math-help

[weak lotus]

2 words

if = +
and = .

your welcome

[prime solar]

Anybody know good material like exam papers for calc 1, 2 ,3. As well as for linear algebra? To use as material to study for exams

[weak lotus]

https://tutorial.math.lamar.edu/

[weak lotus]

for linear algebra i suggest you go trough your notes and watch the series of 3blue1brown

make some p sets and youll be good

[prime solar]

Thank you

[left knoll]

hello guys

I need help with all of it

[thin trellis]

cut all of the figures in 2 common figures

and use all the known formulas so

circle: RxRxPi

rectangle and square: Length x Width

Triangle: (Length x Width) / 2

[thin trellis]

the circles here are in half so dont forget to divide that by 2

and then you combine the seperate answers into a whole

[rugged current]

can anyone explain to me how i should calculate the answer for this: x.f(x)>0

[thin trellis]

Thats hard to say without context, it's most like that you have to prove that the give x.f(x)>0 is true or false with provided info

[rugged current]

well i cant post pictures so... idk

finals week or my final week idk yet

[thin trellis]

oh god good luck

[hardy crown]

u should use microsoft whiteboard i think

[rugged current]

just wrote math paper 1 im cooked idek what to say i studied so hard and they asked ap level shit im dead

[thin trellis]

Ive got exams in a week and tbf I'll probably be going through the same thing so I can imagine what its like, hoping for the best for u

[rugged current]

good luck to you too

[weak lotus]

you need help?

[brittle sleet]

I think they have written the exam

[weak lotus]

Ooooo

Thought it was a practice paper

Mb

[rugged current]

yeah ive already written it, ill just do good in p2 its chill

[dusky cloud]

hello! anyone can explain me please, after i get the critical points of a function a build the hess matrix what does de determinant mean, i mean how can i identify if it is a saddle maximum and minimum point. Thank you! <3

[weak lotus]

its not that difficult

let me explain

you have to look at the sign of your hessian matrix

i hope you know how to make one

thats the most difficult thing about it xp

like actually calculating the derivatives in a good way

lets call our hessian matrix H
we have 3 cases:
case 1:
H < 0 our function has a saddle point for (x_0;y_0)
case 2:
H = 0: we do not have enough information about our function
case 3 (i call it the special case):
its where you have to do another "test" called the second order derivative test
lets say we are looking at saddle point or maximum for our function f in a point (x_0,y_0)
what we can do is pick any 2nd order derivative. The easiest is if you take your partial derivative with respect to x, 2 times, or with respect to y, 2 times
(partial of f)^2/(partial with respect to x or y)(x_0;y_0) > 0 then we have a local maximum
(partial of f)^2/(partial with respect to x or y)(x_0;y_0) < 0 then we have a local minimum

[rain solstice]

can someone solve this lim +00 and lim -00

note you are not allowed to calculate directly since we didn't study about lim when x is into the power back then

this was my hs final exam and I'm in college can't solve it with what we had only back in hs

[weak lotus]

been a long time since i did one like these but i think you have to use the the special limit of e

but not 100% sure

[rugged current]

does anyone know where i can find some Euclidian geometry practice questions online?

[weak lotus]

https://www.mathcentre.ac.uk/resources/uploaded/euclidean-geometry-october-final.pdf

[cosmic kestrel]

Can you use Taylor series?

[rain solstice]

nope

just non advanced things taught in college this is from hs

my best bet is to change the variable from x/2 to lets say t and calculate f(t)

[weak lotus]

use approximation

@rain solstice

mathematicians would kill me

but|| fuck|| it right?

[left knoll]

Nice keyboard

[brittle sleet]

What do I have to do to send images?

[weak lotus]

click on the left when you want to type a message

there is +

[brittle sleet]

yh but there's no option to upload files

[weak lotus]

the first option

"upload a file"

[brittle sleet]

Not showing for me

But it appears for other servers

[weak lotus]

hmm

what do you need help with?

maybe sent me a dm

[brittle sleet]

will do that now

[blissful ridge]

i am doing analysis 2 in my uni and there we need to draw some graphs but i have never learnd how to do so... Can someone give me tips on how to draw graphs?

[atomic spindle]

does anyone know why tau is wp is positive here? isn't the pole the zero denominator and shouldnt it be negative 1/tau? or is it because of the symmetry in the bode plot that the negative pole also causes a pole on the right side?

[atomic spindle]

ngl i just always used my ti-84

[blissful ridge]

we cant use those

we need to do everything by hand otherwise i wont bother asking

[weak lotus]

belgiummmmm

hahhaha

[weak lotus]

why would you want to know the graph of these?

first 2 are just subs

so is the 3rd one

same for the 4th one, 5th one is just rewriting the bottom half

last one is partial integration

[atomic spindle]

manneekeeeee

[weak lotus]

welk vak eje

[atomic spindle]

systeemtheorie

[weak lotus]

burgie?

[atomic spindle]

nee industrieel 😢

[weak lotus]

zou u graag willen helpen ma heb de fysica er nog niet achter gezien, heb dat vak ook niet

sorrey

[atomic spindle]

geen probleem

nog veel succes met de blok

[weak lotus]

gij ook! nog effkes 😄

[atomic spindle]

wa studeer jij?

[weak lotus]

fysica en sterrenkunde

[atomic spindle]

noem nu alle deeltjes van de standard model of particle physics 🔫

[weak lotus]

zit daar nog niet hahaha

[left knoll]

Ask the mods for image perm

[brittle sleet]

Alrighty

[languid olive]

is anyone currently studying further maths in their a levels?

im gonna finish my igcses soon and need to decide on my subjects asap

its rlly difficult finding a further math teacher whos both good at teaching and has an affordable rate, plus i wanna et good rades so if FM takes up too much of my time the oppurtunity cost is gonna be too high

any advice?

i took additional mathematics

and usually get 93-96% on mock tests

ill know my igcse results in august so idk ig pure maths should be easy for me

and im aiming to finish phy and chem as much as possible during the summer

so i can put full focus on FM if i do end up taking it

idk if this even qualifies for math help in the first place but i thought id just ask in case

[weak lotus]

to be fair yh, tom rocks maths is really good

he has an app or site where he explains all kinds of topics

if your tutor is shit, just use him

[candid rivet]

Solve 3^m=8+n^2 for (n,m) two integers
my guess is that only (2,1) is solution
i tried to look mod 2, mod 4, mod 8 but idk

[weak lotus]

dont forget (-1,2)

[candid rivet]

yes obviously but i'm only looking for m and n positive integers

i manage to prove that m has to be even, and n has to be odd

[simple storm]

bro i need glasses fr

lol

[weak lotus]

tried for mod(3) ?

[brittle sleet]

Who can decompose this into partial fractions pls? x⁴ + 3x - 2 / (x² + 1)³(x - 4)²

Can't share images sorry

[rugged current]

can anyone explain to me how this: 3(1+2sinxcosx) changes to this 3(sin^2x+2sinxcosx+cos^2x)

oh wait

nvm

[terse meadow]

1 = cos^2 + sin ^ 2

[rugged current]

did you see the 'nvm'

[candid rivet]

no I don't think so, it's hard to predict the value of a determinant since the true definition is a sum over the permutation of different products

[limpid scaffold]

guys can someone explain how do u do this with Lagrange theorem
xy-->extr, x^2+y^2=1

[limpid scaffold]

Oh nvm i got it

[fringe galleon]

does anyone know how to solve for x?

i have unlimited tries for this task so i put in a random number to see what the answer would be and it said it’s 8.5*

i want to know the process for solving it so i can get it right on the next try

[haughty monolith]

I ROUNDOFFED THE VALUE OF TAN16

[fiery bough]

Hey

Does anyone have past papers or questions to practise for maths 1A

With the memo/answers

[haughty monolith]

Which country you from @fiery bough

[fringe galleon]

thank you!! i did tan32x25 - tan16x25 and got 8.5 (rounded to 1 d.p.) and i tried it with another similar question and it worked

[haughty monolith]

SOMEBODY ANSWERED to me🫣
THIS LIFE IS NOW WORTH LIVING

[fringe galleon]

hahaha it’s always worth living, thanks again 🙌

[wispy pendant]

Hello

Anyone know what s the property of a tridiagonal matrix

[fiery bough]

Sour Africa

[rugged current]

South Africa?

[fiery bough]

yeah

south africa

so does anyone have any resources

by any chance

for maths 1a engineering/computer science

[candid rivet]

you should be able to find a recusive relationship, especially if each diagonal is constant,
if you say d_n is the determinant of the matrix of size n, then by developping the matrix with the first line/colum (and do it twice) you should get a relation between d_n , d_(n-1) and d_(n-2) which you should be able to solve

[rugged current]

yo cool, im also from here, still in hs tho

[fiery bough]

hs?

ohh high school

yeah im in first year uni

finished last year

[rugged current]

oh ok cool im in 11th grade

[weak lotus]

just draw

really

[fiery bough]

Cool

[silver pier]

can someone explain the last 2 line in green

[weak lotus]

@silver pier

[fickle swallow]

It didnt work

[weak lotus]

is it with integrals?

i asume it is

i have 16pi

for the volume enclosed

[fickle swallow]

Yes

[fickle swallow]

Ohhh true

[fickle swallow]

Thank u sm

[little mica]

KqQ are constants so they are taken out of the integral which leaves us with itegral of 1/r² which is -1/r

The limits for the integral is from Infinity to R so after inserting the values you get U = kqQ/r

[civic osprey]

nice pen

[weak lotus]

Hahaha ty man

[winged sinew]

"jo listen to my rap
"let me rap
"hey
yeh
hey
i want to say
yes
um
girl
i just wanna rap
for this
to you
and your body
on the cluth on snow
body on the temperature
on your fresh level
i cant think but think
love is different way
but i just wanna be your babie
wanna be 1 2 3
wanna be my prohercy
or you just need the way you end
cause i found you
the level of concern
you can find but you never heard
you bring my heart
the level of concern
i teach you tell me what alright
tell me that you okay"

for anyone who read this, and understand this masterpiece, you guys deserve a good grade in math

[lean barn]

Thank you

[thin radish]

Hello, could someone check over this example for me ? I'm having trouble understanding how the second case for the angle B was solved, I think there's a calculation error

[weak lotus]

the other way has to do with angle inequalities

[thin radish]

I understand this bit, but there's the second configuration of the triangle, is there a different process to solve for the second configuration ?

[thin radish]

Could you show me, please ?

[sterile dune]

Hello
Does anyone have a solutions manual for A Transition To Advanced Mathematics 7th edition

[lament terrace]

Don't know if i should ask that here or on #tech-related-help but we learnt hash maps in school like this:

int ShiftedSum(string text) {
  unchecked
  {
    int code=17;
    for(int i=0; i<text.Length; i++)
    code = code*31 + (int)text[i];
    return code;
    }
  }

int Hash(int hashValue, int length) {
  int index = hashValue % length;
  if (index<0)
    index = -index;
    return index;
  }

a hashmap is a key value pair so and let's assume we allocate an array with the size of (number of assumed elements) * 2

the multiplicator of shiftedSum is 31 because it is an odd prime which (i don't know why) leads to less collisions and the expression
31 * n = (1<<5)-n
since 31 = 2^n - 1

Now what happens if i do this:

uint ShiftedSum(string text) {
  unchecked
  {
    uint code=17;
    for(uint i=0; i<text.Length; i++)
    code = code*127 + (uint)text[i];
    return code;
    }
  }

uint Hash(uint hashValue, uint length) {
  uint index = hashValue % length;
  if (index<0)
    index = -index;
    return index;
  }

I've made two changes:

1. changed everything to uint so we have no negatives but only postive numbers but it takes twice as long to cause a overflow where you start at (largest possible number)x(-1)
2. changed the multiplicator to 127 this means that the there should be more spread between the numbers and still you can optimize to (1 << 7) - n

My question now:
how do i get the probability of a collision (Hash(ShiftedSum(string))
where the parameters that change in the math expression/equation would be

• size of integer (if it's a uint it's just the size of an integer*2) - depends on CPU architecture
• size of the multiplicator like 127 or 31
• size of of possible elements we will insert (N)
• size of Hashtable (let's assume M=N*2)

[weak lotus]

https://quizlet.com/explanations/textbook-solutions/a-transition-to-advanced-mathematics-7th-edition-9780495562023

https://www.scribd.com/document/696896625/Solution-Manual-for-a-Transition-to-Advanced-Mathematics-7th-Edition

internet is a wonderfull place to find things yk xp

[weak lotus]

imma be dead honest

i have no clue where the second configuration is

im being mad blind rn

[sterile dune]

@weak lotus thanks, but looking for a pdf file

[weak lotus]

you can download the last link no?

https://www.chegg.com/homework-help/a-transition-to-advanced-mathematics-7th-edition-solutions-9781133007456

you can also try this

pretty handy with quick acces to different chapters

[sterile dune]

@weak lotus thank you

[weak lotus]

more then welcome!

[civic osprey]

sick pens

[weak lotus]

Eyyyy

You got the other combination

And greek aswell

Love the handwriting!!!

[civic osprey]

haha thanks

Sometimes I think about how much harder math would be if I wasn't Greek

[weak lotus]

Because of the symbols? xp

[civic osprey]

yes

[thin radish]

Me too 💀 Even the slightest bit of trigonometry messes me up

[weak lotus]

tbh

just make sure you know how those 2 rules work

youll be just fine

and make sure you 10000% understand the trig circle

youll be chilling for you final

[thin radish]

Actually I'm just reviewing some basics, not studying for anything right now other than leisurely for myself

And I did get those parts, so I think I'm good

[weak lotus]

i suggest getting into circles to

[weak lotus]

in combination with triangles

always fun questions to do

and trig in general

[thin radish]

I'll try to look into them more, I don't know much about them

Thank you very much !

[left knoll]

@left knoll

lmao

[left knoll]

STUDY

[left knoll]

okay bro chill just wanted you to see this cool rap zomtives made

[civic osprey]

yo can anyone help me with this question?

[civic osprey]

nvm I solved it

[lean barn]

Was ez innit

[teal moon]

The Boolean expression ((p∧q)∨(p∨~q))∧(~p∧~q) is equivalent to

[weak lotus]

¬p∧¬q

not p and not q

[wispy pendant]

Guys

Between these 2 steps

Did they do a +1

If yes why ?

If no

Where did the -1 went

[candid rivet]

on prend n le plus petit entier qui est supérieur au truc encadré (que j'appelle A), et c'est en fait prendre la partie entière de (A+1)

si tu prenais la partie entière de A et que A valait par exemple 2,3 alors t'aurais n=E(2,3)=2 ce qui ne convient pas

d'où le +1

[wispy pendant]

Donc le +1 c est annulé avec le -1 de A ?

[candid rivet]

oui !

[wispy pendant]

Merci bcp

Je ne savais pas que y avais des gens qui parlaient fr dans le serv

C est cool

[candid rivet]

de rien bg

[limpid crane]

anyone?

[candid rivet]

What i usually do when there's a floor function is to write the inequality x-1 < [x] <= x or to rewrite x=y+z with y an integer and z between 0 and 1
also be careful when you're looking a the floor function of a negative number

[limpid crane]

thanks man

[left knoll]

<@&942391219206647828>
I was asked to ping once earlier few months back but it's still here

[clear beacon]

Hello, how do you study for math exams?
I reflect on my study method: I list through all definitions and theorems (after each topic I actively recall everything), simultaneously do some practice. After I learn everything, I go over everyone once again - applying active recall. But I feel it doesn’t give me the best grades.
When I want to start studying a week prior to exam, I always end up studying intensely in the last 3 days.

[lean barn]

I always practice more and more and more questions
Because there can be various types and methods to solve a single question
When you do all of them and more
The exam day when u see the question
All of this pops up and you might figure out the easiest way to do it
Unlimited questions and then recall a day prior
That's it!

[pastel pecan]

and approach with mindset of experimenting

[winged sinew]

@left knoll

listen to my rap

"jo listen to my rap
"let me rap
"hey
yeh
hey
i want to say
yes
um
girl
i just wanna rap
for this
to you
and your body
on the cluth on snow
body on the temperature
on your fresh level
i cant think but think
love is different way
but i just wanna be your babie
wanna be 1 2 3
wanna be my prohercy
or you just need the way you end
cause i found you
the level of concern
you can find but you never heard
you bring my heart
the level of concern
i teach you tell me what alright
tell me that you okay"
Zomtives — 06/06/2024 7:10 PM
"jo listen to my rap
"let me rap
"hey
yeh
hey
i want to say
yes
um
girl
i just wanna rap
for this
to you
and your body
on the cluth on snow
body on the temperature
on your fresh level
i cant think but think
love is different way
but i just wanna be your babie
wanna be 1 2 3
wanna be my prohercy
or you just need the way you end
cause i found you
the level of concern
you can find but you never heard
you bring my heart
the level of concern
i teach you tell me what alright
tell me that you okay"

@left knoll rate my rap ❤️

[spark spire]

can anyone help me find the domain for this function?

g(t)=sqrt(4-7t)

[left knoll]

I don’t care

[lean barn]

Anything underroot cannot be zero

So put it and try

[plucky sedge]

Can someone help me with the topology of ricci flow

[weak lotus]

you forgot something 😄

if you work in IR everything under root has to bigger then 0

if you work in CI everything has to be different then 0 but it can be smaller then zero, where you use that i^2 = -1

[lean barn]

I thought I would be applicable

😓

Anyways you got ur solution

[weak lotus]

nah you did great dw

we just dont know the field he is working in

[somber flare]

Uhh can anyone tell me how do you find the value of theta in tan theta ^ -1 ( 1/2)

Without using calc 😭

[unborn creek]

umm what

[lean barn]

So your asking tan inverse (1/2)

So actually you cant

[somber flare]

Uhhh yeah

I am asking for tan inverse

But ig we can do an approximation using taylor series

[lean barn]

True but that takes it lengthy unless u got a trick

[unborn creek]

https://math.stackexchange.com/questions/128514/solving-the-arctan-of-an-angle-radians-by-hand

good stepping point

[lean barn]

@unborn creek Arigato sensei

[unborn creek]

np

[stoic kraken]

heyy guyss, I have f(x)=7x^5-5x^7, how many solutions have the equations if f(x)=1? the correct answer is 3 but how can I solve this problem?

[candid rivet]

Most of the time if we ask you what's the number of solutions to an equation the method is to calculate f' to know when f is increasing or decreasing to get the "graph" of f

and it only works if f is continuous (since it actually is the intermediate value theorem when f is monotonic)

[stoic kraken]

wooww thank you so much, last question, why did you choose as a x -1 and 1?

[candid rivet]

these are the points where f' goes from <0 to >0 (or the contrary). It comes from the factor (1-x^2)

[stoic kraken]

ah okok right! thank you so much again ❤️

[candid rivet]

You're welcome !! (:

[sick sedge]

does anybody have the quizlet solutions to introduction to linear algebra by gilbert strang 5th edition they used to be free but now they are locked behind a paywall.

[lean barn]

Mind if I hack n try

[sick sedge]

please i already tried a plugin to bypass it but it wouldnt work for me

but im not very experienced with bypassing paywalls so maybe u will have more luck

[lean barn]

U want it from Quizlet site itself?@sick sedge

[sick sedge]

yes i can dm u the link

if u want

[lean barn]

Yes please

[sick sedge]

i dmd it to u

[weak lotus]

https://math.mit.edu/~gs/linearalgebra/ila5/ila5sols.pdf

your welcome

[sick sedge]

Thanks but I already found this but for the harder questions it just gives the answer and doesn’t show each step. The quizlet solutions provide step by step answers

That’s why I’m trying to get access to the quizlet ones

[weak lotus]

oh shit my bad

[sick sedge]

No worries thanks for the effort

[left knoll]

can someone explain local maximum and minimum values to me?

[remote terrace]

Can someone solve the 5th question please 🙏

[silver pier]

how do i solve a?

[silver pier]

imagine y=x^2 function plotted on a graph, you can input infinite values of x and get infinite output values of y

but y=0 is the least value you can get

so this is the local minimum

now imagine

here you are getting infinite negative values and infinite positive values

you can not quantify the maximum and minimum values of the function

but look at the peak

the value at the middle of the peak, is the local maximum

and 0 is the local minimum

we use local because its not the maximum\minimum value of the function

[left knoll]

OHHH

OMG I GOTTT ITT

TYSMMMM

[silver pier]

welcs

[brittle sleet]

I assumed that the muzzle is a cylinder with a base area of 0.00016m² so the volume of the cylinder is the base area * height. Since density = mass / volume the mass = density*volume, so the height of the muzzle is 150m from the velocity hence volume is 0.00016m² * 150m === 0.024m³. The mass is then = 0.8kgm^-3 * 0.024m³ which is 0.0192kg OR to relate to velocity 0.0192kg per second.

[solar mesa]

isnt 0 the global minima in y=x^2

[silver pier]

Wasnt aware of the term

[silver pier]

Thanks

[sharp stag]

The complex no. Z satisfies
|z-25/z | =24 . The maximum distance from origin is?

[weak lotus]

from what i see

dont have much time to write it out

you use that one formula where you represent a complex number by r.e^(i.theita)

which is ofc equal to z

you fill that into your given equation

you should rewrite a bit

you pop some magnitudes

rewrite using (cos(theita)^2 + sin(theita)^2 = 1

dont forget to rewrite in a way where you have a + ib

you should get an quadratic equation

solve for r

and get 12 + sqrt(119)

made some scratch notes so not really usefull

[sharp stag]

Yeah I thought I'd use the inequality tho, instead of the eulers form

[weak lotus]

tbf its kinda a shit question

[sharp stag]

|z-z1 | > |z1| - |z2|

[weak lotus]

also an option

but youll get there with euler to

[sharp stag]

Cause we technically have the maximise |z|

[weak lotus]

what ever you prefer

[sharp stag]

I cant thats the problem 😕

[loud storm]

can someone help me

[timid delta]

x of M = avg of x of both points, same for Y

just solve the eqn and find the x and y coordinates for u respectively

[left knoll]

can anyone please help me??

[celest hatch]

New no of toys of deb = x-3
Initial no of toys of Ananya = 20 - x
New no of toys of Ananya = 20-x-4=16-x

(16-x)(x-3) =42

[left knoll]

got it thanks!!

✨

[left knoll]

@celest hatch sorry for the ping but can you explain this one too?

[cosmic kestrel]

the slope is equal to derivative of function or 12x+10 or in point (x=2) it's equal 12*2+10=34

[left knoll]

thanks!!

[loud storm]

guys

how is this wrong

im confused lol

[timber raven]

@loud storm maybe AD and BA are oppositely directed vector?

the angle should be 180*

[loud storm]

ty

is this right @timber raven

[left knoll]

can someone explain please?

[whole spire]

Can somebody help me to identify that why in the 4th part of question 5 the relation is transitive

[celest hatch]

Slope of h(x) is -2x/125
-2x/125 = -0.64
x=40

Height of players head = h(40) = 7.2 feet

Now min value of x^2 is 0 hence putting x=0 we will get max height of ball which is 20 feet

[celest hatch]

The only two soln possible are (2,2) and (6,1)
I am not sure about this but if the answer is given to be transitive then
Definition of transitive is if (a,b) and (b,c) satisfy the relation then (a,c) also should satisfy it
But in this case there are pairs satisfying in the form of (a,b) with b =1,2 but there are no pair of soln in the form (b,c) hence there is no need for a (a,c) pair to be there

[whole spire]

So is it transitive or not

If it's not which I think is the case the book is wrong

[celest hatch]

I think it might be

[left knoll]

still didnt get it how u did it 🥲

[celest hatch]

I’ll write h(x) as hx for convenience
The given equation of hx is the relation between the height of the ball and the horizontal distance it has travelled if you differentiate it with respect to x you get its slope which is
Slope = -2x/125 let this be eqn 1
Now the player heads the ball when the slope is -0.64 if you put slope=-0.64 in eqn 1 you will get a equation for x and solve it to find x =40 feet

Now if you put this value of x in hx you will get the height of the ball at the horizontal distance x
Now for the player to be able to hit the ball with his head the height of head and ball should be equal
So the height of ball= height of the head of the player which is equal to
hx at x = 40
h(40) = -((40)^2)/125 +20 = 7.2 feet

Hope that helps

[timber raven]

ye!
11,5 - 2 = 9,5

[left knoll]

it did, thanks!! ☺️

[past thunder]

Can someone explain to me how does F distribution come from

[loud storm]

can anyone help me

[past thunder]

I may

[celest hatch]

Could you elaborate on what’s F distribution?

Do you mean to say dividing a vector into components?

[loud storm]

I need help

[shell pasture]

thats the error right

it seems pretty right to me the only thing i could think of was AM being perpendicular to BD

[shell pasture]

aintnoway bros hoppin on the rd sharma

[whole spire]

I understand it now

In transitive u need the pair a,b but if the pair b,c is not there then it automatically becomes transitive

That's some property idk

[shell pasture]

i dont fw relations a lot

if you need help in domain range

questions

im pretty decent at those

[whole spire]

Ohh alr mate 😎

[spark spire]

Hey I know this is kind of a too late situation.
but i have a test on maths on Tuesday on Vector calculus & Laplace transforms
and another one on jul 18 on Ordinary differential equations, Laplace transforms and vector calculus.
I have minimal understanding in calculus. How can i catch up quickly to pass the tests?

Should i watch crash courses on YT from Calculus 1 to multivariable calculus?
Or
if anyone experiences in this can provide some essential fundamentals that i need to study to be able to understand the topics for the test.

Any help is much appreciated!

[brittle sleet]

Watch crash courses and solve as many questions as possible before Tuesday. Solving questions will actually help a lot. Goodluck.

[zenith quest]

PRE UNIVESITY EXAMS

[zenith quest]

CF, PI , Lapalce transformation , complex integral , :>

[spark spire]

Could you maybe elaborate a bit please?

[zenith quest]

complementary function , and its also include change of independent variable, homogenous function , variation of parameter, etc

[zenith quest]

talking about lapalce transformation is easy beacuse u just need to learn formula of ao,an,bn and integrate it to get the answer

[spark spire]

So, what I'm getting from you is laplace transforms are easier to get started on, right?

[zenith quest]

i mean yeah if you know integration very well then it is

[spark spire]

Unfortunately I don't
Any crash courses or quick way to catch up that you can recommend?

[zenith quest]

are you from india?

[spark spire]

Yes

[zenith quest]

ok then search dr.gajendra purohit sir he is good teacher about maths

[loud storm]

Guys

[shell pasture]

yes

[zenith quest]

does anyone know fourier series ?

[hot pilot]

i do

[main hill]

Hii

[zenith quest]

do you know how to identify odd and even function in fourier series

[pastel pecan]

even
f(-x)=f(x)
contains only cosine
odd
f(-x)=-f(x)
contains only sine

[merry comet]

just remember cosine and secant. cos(-theta)= cos theta, sec(-theta)= sec theta. The rest follow that f(-x)=-f(x)

[fleet raven]

Anybody know how to easily write in Latex in Anki and Obsidian?

I downloaded a gitbuh code which is an Obsidian plug-in for converting text to Latex.
How do I enable this in Obsidian or attach this code to Obsidian.
I haven't used GitHub before.
Kindly help.

[unborn creek]

I think for Anki you have MathJax

For obsidian, I thought it already supported latex without plug-ins.

Did you use community plug-ins, if so then go to settings, look for the plug-in, and enable it

[gleaming tundra]

Hi there!

I need some suggestions

I love maths, I understand the theories but not able to solve Harder problems.

[hot pilot]

i dont know the answer but im sure if you ask chatgpt it will answer it. its good at answering tech related questions. or any type of question in general.

dont be shy to explain your specific details about the problem

[fleet raven]

Well it's hard to type in Latex...therefore I was looking for a plug in which allows text to Latex or reduces the amount of code required.

I had found that GitHub code for that purpose.

[sinful narwhal]

start with the most basic exercises and gradually increase the difficulty. knowing the theory is never enough when it comes to mathematics. you always have to practice all possible types of exercises. so start with the simplest exercises before looking for something more complex

[pearl gazelle]

Hi everyone. ¿Could someone recommend abstract algebra books for pures mathematics level? I've really been look for a lot books but none of them have the structure I like, like Bartle's analysis book, with the definitions, theorems and proofs well marked.

[west raptor]

Can anyone help on geometry

[tranquil sapphire]

Two aluminum sheets have a separation of 1.20 mm, one
capacitance of 9.70 pF and a charge of 13.0 V. a) Calculate the su
plate surface, b) Now the separation is reduced by 0.10 mm
keeping the load constant. Find the new train
Inc. c) How much is the potential difference altered? Explain of
How could a microphone be built using this?
principle?, somewhre, could me help, with the C?, is the last question I try but dont know, how to do it, es the exercise 30-6 from resnick

[torpid pivot]

please help idk how to square root with variables ??

i have never felt dumber in my life

[earnest heron]

square both sides and you will have a quadratic equation

solve it and you will get 2 roots

1 will be negative and 1 positive

we use the positive since a negative length is not possible

[unborn creek]

It's d

Do l'hopital

[candid rivet]

you mean (a) ?

[unborn creek]

how so?

[unborn creek]

it wouldn't be as you reach 0, would give 0/0 which would benefit from l'hopital which happens twice more to then get to 1/0 which doesn't exist

[candid rivet]

but with higher maths knowledge you know that cos(x) ~ 1-x²/2 and so you get sqrt(2)

[untold folio]

It's d saotajan

[unborn creek]

where did you get that number

[candid rivet]

well check on wolframaplha but it is sqrt(2)

[untold folio]

mmh

Actually I just did Hospital 3 times and it doesn't work

u get 1/1/0

[candid rivet]

taylor series of cosine

yep bit i think hospital does not alwayss work

*but

[untold folio]

how are we supposed to do this one then?

[unborn creek]

but that's an approx

as the taylor series of cos(x) is 0

the one I saw is that cos(x) = 1-2sin^2(x/2)

[candid rivet]

more or less, the propoer way to do it is to say cos(x)= 1 - x²/2 +o(x²) where o(x²) is a function that goes to 0 when divided by x² (and for x->0)

[unborn creek]

this is one where you might want to use Right hand limits, i think

[untold folio]

this limit doesn't exist

[candid rivet]

no idea if you don't know what i use
i thought about seeing this limit as 1/f'(0) but you still get the same problem when you try to calculate f'(0)

[unborn creek]

can show your proof

[untold folio]

The limit from 0- and 0+ isn't the same so the limit doesn't exist

[candid rivet]

oh yeah if we're talking about the real limit and not the limit for x>0 then yeah you're right

[unborn creek]

if it's lim of x -> 0+ than probably sqrt(2)

[untold folio]

we're looking for the limit -> 0 of this f(x)

[unborn creek]

but it doesn't align when you consider lim of x->0- as shown by liam on desmos

[candid rivet]

well in france we call this "equivalent"

[unborn creek]

not for the cos, but for the whole question

[untold folio]

La limite à gauche et à droite est différente donc la limite existe pas, c'est une des premières propriété qu'on apprend

[unborn creek]

hmm

oh man, now i can't understnad

[candid rivet]

ah t'es francais 😂

[untold folio]

Belge

[untold folio]

Nah I was just explaining the limit from this f(x)

But no idea how to solve this one without the graph

[candid rivet]

oui si tu parles de limite a gauche a droite effectivement ca nexiste pas, mais sinon t'as les equivalents (avec les petit et grands o et ~) qui donne bien sqrt(2) en x>0

cours de prépa ou L1

[untold folio]

tu parles seulement en R+ sauf que là il demande la limite en 0 tout court

[naive dew]

The answer is root2 this way but

The solution shows d

But in the exact reciprocal question the answer is 1/√2. That's why I'm confused

[unborn creek]

the inverse of the function is different can't be expected to share the same qualities

[candid rivet]

sqrt( sin(x/2)^2 ) = | sin(x/2) | (the absolute value), and so actually it depends of the sign of x
if x>0 then you get +sqrt(2)
if x<0 then you get -sqrt(2)
thus, the limit at 0 does not exist
Yet the question seems to calculate the limit for x -> 0+

[west salmon]

hi. i am not allowed to send images here so sorry about that, but im trying to solve a problem asking when the tangent line for y = x^(1/x) is horizontal. I got the derivative of y is equal to (ln(x)-1)/(x^2) * x^(1/x), but im not sure how to prove that it can equal 0. any ideas on how i can progress here?

[left knoll]

You can send pics now ig

[candid rivet]

x^(1/x) is only defined for x>0 (since it is actually =exp(ln(x)/x)
In your question we want to know for what x does its derivative equals 0.
x^2 and x^(1/x) are both always different than 0, so we want the term (ln(x)-1) to be equal to 0, so x=e

[loud storm]

help

help

[candid rivet]

because of the angles you should have that the lengths are equal, so
3x-5 = y +12 = 5y -4,
5y-4=y+12 implies y=4
thus,

3x-5=y+12, x=21/3=7

[loud storm]

THANKS SO MUCH

im confused on this one too

[loud storm]

why did u put everything equal to eachother

[candid rivet]

it is because of the angles. We have an isocele and an equilateral triangle and for those we have some equalities with the sides (look it up on internet if not clear)

[loud storm]

thx so much

i dont get ur work babe wtf

[earnest heron]

this should be easier to understand

[delicate tree]

why can't i upload an image?

In this number series
∑(n=0)^∞▒1/(n^2-3n+4)
A) Prove it's a convergent series
B) Find the upper limit (b) and lower limit (a) in the form of
a≤∑(n=0)^∞▒1/(n^2-3n+4)≤b
C) Find the minimum length of ⟦a,b⟧ numeric range
D) Can the exact answer of this number series be found? (like ∑_(n=1)^∞▒1/n^2 =π^2/6) explain.

any idea on this? (sorry if its translated poorly i had to translate the question and I'm not the best english translator as you can see)

[loud storm]

thanks!!

[forest trail]

Is it possible to formulate a multivariable function from two polynomials

something like that

[candid rivet]

yes i think if f(x)=ax² and g(y)=by², then you can create the function h(x,y)=ax²+by²

[untold folio]

u can also use a circle to prove that y+12 = 5y -4

[untold folio]

only possible in Oxyz then?

[candid rivet]

Well it depends on what you want to do, but here you wanted to create a function that takes two real number x and y and gives a real number, so yeah Oxyz

[near garden]

Hello

3 , 9 , 21

Can you tell me the formula of this pattern?

[celest hatch]

n th term can be written as
3x^2 -3x +3

[pearl gazelle]

Hello everyone! ¿Could someone help me with this exercise?
If H is a subgroup of G and [G:H]=2, prove that H is a normal group of G.

It's excercise of the book ''An introduction to the theory of groups - Joseph J. Rotman''

[candid moth]

Parse error
On line 1 at position 7

a+b+c = 0
      ^

[mystic thunder]

how

[magic badge]

How could I get a handwriting like yours 🥹

[mystic thunder]

PLSSS EVERYONE SAYS IRS DISGUSTING 😭😭😭

THABK U SM U MADE MT DAY

idk man i just write like that

with weirdass grip

[magic badge]

I would die for a handwriting like that

Honestly

[mystic thunder]

stoo im flattered 🥺

https://tenor.com/view/happy-cat-gif-26283306

[past panther]

Is it 👀 ? I thought it was very slanting kind of hard to read that way

[magic badge]

Well to me it looks nice

I like it

[mystic thunder]

it's true

[halcyon vapor]

what part ?

[mystic thunder]

No like where did the graph come from

[halcyon vapor]

just take some random points and plot them

[mystic thunder]

ohohou

aight bet

[potent oriole]

Hello please i dont know how to deal with substitution in limits with the right or left helpp please

[lean barn]

Is the question x+√x²+x??

@potent oriole

[potent oriole]

X+sqrt(x²+x) @lean barn

[lean barn]

U know X and x mean a whole diff thing right??
If they are diff then whose limit is tending to zero?

If they are not diff
Then it's simply zero my friend

[potent oriole]

Sorry it's just the keyboard i meant x+sqrt(x²+x)

[potent oriole]

Yeah but it depends if it's 0+ or 0- to know if it's +-♾ with -2 on top or am i wrong please

[mighty matrix]

Any calculus expert here? I need some help.

[graceful harness]

what is your question

[potent oriole]

🙏

[mighty matrix]

i need some work to be reviewed.

[lone heart]

How can I compute a test-value without the sample standard deviation (s)?

$$t = \frac{(\bar{X} - \mu)}{(s/\sqrt{n})}$$

[delicate tree]

first one doesn't have an answer because there will be a negative number under square root
and second one is infinity because the denominator is almost zero

[brisk holly]

anyone can help me with this. It in linear algebra so i'd ask in this channel. ( appreciate solving in linear algebra way :33 )

in physic way is also fine

[potent oriole]

Thank you sm for the help. Can i ask u if it's gonna be +or- infinity

[potent oriole]

Can u explain 🙏

[delicate tree]

yes. it's a bit advanced. the diagram for sqrt((x^2)+x) near zero has steeper slope than diagram for x near zero. therefore x-sqrt((x^2)+x) has a negative amount. so the whole fraction is a negative real number on a negative limit zero which is positive infinity

[delicate tree]

Its A 3.68
Just go from C to A from three differerent ways and calculate the electric potential difference
-2 I1 -10 = -5 I2 = -4 I3 +10
I1 +I2 +I3 = 0
I1 is the current running through R1
I2 is the same for R2
I3 is the same for R3
Then solve for i1

[potent oriole]

Thank you as much as where it tends 🙏🙏🙏🙏

[forest trail]

Does anybody know how to make a visualisation of a double integral over non-rectangular regions

[weak lotus]

yeah

you need help?

is trivial for the rest, you are just projecting a 3D figure onto a 2D plane

thats about it

x and y-axis, and the z-axis is f(x,y)

if you go to triple integrals you actually need a forth dimension but we kinda neglect it

x,y,z axis and youd need another one for f(x,y,z)

have fun!

[loud storm]

hi

i dont understand'

@sweet bridge

[candid rivet]

Thale's theorem (or intercept theorem, depends how you name it), but it needs the 6 and x lines to be parallel

[grizzled gorge]

Not an expert at all, but I think this could be it

[supple yoke]

Hi! I have no idea how to solve this question. Please help!!

[weak lotus]

Find the roots

fill it in

done

😅

use the method of horner

[supple yoke]

Hey so we haven't been taught horner method but I checked it online and they are usually specifying the value of x we should take to solve the polynomial. Here we aren't given any value of x though

[weak lotus]

which is normal

it has to do with looking at the number 2

you need to find numbers that devide 2 into a number element of ZI

you call this x
so 2/x = y with x,y element of ZI
where y is the number you have to plug into your polynomial.
so call your polynomial f(x)
horner says that you need to find a y such that:
f(y) = 0
which means you can try:
2,-2, 1 and -1

if for example -1 is true
then you can write f(x) as:
(x-(-1)).(f(x)/-1))

might be a bit sketch but ill write it down

Turns out there is no such number lmao

lemme see

i reckon you have to do it with a computer no?

i remember somethign as the brents method?

[supple yoke]

I don't think so since this a jee advance question

[weak lotus]

use newton raphson method then

yes^

i get 3

where my alpha is about 1.2

(big approximation lmao)

[weak lotus]

kinda crazy how you are meant to solve this but dont know how horner works

learning derivatives over horner, yeahhhhhh

[supple yoke]

Yeaa well idk what our teachers are teaching us :')

[supple yoke]

We haven't been taught this as well T-T

[weak lotus]

what grade are you in?

isnt jee for grade 12?

[supple yoke]

11th

[weak lotus]

damn

[supple yoke]

You would need to study for it from 11th if you want to clear it

[weak lotus]

then maybe there is a method i dont know off lmao

[supple yoke]

Haha idkk

[supple yoke]

Also what initial value did you take to solve it?

[supple yoke]

Wait if your alpha is 1.2 then when its raised to the power 6, it's floor or gif would be 2 and not 3

[mystic thunder]

how

[fast torrent]

yall good at math?

[celest hatch]

Hp

[mystic thunder]

I know bro but kidhar se aaya

j forgot how to deal w summation

[celest hatch]

Sum of infinite gp when common ratio is less than 1 is equal to
a/(1-r) a is first term and r is common ratio

[forest trail]

Nawh

[celest hatch]

Hence x= 1/(1-a) because first term of the series is 1 and common ratio is a

Similarly y=1/(1-b) and z=1/(1-c)

Now since a,b,c are in ap
Then -a,-b,-c will also be in ap
And 1-a, 1-b, 1-c will also be in ap

Hence 1/(1-a), 1/(1-b), 1/(1-c) will be in hp

@mystic thunder

[mystic thunder]

TYSM I REMEMBER NOW

TY

[celest hatch]

I guess you would have to factorise it, on factorising you will get

(x^2 - x + 1)(x^3 + x^2 - x - 2)

[fast torrent]

😔

[fast torrent]

which question bro

[celest hatch]

.

My bad thought I was replying to the comment

[raven galleon]

anyone know if u can solve a quadratic equation on a ti-83+?

[limpid crane]

you can solve the equation but that will be just waste of time
so we can solve GIF we get alpha between 3^(1/6) and 4^(1/6)
putting these two one by one in the function we should get a positive and negative value of function as it will be cutting the x axis (OBVIOUSLY)
hence proved
but thats not valid cuz imagine the exam asks you for the value of [alpha^6] which is 3 but then how will you find it
for that ill have you think on that but in this question its easy

see

this might be the manipulation other than that for your question everything is given prove it with contradiction or reverse it and then prove nothing really matters there

one more

[fast torrent]

I don't have media perm 😭

[naive dew]

Is this correct?

Help guys

[loud storm]

can someone help

i need help ASAP

[unborn basalt]

law of sines

[loud storm]

Thanks

I got it

[potent oriole]

Help plz

[weak lotus]

Cela a l'air plus difficile que ça ne l'est :
Remplacez x par 1 dans le numérateur, vous verrez que celui-ci tend vers 0.

Le dénominateur ne dépend pas de x et est constant puisque α est considéré comme une constante.
Nous obtenons : 0 / constante ce qui est égal à 0.

[potent oriole]

N'est ce pas possible que le dénominateur soit égal à 0? Sinn comment puis je le démonter svp?

[potent oriole]

C'est comme ça que j'ai fait j espère que c juste et merci pour votre réponse rigoureuse

[weak lotus]

i forgot to answer

my french be kinda shitty to imma type in english

the thing that you have to keep in mind is that alfa is a constant

so instead of looking at the values

[weak lotus]

i would simply do this xp

[magic gull]

dam which grade

[crisp sigil]

https://cdn.discordapp.com/attachments/646751050883399706/1267169691596619876/image.png?ex=66a7cf3d&is=66a67dbd&hm=d848dd31a04990fe42d6cc8e314e0ee3f26c8ccb69556e62c32829080ad1f08c&

[left knoll]

you can approach the problem in two ways: either you eliminate the fractions by multiplying by the common denominator (in this case 4) or you work with the fractions, but that's more steps for nothing imo

[unkempt bloom]

anyone good at calc

[left knoll]

what’s the problem?

[unkempt bloom]

idk how to do the usub

[unkempt bloom]

my goat Gilles

[weak lotus]

my pleasure!

[naive dew]

Jee mains prep

[fast torrent]

this is silly but can u solve it

[magic gull]

what the flip

[weak lotus]

there is a yt channel that does all these kinds of questions

just use symmetry and shapes you know

1/4 circle in total, then 2 half circles in that circle, find the blue egg shaped thingy first splitting it then substract white and blue and you have the weird shape

[fast torrent]

i got the question from the channel and that method was too confusing so asked here to see if theres a better method

[near garden]

Hello how can I improve my math

[naive dew]

By doing it

[near garden]

Practice?

[fast torrent]

ty

[naive dew]

Yessir

[lethal kraken]

hey guys can anyone make these? the ones on the right are the solutions but I never get the same ones

[near garden]

Thanks

[waxen scarab]

Hey guys, I am currently reading the GOPL book but some 'mathy' examples I struggle on, for example this. I think I struggle here because I have only briefly covered trigonometry in school, can anyone suggest any resources to provide a basic and maybe even advanced level of understanding of trigonometry? videos, books etc. thanks 🙂

[zenith quest]

can some tell me how to identify if the given function in fourier series is odd or even for example:- f(x)=sin2x is odd or even?

[weak lotus]

A function f(x) is even if f(−x)=f(x) for all x in the domain of f.

A function f(x) is odd if f(−x)=−f(x) for all x in the domain of f.

[zenith quest]

ooh thanks bro you just clear my confusion :>

[naive dew]

Country?

[waxen scarab]

follow the igcse progam

[naive dew]

Brother trigonometry is like salt, it’s hard to swallow it and you will find it in every dish(every chapter ITF, functions, calculus, matrices) so I say get a good base. Focus on the fundamentals of trig. The book I suggest is SL loney plane trig part 1. You can watch lectures on YT too to get a better understanding

[waxen scarab]

okk tysm

[vocal zodiac]

.

[left knoll]

someone down to group study Laplace integration? (I can't do this sh on my own) 😠

[left knoll]

@naive dew how do you self study it though and perfect it way above your grade if you don’t mind me asking please

[naive dew]

I was studying mathematics the wrong way for years. Other subjects are different from mathematics, you can learn other subjects just by reading and doing a few questions. But your math skill is directly proportional to the number of questions you solve. Mathematics = question solving, you won’t get anywhere if you don’t solve the questions YOURSELF. Looking at videos related to math, looking at other people solving math won’t get you anywhere if you don’t do it yourself . So just do it, if you want a learn a topic, find a lecture which explains the topic and make some notes/write formulas, do QUESTIONS on that topic

I hope that helps

I can do almost any question on permutation and combination because I did 500+ questions on that topic. A guy did 1000 integrals in my school, he was the best in integration that year

Wanna get better = do more questions

[left knoll]

Thanks so much man .

I want to be like you one day helping everyone here

[naive dew]

I’m on the learning path too brother, we all can help each other out 🤝

[left knoll]

Real

Also @naive dew if ydm me asking what studying level are you at right now ?

[naive dew]

I’m preparing for jee rn

It’s a college entrance exam

[left knoll]

WHAT

HOW ARE YOU THIS SMART BEFORE COLLEGE

[left knoll]

So your like 16-17 right

[naive dew]

18

[left knoll]

Damn college is late for you guys

[vast rune]

He prolly took a year for preparation ig

[vast rune]

Ex.11 Three positive numbers form a G.P. If the second term is increased by 8, the resulting sequence is an
A.P. In turn, if we increase the last term of this A.P. by 64, we get a G.P. Find the three numbers

guys help

[weak lotus]

4, 8 and 16

[mystic thunder]

sequence and series 🙏🙏🤬

[vast rune]

🤬🤬🙏🏻🙏🏻

[teal moon]

Help please

[vast rune]

Guys help him

[vast rune]

Boy you in 11th?

[vast rune]

If q2
– 4 p r = 0, p > 0, then the domain of the
function, f(x) = log (px3+ (p + q) x2+ (q + r) x + r) is

[weak lotus]

First one indicate all positive points

(which is just the quadric equation, idk how you call it)

[vast rune]

yeah get it

[weak lotus]

and for the log itself is just all real values for x >0

or do you need to find values?

[vast rune]

(x+1)(px^2+qx+r)>0

what do i do aftwr this

[weak lotus]

2 separate eq

x + 1 > 0

[vast rune]

oo

[weak lotus]

so x > -1

and then for the other you find all values for which that eq holds

[vast rune]

ooo

tysmmm

[mystic thunder]

yes wbu

[vast rune]

Yeah same

[vast rune]

U preparing for entrances?

[mystic thunder]

yes

why are u learning how to find domain in 11th

domain toh 12th ka hai

[vast rune]

Relations and functions?

Am doing modules

[mystic thunder]

AHHH

I SEE

[nimble delta]

I know its a silly doubt, but is the 2nd one right? or should it touch the circumference?

[vast rune]

No it's okay if it doesn't touch the circumference (am not sure tho)

[left knoll]

90⁰ angle is made only when it touches the circumference

In this case, second one will subtend some angle, but not 90⁰.

[nimble delta]

Okieee thank you!!

[nimble delta]

a = 6?

[reef kraken]

this question has to be incomplete

[trail flicker]

yea

[nimble delta]

okieee!! thanks!!

[trail flicker]

oh wait, its not 6

it’s 1/6

[nimble delta]

How?

[trail flicker]

wait a sec

[nimble delta]

sure

[trail flicker]

6/1 is 6

the answer is 1/6

[nimble delta]

Idk if its correct transposing denomitor in that way

So wanted to confirm the answer

@trail flicker here's how I did

[nimble delta]

cuz simplying DOES NOT WORKKKKKKKKKKK

😭

[trail flicker]

it’s 1/6 😭🙏🏻

broski @nimble delta

[nimble delta]

even i got stuck

[vast rune]

Yo now I know you in 10th grade

[nimble delta]

And u in elementary grade

[vast rune]

U aren't?

Mb gang

[mystic thunder]

how

[vast rune]

Pro lebel meth

[mystic thunder]

no it's easy

bufy

but

bren no wrk

[vast rune]

Maxima and minima in 12

how u doin it now

Pro confirmed

[vast rune]

@weak lotus help

[mystic thunder]

basic math

[vast rune]

O

[weak lotus]

apperently not xp

[left knoll]

if it was a obj i would do it the 2nd way other wise you should be able to solve after that simplification ig

[mystic thunder]

we get taught this stuff in the beginning of the year for physics 😔

not quite basic but yeah

[mystic thunder]

OMG THANK U SM

[odd salmon]

hii guys i need some help with this question

i calculated the angle and it was 11.. like the opposite of the right ans (13)

so i wondered what step i did wrong TT

i guess it's somehow relate to the direction of the angle?

ty in advance ❤️

[nimble delta]

Ur steps were correct, it's just that u took the direction clockwise and calculated the degree.

In cartisian plane we are suppose to take angles anticlockwise if not mentioned

[odd salmon]

Ahh thank you, I did re-check it again. I think my fault was drawing the diameter “imaginatively” so I drew it behind the O, while in actual scale it’s above the O 😓😓 But I think this Math problem was kind of ambiguous then? Because you can’t define the position of the circle and the O, except taking the O as (0,0) and drawing x^2 + y^2 = 1…

Then go on defining the diameter and the angle

[meager juniper]

about to start calc 1 this semster, anybody have any tips for me to sucseed? ive always been mid at math getting Bs so just wonding what worked for yall!?

[naive dew]

Become a master at trig and algebra

Math builds on prior knowledge

[weak lotus]

https://tutorial.math.lamar.edu/

[odd salmon]

hi! i am kinda stuck on this. can anyone help? ty ❤️

[weak lotus]

is z a complex number?

[odd salmon]

@@ sorry idk either because the problem doesn't mention the z's condition

[weak lotus]

answer is 94

[odd salmon]

wow how did u solve it?

[reef kraken]

do u know the answer to this question

is it 34?

[odd salmon]

ooh i figured it out

[odd salmon]

the ans is 2381 sadly

[reef kraken]

underroot?

is that 30 into 64?

nope nvm

howd u do it

i found that the minimum value of b/q is root 1920

by amgm

i couldnt get far from there

[odd salmon]

actually i knew the answer but idk how they got to the final result though

it was close

in my way i’ll write the equation to

but the ans is 2381???

😭😭😭

[reef kraken]

wait 70??

[odd salmon]

AH sorry my teacher adjusted 60 to 70

=))))))))

[reef kraken]

i got it

its am gm

wait no

i dont got it

it literally should just be

root 2380

[odd salmon]

yea right

OH

[reef kraken]

thats the minimum value tho

[odd salmon]

I ACTUALLY GOT
IT

i think the maximum is like

qnrn = 2380 so possibly qn and rm can be like 1 and 2380

[reef kraken]

wait im differentiating shit rn

[odd salmon]

?

so the maximum

can be plus 1

= 2381…

🙂‍↕️🙂‍↕️🙂‍↕️

[reef kraken]

that doesnt work tho cuz

inside the root

it will just be multiplied

OH WAIT

nah

thats qnrn

we need qAYY

i got it

nvm im got it

sending the soln

[odd salmon]

hmm i just simplify it
like u have xy = 100 so max sum of x + y could be x = 1, y = 100 and = 100 + 1

does that make sense 🙂‍↕️

[reef kraken]

answer doesnt match tho

but it cant be wrong

[odd salmon]

u mean the ans 2381?

[reef kraken]

no

my answer is coming out to be

2*root 2380

but it seriously doesnt seem wrong in any sense

[odd salmon]

shit i wrote the wrong equation here: qmrn = 34x70

[odd salmon]

hmm

can u tell me ur steps

[reef kraken]

one sec im sending it

[odd salmon]

okayy

[reef kraken]

that literally can not be wrong

u seeing this?

[odd salmon]

yea wait a sec

imma check it out

[reef kraken]

damn but this aint the maxima

its the minima

god are we just dumb

im just annoyed at this point

[odd salmon]

ig u can follow my way then

as qmrn = qnrm = 2380

to let b max

then qn + rm = max

[reef kraken]

oh yeah

OH YEAH

ur a genius

[odd salmon]

qn = 1, rm = 2380 can satisfy the question then

[reef kraken]

wait but

[odd salmon]

💀💀💀

[reef kraken]

howd u know that

[odd salmon]

NO

[reef kraken]

oh wait

[odd salmon]

i struggle when qnrm = 2380

[reef kraken]

but thats literally

whats the use of that tho

[odd salmon]

didn’t know how they get to 2381

[reef kraken]

we got root qnrm <= 2381

now what

[odd salmon]

no

qnrm = 2380

to qn + rm max

then one must be 1

[reef kraken]

that doesnt make any sense

at all

[odd salmon]

so the sum can be largest

WHAT

[reef kraken]

how

why

is one 1

[odd salmon]

i mean so that the sum is the largest

because

[reef kraken]

?

[odd salmon]

when xy = 6 then x + y <= 6 except for x = 1, y = 6 then x + y = 7

q, r are positive constants

[reef kraken]

huh

then thats it ig

im still a little mindfucked by this

[odd salmon]

yeah @@@@@@ like the largest sum thing

idk if it’s validated

hâhhahahaha

[reef kraken]

yea same

[odd salmon]

just through calculations 🙂‍↕️

[reef kraken]

theres no real explanation

its just

it is true

[odd salmon]

yeah

[reef kraken]

but its not like

it doesnt feel real

[odd salmon]

hey u wanna try another ques

[reef kraken]

ugh

sure

[odd salmon]

it’s interesting also hâhhahaahah

[reef kraken]

god i hate algebra

u got something in calculus

[odd salmon]

no…

i just got

SAT

💀💀💀

[reef kraken]

pft

WHAT

what is that

thats so easy

[odd salmon]

WHAT REALLY

🙂‍↕️🙂‍↕️🙂‍↕️

[reef kraken]

yeah

[odd salmon]

i was stuck

urgh

lenme try it again then…

[reef kraken]

its c right

[odd salmon]

u are done bro

it’s B

HHHHHHH

[reef kraken]

WAIT

fuck no

i just realised

what i did there

[odd salmon]

omk i had figured it out

i was missing the (-) the whole time

💀💀💀💀💀💀💀 like idk why i did it wrong over and over again

[odd salmon]

maybe u was missing (-) as well hhhh

[reef kraken]

yeah i got it

[odd salmon]

yeah yeah

okay

it’s not as hard

hhhh

i think i was brainrot when it comes to coefficient thing though

for example

💀💀💀

now i know how to do this type but idk if im right

u can try this one

[reef kraken]

i am so unbelievably

dissapointed in myself

[odd salmon]

…

dont worry bro

i miscalculated the surface area from x6 to x4

i lost 40 points

😅😅😅😅😅

huhuhuhuhu

[reef kraken]

wait im so confused

what do we have to do

i dont get it

[odd salmon]

y-intercept

so x = 0

argh no

[reef kraken]

no ur right

thats the y intercept

but what do we have to do here

OH

THIS IS A

omg

wait no i

still dont get it

[odd salmon]

substitute them in the functions, then if you see the result as the base/coefficient then it’s right