math-help

[left knoll]

how

from where

[alpine escarp]

From the mock that you just gave

do it again

take 24-48 hours.

[left knoll]

okk

you must be good at math from genes

[alpine escarp]

lmao jokes on you man. my parents absolutely suck at math.

[left knoll]

nah your brain must be like that

[alpine escarp]

idk if i should be going into all this but trust me nothing beats hard work. You can blame the whole world and say that someone else is more priveleged than you are but you'll taste coffee beans soon with that attitude.

[left knoll]

my adhd brain cant do shit

[alpine escarp]

I'm speaking from my own experience and if you haven't already, read "Can't Hurt Me" by David Goggins

[left knoll]

i have deep interst in a lot of subject sometimes i can hyperfocus aswell but im just another idiot

[left knoll]

i will

[alpine escarp]

well you can keep saying that to yourself or you can work on a field of interest. That said, the Indian education system pushes you to do something that you dont want to do. You have to do Phys, Chem and Math even if you're interested in say Computer Science. The system is built to push you down. And yea don't spend days blaming the system. You've gotta live with it.

Anyway I've to go now. Take care. Wish ya luck out there.

[deep horizon]

Hey there! How yall doing ?

[covert anchor]

Can someone help me on how to start

I tried using Log_10 but it did not work

[near acorn]

you can use log addition rule

log(5^x * 4^(2x)) = log(5^x)+ log(4^(2x)), and then do the same on right hand side

[covert anchor]

wait what happens to the 7

[near acorn]

log(7*11^x) = log(7)+log(11^x)

[covert anchor]

Im confused hold on ill try again

[alpine escarp]

i've left the last part for you to solve.

[covert anchor]

b4 this can i show my workings

Ive done till this is this wrong ?

[alpine escarp]

sure

you're correct!

now take log base 10 on both sides

you'll get x(log(80)-log(11))=log(7)

now x=log(7)/(log(80)-log(11))

perfect!

[covert anchor]

oh i did not see that

thanks for guiding

[alpine escarp]

no worries :))

[covert anchor]

I just started learning this and I may ask quite a no. of stuff

Any idea what i did wrong ?

[alpine escarp]

you pulled an oopsie

check your first two steps

[covert anchor]

? Still cna find 🥲

[alpine escarp]

a^x*b^x=(ab)^x

but a^x+b^x /= (ab)^x

/= :- not equal to

[covert anchor]

Oh ic

lemme retry

so it should be 12 instead of 27 ?

[left knoll]

ik im into VFX but i still have to study some unusual math and physics\

[covert anchor]

Not sure tho

[alpine escarp]

nope

[covert anchor]

Oh im not sure

[alpine escarp]

ah cool.

[alpine escarp]

so your first step is right

i presume you've done quadratic equations right?

[covert anchor]

yes

done b4

[alpine escarp]

so take 3^x=t and give it a try

you'll get t^2+t=3

[covert anchor]

oh ok subsituiton thks

[alpine escarp]

yep

[covert anchor]

then i will get 2 answers for t rite

yay got the ans

[left knoll]

Explain this

I haven't studied quadrants

[covert anchor]

same

[long harness]

You should try drawing a right triangle with the base=77 and the hypotenuse=85. Then use the pythagorean theorem to find the perpendicular distance and then find perpendicular/base which is the answer. (36/77). The quadrant doesn't change anything because it is quadrant 1 where all the trigonometric functions are positive.

[left knoll]

I'll sss

See

[long harness]

For your reference, only sine and cosecant are + in Quad 2, tangent and cotangent in Quad 3 and cosine and secant in Quad 4

[left knoll]

Thanks

I'm gonna start studying and stop procastinating

[cosmic epoch]

any can help me;(?

cc: consider the development of: Determine, if the coefficient exists

[quaint imp]

what r inequalities and equalities

[wheat ridge]

what exactly do you mean by that?

[quaint imp]

basically inequalities on a number line

[wheat ridge]

hm well inequality on a number will be a collection of points

line*

[quaint imp]

yes

but how do u graph it

[wheat ridge]

only one axis right?

[quaint imp]

yes

[wheat ridge]

i guess you just start drawing a line from where its supposed to start

like x>5

[quaint imp]

ok yes

[somber hemlock]

It exists. Do you want working?

[wheat ridge]

so draw a dot on 5 and then draw

yoo what is your age @quaint imp

[quaint imp]

im 14

[cosmic epoch]

yes=(

[wheat ridge]

you are pretty dumb for a 14yo

[quaint imp]

how

[wheat ridge]

XD

just kidding bruv chill

[quaint imp]

we just started this topic in school

[somber hemlock]

Write the general term in terms of r and equate power of x with -7

[quaint imp]

grade 8

[wheat ridge]

oh.. are you prepping for any competitive exam?

[quaint imp]

no for final test

[somber hemlock]

No need for that dude

[wheat ridge]

oh acha samjha

[quaint imp]

lol keep it english we can do that hindi/urdu in non english chat

[wheat ridge]

sorry i was doing banter XD

[wheat ridge]

yeah sorry about that

[quaint imp]

llol

[cosmic epoch]

thx

[quaint imp]

k thanks for helping me

[wheat ridge]

yo btw if you need help in maths message me uk im pretty good at it 🙂

[quaint imp]

kk thanks so much

[quaint imp]

lol thanks

[green summit]

Goodbye

[haughty rampart]

Anyone here that is a math genius can help me with this? Its in german but summed up it wants me to prove that the function given in task 1a) represents the graph in the pic above. I also have to explain what the parameters stand for. 1b) I have to fill up the parameters and basically do proper function for the graph above

[frail nova]

Got this and cant know how to solve

It got too complecated

[silk quiver]

the solutions are complex numbers

[icy vessel]

Here is the solution

x= -1, -5/2 or -2.5

[silk quiver]

yeah i got it wrong

it's -1 and -0.5

[icy vessel]

Please check it once again

I've sent the solution for it in the above image

[silk quiver]

i've checked your solution

you've got it wrong here

[languid gazelle]

did someone know how to do this probability question, idk how to get the answer.QAQ

[silk quiver]

also this

[icy vessel]

damn

lol

sorry

my bad

[silk quiver]

it's fine we all make mistakes tho

[icy vessel]

that was too silly

[willow basin]

So...
OA = OC = radius of 4cm
OB= 10cm
OK.
So, the mark scheme Cos<AOB = OA/OB. In other words, we do cosine(x) = adjacent over hypotenuse.
But that doesn't make sense to me when because they're saying angle AOB
Can anyone help me understand why they're saying <AOB instead of <OAB?

so h is the hypotenuse if we go from angle o
but where is the opposite of angle o
it's the hypotenuse
where is the adjacent
where is the opposite
it doesn't make sense, does it?

if we go from angle a, the opposite is side ob

the adjacent is side oa

the hypotenuse is side ab

i'm just trying to make sure i'm right cos my teacher hates it when i try to correct them

[silk quiver]

for these 3 events to happen at the same time just multiply all their probability

[rugged imp]

Condition given is that they say he commits the crime

So we have to take just those cases as the denominator

I don't think we can simply multiply

[silk quiver]

i think we can it's just three events happening at the same time

[rugged imp]

We can't because the question has already stated that they say he commited the crime

[languid gazelle]

hmm, it can just multiply?

[rugged imp]

Idts

[languid gazelle]

ohh

ik

[rugged imp]

Is my solution fine?

I think it might be a bit wrong

I can't tell what exactly though

[languid gazelle]

i think the though seems correct

[rugged imp]

Yeah I don't think we can just multiple

But I think that my tree is a bit wrong

Idk do you have the answer to this ques?

[languid gazelle]

i just draw the tree like that @rugged imp

[rugged imp]

The we both might be wrong lmao

[languid gazelle]

hhhhh

maybe

[rugged imp]

Do tou have the answer though?

[willow basin]

Thank you.

https://tenor.com/view/merci-minions-despicable-me-cheer-happy-gif-9265482

[rugged imp]

No worries

[languid gazelle]

actual my thought is same as yours

but the probability is small....

idk if it correct

[rugged imp]

So you want m to commit the crime

Jokes

[languid gazelle]

hhh

[rugged imp]

Probability will be small because it was already 1/1700

[languid gazelle]

yep

[rugged imp]

So I think it should she alright

Either way a good question

Don't see ques like that here

[languid gazelle]

yep, i took a course is talking about probability (i think..)

[rugged imp]

You in college?

[languid gazelle]

that was actually hard

yea im in yorku

[rugged imp]

Oh nice

[languid gazelle]

how about u

hhh

[rugged imp]

12

[languid gazelle]

it seems u r good at math

[rugged imp]

Grade

[languid gazelle]

wow

great

[rugged imp]

Nah man I have seen way better

Way way better

Too much anime for me I guess

Please do tell if you get an official answer

[languid gazelle]

sure

[haughty rampart]

Does anyone have a clue cuz I need serious help lmao

[frail nova]

Answer
X1 = ?
X2 = ?

Really need to know

[rugged imp]

Can you describe the question a bit more?

I think it's a comprehension type question

But this question seems a bit above my level either way. I don't think I can describe an arbitrary curve using equations.

[haughty rampart]

Sure, so basically I have to prove that the function on task 1.a) describes the graphic above (more specifically the curve) I also have to say what the parameters stand for and what function they have. That is actually it pretty much. There is no more info given.

[haughty rampart]

Thats ok ☺️ Ikr its such a complex task

[rugged imp]

Where is this from?

Also can you tell me what the line AB describing? Just a tangent?

[haughty rampart]

Im in 12th grade this is actually my oral exam.. I hope I don’t get in trouble for that lol

[rugged imp]

Oof

[haughty rampart]

Yes its a tangent

[rugged imp]

Wait you need to see the question on the spot and do it orally?

[haughty rampart]

I could swear that my teacher gave me the hardest task lmao

[rugged imp]

How much time do you have for it?

I can have a crack at it maybe

[haughty rampart]

No, I have 2 week for preparation, but I only have 1 week to hand him out my results.

[rugged imp]

Oh I thought you had like 15 mins

Dang 2 weeks for one problem. This one sure is a heavy weight

[haughty rampart]

Lol

There is also a second task and the last task is to form questions myself and answering them😕

[rugged imp]

What? Make a question and answer it yourself?

Also I have to just describe the curve k0 to k1 right

[haughty rampart]

Yes exactly

[haughty rampart]

Yeah... 😕

[rugged imp]

Is anything give about where the line ab is tangent to the curve

[rugged imp]

I can send some good questions

[haughty rampart]

so for the tangent the point A adn B is given as u can see but the point S is where the tangent and the curve meet

But y is not given

[rugged imp]

Ok

[haughty rampart]

That would also be helpful 🙂

[rugged imp]

Any specific topic?

[haughty rampart]

Actually, I think the question has to relate to task 2. And I think I would have difficulties translating it, its all about vectors in a 3 dimensional coordinate system

Thank you though😊

[rugged imp]

Oh so the question has trip be related to this.

[haughty rampart]

Exactly

[rugged imp]

I am gonna be real. I have no idea how to do this. I haven't even seen anything like this before

[haughty rampart]

I feel you😢 Thats ok, maybe anyone else can... Thank you so much tho

[rugged imp]

I will still ponder upon it for a bit

[haughty rampart]

👍😊

[rugged imp]

Does this do anything?

Now x=w/2 is a focus

So maybe you can describe w?

Any ideas?

I don't know what to do with the tangent.

Maybe we can say that the line is tangent to both ellipse and parabola

[haughty rampart]

Thank you so much amd yess anything helps at this point

[rugged imp]

Wait did you get something from this?

Maybe we can say that the parabolic nature of the graph dominates for lower y values while elliptical nature dominates for value closer to w/2

This sounds like nonsense though

Especially mX+n

[haughty rampart]

Yess I think you described the graph right? Like which parameters stand for what adn has an influence on its shape? Or did I completely miss it

[rugged imp]

I did that sort of

I am going to be honest I am used to doing objective questions. Subjective questions and descriptions aren't my forte

But if you say I am right I can trudge up more info about the oarameters

I don't know what is actually required

By your teacher

[haughty rampart]

Nahhh I asked a lot of people to help me out but they didnt understand either, honestly I dont think this is a task for a highschool student 😕 I mean I get it this should sorta prepare me for university and stuff but like we didn’t even do stuff like this in class

[rugged imp]

This seems too vague

I think parabolic nature dominates for higher values

And elliptical for smaller vakues

[haughty rampart]

If you feel like not much is going to come out of it, honestly no need to spend your time on this, I would completely understand it. Ive asked a relative who studied mathematics and she had difficulties too

[rugged imp]

I think I am close

To something

You see the focus of parabola and ellipse coincide

The axis I meant

X=w/2

I'll send you something

[haughty rampart]

Wait i will experiment with geogebra a little bit

[rugged imp]

What geogebra

Oh we use desmos here

It's something similar right

[haughty rampart]

Its a software where you can like portray the graphics

[rugged imp]

Yeah yeah

[haughty rampart]

Yup

[rugged imp]

Wait that's a good idea

Why didn't I think of that

I am generally averse to using devices for math though

[haughty rampart]

Yupp it is actually sometime more time consuming

But it helps me understand some functions

[rugged imp]

It's 2 am here right now

I was about to go to sleep when this popped up

I think this question is a bit more visual based

Maybe the line mx+n had something to do with the tangent

The slope near the tangent is pretty close to being constant

So maybe line nature dominates for x=s

[rugged imp]

Did you get anything

[rugged imp]

Also the one which has a faster rate of change of slope will dominate right. Like d2y/dx2

[haughty rampart]

Actually not much lol

[rugged imp]

What?

[haughty rampart]

The geogebra software I mean

[rugged imp]

T you got something

What did it say?

Wait did you describe the whole graph on the calculator and then sorted the parameters?

[haughty rampart]

Exactly

[rugged imp]

Oof

How wrong was I?

[haughty rampart]

And the tangent

No I actually just wrote down the whole function

[rugged imp]

Yeah I get it

And then you slid parameters till you get something resembling the graph

King shit

[haughty rampart]

Yupp

[haughty rampart]

Lmaooo

[alpine escarp]

king and queen doesnt exist in other countries mate XD

this is a good question tho lol

[rugged imp]

Can you send me picture of the parameters you found

[rugged imp]

Umm yeah. It was just.... I uh...

King shit is something a king would do

[alpine escarp]

oh lmao you meant it in that sense

ma bad lmao

we use king and queen theorem here right... thought you were talkin about that

[rugged imp]

Ah

Integration

[alpine escarp]

i was like how would you use that here

[rugged imp]

Nah man

Don't read too much into that

Stuff like this doesn't give in jee tho

[alpine escarp]

i'm not a math major. couldn't care less XD

[rugged imp]

Oof

[alpine escarp]

not studying for JEE lol

i already gave my JEE

[rugged imp]

How was it?

[alpine escarp]

last year to be precise

umm bad? lol

[rugged imp]

IIT?

[alpine escarp]

97.6 and 11898

[rugged imp]

Ahh

[alpine escarp]

yep screwed :))

[rugged imp]

I got 8k in adv and took a drop

[alpine escarp]

nah i didnt have the heart to drop

lockdown messed me up enough :/

[rugged imp]

So nice nit?

[alpine escarp]

nah bruh i was interested in cse

didnt wanna compromise branch at a better college just for brand image.

i was left with EEE at BITS Goa, CSE at VIT and yk normal courses at NITs

ones you get with a 97.6 percentile in JEE

lmao

[rugged imp]

I didn't think too much about mains

[alpine escarp]

chose CSE coz i wanted it. Don't think I could've made a better decision

[rugged imp]

I was too focused on adv

[alpine escarp]

what

[rugged imp]

And I screwed it up

[alpine escarp]

what's your mains percentile if you dont mind me asking?

[rugged imp]

Now?

[alpine escarp]

man that's something that all of us do wrong

yea rn?

[rugged imp]

Still not good

I am in Allen

[alpine escarp]

arey lmao it's not that imma dwell deep

[rugged imp]

So our course wasn't even completed

[alpine escarp]

chill man i was in Allen too

[rugged imp]

It's97 rn

[alpine escarp]

cool cool.

my advice would be to focus on JEE Mains and BITS as well

[rugged imp]

I focus on bots and adv

[alpine escarp]

the IIT dream isnt worth it unless you get a branch of your choice

[rugged imp]

I am good at tough questions but I am very sir

Slow

Mains is my exact antithesis

[mystic python]

Question says leave 5.96 to 1 decimal place. Would you leave as 5.9 or 6.0?

[rugged imp]

6

[alpine escarp]

6.0

[alpine escarp]

same lmao

[mystic python]

Aight thanks

[alpine escarp]

i absolutely love organic chem tho

couldnt choose that as a major coz you know... it's India

[rugged imp]

My parents aren't like that

[alpine escarp]

lmao you didn't have to delete. A lot of people hate organic.

[rugged imp]

I don't think I can swear here

[alpine escarp]

Neither are my parents. It's just that there's no college here that allows you to major in OC

[left knoll]

my 11th didnt go quite well

[rugged imp]

F

[alpine escarp]

Focus on 12th

[rugged imp]

Yeah

[alpine escarp]

eff 11th

[left knoll]

ill have trouble in jee

[alpine escarp]

no you won't

calculus is a whole new thing. Focus entirely on that

[rugged imp]

Focus on integration and vectors and 11 irodov is a piece of cake

Chem just sorry about ncert

Worry

[alpine escarp]

depends actually

[rugged imp]

For inorganic

[left knoll]

whats waitage of 11th and 12th according to you

[alpine escarp]

45 55 imo

[rugged imp]

40 11th 60 12rlth

[alpine escarp]

40 60 sometimes

yea

[left knoll]

ummm

[rugged imp]

Listen don't worry too much

Just focus on one thing at a time

[alpine escarp]

bro i started OC in 12th and it ended up being the only reason i got a rank in advanced lmao

[left knoll]

yea ill have to stop thinking about it

[alpine escarp]

i think i got all the OC questions right

dont be like me

[rugged imp]

Yeah oc was easy in this adv

Phy paper 2 for me messed up

Even though phy is my strongest

[left knoll]

your mechanics is strong?

[rugged imp]

Sort of

[left knoll]

great

[rugged imp]

I did since irodov

So it should be fine

[alpine escarp]

aright imma go study

good night yall

[left knoll]

same

[rugged imp]

Damn grinding in college as well

[alpine escarp]

lmao you have to

[rugged imp]

Well I have to be up at 7 so imma head to sleep

[alpine escarp]

dont come to cllg with the expectation to "not work"

[rugged imp]

F**k me really

Isn't first year cool

[alpine escarp]

idk im in a priv cllg.

i'm doing two degrees lol

so it's pretty harsh

[rugged imp]

Huh?

Cse+eco?

[alpine escarp]

BTech Computer Science Engineering from VIT Vellore and BSc Programming and Data Science from IIT Madras

[rugged imp]

Oh that thing

Yeah I remember that

[alpine escarp]

yep lmao

[rugged imp]

That one started by IIT and iim

[alpine escarp]

the IITM thing is strenuous asf if you're doing BTech

[rugged imp]

How do you even get into it?

[alpine escarp]

you have to give a qualifier exam

if you qualify, you're in

[rugged imp]

When?

It's it the same as jee?

[alpine escarp]

dont worry about that rn

[rugged imp]

Oh yeah

I have bigger fish to fry rn

[alpine escarp]

yea. Focus on JEE.

[rugged imp]

Anyways bro

Imma go sleep

Best of luck in your future endeavours

[alpine escarp]

aighttt byeee

you too!

[fallow minnow]

bye

[lapis quarry]

Hello anyone here do actuary?

[covert anchor]

I procrastinate allot , what do i do

[lucid basin]

HI everyone, can you help me to solve this , I'm foreigner don't know well "using row-equivalent matrics's" exact meaning.

[sullen lantern]

i think this means to put it in reduced row echelon form?

[primal canopy]

Well, the row elementary matrices are obtained by applying a row elementary operation to the identity.

[lucid basin]

tnx, but if possible can you solve one of them on paper 🙏 I'm little bit confusing

[primal canopy]

here you have an example

[primal canopy]

Solution 6

I hope it helps you

[left knoll]

Hi guys!can someone please tell me what is the range of this function??🙏🏻🙏🏻

[lucid basin]

thank you so much 😍

[silk quiver]

it's hard to solve but based on the graph it's y/= 0

[left knoll]

Thank you so much🙏🏻

[random flame]

Ayo can someone help me with Q3a? Ping if you do and thankiew!!

[silk quiver]

the number not included in the domain are the numbers that will make the denominator zero so in f(x) it is 1 and in g(x) it is 0

[random flame]

Ohh okie thankiew!!

[formal prism]

how does this equal that im so confused

they are making u = x/2 apparently

[hollow mauve]

is u = x/2 given?

[formal prism]

its an example from princeton review and they made u=x/2 to solve it

[somber hemlock]

You can take take any variable equal to anything

[formal prism]

oh what the heck u can do that

[silk quiver]

remember the derivatives of inverse trigonometric functions

[hollow mauve]

The question was to prove yeah?

[hollow mauve]

So when multi-variables are present then we can yes

[formal prism]

what did you do to get du, idk why you did 2-x(0)/2^2

[silk quiver]

remember this?

the derivative of fractions. our prof call this the low(dhigh))-high(dlow)/low^2

[formal prism]

o

dang you just enlightened me

this entire time i never knew you could just solve for du like that

thank you

[silk quiver]

you're welcome

[random flame]

Ayo it’s me again 😅
I don’t get Q3b- ping if you know Thks thks!!

[left knoll]

anyone

is here

[peak eagle]

https://en.wikipedia.org/wiki/Exponentiation look at the rules

if you still don't know what to do ask again 🙂

[left knoll]

I GOT IT

[pseudo hearth]

I don't know but it might be
The real number that cannot be in the domain of f(x) is 1
and the real number that cannot be in the domain of g(x) is 0

[random flame]

Nvm I asked my friends, thanks tho! -^-"

[pseudo hearth]

I'm a highschooler from Vietnam so I don't do maths in english

do u know the rule?

[molten saddle]

no, i don't do anything 👀

I'm just complimenting you, don't care

[true drum]

Hey man this easy@left knoll

Do the thing take the bottom in upper portion like xpower a-b by the rules of indices

Then u get a2-b2

Try using in three

You get the answer xpower0

So its 1

[cedar crane]

Hello, I have an exam tomorrow so er, can someone help me with these two questions of simple/compound interest?

[left knoll]

P = IRT

Something formula

I don't remember

[hollow escarp]

Post the questions

[cedar crane]

These are the questions 😓

[hollow escarp]

do u have the final answers ?

[cedar crane]

No I don't, that's why I'm having trouble with this

[hollow escarp]

If you did not understand something , just ask

[cedar crane]

Thank you so much, I understand :D

[hollow escarp]

cool

[cedar crane]

Can someone help me with Q 26?

[hollow escarp]

Is it to simplify ?

[cedar crane]

Thank you a lot! It was to simplify, sorry for not clarifying that

[hollow escarp]

no problem

[half stream]

hii, does anyone know how to explain what a fourier tranform does?

[wooden wolf]

its a way to transform time-domain functions into frecuency-domine and that way you can get the spectrum which tells you interesting things from the signal

and makes the maths easier, you dont have to do sometimes the convolution (time-domain), in the frecuency domain the convolution is a simple multiplication (much easier)

[half stream]

thank you very much! im working on its quantum version but i didn't even know the normal one so it helped me understand things better. thanks again!

[wooden wolf]

you are welcome, I´m sorry for the shorter explanatio

maybe some1 can explain it much beter haha

[half stream]

no no it was great, it helped me put all the pieces together !!

[latent siren]

You can also think of the Fourier transform as the operator that 'extracts' the relevant frequencies of a signal. You can see this attribute if you try to look at the sine function. Without doing anything to the sine function, we already see that it really only has 'one frequency', i.e. its oscillatory behavior does not change through time. I.e if f(t)=sin(2 pi k t), then its frequency is obviously k. If you apply the fourier transform to the sine function (I hope they discussed this with you), you get something called the 'dirac-delta function' which only has two values (one value for each of the positive and negative fundamental frequency).

To make all this more concrete, consider again the sine wave f(t)=sin(2 pi k t). The Fourier transform of f above only has nonzero values for frequencies w=-k and w=+k, telling you that there really is only one frequency up to positive or negative values of a sine wave.

[left knoll]

Can anyone tell a good book to study multivariable calculus? In depth

[half stream]

oh my, thank you so so so much for this explanation!! is it fine if i text you privately to ask some clarifications?

[latent siren]

Oh sure

[left knoll]

Can anyone tell a good book to study multivariable calculus? In depth @latent siren

[latent siren]

Hm, most elementary calculus books have a section dedicated to multivariable calculus. The one that I used when I was in college was Letihold's "The Calculus 7"

[left knoll]

Okay thanx @latent siren

[latent siren]

Some people swear by James Stewart's calculus books too, maybe you can check it out.

[left knoll]

@latent siren yup sure.... Btw is Thomas calculus and Joseph Edwards good?

@latent siren coz my main agenda is to learn multivariable calculus is for physics olympiad prepartion

[latent siren]

Never really tried them, but elementary calculus is 'elementary' enough that most of these books will probably be talking about the same things.

[left knoll]

@latent siren ok 👌👌👌👌

[latent siren]

Oh, I may not be the best person to ask about this. I'm not into math contests, you're better off asking a coach about this. There's quite a different skill set that goes into math contest than just learning maths I guess.

[left knoll]

@latent siren ok no problem... Still ul helped a lot

[topaz narwhal]

it's little questions like this that I continue to get wrong. anyone great with statistics mind giving some input ?

[pseudo hearth]

why n-1 >=0?

it's a cube root

[willow basin]

hi

can anyone help me understand why i got these questions wrong?

i got that adc = 103 bc angles in a triangle add up to 180. so 180 - (33+44) = 103. Opposite angles in a quadrilateral add up to 180, so 180-103 = 77.

So i got <ABC = 77.

Why is it saying <ABC = 103.

?

Then for the second question, I got 23+17+10 = 50. So 50% is left. so it's a 50% decrease.

why is it saying 42.5?

anyone know?

https://tenor.com/view/help-me-please-puss-puss-in-boots-cute-eyes-gif-16046923

[delicate turret]

https://youtu.be/pTnEG_WGd2Q this video talks about books you can use to learn maths by yourself

[left knoll]

Each two opposit sides are parallel, therefore the quadrilateral is a parallelogram.
Where m<ADC =m<ABC (parallelogram property)
So, m<ADC= 180-(33+44)=103° = m< ABC

[vestal minnow]

Opposite angles of only cyclic quadrilaterals sum up to 180 . Opposite angles in a parallelogram are equal.

[stuck pewter]

Pls help me I suck at math

TwT

[hollow escarp]

Do you need the answer in terms of sqrt5 or as a number ?

[silk quiver]

is the answer 7?

[hollow escarp]

yes

[hollow escarp]

Here I gave value to sqrt(5) while finding out x^2 nd then simplified.

[hollow escarp]

In this , I kept sqrt(5) as it is and then simplified in the final step.

You can do it either way i guess

[stuck pewter]

Yes.

Thank you so much y'all TwT

[stuck pewter]

Thank you

How are y'all so good at maths? TwT

[hollow escarp]

Used to find it interesting back in school. Also, this is not very hard 😅

[hollow escarp]

@stuck pewter btw,you should follow this method if you're not supposed to use a calculator

[stuck pewter]

Yea I'm not supposed to use a calculator

[stuck pewter]

TwT I wanna be good at maths too coz I have to study it for the rest of my student years

[stuck pewter]

Oh- so u must be an adult r?

[hollow escarp]

yeah

Let's just say I've been an adult for a while

[stuck pewter]

I'm just 14;-; lol

[stuck pewter]

O

[hollow escarp]

I was twice your age three years ago. Let's see if you can solve that

[stuck pewter]

Not u testing me on linear equations pls- XD

[hollow escarp]

it's an easy one. Can't be good at math if you don't try .

See you around Jess

I hope that's your name

[hollow escarp]

You can DM me if you find the answer

[stuck pewter]

Are u 25? ;-;

I'm dumb if that's not correct

[stuck pewter]

O lol

[stuck pewter]

Yea call me that

[hollow escarp]

That was fast . 👍

good job

[stuck pewter]

Oh

Thanks lol linear equations is actually the only topic I'm really good at in math

[stuck pewter]

Ok :)

[mild idol]

hey guys anyone here who knows excel and can help me

i wanna know how I can set a formula and use it on multiple values without entering those different values again and again

[silk quiver]

i can try

[mild idol]

can I DM?

[silk quiver]

yes

[steel plover]

can someone help me understand how it goes from this numerator (x+ Δx)^n−x^n to this one (x^n+n(Δx)(x^n−1) +O(Δx)^2)−x^n

[willow basin]

Thank you!

[willow basin]

Thank you!

[willow basin]

Thank you!

[willow basin]

Thank you!

[silk quiver]

yeah, my curiosity really helped me in math. i always try to experiment in formulas and ask myself what if i do this or what if i do that. also, understanding how they come up to each formula really helps, so you won't just memorize formulas but really understand where it came from.

[stuck pewter]

Okok thank you I'll surely try that out

[serene ginkgo]

can someone help me with b?
a) find all the roots of z^3=-8i (i found them as 2i, -(root 3)-i, (root 3)-i)

b) hence solve the equation w^3+8i(w-1)^3=0 giving your answers in exact cartesian form

[left knoll]

true, I thought it was a square root... mb

[hollow mauve]

I have distributed it to all x's now I am unable to take it as common

I want to take X-1 as common

I am missing some basics here 😅

@silk quiver @somber hemlock

Nvm I used the Identity amd solved it thanksss

[left knoll]

find the area of the region bounded by the curves y=sinx and the lines x=0 and x=pi

[wooden wolf]

is that a question? if it is just integrate from 0 to pi the sin function

[hollow mauve]

Yeah

[wooden wolf]

Yes

What a strange way to write pi hahhaa

[somber hemlock]

I am curious though. How did you do it?

Simple l’hospital?

[silk quiver]

yeah i think that's how he did it just summation of 1-99 then divide by 2475 equals 2

[pseudo hearth]

can you show me how u did it

[neat bay]

@cloud wagon is the answer 2π/3 and π/6?

[cloud wagon]

yes, thank you 🙂

[neat bay]

@cloud wagon you want the solution for it?

[cloud wagon]

yes please

@neat baywhat was the modulus?

[neat bay]

@cloud wagon modulus is 2 and 1

@cloud wagon is that correct?

[cloud wagon]

yes

thanks a lot for ur help, appreciate it

[hollow mauve]

Hahaha saves time lol😂

Speed Calculations uk😅😂

[hollow mauve]

Sure will send you the solution in a bit

[latent siren]

You might want to look at something called the binomial expansion. I think that's what they used here, then the expression is written in terms of the big-O notation.

[steel plover]

I'm somewhat familiar with the binomial theorem so I'll look into big-O notation a bit

thanks for the help

[serene ginkgo]

im in so much pain im still stuck on this😔 help would be greatly appreciated:)

[fading leaf]

Can someone please send a list of sketches of all graphs with the graph names mentioned in sat subject test math level 2.I really am struggling with graphs!!

[latent siren]

@serene ginkgo

[vestal minnow]

@serene ginkgo could you confirm if the answer matches? I'm curious😂

[glad sierra]

I do 🙂

[left knoll]

Hi ! Is anyone really good with functions?

[rustic sapphire]

uh hi can you all guys help me with my assignment today

[modest apex]

I could try if you’d like

Though I’m a bit rusty

[rustic sapphire]

help

[serene ginkgo]

heyy:) thanks for the help the answers for b are:

4/5-2/5i
(14-3(root3))/13 + (5-2(root3))/13i
(14-+(root3))/13 + (5+2(root3))/13i

and i have no clue how to get there

[left knoll]

Alright!
I did get some questions addressed by my teacher but if I have more,I'll be sure to ask you

Thank youu :D

[modest ice]

Yall whenever we integrate sth like (r dr) we don’t solve the “dr” part right coz alone the integration of dr is r but when we use this dr as a postscript we don’t solve it .....so then why do we even mention it as postscript .....

[neat bay]

@rustic sapphire is lambda equal to -11?

[full sapphire]

@rustic sapphire dude I see you sending these math problems left and right, you need a tutor

[ashen flower]

I can't understand conditional probability, anyone help me??

Make a account it's eazy, but I can't understand the utterance

[modest apex]

At least he’s learning and willing to learn that is most important.

[vestal minnow]

I got it😄 do you need it still?

[serene ginkgo]

omg thank you yes pls 🥺

[serene ginkgo]

thank you!!!!

lifesaver

[vestal minnow]

;)

[vague wave]

Could anyone help me out. So I rly struggle with integrals does anyone know a website where I could study them?

[solid anvil]

discount rate is discount amount/marked price times 100 right

[peak eagle]

believe it or not youtube is your best friend in explanations 🙂
than you can write some polynoms and just integrate it (for practice) and then if you are unsure if you did right put your integral in wolframalpha.com do see if you did it right 🙂

[hollow escarp]

Yes

[hollow escarp]

((Selling Price-Cost Price)/Cost Price)*100

[modest apex]

Is that the mark-up?

[somber herald]

Can anyone explain what martingales are I’m so confused lol

[hollow escarp]

Yeah . Although when I learnt it in school, the term mark-up was never used

[modest apex]

Ah, I see.

[steel plover]

I'm having some trouble with this problem, mostly because I'm new to using mathlet. I believe I've set x to -0.75 and delta x to -0.50. I'm still getting -0.90 as my slope though

when the solution says I'm supposed to be getting 0.53

[green barn]

Does anyone know how I should get back into calc? I haven't done math for over a year and a half, and the last math I did was calc 1, but I forgot most of it. Will be taking Calc 2 in the summer. Anyone have any advice to help me get back on track with the course?

[mystic python]

How do you find if a function is even or odd depending on its graph?

Like if you were given the general shape of the function only on a graph, no points at all

[bleak drum]

As I know If the graph of the function y=f(x) is symmetric with respect to the Y axis, then y=f(x) is even

If the graph of the function y=f(x) is symmetric with respect to the origin(0,0), then y=f(x) is odd function

Sorry for my English

[left knoll]

@modest apex

[mystic python]

So then are you saying that if f(x) can be reflected on the x-axis, it will look the same if its even

[bleak drum]

As far as I know, no, it's work only with Y axis

[empty sedge]

f(x)=x^2-1 and g(x)=sqrt(1+x) for what values of x is g(f(x))=x

[left knoll]

somebody could please explain me in the easiast way possible, how do you cauculate a circunference and why do you need the number pi to cauculate it?

[modest apex]

The formula is 2(pi)(r). An example of this would be:

A circle has a radius of 4 cm find it’s circumference using 3.14 as pi

To solve this you simply add each into the brackets

Put the 3.14 where pi is as that is what the question asked.
Put 4 in the r as that is the radius

And put the following into your calculator: 2(3.14)(4)

This is only from the top of my head but from what I can see it’s right

[left knoll]

oh, thank you for the explanation ❤️

[wraith elk]

the ratio of the circumference of any circle to the diameter of that circle. Regardless of the circle's size, this ratio will always equal pi. Hence, it is useful to have shorthand for this ratio of circumference to diameter.

[modest apex]

If you need another explanation for this don’t be afraid to ask another person in the server

[left knoll]

oh that makes sense! thank you

[wraith elk]

Another one- If you have a circle, you can measure two things: the distance around the perimeter of the circle (circumference) and the distance across the widest part of the circle (diameter). No matter how big your circle, the ratio of circumference to diameter is the value of Pi-3.14

[wraith elk]

No worries

[left knoll]

aaaah now its clear

[wraith elk]

Greaatt

[gray tusk]

it might be helpful to think of pi in degrees so pi is 180 degrees, 2*pi would be 360 degrees or a full circle, add radius (r) into the equation and you get the circumference of a circle, the bigger the radius the bigger the circumference, ofc you wouldn't use degrees in the formula therefore the value of 3.14, this is just the way you can think about it if you don't understand what pi is

[edgy crag]

Does anyone know the answer to this and if you do can you explain it to me please

[burnt mirage]

yes my freind

[edgy crag]

Omg thank you where do i start?

[burnt mirage]

whats the question? I cant speak english very good. so i dont really understand what they want

do thes want the area in dependence of x or what is asked?

[edgy crag]

Umm they want to know the polynomial for each dimension for the white rectangle im sorry this is the best i can re word it

[burnt mirage]

thats the area. you can simplify it to a polynom

oh

you mean height and bright?

[edgy crag]

No i mean height and length sorry if i was being confusing

[edgy crag]

Omgggg thank you

[burnt mirage]

wait if your prof wants a "perfect polynomial function": h(x) = -2x + 8 and l(x) = -2x+10

[edgy crag]

Yessss thank you so so so so muchhh i really apreaitate itt :))

[burnt mirage]

np.

america is weird. the problems are a lot easier than in germany.

[edgy crag]

Haha yeah it is a bit wierd but still thank you um if its not too much of a problem can you send the work of how you did it my prof is really strict on that type of stuff

[spare shale]

if anyone here can help me with a math question would legit be soooo helpful and appreciative

struggling hard with this trigonometric graph y=10sin(6x-3)-2

would be nice if i can get help

[graceful dagger]

Would you like to draw the graph, or do something else with the equation. Because if you want to plot it you can just put the equation into a graphing calculator online and it will draw you the graph. Here’s an example of a graphing calculator https://www.desmos.com/calculator.

[spare shale]

yeah but i need to plot it with the pi values

domain range etc

desmos doesnt show that

[graceful dagger]

Oh sorry I’m not sure how to do that good luck with trying to figure it out.

[jaunty aurora]

confused asf for both of these

all values 0<x<2pi

[burnt mirage]

x = 0 or x = 2pi

[burnt mirage]

x = 0 or pi

these should be some answeres, but for 0 < x < 2pi for the cos-problem the answere is just "pi" and for sin there isnt a answer

i think you meant 0 <= x <= 2pi

[burnt mirage]

whats the question?

[spare shale]

just graph y=10sin(6x-3)-2 in domain [-2pi, 2pi]

[burnt mirage]

Ok, and whats should i do with it? Analyze it for Maximum/Minimum. Get Differential? What is specific wanted? Because just "y = ..." isnt a question. I need sth like. "Do.... " or "What are the maximu...?"

Thats the graph

Thats a ploted view of the values of x in [-10; 10]. (open in browser to see it clearer)

[burnt mirage]

Maximum at 8. Minimum at -12.

[spare shale]

I see, thanks alot

[jaunty aurora]

i love my trig teacher lol

[burnt mirage]

you have teacher for every subject of math?

wtf we have "the one" math teacher and thats everything

[jaunty aurora]

what does that mean lol

yes i do

bruh

ur name

[burnt mirage]

yes whats wrong with that?

[jaunty aurora]

its like mine except with sunglasses

[lunar rover]

it is what it is

[ivory heart]

4

[torn torrent]

Help!

[burnt mirage]

a + b = 20

(a - 4) = (b-4 )/2

if you solve that Linear Equationsystem it should be

[burnt mirage]

the 4th answer

[torn torrent]

This one too please

Thanks a lot

[hasty torrent]

Can someone explain this

[burnt mirage]

Is the interest 11% per year?

[torn torrent]

Yes

[burnt mirage]

Sorry i struggle with the english language. what is Rs.?

[torn torrent]

It's okay, I've solved

Three equi-dimensional cubes are joined face to face in a row and are coloured with Blue on all faces. The first cube is cut into 8 equal pieces, middle one into 27 equal pieces and last

into 64 pieces.

How many cubes have three faces coloured?

Please help

A clock is set right at Tuesday 10 a.m. The clock gains 10 min in 24 hours. What will be the correct time on the following Thursday, when the watch indicates 8 p.m.?

[burnt mirage]

should be -1, but i have to youse a calculator for it

so equal

[left knoll]

Easiest way would be with Complex no.s:
Given √3+i
Multiply by i for 90° anticlockwise rotation:
(√3+i) × i = -1+ √3i
Hence Q is (-1,√3)

[hearty sandal]

Hello can someone tell me why the matrice rank is equal to 2

please

[burnt mirage]

Cause you can make the 3rd row out of the Second one

[hearty sandal]

Ohhh thank you !

I see now

[burnt mirage]

If you can make a row out of a combination of the other one (even if you multiply them with a number) this row doesn't count to the rang too

[rain magnet]

https://tenor.com/view/rick-astley-rick-roll-dancing-dance-moves-gif-14097983

[left knoll]

https://tenor.com/view/rick-astley-rick-roll-dancing-dance-moves-gif-14097983

[burnt mirage]

https://tenor.com/view/rick-astley-rick-roll-dancing-dance-moves-gif-14097983

[left knoll]

heyy guys very silly question

but

what is log 2 by 10

pls answer

[inner terrace]

not got a calculator?

if you mean log_2(10) then the answer is 3.32

[left knoll]

noo

not in this way

solve by a^x=N

[inner terrace]

what are you solving for?

[left knoll]

the answer is 1 minus log 5 by 10

but how

[inner terrace]

dont know what youre solving for so cant say

[left knoll]

logarithm

exams

[inner terrace]

https://tenor.com/view/alright-then-kevin-hart-nodding-gif-9852215

[steady ravine]

i think he was asking what was the question

or the problem

[quick violet]

Please , can someone help

[burnt mirage]

maybe x = 3 and y = 3?

[gentle plank]

mb

[quick violet]

I think x = 7/y and substitute this in the upper inequality

[left knoll]

Hey guys!can someone help me with this question please?

[left knoll]

simplyfy tan in sin and cos

sin/cos = tan

[queen flower]

does anyone here have recommendations for self-teaching methods for math?

[queen rover]

lemme give it a try

[left knoll]

Thanks:)

[queen rover]

i'm not sure my guy...

[left knoll]

Omg thank you so much i actually got it🙏🏻🙏🏻

[queen rover]

I object to the validity of this math

[crimson geode]

Apparently the answer is 8. Can someone explain please? The question mark might seem weird but we’re supposed to find the bottom of the triangle

[heavy narwhal]

im in 8th grade

[weary arrow]

a^7/8^2

[latent siren]

((1/8)^2)*a^7

[noble viper]

Can someone show me how to make x the subject for y=e^(x) - e^(-x)

[latent siren]

Do you know hyperbolic trigonometric functions?

[manic tartan]

hey can anyone help me with this problem

[atomic cipher]

do you still need help?

[manic tartan]

yes please

[atomic cipher]

what's the definition of Corr(X, Y)?

[manic tartan]

(x-E(x)) (y-E(y))
var(x)x var(y)

[atomic cipher]

ummm

[manic tartan]

the correlation of two variable

[atomic cipher]

that doesnt' seem right

where did you get that from?

[manic tartan]

what do you mean?

the formula?

[atomic cipher]

yes

[manic tartan]

oh yes it should be the standard deviation at teh denominator

not var

my bad

how do you deal with the condtion <0<x<y<1 in the intergral

[tall pumice]

GUYS GUYS SOMEONE HAVE SYMBLAB ACC ?

[atomic cipher]

you put that as bounds in the integration

Corr(X,Y) = Cov(X,Y)/(sqrt(Var(X)Var(Y))

Var(X) = E(X^2) - E(X)^2

E(X) = integral 0 to 1 integral of 0 to y of (x*(8+xy))dxdy

@manic tartan solve this

[left knoll]

do we have to solve like this btw thanks

[manic tartan]

7/5

[atomic cipher]

i get this

good luck with the rest

also remember Cov(X,Y) = E[XY] - E[X]E[Y]

with that you should be able to do it

[manic tartan]

33/8

i calculate E(XY)= 19/9

[atomic cipher]

show integral

[atomic cipher]

inner integral bounds should be 0 and y

not 0 and 1

[manic tartan]

16/15?

[atomic cipher]

idk i didn't do it

[atomic cipher]

19/18

mistake in 2nd to last line

[manic tartan]

yes thank u very much

[modest ice]

Yall is this right?🥶

[modest ice]

Wait so this means if this is correct we need to go for the subtraction sign first and make it positive for it to be multiplied or divided? I can’t understand what’s going on

[silk quiver]

it's supposed to be -36V

[modest ice]

Right?😭 I got the same ig there must be mistake there

[stray tiger]

Isn't that a phy6s question?

[modest ice]

Yeh but like I was just trynna check the maths over there

[hearty sandal]

Hello can someone explain me why the "e1,e2,e3" equal (0,0,1);(1,0,0)...

[left knoll]

a = ?
b = ?
x = ?
z = ?
y = ? ( x ≠ z ) help?

[thick pine]

That’s the definition of e1 e2 e3

[left knoll]

law of sines : 3

[thick pine]

Yeah law of sines then I guess

[left knoll]

https://i.redd.it/1ykx2o59jt271.png

[left knoll]

can anyone help

[hollow escarp]

Answer is C

[left knoll]

thank you

[hollow escarp]

Is that Shoto on your DP ?

[left knoll]

yeah

[hollow escarp]

Noice

[left knoll]

please help with 3rd problem. use the rules of correct digits, find with two correct digits(translated)

[fervent gulch]

we have to aassume that its raationaal, and prove our assumption wrong, but ive never solved one with 2 roots at once

[random flame]

Hi can someone help me with this? Ping if you do and thanks!!

[fervent gulch]

thanks a lot

[wintry olive]

Im calculating planar motion with integrals, and after finding the value, we have to subtract a certain amount, and im so confused, because the amount keeps changing depending on the integral and i dont see the pattern

Δx

=∫
3
5
​
−12dt
=[−12t]
3
5
​

=−60−(−36)
=−24

i dont understand, why subtract -36?

OHHHHHHHHHHHHHHH

i get it

nvm

lol

[left knoll]

use the rules of correct digits, find with two correct digits a) pi + 7.3 b) cos(0.7) * ln(2)

[potent pewter]

Is this correct? I’m 99% sure it is..

[left knoll]

i have no motivation left to do anything

[latent siren]

It is

[potent pewter]

Thanks man 😁

[wintry olive]

oof

did you really run all the way out?

You could just be burned out, just take a short break for a day

we're all human, and we all need our rest sometimes :)

we're not james, where he can just study 12 hrs a day everyday lol

[potent pewter]

I need help 😭

[latent siren]

Hint: 7 and 3 are congruent

If you find the measure of angle 7, you get the measure of angle 3.

[potent pewter]

Ik

[latent siren]

Similarly, if you find the measure of angle 6, you get the measure of angle 2.

[potent pewter]

So I got

Angle 2 is 53

and angle 3 is 127

[latent siren]

Yep

Nicely done

[potent pewter]

Is that correct

Thanks 😊❤️

[left knoll]

like i can study 12hr a day

if there was a quiet enviroment

unless my parents playing TV out loud and disturbing me every fuvking minute

and if i had a good setup like him

and also if i had someone who can make me a coffee coz my mom doesnt like me studying at night and telling me to do that crazyass yoga

[wintry olive]

lmao

relatable

i study alot, i mean, obviously, im a james scholz viewer, but my family is so god damn loud and annoying asf sometimes

[left knoll]

all the time

[wintry olive]

lmao

[slow hawk]

Hi
Does anyone have good notes for linear algebra?

[cobalt holly]

i can help understanding a problem , but i don't have notes

[copper condor]

guys, I have a problem
does lim f(x) (x tend to 2) exist
if the Domain of "f" is IR\{2} ?

[latent siren]

It depends. Let me elaborate. It is possible for a function that is not defined at, say, 2, to both:

1. Have a limit at 2;
2. Not have a limit at 2.

Example:

Let f(x) = 1/(x-2) then lim x->2 does not exist. This is actually called an essential discontinuity.

Another example:

Let f(x) = (x^2-3x+2)/(x-2), then obviously the domain of f is IR\ {2}, however, upon computing, we will find that the limit of f as x->2 is 1.

So yes, it is possible for a function to have a limit at a point where it is undefined.

[silver bay]

hey! can someone help me solve a quadratic equation by the method of completing squares? I actually didn't understand this method very well, I think it's much simpler by Bhaskara but it's not allowed to use it in this exercise

[hollow escarp]

if you have a specific question , leave it here?

[silver bay]

it's this equation: x^2 - 7x + 12 = 0

I'm just stuck because of this method I guess

[hollow escarp]

its 4 and 3 right ?

[silver bay]

exactly

[hollow escarp]

so , how i usually go about it is , think of it this way .the equation is in the form of ax^2 + bx + c =0 ,

look into b and c

sum of two numbers should come as b and their product must be c

[hollow escarp]

here , b = -7 and c = 12

-4 + -3 = -7

-4 * -3 = 12

[hollow escarp]

so the equation can be written as (x-3) (x-4) = 0

now , if the product of two terms is zero , either one of them or both must be zero

if x-3 = 0 ; x = 3

if x -4 = 0 ; x = 4

[silver bay]

oh yeah, it makes sense

[silver bay]

this is easier than I though lol

[hollow escarp]

there's another method to go about it. I used to use that while answering the exams

which includes splitting the -7x and writing it as -3x - 4x

I used to find that method confusing , so this is a trick i figured out to do it better

[silver bay]

okay this really helped me a lot, thank you so much!!!

[hollow escarp]

this is how I used to solve it for exams .But splitting the coefficient of x always used to confuse me . So first I use the method I mentioned first ( sum is b and product is c ) and find the numbers first and split b accordingly and then write it down as a proper solution form

[hollow escarp]

@silver bay

[open mango]

if f(u) = u^6 and u=x^4 +5, then express 6u^5 x 4X^3 in terms of x alone.

Anyone got any ideas? I've very confused, lol

hmm maybe I substitute the u in 6u^5 with the equation x^4+5

[hollow escarp]

I haven't done this in a very long time , but i think you have to put f(u) = d (denote it with any letter) and then solve it. In this case , d= u^6 and then try to solve . I'm not exactly sure though

[open mango]

Hmmm

Okay now I have 6(x^4+5) x 4x^3

6x^4+30 x 4x^3 ?

seems right

[hollow escarp]

24x^4 +120x^3

[hollow escarp]

i didn't check if it was right btw, i just simplified this

[left knoll]

Counting principle help!!! Doing practice practice problems:

How many 4-digit numbers that are odd can be formed of no digit repeats?

[open mango]

But how can I multiply the 6 and the 4 if the exponential value is different?

Or am I being a complete idiot

... it's been a long day

[hollow escarp]

oh shit

[open mango]

lol?

[hollow escarp]

24 x^7 + 120x^3

x^a * x^b = x^ a+b

[open mango]

Uh like 2240?

[silver bay]

got it! I'm doing the other exercises and they seem easier now. I used to do it by a method but I forgot it, thanks for your help!

[hollow escarp]

No problem

[eager falcon]

6u^5 * 4X^3 = 6(x^4 +5)^5 * 4X^3 = 6(x^4+5)^2 * (x^4+5)^2 * (x^4+5) * 4X^3 i think, then simplifying it furthermore shouldn't be a problem i think

[open mango]

OH YOUR MULTIPLYING

the exponents