged imp]

is it fine now?

[covert anchor]

yes thku so much

[autumn robin]

anyone can help with linear equations?

[left knoll]

Yes

Nice username can relate

[chrome cypress]

dont ask to ask just ask init

[left knoll]

Unga bunga

can someone explain me lines and angles i am in 9th grade

[elder socket]

hello guys i ama sorry i know that 9th grade math but if you arenot lazy can you help me?

you have to find area

[weak mortar]

so what i would try to do is connected the intersection points of the two circles with the centers of the circles that way you get a kite using some by then multiplying the length of both diagonals and dividing by two you get the area of the kite. You the calculate the area of the partial disk between the two intersections of both circles. For this you would need the angles between the lines connecting the intersections and the center of a circle buy using the cosine/sine rule you can calculate this. The idea is to then sum both these areas and substract the area of the kite from this sum. When summing the two partial disks we get the area of the kite + the shaded area so our final result will give the desired answer

i hope this help a little

[covert anchor]

hi

anyone can help me with iii ?

[rose otter]

Hi, don´t remember if it is actually like that but you have solved previously 2log3 x= 4 ; log3x=2 ; x=3^2=9. So now for the inequality the solution is an interval where x>9 . x (9,00)

00 as infinite

[weak mortar]

yes thats correct since log3(x) is an increasing function

[covert anchor]

oki thks

anyway to do this

[supple island]

hint: sqrt(27)=3^(3/2)

[rose otter]

First try to "rewrite" second equation, and isolate x there

[weak mortar]

and for the first one 8=2^3 and 4=2^2

[covert anchor]

???

guys i still dont understand

[supple island]

3^x/sqrt(27)=3^x/3^3/2

which is 3^(x-3/2)

[granite crow]

@covert anchor

[covert anchor]

thks

[earnest vortex]

can smb help me please?🥺

[oblique flint]

can I study calculus 1 in 19 days yes or no

[sudden scarab]

yes

[earnest vortex]

https://tenor.com/view/yes-jotaro-kujo-jojos-gif-7297252

[stray tiger]

Have you heard of symbolab?

[stray tiger]

Yes!

[earnest vortex]

yea, but...

thats the same task, but in initial form

[stray tiger]

Argh, disappointing. Let me work it out on paper and see if I can get anything

[earnest vortex]

I'll be very thankful!

[stray tiger]

Apologies, I couldn't figure it out.

[earnest vortex]

ok, thanks for trying 😦

[coral mica]

https://cdn.discordapp.com/attachments/716519713294909460/850372966118457366/Screenshot_514.png

Doubt

[vague wave]

https://gyazo.com/776afdec00557a66d1d501d3e7fb98c6 could anyone help me with those integrals?

Im studying for a exam and I cant crack them...

[polar wolf]

As a phase line, use a U-shaped curve. Let its downward-sloping segment intersect the 45 degree line at point L, and let its upward-sloping segment intersect the 45° line at point R. Answer the following five questions:
(a) Is this a case of multiple equilibria?
(b) If the initial value y0 lies to the left of L, what kind of time path will be obtained?
(c) What if the initial value lies between Land R?
(d) What if the initial value lies to the right of R?
(e) What can you conclude about the dynamic stability of equilibrium at L and at R, respectively?

can someone help me with this please

[polar heron]

we have to find the allowed range of x?

[earnest vortex]

yeah, I already did it, thx

[tawdry hazel]

I think the answer for Q18 is wrong. I also checked it online.

[vague wave]

Oh thank you. I was getting the correct result but was wondering why I should get 3/4 there

[tawdry hazel]

;)

[candid rivet]

How can you prove that e^(x-1) >= x where x can be any real number ?

[bright island]

you need to find the derivative of e^(x-1) - x and understand that for x < 1 the difference of functions decreases, for x > 1 the difference of functions increases, and for x = 1 e^0 - 1 = 0, it means that for any real x e^(x-1) >= x.

[candid rivet]

Oh yeah thank you very much, that makes sense

[bright island]

👍

[elder socket]

i am looking for a book to improve my math skills .i am in second year of high school can anyone recommend me easy to read books ?

[teal karma]

I am confused on what formal to use

[modest compass]

Formal?

[teal karma]

For a

[modest compass]

I would've used a graph lolz

I got the answers for all except e hold on

[modest compass]

Idk if they're right but I'd think of it as a linear graph

[snow remnant]

heyy guys,, does anyone think they can help w any of these questions?:) i have question 1 finished so far

[potent pewter]

I got 5 4/11 and 5 is the mixed number i'm certain thats it's correct someone please let me know. 😄

[surreal hound]

do you have a specific question?

[snow remnant]

omg thanks for answering! question 2 is probably the hardest looking at it, i just dont know how to explain whats going on😩

[surreal hound]

have you tried simplifying the SEC or taking the inverse of the whole expression ?

I would start there

and then draw a unit circle and mark the possible angles on it just to get a feel for the situation

[snow remnant]

ohh okk,, thank you so much ill try this & let you know how it goes thank you! ☺️

[snow remnant]

@surreal hound is it only able to have two angles? in 2a

and then if it wasnt limited by the 0° and 360° it could have more? idk

[modest compass]

Yeah, only 2 angles within the range, but the graph goes on forever so there are more values

[surreal hound]

correct, you can see that here https://www.wolframalpha.com/input/?i=sec(x)%3D-5%2F3+solve

n represents how many times around the unit circle

so in this problem n = 1

if you had to solve for 0 < x < 720

then you need n=1 and n=2

[snow remnant]

ohhhhhh thank youuuuu that makes sense thank you💘💘

[snow remnant]

that actually makes it a lot easier to understand , thank you so much!

[austere imp]

Can someone explain this to me in further detail?

[weary arrow]

The h(x) is representing a constant

[austere imp]

Oh i get it now thank you

[random flame]

Hi can someone help me with this? Ping if you do and thanks in advance!!

[modest compass]

First you need to find the value for sin^-1(-0.5)

The you can imagine the line for y=-0.5. The two points here these 2 graphs intersect within the range 0 <= x <= 360 are the solutions

[random flame]

I went to check the marking scheme but I'm not sure why they did 360-30

[modest compass]

That's to give you the other solution

[random flame]

Ohh

[modest compass]

I presume sin^-1(-0.5) = 30 in that case then

[random flame]

Yea I got it, thank you!!

[modest compass]

No probs

[slow valley]

cuz sin value is negative only in the range 180 to 360, and we know sin 30 value is 0.5. they've given one value sin(180 + 30) and the next one has to be sin(360 - 30)... sin(270 + 30) and sin(270 - 30) will change it to cos 30 and not sin, so in that case you also do it like sin(270 - 60) and sin(270+60) which gives you - cos60 which is also -0.5 🙂

[supple igloo]

Hi, can someone help me with this question please and thanks I’m so lost

[celest quarry]

yea hold on ill try

[celest quarry]

here u go! steps definitely don’t have to be as detailed but i did it for the ease of explanation and understanding, final answer is in the boxes

[supple igloo]

🤩wow thank you so much

[left knoll]

Hi guys!can someone help me with this?

[silk quiver]

is the answer 0.67?

[left knoll]

Yes it is but i didn’t know how to do that

[ivory pumice]

That quadrilateral will help

Let that point be E ( on DC) , then angle AED would be alpha

So cot Alpha= 6/9

[left knoll]

Thank you so much🙏🏻🙏🏻

[covert anchor]

can someone guide for first qs only ?

im kinda lost on what to do

[supple island]

you basically need to see what y is if x is something, like for y=7^x, if x=0, what's y? you do this for some numbers (positive and negative possibly) and the ou draw a line that connects them, also you need to ask yourself:"what happens when x tends to infinity and -infinity?"

[covert anchor]

wait so i just need to draw the line ?

[supple island]

yeh, that's a graph of a function is

[covert anchor]

Is this sufficient information ?

[bright island]

if m is even, then m = 2 * k, k - some int number, and you know, that m + n = 2 * s, 2k + n = 2s, n = 2(s-k), n is even

[covert anchor]

or must i have intercepts

[bright island]

n cant be odd

[mental snow]

yep sum of two integers can only be even when either both of them are even or both of them are odd

[sage cobalt]

Can anyone help me with this

Question 5b

[mental snow]

is the answer

1

for 5b.

[sage cobalt]

Yeah bit I don't know how to get to that conclusion

But*

[mental snow]

yeah okay so

change the base of the logarithm to xyz

by using the change of base rule you can bring them up

[sage cobalt]

Nani

[mental snow]

Hold up

[upper moth]

help pls i need to construct a two column proof given this statement

[mental snow]

Hey can you tell me what exactly do we need to do

How do we prove by CONTRAPOSITIVE
Are we required to make a truth table with all the values

Ohh so If I prove if the reverse of the above given condition happens then xy ≥ 0

[upper moth]

no i just have to assume that the negation of the conclusion is true in order to show that the negation of the premise is true as seen here

[mental snow]

Oh ok

[sage cobalt]

@mental snow thanks dude, I understand now

[mental snow]

OkieDokie :D

[mental snow]

Right...well if We look at the Cartesian plane we can prove this so Intuitively
But we can simply assume that both the variables have same nature i.e.(being ≥ 0 at the same time or being ≤0 at the same time) then their product will always be positive (≥0)

[supple island]

it's ok, i'd point out that for x=0 y=1 and that at -inifinity it tends to 0

[covert anchor]

ok tgks

wait

basically any number

[covert anchor]

etc y=4.5^0 will be this too ?

[supple island]

every number to the power of 0 is =1

except 0

[covert anchor]

ok so basically all the intercepts of y=a>0^x is the same

[mental wraith]

@supple island 0^0 is also 1

[supple island]

theorically it's undefined, but 1 is a possible answer

[mental wraith]

ya in analysis they consider it undefined but it doesn't look like anyone here is taking analysis

[supple island]

well they're doing the basic calculus

[covert anchor]

so if y=e^x it is the smae thing

taking x=0

[chrome cypress]

yeah cos anything to the power 0 is 1

so y intercept is always 1

[supple island]

e is a number, just a very useful one

[chrome cypress]

unless its y = ab^x where a > 1

then intercept is just a

[mental snow]

Yes,
0^0 is an indeterminate form and can be solved by L'Hospital or any other method by which a finite limit could be Calculated (a finite value is not always the case)

[surreal hound]

i believe you can only use L'Hospital if you have 0/0 or inf/inf

[mental snow]

yes true in several cases which i saw somewhere it was convertible to 0/0 or inf/inf indeterminant forms

[surreal hound]

ahh yes, then that is correct.

[mental snow]

lim x tends to 1 (x-1)^(x-1) is what i saw

so we can just take logarithm of the limit and then solve like L'hospital

[surreal hound]

correct

https://www.wolframalpha.com/input/?i=lim+x+tends+to+1++(x-1)^(x-1)

[dense cliff]

can i hav sum help plz

idk how to do this

[bright island]

OP is parallel to QT, it means that angle QTO = angle TOP = 58, PT is tangent to the circle, so angle OTP = 90, angle OPT = 180 - angle OTP - angle TOP = 180 - 90 - 58 = 32

[mild idol]

hiya, does anyone know some good help books to practice word problems for differential equations?

[atomic cipher]

can anyone help me understand how: convergence in probability/distribution, WLLN and CLT are related?

[dense cliff]

THANK U :))))

[bright island]

👍

[hushed bane]

Advanced Engineering Math by Erwin Kreyszig is a good book

[dense cliff]

It's a translation
Scale factor of 3
But I do not know the center of rotation. can i hav some help plz

[modest compass]

Draw lines connecting each of the corners of P and Q and that should give you the centre i think

[dense cliff]

thankk

[modest compass]

No probs

[tough helm]

I think that’s an enlargement ...not a translation

[mild idol]

thank you!

[supple igloo]

🙋‍♀️ hii, can someone let me know if I did this right and got the right answer? Thankss

[dense cliff]

oh yeah oops thank u

[hushed bane]

Well I think $\vec{AE}$ = (-3,4,5) and not (0,4,5) but apart from that it looks alright

[glad sierra]

@scenic remnant shouldn't it be -1/5 instead of 1/5 in the solution?

[scenic remnant]

@glad sierra hold up, trying it

[marsh kettle]

No because you multiply the (-1/5) by -1

Making it 1/5

[left knoll]

you are 18-25yo but in high school?

[supple igloo]

Ohh I see now thanks

[glad sierra]

where'd the -1 come from @marsh kettle ?

oh wait nvm

blonde moment smfh

[marsh kettle]

Ye its just the exponent

[scenic remnant]

the given answer is correct

[glad sierra]

oh it is
i was just wondering why my brain says it's not xD

the books more or less error proof lmao

[marsh kettle]

If u got any more questions Feel free to @ me I’m pretty good at calc

[left knoll]

i will

[glad sierra]

thanks man
im touching calc after years i've forgotten the basics ;_;

[scenic remnant]

yes i am 18, due to covid our final exams got cancelled and everything is delayed, but i'll be in college soon.

[left knoll]

ohhh

cool cool

[glad sierra]

thanks totoro @scenic remnant ❤️

[marsh kettle]

Haha just took calc bc exam so all info fresh for me

[scenic remnant]

i got so much into integration past few days for a sec i really forgot differentiation XD

[glad sierra]

bro i find it embarrassing to say an actuary is find calc basics tricky ;_;

[left knoll]

im just started with diffrentiation

[scenic remnant]

oh what grade are you in? :0

[glad sierra]

they throw this shit after some mountain of knowledge you legit forget calc lmao

[left knoll]

i just entered 11th

[scenic remnant]

yea you learn the basics of integration and differentiation in 11th :0

[left knoll]

dy/dx amd stuff which is hard for me for now

[scenic remnant]

its confusing in the beginning, tbh its embarrassing but i really couldn't do integration a few months ago XD

[left knoll]

integration sounds hard

some big azz brackets

[scenic remnant]

i ignored math cuz there was so much to do in chem :' D it happens yea

[left knoll]

and diffrent signs

[scenic remnant]

just try to do your best and get your concepts strong in 11th, it really helps in 12th :))

[left knoll]

which country

[glad sierra]

ye and im like 25 now dude
feels like years ago xD

[left knoll]

yeah

[left knoll]

what are you doing like which job'

[scenic remnant]

||india|| 👀

[glad sierra]

analyst in the actuarial profession

[left knoll]

cool co cool cool

[left knoll]

sounds legit

[scenic remnant]

is it fun :0

[left knoll]

and hard

[glad sierra]

i make it fun in a way lol but pandemic hasn't helped

[left knoll]

lockdown helped me a lot

[glad sierra]

i do my best to make work fun
i get stuff done and ensure i involve people soooo yeah it's not bad
the money helps :p

[left knoll]

how much

earnings?

[glad sierra]

never ask people that question 😉

[left knoll]

oops

sorry

[scenic remnant]

that's nice, i wanna get a job asap too XD (not even in college yet but imma try to do internships from 3rd year)

[glad sierra]

na it's fine
just letting you know lol

[scenic remnant]

i agree, its kind of rude somehow

not rude but just no

[left knoll]

ill be doing internships next year

[glad sierra]

but ill tell you this much
it's enough to have a happy life 🙂

[left knoll]

im 15 btw

[scenic remnant]

woah that's nice!!

what internships btw??

[left knoll]

just struggling financially

[glad sierra]

choose what piques your interest and you'll be well

[left knoll]

a lot of job streams

[scenic remnant]

at the end of the day, happiness matters the most :))

[glad sierra]

just don't target a shit job that pays well as opposed to a decent pay with lovely people

[left knoll]

android dev or web dev

final job as a data scientist

[scenic remnant]

yea i'll try man, but its hard ig...to do something different..heh

[left knoll]

few more fun jobs as a vfx artist or game developer

[glad sierra]

my goal is to do something different
i'm not going to settle with just office and family

[left knoll]

same

[scenic remnant]

not hard as in yea every field requires hard work i mean, its hard to ignore people and what they say when you do something different.

[left knoll]

i wanna do something in sports as well

[scenic remnant]

same bro, i don't want to live the usual boring life :((

[left knoll]

like a martial arts teacher

coz im reety good at it

i started at 9

gtg bye

[glad sierra]

youll want to do a 100 things
if you're struggling financially get something you can do decent and be of value to the company
then do something a few yeras in

[glad sierra]

life is boring if you live by the rules of boring people 😉

[scenic remnant]

that's very true :))

but yk sometimes people expect certain things from you and it hurts to let em down heh, but that's a risk every successful person had to take once in their lives :))

[glad sierra]

there's a billion people
can't let a few people ruin it xD

if those people love you they'll understand eventually as long as you're not being mean or toxic 🙂

[scenic remnant]

true :))

welp goodluck to you mate, cyaaa : D lemme know if you have other doubts (it'll honestly help me brush up my concepts too XD)

[left knoll]

anyone helping me

@marsh kettle

[cunning echo]

lemme try

i got 5 @left knoll

[left knoll]

okk

how

[cunning echo]

idk how to explain

[cunning echo]

:0

[left knoll]

this one is killing me

??

[cunning echo]

is cosec cosini?

or it's different

also the "tan(1200)^0" is it suppose to be that or "tan(1200^0)"

[left knoll]

tan(1200^0)"

rasied to

[cunning echo]

i got -squareroot(3)/2

base on my casio calc

idk if im wrong or not

i hope someone else could check tô

[left knoll]

is it 3/2

[cunning echo]

no i got it differently

[left knoll]

okkk

this one

[cunning echo]

i cant do everthing for u man

sorry

im quite busy now

good luck pak

[left knoll]

ok

[bright island]

sqrt(2ssqrt(2sqrt(2..))) = A, sqrt(2 * A) = A. A^2 = 2A, A = 2 or A = 0, it is obvious that A> 0, so A = 2. sqrt(2 + sqrt(2+sqrt(2+..))) = B, sqrt(2 + B) = B, B^2 = 2 + B, B^2 - B - 2, B = 2 or B = -1, again B > 0, B = 2, A - B = 2 - 2 = 0

[cunning echo]

👀

astonishing

[bright island]

easy problem))

but you need to know this idea))))

[left knoll]

anyone help

[bright island]

answer is 9/2

cos^2(x) = (1 + cos(2x))/2, so your sum is equal to (1 + cos(18))/2 + .. + (1 + cos(180)) / 2 (in degrees). 10 * 1/2 + (cos(18) + cos(18*2) + ... + cos(18 * 10)) / 2, it is easy to prove that the sum of such cosines is equal to sin(18 * 10 / 2)*cos(11 * 18 / 2) / sin(9) (in degrees), sum of cosines is equal to sin(90) * cos(99) / sin(9), cos(99) = -sin(9), sin(90) = 1, answer is 10 * 1/2 - 1/2 = 9/2

not 4))

you should know that the sum of the cosines cos(a) + cos(2a) + .. + cos(n * a) = sin(n * a / 2) * cos((n+1) * a / 2) / sin(a/2), sum of sines sin(a) + .. + sin(n * a) = sin(n * a / 2) * sin((n+1)*a/2) / sin(a/2).

[left knoll]

but its till cos2 90

not cos 81

is the answer 10/2 = 5 or 9/2

[bright island]

wait, cos^2(9) = (1 + cos(18))/2 right?

[left knoll]

yeah

answer is 9/2 right?

[bright island]

yes

because your sum is equal to 10 * 1/2 + sum of cosines/2

[left knoll]

An object is first transported via Road on land through a displacement of 2 km towards North, then by boat through a displacement of 2 km towards West on water, followed by a vertical displacement (straight up) of 1 km by a helicopter, then the magnitude of it’s net displacement is (in km) ?

and how about this

[golden otter]

Hey does anybody know anything about piecewise function graphing?

[bright island]

sorry man, im too lazy to solve such problems

[left knoll]

okkk

[dense cliff]

im kinda stuck on this one

[pastel helm]

Is it 6?

[dense cliff]

can i hav some help please :)

[left knoll]

too late

[bright island]

maybe 36?

[dense cliff]

it was 32

[pastel helm]

Minus 4

[dense cliff]

i dont understand how

[bright island]

oh,yeah

[pastel helm]

Find value of OA^2 from the given area ofsmall hexagon(a=OA) and use it to find area of tha large hexagon(a=3OA).Then subtract the area of small hexagon from it.

[dense cliff]

ughhhh

yeah

thank u

[golden otter]

Not sure how to graph this piecewise

[rose otter]

Well your domain is divided in three functions.So draw them. Start in x=-2 there you have the function y=2+x until x=0. Draw that line. Then your function in x=0 is y=2, so include that point. And then x>0 you have a quadratic function ( you will only have to draw from the vertex, just the half)

[golden otter]

Ok I think I kind of get it. I was mostly confused with the third one but I guess these should've been self explanatory. Thanks for the help

[rose otter]

😋

[golden otter]

Not even super sure if (0,0) should be filled. I think this is enough for me to get credit 🤷‍♀️

[sudden quiver]

hlo

pls help

[rose otter]

you have to fill (0,2) amnd (0,0) is not filled

[golden otter]

Didn't fill (0,2) because it is less than not equal to 0. My lines are a little messy but I remember my teacher doing that. I made sure to mark 0,0 as not filled though 😂 thanks for pointing that out

[rose otter]

yep it is less but you have the function y=2 if x=0

[naive cape]

I'll just put it here cuz I've been trying to solve it for 3hrs straight
plz HELP
I'm stuck in 2nd question

[bright island]

I dont know how to prove it, sorry, but I dont think that this is some kind of ideologically difficult task, you just need to know the definitions and some theorems well (I don't even know these definitions;)))), try to open some book about topology or functional analysis, everything will be there for sure

[latent siren]

I do functional analysis. I'll be back here later.

Seems like a good exercise.

Just a question, what definition of "Locally compact" are you using?

[naive cape]

Idk probably I am missing something in my solution

[mental snow]

i have no idea about this question but i would love to see the answer 😄

[dusk harbor]

can someone confirm the solution of this pls

[naive cape]

@latent siren here's what I wrote

[golden otter]

Ok my mistake. I fixed it!

[mental snow]

what topic in math is it? its not in my syllabus right now i would love to learn about it

[weak mortar]

the solution is ln(20)-ln(16) i think

[dusk harbor]

i got the same answer ty

[weak mortar]

np

[naive cape]

topology AKA functional analysis
well it's an exercise of 1st chp:banach space nd complements
so it doesn't have to be complicated
but here I am it's frustrating

[mental snow]

how do you do double integrals
would you tell me please

[weary arrow]

iirc it's pretty straight forward actually, you just do one first, and then focus on the other. So no worse than single integrals 🙂

[mental snow]

i considered y constant first and then solved x but then i am getting arctan function in the integral

but the solution was in log terms

[weak mortar]

well in this case i first integrated over y

ooh waait

@dusk harbor i made a mistake

[mental snow]

wait can you check my answer then?

[dusk harbor]

i think you forget to divide by 4

[weak mortar]

wahts you answer puppy?

[mental snow]

its in arc tan

😦

i think i am doing something wrong

[mental snow]

1/8 arc tan 1/2

[dusk harbor]

you have to use this idea

[mental snow]

I used

dx/1+x^2 = arctan x

[mental snow]

ok so do you put y as x for that

i am sorry if i am asking weird questions this is my first time dealing with double integral

[weak mortar]

btw vasco the right answer should be zerro since if you integrate y from -x to x you get zero since y is an odd functuon

[dusk harbor]

oh

[mental snow]

but it says (x,y) belongs to R^2

R^2 is positive

[dusk harbor]

then what is the integration domain? im a little confused aswell now, i use the integration domain of 0<= x<= 2 ^ 0<= y<= sqrt(x)

[weak mortar]

well you have the condition that y^2 is smaller than x^2

so that means the integration domain becomes -x <y <x

[dusk harbor]

ahhhhh

[mental snow]

and then we gotta change to 0<=y<=x as (x,y) are positive

[weak mortar]

as for puppy when you integrated over x first what where your integration boundaries?

[mental snow]

0 to 2

i guess if i send my work you would be able to easily see my mistake

wait

[dusk harbor]

so the draw of the domain would be something like this?

[mental snow]

i tried it like this 😄 @weak mortar I would be grateful if you check this please hehe

[weary arrow]

I also get an arctan solution, I think the confusion lies in the domain of y tbh, I'm not sure if the domain is correct

[dusk harbor]

what was your domain eva

[mental snow]

@dusk harbor can you please check this ?

[dusk harbor]

i could but I dont think im the right person i have my doubts on my answer aswell

[weary arrow]

First my domain was -x<y<x but then I ofc got zero, then i changed it to 0<y<x and got an arctan solution

[weak mortar]

puppy what you calculates is domain [0,2]x[0,2]

[weary arrow]

I think someone else might be better equipped to help y'all lol I haven't had maths in a year

[mental snow]

oh how do i rectify this mistake?

[weak mortar]

you integrated y from 0 to 2

[dusk harbor]

you have to consider -x aswell

[weak mortar]

but you should see what values for y are allowed in function of x

for example if x = 1 then y can't be zero

1-2^2 is smaller than zero

[mental snow]

if I do that the answer comes out to be 0

[weak mortar]

real numbers can also be negative

so you can't just exclude them

[mental snow]

but square of real numbers cant be negative

the domain is given to be R squared

[weak mortar]

R squared simply means that the first coordinate and second coordinate are both real

[mental snow]

i dont understand what R squared stands for so i thought its just square

[mental snow]

OHHHH

okayyyyy

then my answer is 0

😦

[weak mortar]

@dusk harbor the answer should be zero

but you can always check with wolfram

[mental snow]

yeah its an odd function so

[dusk harbor]

ty very much

[weak mortar]

np

[mental snow]

thankyou so much guys 😄

[dusk harbor]

sorry for bothering again can someone help me with the domain sketch of this expression?

yes but this one its a new expression

[weak mortar]

it is the quarter of a disk in the second quadrant

and the disk has radius sqrt(pi)

[dusk harbor]

something like this?

[mental snow]

but x is 0 to 2 then how in second quadrant

[dusk harbor]

we are talking about the expression with pi

puppy i think you are talking about the wrong expression

[weak mortar]

you need to rotat your disk by 90 degrees to the left as x is smaller than zero

[dusk harbor]

ah it makes sense

[mental snow]

it cant be a disc

x^2 - y^2 <= 0 make straight lines on the graph

had it been x^2 + y^2 it would be a circular shape

[mental snow]

pi? oh sorry are you discussing a different question

my bad

[mental snow]

Ohh this oneee

SORRY my bad

[mental snow]

oops

[mental snow]

yep quarter of a circle with radius root pi in second quadrant 😄

[naive cape]

can someone check nd tell if I'm wrong

@latent siren

[pure garden]

I prob made a stupid mistake but i cant spot it

You are meant to find the gradient and determine whether the turning point is a local max or min

[weak mortar]

x^3=-1 implies that x = -1 not 1

[pure garden]

i'm actually blind

lol

[latent siren]

Wait I just came back

[latent siren]

The idea is correct, you use the fact that 0 has a compact neighborhood.

Do you know that local compactness is equivalent to the fact that every bounded sequence in the Banach space has a convergent subsequence?

Did you prove this characterization?

[latent siren]

Seems like you don't need compactness of the unit sphere.

@naive cape

[naive cape]

Well I didn't think of it that way but tbh I didn't use that characterisation

[latent siren]

I feel like this is how you're supposed to do this because you can directly use the result of item 1.

[naive cape]

but the local compactness is just one way implication

????

[latent siren]

If you can prove one way implication, that is sufficient.

Ahhh

Actually, it might be a one-way implication only. I think the equality is that M is locally compact iff every bounded subset of M has a compact closure in M.

[naive cape]

I guess having compactness of the unit closet ball is the key to the convergence of sequence (Xk)

[latent siren]

Do you know of the sufficient conditions for the Bolzanno Weierstrass property?

In any case, I have to go. You're pretty much done if you can prove the characterization. Or... you can look the proof up. It's probably on some Functional Analysis book.

[naive cape]

to proove the convergence it has to be bounded , compact as well

[naive cape]

well I see now , I was just confused ; I was struglling using the result of the 1st question

[naive cape]

thanks alot for your help I really appreciate

[dawn shale]

hi !can some1 remind me how to calculate it ?

the equation*

[lapis relic]

y=m*x+n

lol

[dawn shale]

is it : " 4*(t-2)u(t-2)" ?

[sharp ferry]

Can someone help me with this

[lapis relic]

4u(t-2)

[dawn shale]

100% sure ? 😮

[lapis relic]

not sure, let me revise it

4tu(t-2) asuming the ramp doesnt have an end

i missed the t

you have to think that u(t) is a step

you multiply that step constant by another function, and you get the signal you want

[sharp ferry]

Nvm I got itt

[lapis relic]

and the way you move the step u(t) function is by add or substracting the number u (t-2) the step to the right // u(t+2) step to the left

@dawn shale easy?

[dawn shale]

nahhh im super lost XD. Again, what is "in your opinion" the final result ?

[lapis relic]

its laplace transform right?

[lapis relic]

this function is:
{
0 for 0<t<2
4t for 2<=t
}

that means 0*(u(t) -u(t-2)) + 4t* u(t-2)

so the final ecuation is f(t)=4tu(t-2)

[atomic cipher]

anyone doing statistics here?

or econometrics?

[lapis relic]

everything is maths lol

[surreal hound]

yea

[surreal hound]

no, but interested

[atomic cipher]

I have 1 day to figure out how to do this:

[surreal hound]

any luck so far?

[atomic cipher]

not really

let me show you what I have for a

okay I can do a, but not the rest

[surreal hound]

show me what you got

[fervent dust]

we learnt "y=mx+c" but it's the same thing. heard of "y=mx+b" but not "y=mx+n"

[atomic cipher]

@surreal hound

[lapis relic]

it may vary depending on the country, i guess

[fervent dust]

uk is "y=mx+c" for the gradient of a line

[lapis relic]

spain is "y=mx+n" lol

[fervent dust]

oh cool. same thing really but interesting nonetheless. same with BODMAS, PEMDAS and BIDMAS for order of operation

[lapis relic]

they dont teach a pnemotechnique for that

we just know the order

[atomic cipher]

for b) this is given in the formula sheet:

[fervent dust]

oh so your just straight up taught it lol, acronyms were always helpful for me when it came to everything

[lapis relic]

no, the same in english order of adjectives

[fervent dust]

oh okay

[surreal hound]

i don't think ill be much help on this one :/

[surreal hound]

Argentina and US is y=mx+b

[atomic cipher]

why are they taking the sum here?

[full solar]

i didnt study and my exam is tomoz what do i do

@everyone

please

[covert anchor]

how mAJOR is it ?

[mental snow]

I guess you can just see past year papers and have a general idea of what's being asked... Identify the topics which carry heavy marks weightage and try to read / revise / learn those heavy weightage topics

Also you can learn small / Less time topics from which maybe 1 or 2 questions were asked...

[mental snow]

The main point is to maximise your marks in minimum time (as you have only one day)

[mental snow]

Oh wait, you said tomorrow... 5 hours ago...is it Today!?

[covert anchor]

damn

[covert anchor]

how do i express as in iii ?

[mental snow]

c=1 d=5

volume = base area x height
V = (5root2 - 5/2) x (root2 + 3)

[neon solar]

hi

i need help

someone can help me pls?

[neat trail]

can someone help me answer this?

[mental snow]

Center of mass of Both the functions separately or...

Or the intersection of these function revolves around x

[neat trail]

their intersection

[mental snow]

Umm...by any chance do you have the answer to the question

I want to confirm

[neat trail]

actually the given function has 5 other questions and the center of mass (centroid) is the only thing i cant solve

[gleaming ridge]

help iin what my guy

[mental snow]

I might be wrong so i ll try it a couple more times

but did you get a similar answer or something

[neat trail]

among the 3 questions we have the same answers but not this one tho

[rugged imp]

Is the answer x=2. ( I am doing this type of ques for the first time so I might be wildly wrong)

[neat trail]

idk im still figuring it out

[rugged imp]

did you get an answer?

[neat trail]

nope not yet

[rugged imp]

but is the y-coordinate 0 for you?

[mental snow]

yes

the Y coordinate is 0

i am still figuring the x out

[rugged imp]

it should be 2

idk i might be wrong tho

but i used physics COM

idk how to get centroids

[mental snow]

yes integral x dm / M

thats how I did

[rugged imp]

oh you used the same as m is directly proportional to A

[mental snow]

No

I just assumed Rho as the density

[rugged imp]

yeah

[mental snow]

and then it gets cancelled in numerator and denominator

[rugged imp]

but then cancels to get

[mental snow]

yes

[rugged imp]

the same thing

[mental snow]

okie dokie

i gotta try again

[rugged imp]

I think then I must have gone wildly wrong somewhere because my integral was fairly straightforward

[mental snow]

haha

happens

idk

lets try

[rugged imp]

i got 2 which is way too simple

wait it should be 2 as the curve is symmetric about x=2

x^2-4x=0

[mental snow]

x^2-4x?

5x - x^2 and y = x

[rugged imp]

yeah but then upper curve -lower curve

tp get the resultant curve

[mental snow]

ohh

i have squared them

[rugged imp]

huh?

why?

[mental snow]

I am considering a disc

[rugged imp]

it wont be a disc

[mental snow]

my element is a disc

not the whole thing

[rugged imp]

it would be a part of a parabola

the area

[mental snow]

bro

disc is just a differential element

the whole structure

would be part of a paraboloid

[rugged imp]

idk bro i havent done that yet

[mental snow]

its rotating around X axis

so it has volume

[rugged imp]

yeah but what i thought was lets take its COM in xy plane

]

[mental snow]

lol

hehe

[rugged imp]

we would get a CM

[mental snow]

maybe that might work

lemme try

[mental snow]

we would get a com of the 2d area formed

[rugged imp]

then when we rotate it we would get a circle looking at it from the yz plane and

[mental snow]

but since its rotated its a 3D shape

[mental snow]

yes

yes

it will have a circular base

hold up lemme try and then i ll try to send u a notebook page shot

[rugged imp]

no what i meant was we would rotate just the point COM to get a circle

i havent dealt with 3d before

this is my first time with this

ill write out somethings and then please help me see the problems

lets take this to pm's

[mental snow]

@rugged imp

@neat trail

I am getting (2.222,0) as COM

[neat trail]

can i see ur solution? if it's okay

[mental snow]

i did this in my notebook and the calculation is....so i left it at the calculation part

20/9 ~= 2.22...

[neat trail]

can i ask u in dm?

[covert anchor]

hiii

for b what is exact form ?

[sage rock]

b is -2

[mental snow]

sure

[covert anchor]

how

feel free to dm

[sage rock]

Done

[covert anchor]

ii a what should i do

[safe ruin]

yo??

this bbe hard

lmfao

[full venture]

Yo anyone’s halp

[safe ruin]

the numbers written by pen is the actual answer or are those just your answers?

[supple island]

what you can actually write is x=120%p and y=150%q, you can't consider p and q equal

[full venture]

yup i just saw the answer sheet and i couldnt belive my eyes

[supple island]

knowing this you can write xy=120%p150%q

[quiet kestrel]

Just do x=1.2q and y=1.5q

Multiply and bam

[supple island]

yeh and then multiply by 100 cuz they want the answer in percentage

[quiet kestrel]

^

[full venture]

Are u trying to factories

[safe ruin]

yes ;)

[covert anchor]

can someone help ?

[quiet kestrel]

Remember properties of logs and ln

https://mathinsight.org/logarithm_basics

Basically simplify as much as you can and then express in the way they want.

So loga (a^3x)^(1/3) - loga y

And go from there

[covert anchor]

can i dm ?

[quiet kestrel]

Sorry but I am afraid not for the time being.

[covert anchor]

sure

is this ok

[quiet kestrel]

The step from line 5 to 6 is wrong

So is line 3

Why are you putting the x there?

[mellow smelt]

Anybdoy know how to do it

[covert anchor]

?

[covert anchor]

what should i do then

[quiet kestrel]

So loga ((a^3)x)^(1/3) - loga y -> 1/3loga((a^3)x) - loga y

[safe ruin]

yo?

[covert anchor]

?

[sage rock]

Its a science question

[mental snow]

1.2?

[mellow smelt]

Ok

Ty

[safe ruin]

;-;

[supple island]

do the sum of the forces on the block on the top and remember that to start motion the force has to be equal to the static friction force

[mellow smelt]

Ok

[supple island]

sec, lemme rephrase

[mellow smelt]

Ok

[supple island]

to start the motion the sum of the forces must be 0

which is basically the same thing in this case, but it's more appropriate generally

[mental snow]

if there is sliding between the two blocks we cant take net sum of forces and the 2 blocks behave as 2 separate bodies whereas if they were not sliding the two block system could be converted to a single system