math-help

[proper venture]

Can anyone give me Edexcel GCSE last year math paper or mock onen

If not any site? Please help

[left knoll]

how do u do this?

[queen rover]

Hope you can read it!

[left knoll]

Appreciate ur help! I'll check this out rn

[left knoll]

h with respect to cliff t is on?

[queen rover]

I’m not sure what your question is. h refers to the position of the ball, its height with as a reference the cliff’s top. t is for the time which starts running from 0 the moment the ball is thrown. (At time = 0, height is 0)

[nova drum]

do you happen to have a slavic backgorund?

[queen rover]

Haha I wonder why you think that but no. I live about 2k kilometers westward

[nova drum]

interesting, I asked because your handwriting is similar to slavic

especially the h,p,s and w

[queen rover]

Haha nice to know!

[acoustic crag]

hey guys

I need help

How do u do to find the trigonometric and algebric value of the exponential of a complex

like lets take 2epx(-i*2pi/3)

can u pls stop ??? its not about math lol

[left knoll]

<@&942391219206647828> Please do something about this guy
he is spamming everywhere

[acoustic crag]

I'll open a ticket just in case they dont see it here

and then send back my msg lol *

[sweet bridge]

Done!! Lots of bots today

[acoustic crag]

Sorry I open a ticket for nothing admins are too fast lol

[sweet bridge]

It's all good!! You did well, this way anyone can just hope in to help, also the tickets work a lot for when you want to leave evidence of something, so it's okay, thank you so very much

[nova drum]

does anyone do discrete maths here?

[unique kelp]

Hey can anyone help me with math question?

[deep edge]

Anyone know how to answer this? I've been having a hard time answering this two questions :((

[viscid knot]

A solução é fácil meu chavalo:
2+2=4

2+2-4=0
0=0
(Prova da Solução)

Demorei algumas horas para encontrar uma resposta concreta.

[next kraken]

@viscid knot obrigadissimo meu caro, ainda bem que o meu exame é só amanhã. Assim estarei pronto pro que der e vier

[viscid knot]

Boa sorte meu camarada, as melhoras, e bom teste.

[limpid crane]

use AM (arithmetic mean)
you will get a cubic equation with no constant in variable 'n'
then you need to solve it and get a value of n and solve the summation of nC1 + nC2 bla bla bla

(n cannot be zero) so you will end up with a quadratic

[limpid crane]

I know a Lil bit

idk what did you find difficult in it doe if you wanna ask something i might help

[chilly flower]

guys pls help

[unique kelp]

ohh

like this?

[unique kelp]

but isn't this permutations and combinations

[limpid crane]

yeah but maths is maths

[limpid crane]

yes

[unique kelp]

Yeahh

[limpid crane]

probably like this if your answer is correct

[unique kelp]

okay

Thank you!

[limpid crane]

np

[candid rivet]

for the exp(x)/(1-x) I use the Cauchy product of two series

[chilly flower]

yoo thanks

[random atlas]

Help

[candid rivet]

do you know what's the solution ?
I get 130/1260 but I probably did a mistake

[random atlas]

C

I solved it

[candid rivet]

If i'm not wrong, the number of different rows is 1260, and only 42 divides 1260 so i'd go with c but I got 130/1260

[candid rivet]

oh okay

do you uust go trough every possibility ? (1st tile is blue then... , 2nd tile is blue then.... )

[random atlas]

No

There is a method called cross method

If you have studied permutation and combination, you would have studied it too

[candid rivet]

ohh okay thanks

[left knoll]

How do we get these mean values??

[mystic thunder]

can someone tell me what happened in the step which i circled in white

how is sin x cos x = sin 2x

[candid rivet]

the formula is : sin(2x)=2sin(x)cos(x)
If you know the formula of sin(a+b) then it is easy to prove it
If you know compex numbers, you can check that the formula is right

@mystic thunder

[mystic thunder]

ohhh i see i havent done that before ill check it out

TYSM

[limpid crane]

anyone?

[hushed swift]

I got most of the question, but the part in red just bugs me

aren't we supposed to do ln(3.7) to get the value of capital Y just like we do for m as m = lnb ???

[pastel pecan]

who solved this

[hushed swift]

me

[pastel pecan]

aight wait a few min

[hushed swift]

🙏

the answers are correct or at least the marking scheme says it’s this way

[pastel pecan]

what

ill start throwing hands at your teacher

[hushed swift]

idek throw hands with the examination board 😭😭

[pastel pecan]

I will.

[pastel pecan]

the hell do they smoke anyway

[hushed swift]

br*tish examination board so

[pastel pecan]

you haven't been taught dervatives right

dy/dx

[hushed swift]

we have we have

differentiation and integration

[pastel pecan]

im bored af
ill try to do one by your method and one by mine

[hushed swift]

ok if u could pls

i’m going to sleep but i’ll check it

[pastel pecan]

nvm the graph was lny vs x
and not y vs x
yeah your answers are correct

short answer: the points are given in terms of lny and x and not y and x
so you directly subsitute the values
and for long reasons:

[hushed swift]

ok it makes a lot of sense now

tysm it was killing me

[lucid cairn]

Does anyone know how to find the primary measure for 7pi/6? Idk how it's called in english but in french it's called "mesure principale"

[violet estuary]

do u still need help???

[lucid cairn]

Yes but now i have another question

[violet estuary]

dm

[left knoll]

Can someone please explain or teach me calculus please

[agile trench]

what do you want to know

[frosty barn]

Its B

[deep edge]

Does anyone know how to find the determinant of this matrix in three ways? We were asked to find the determinant in three ways and I only know 1 way :((

[cobalt mural]

need some help with understanding number theory and solving congruence pls reply to this message if ur able to help ty

[undone ledge]

Question a and b…… I’m confused can someone guide me

Or teach me 😭

[candid rivet]

what are a and b ?

[candid rivet]

I know you can use the (disgusting) formula with the sum of product of coefficient.
You can also try to get a triangle matrix (not sure how we call them, but with only zeros under the diagonal) by adding, substracting, multiplying the rows) then the determinant is the product of the numbers on the diagonal.
Write the equations (AX=Y iff X=A^(-1)Y where X=(x1, x2, x3, x4) and Y=(y1, y2, y3, y4) ) and solve the linear system of equations

however, the 2nd and 3rd method are kind of the same so idk

[left knoll]

ig ax+b

[undone ledge]

Oh so sorry ummm a= 171

B= -17/3

[candid rivet]

I don't really undesrtand the problem
if a and b are the constant such that the equation of the tangent is y=ax+b, then a=f'(2) and for x=2 you get f(2)=2f'(2)+b
doing the same for g gives g(2)=2g'(2)+c
So the equation relating a and b is f(2)=2a+b ?

Now if the curves touch at x=2, then f(2)=g(2), and the tangents are the same so y=ax+b=ax+c so b=c, and then you have f(2)=g(2)=2a+b so...?

@undone ledge

[undone ledge]

Wait I will send the whole question…. 🤓

This is the full question

Maybe I went wrong at the start?

@candid rivet

Thanks for the help though ur amazing

[candid rivet]

okk i juste neeeded to know who are f and g haha

[candid rivet]

Thx (: and you're welcome

[left knoll]

May sound satire but everything

[left knoll]

what r u struggling to understand ?

[ripe gale]

can someone help me?

[lethal slate]

Need a super computer to compute that

[lethal slate]

Hope that answers it 🙏

[left knoll]

Wtf do you need the value or smth else?
If it is to be solved without calculators,.perhaps you should try A2 and A3 and A4 and maybe see a pattern rise up?

[lethal slate]

It’s a weird question writing the answer down would take a few hours
Are you supposed to just copy and paste the answer?

Also the question isn’t shown fully, so it’s very ambiguous

[rain sun]

Small example, but you just have a 3x3 matrix in which n = 2019

the D matrix is made up of your eigenvalues for A and the P matrix are the eigen vectors as columns. Make sure they line up. In the screenshot I provide here, if you swap purple and pink on P, you would need to swap it on D. You can't mix up the way they're aligned.

[candid rivet]

If you dont know about eigen values, a common method is to write A as the sum of two matrixes which are easy to calculate the nth power :

[candid rivet]

I looove your notes it's beautiful

[wild gull]

like holy

[vagrant gale]

One message removed from a suspended account.

[vagrant gale]

One message removed from a suspended account.

[odd sparrow]

hey guys! im having some trouble doing those derivatives, can u help me? thxx

[muted grail]

a) you can use the chain rule to solve it
b) you can also use the chain rule
c) quotient rule
d) chain rule again

[odd sparrow]

if its possible, can you show me how to do the 1st one? Im always glitching in the middle

[candid rivet]

maybe have a look at a youtube video about the chain rule with examples it can help

[odd sparrow]

I found my mistake! thank you guys

[rain sun]

lol I didn't write that. Those were my instructor's notes. They run fundamental graduate math classes during the summer like clockwork for hundreds of students at a time, so they have a lot of those notes ready to go.

[limpid crane]

yo anyone?

i tried kings rule but at one point x is left and i am not able to remove it by any means maybe the question is wrong or im bluffin

[candid rivet]

I've found this : https://www.sarthaks.com/3593162/the-value-of-120-3-x-2-sin-x-cos-x-sin-x-4-cos-x-4-dx-x-0

first step is rewriting the integral as the sum of the int between 0 and pi/2 and the int between pi/2 and pi, and then you do u=pi-x in the second integral
But i don't understand the fourth step (how to get rid of the x) (yet should be doable by integration by parts since sin(x)cos(x)/[sin(x)^4+cos(x)^4] has a primitive (weierstrass substitution) )

but damn that's hard

[limpid crane]

oh yeah nvm you are right by parts is the sol

lemme try

yo thanks i actually solved it lmao

by parts was easy there

[candid rivet]

niceee

[somber flare]

Can someone help me with this 🙏🙏

[candid rivet]

all we need to know is :
tan=sin/cos
sin²+cos²=1
if -90°<x<90° (you can replace 90° by pi/2 if you work with radians) , then the equation tan(x)= r (where r is any real number) has a unique solution

[somber flare]

Thank you 😭🙏

[candid rivet]

haha you're welcome (:

[past thunder]

I am still confused as to when to use which trig substitution in integral

[candid rivet]

https://tutorial.math.lamar.edu/classes/calcii/TrigSubstitutions.aspx

and if you don't want to learn by heart you "just" remember it might be a trig sub when there is a sqrt of ±x² ± constant, and then try to think of which trig identity does it look like in order to make the sqrt disappear

[little hamlet]

Hi could someone explain to me why we multiply by pi for part c, how is that gonna give us volume

Also why don't we square root the answer back?

Anddd finally why don't we times by 4¿

I don't understand what volume it wants tbh

[wild gull]

this does a way better job of explaining it than I could:
https://www.sfu.ca/math-coursenotes/Math 158 Course Notes/sec_volume.html#:~:text=We can think of the,that of the solid of

essentially you're doing a lil rotation about the x-axis

like so

the article is really good but it boils down to rotating the graph (to form a solid)

slicing it into cross-sectonal circles

the area of a slice would be πr^2

integrating between two slices would end up giving you the final formula

[little hamlet]

wow

that article was so helpful

tytyty!

[wild gull]

🫡

[nimble knoll]

Hi, can someone please help me with an exercise from statistics?

I do not understand how the two underlined terms combine into the one that is underlined in the solution

It’s a problem showing what is the maximum range/uncertainty after two terms are and b are divided

[undone ledge]

Could someone help me with this question please?

[left knoll]

Think out of the box

That curved roof is a parabola

A would be (0,30), because it is located at x = 0 and y = 30

And so on

From there you have a basis on which you can guess the values of a, b and c and, therefore, the function

Or the other way around mb

[undone ledge]

OHHHHHHHHH OMG

WHY WAS I EVEN

TYSM

[left knoll]

🤝

[acoustic crag]

Hey

Can somoene help with this

I have to find the exponential form of this complex

But smh when im tryna find z1 the answer is nonreal (negative square root)

[left knoll]

Can you send me the question...imma sorry I can't understand your handwriting

[acoustic crag]

Np ill write it down so g(z) = z^3+(1-i)z^2 +( 1-i)z - i = (z-i)(az^2+bz+c)

[acoustic crag]

1. find a,b,c by identification
2. find the exponential form of this complex

But as I said when im tryna to find z1 after finding delta the square root is negative

[candid rivet]

if delta is <0 you actually have two solutions (for a polynomial of degree 2) : for instance, if delta is -3 then d= i * sqrt(3) is such that d^2=-3 (and -d is the other solution to x^2=-3 (there are exactly and only 2 solutions)
So here, z1="(-b+-d)/2a" and you get that z^2+z+1=(z-[-1-d]/2)(z-[-1+d]/2)
And then if z=r exp(i theta) then you can get the norm and argument of (z-constant) by using the facts that |Z|=sqrt( Re(Z)^2+Im(Z)^2 ) and arg(Z)=arctan( Im(Z)/Re(Z) )

maybe there's a better way to do it because my method is pretty ugly imo

also if you wanted to factorize z^2+z+1 you can do it faster if you know the number j=exp(i 2pi/3)

[acoustic crag]

actually I'm using the norm of the complex to find theta but smh the norm in negative so I can't use it , my teacher use this method ans said that we have to use too

like you have cos(theta) = a / |z1| and sin(theta) = b/ |z1|

with a the nonimaginary part and b the imaginary part

okay mb

I'm dumb lol

I did put the i on the norm wich is not what you have to do because as it power 2 you'll always get smt negative

ty for the help btw you made my brain work proprely 😉

[candid rivet]

Glad you got it !

[tardy crypt]

Hello guys, I need suggestions for a road map along with math book recommendations for engineering ( please separate each engineering), thank you,

Math only

[lavish copper]

hello can someomne plz help me with this onee

[left knoll]

help needed

[gloomy topaz]

If anyone's has AS CAIE mocks papers from their school (past year or this years) please send them to me!! I wanna practice :> I can send mine also

[pastel pecan]

.

[gloomy topaz]

OK um

Can someone try these questions and show me their workings 😭

[pastel pecan]

cheers

[gloomy topaz]

wgat 💀

[grizzled lotus]

What is this?

[mellow mesa]

√10000 = 100

[grizzled lotus]

Why square root

How does it relate to the picture e

Sorry I’m just a bit dumb

[mellow mesa]

You know, under root of 10k

Under the root

[maiden minnow]

[grizzled lotus]

U smart 😭

[worthy timber]

Can somebody solve the letters: "k." and "l." with explications...

[undone ledge]

Hii is there a way to solve this without using simultaneous equations?

[pastel pecan]

Im going to sell you for 50$.

Sup gillies uwu

[weak lotus]

oh no, im not even 21

can you cash-app me that 50 though

[weak lotus]

all these scams, f*ck

https://tenor.com/view/ban-hammer-yoshi-mario-discord-gif-12444703281338986867

[pastel pecan]

Sure first need a buyer for that guy

[weak lotus]

do a hundo while we are at it

[candid rivet]

i don't think so, the only things you ca know before solving the equations are that a>0 (limits when x-> infinity) and e=12 (which actually is one of the 5 equations)

[candid rivet]

k. True. T={1,3,pi} is a set of three element, and U={ {1,3,pi}, 1 } is a set of two elements, these two elements being 1 and {1,3,pi}=T, so T is in U

l. True. T={1,3,pi} is not in R. However 1 is in R, 3 is in R and pi is in R, but the set of {1,3,pi} is not

Note that {a,b,a,a} is the same set than {a,b} and also the same than {b,a}. So {a,b,a,a}={a,b}={b,a}

And note that { 1, {2,3} } is different than { 1,2,3 } since :
{ 1,2,3 } = set of elements 1 and 2 and 3
{ 1, {2,3} } = set of elements 1 and {2,3]

[lethal slate]

Guess it

[left knoll]

How many different numbers that can be represented between 2^13 and 2^14 in the IEEE single-precision float standard. Justify your answer.

[undone ledge]

Okay thank you :)) I just wanted to make sure!!

[proper venture]

Brass is an alloy consisting of copper and, frequently, zinc. Cartridge brass contains 70% copper and 30% zinc by weight and is commonly used for plumbing accessories and decorative hardware. A metal worker has a supply of a different brass alloy containing 55% copper and 45% zinc by weight and a 3 pound supply of pure copper. How much 55/45 brass alloy should be added to the pure copper to create the 70/30 cartridge brass?

The percent of zinc in the 70/30 cartridge brass will be equivalent to the ratio of the zinc's weight in the mixture and the total weight of the mixture.

Formulate an equation that could be used to calculate the amount of 55/45 brass that should be added to the pure copper to create 70/30 cartridge brass.

Can anyone please tell me what to do 😅😭

[pastel pecan]

Hey bill nye

[wild gull]

if you still need help

[pastel pecan]

Been stalking you

[wild gull]

have you got sharingan wth

[pastel pecan]

I smell the future

[wild gull]

how has no one helped this young lady😭

[pastel pecan]

I was bored so
I came here to solve that long ahh paragraph

[wild gull]

oh lmao

go do your work

[pastel pecan]

https://tenor.com/view/wesker-albert-albert-wesker-resident-evil-resident-evil-4-gif-5143688443782660001

This is why

[wild gull]

icl my head hurt trying to decipher all of it

[pastel pecan]

Yeah i know

Lets make it fun

Whoever solves it first wins

No chatgpt allowed

[proper venture]

🥲

I got it by myself

[pastel pecan]

Shhhhg

[proper venture]

Thanks though

[wild gull]

https://tenor.com/view/johan-liebert-monster-johan-meme-nothing-personal-gif-25797708

oh

[pastel pecan]

Feettuccine and I are having a good moment here

[wild gull]

oh ffs it's been solved

[pastel pecan]

The games still on my guy

[wild gull]

no fun for us allowed mr was

I MAY have already solved it

[pastel pecan]

Fk

[wild gull]

pay up

[proper venture]

I mean I was trying but I read paragraph and was like dude....

[pastel pecan]

Alright show me those toes
Ill suck it

[proper venture]

But then I realised I've to do it by myself 🥲 . So tried . Who make these long ass questions at first place

[wild gull]

haram

[pastel pecan]

Cheers

[proper venture]

Broooo....this is math help. Not toe help 😂

[wild gull]

you get 6 pounds? as your answer

[proper venture]

As answer no. As calories yes

[wild gull]

ok i'm gone

[balmy wedge]

i keep making really stupid mistakes with arthitkic but like i understand math concepts, how do i fix this 😭

[candid rivet]

Maybe practice more, like more exercises and do the calculations whenever there are some

[lethal slate]

Let's denote the amount of 55/45 brass alloy to be added as ( x ) pounds.The total weight of the mixture after adding the 55/45 brass alloy to the pure copper will be ( x + 3 ) pounds.To create the 70/30 cartridge brass, the amount of copper in the mixture should equal 70% of the total weight of the mixture, and the amount of zinc should equal 30% of the total weight of the mixture.The amount of copper in the mixture will be the sum of the copper from the pure copper and the copper from the 55/45 brass alloy, and similarly for zinc.Therefore, we can set up the equation as follows:[ \text{Copper in mixture} = 0.70 \times (x + 3) ] [ \text{Zinc in mixture} = 0.30 \times (x + 3) ]Given that the 55/45 brass alloy contains 55% copper and 45% zinc, we can express the copper and zinc in terms of ( x ):[ \text{Copper in 55/45 brass alloy} = 0.55x ] [ \text{Zinc in 55/45 brass alloy} = 0.45x ]The equation can be formulated as:[ 0.55x + 3 = 0.70 \times (x + 3) ]This equation represents the balance of copper in the mixture. Solving this equation will give us the amount of 55/45 brass alloy (( x )) needed to create the desired mixture.

You’re welcome.

[gloomy topaz]

im sorry WHAT is this 😭 what programme are you taking

[graceful gorge]

hello everyone can someone please help me with my task? :__ i jss try so hard to understand what to do

Justify that if we connect the centers of successive sides of any quadrilateral with segments, we get a parallelogram

it's about Thales' theorem

prbl inverse theorem

[safe coral]

may someone help me plzz

simplify this

[candid rivet]

hope this will help

[safe coral]

it helped a lot, thanks!

[candid rivet]

I use the fact that
WXYZ is a parallelogram if and only if XY=WZ and [XY] // [WZ]

notations :
[AB] is the segment AB
// means "is parallel to"

[regal nova]

is anyone familiar with statistics using the language R

[graceful gorge]

thank you!!

[proper cosmos]

can someone help me with this pls

[hardy mason]

Does anyone have an idea how can I find the value of x?

[torn phoenix]

is that 1.5 raised to the minus power?

[hardy mason]

No it’s just 1.5

He told us to use logic to solve it but I don’t have any

[candid rivet]

i hope you know what ~ is
If not I don't really know how to do it. What it says is that if x is really close to 0 then
ln(1-x) is approximately x
sin(x) ~ x
tan(x) ~ x

[undone ledge]

Could someone please help me understand this questions I differentiated it since it’s talking about stationary points then I expanded the term.. but if it’s only one stationary point the discriminate should be 0 right? But the leading x term I got from expanding is x^3 and now I’m just confused 😭

[pastel pecan]

why you shooting shooting at your own foot

[undone ledge]

OH MY GOD

[undone ledge]

I literally was.

Thank you so much..

[pastel pecan]

hence there is no root or solution from quad*

[pastel pecan]

10$ rn

[undone ledge]

https://tenor.com/view/burying-dying-dead-grave-gif-17189345

[undone ledge]

Yep i understand:))

[pastel pecan]

sleep is important my child

[worldly dome]

textbook says B is a basis for R3
i dont see how thats possible do you guys think this is just a mistake on textbook end?

nvm i figured it out

[undone ledge]

sleep? what.. is that?

haahha

jkjk tysmmm

[candid rivet]

well a basis of R^n has to have exactly n vectors, so yes it is not a basis of R3.
Yet it is a basis of R2

[hardy mason]

Today i had an exam , on that exam there was a question that asked if it was possible or not to create a function g(x) that would make f(x) continuous and differentiable on x=3. Does anyone have an idea of how to solve this question?

[proper cosmos]

Thank you very much

[candid rivet]

So the idea is to calculate f(3) and f'(3).
You should get f(3)=10 and f'(3)=4 if I don't make any mistake.
So you know g(3)=10 and g'(3)=4.
The easiest is to think about polynomial functions (they are differentiable and easy to creat if you want to impose that P(3)=10 for instance)
We want P'(3)=4 which is different than 0, so P has to be of degree 1 or more. Let's take the simplest, which is P(X)=aX+b. Therefore P'(X)=a

And now you just have to solve the system of equations
P(3)=3a+b=10
P'(3)=a=4

(and g(x)=P(x) )

[hardy mason]

I still didn’t get what would be the function of g(x) . I tried to make a function that gives value of 10 but it doesn’t give a value of 10 when i find the derivative of the function

[candid rivet]

a=4 and 3×4+b=10, b=-2
so g(x)=P(x)=4x-2
and yes you have g(3)=10 and g'(3)=4

[grizzled lotus]

I’m having a hard time doing the second question . Can anyone help 😭

I used YouTube but until this step it’s kinda different from the amount in the YouTube and I got confuse on how to continue

[median hound]

Can anyone help me figure out how to get to the answer? I can't seem to get there

[uncut oriole]

If the circle passing through the point (2,1) is tangent to the two coordinate axes,the distance of the centre of the circle to the straight line 2x-y-3=0 is

[uncut oriole]

If someone can help me

I’ll be grateful

[torn phoenix]

B

[uncut oriole]

Solution? 🙂

[candid rivet]

I think there is also a "well-known" formula for the distance between a point and a straight line, but if you know the distance is actually the distance OH then you can just try to get these coordinates

[uncut oriole]

Can we use point form equation formula

[candid rivet]

(also there's actually 2 circles that pass trough (2,1) and are tangent to the coordinates axes, but let's suppose it is the small one)

[uncut oriole]

Y-Y1=m(X-X1)??

[candid rivet]

what is it ?

[uncut oriole]

For gradient?

[uncut oriole]

.

[candid rivet]

yes

[uncut oriole]

But

What is gradient between it?

That was my confusion

[candid rivet]

well you want to get an equation of the straight line OH

and what i used is that the perpendicular of a certain line has a vertex of -1/m

[uncut oriole]

Like reciprocal of the gradient?

[candid rivet]

yess

[uncut oriole]

It was really helpful! Thank You so much!! Really appreciated 🙂

[candid rivet]

you're welcome, glad it was helpful !

[weak lotus]

if i can give a tip, when you are dealing with circles, try to draw as much as you can

like saotajan did, its really helpfull

[crimson heart]

can someone pls explain how to do this

ik the general steos like finding the limits and then integrating for the area but can someone actually do the question pls

[fleet forge]

Grade 12 quadratic sum, with 2 formulas involved

is this correct?

[pastel pecan]

almost

[fleet forge]

You didn’t divide the 7 by 2.
Did you use chat gpt?

Hard to explain but second formula is (x+1/2b) - 1/4b(squared) + C

[candid rivet]

There you go ! I hope I got it right

[candid rivet]

well if you develop your last expression you'll see you don't get the +7 so it is wrong

[fleet forge]

but you do tho, the 7 is divided by 2

[candid rivet]

why would you divide the 7 by 2 ?
You would have to divide it by 2 if you write the whole thing as 2 time something

[pastel pecan]

nah

[fleet forge]

look the a is the 2

[candid rivet]

they want it in the form a(x+b)²+c, not a( (x+b)²+c)

[candid rivet]

yes here yes, but the problem doesn't ask to put it in this form

[fleet forge]

the answer isn't in that form, it's just a way of calculating it

we take A out and (complete the square which is the Divide 2 and after the divide 4 thing) then add C

[fleet forge]

Do you get what I am saying?

[candid rivet]

ok got it, it does work if at the end you multiply the vonstant term by a

[candid rivet]

okay sorry I didn't actually read the different steps of your calculation

it's just a sign error, it should be -(+36/4)

and you'll end uo with the -11

[fleet forge]

so the formula require that you - and since the b is a negative the brackets between two - turns into a postive

[fleet forge]

anyway thanks for helping, you helped me feel more secure about my answer

[fleet forge]

OH FUCK

[pastel pecan]

hehehe

[fleet forge]

I see now, it's -11

• squared makes a positive

[pastel pecan]

https://tenor.com/view/hahaha-dogo-smile-cute-gif-16039989

[candid rivet]

yeah be careful about the b² that will be positive anyway

[candid rivet]

niceee

[fleet forge]

thanks

[candid rivet]

you're welcome (:

[crimson heart]

damn how you get all of that

im so sped idk how to even do the first one

thanks

[limpid crane]

you can do it you are tenz! lol

[crimson heart]

cheers lol

[crimson heart]

wait im confused as to how you got ur R1 working outs

[candid rivet]

R1 is the whole area between the x-axis and the curve C, minus R2, but you can remove the small portion between P and A

[candid rivet]

tell me if you need a more detailed solution !

[crimson heart]

i understand that, what im not sure about is how you got this

[crimson heart]

beacuse thats how i did it

because ur integral says u integrated x then took that away from the integrated x^2 and im unsure why it wouldnt look like the integrals i wrote

can someone also help me wih thi spls

[pastel pecan]

only with a
b im not sure
i can only find for displacement not distance

[candid rivet]

yes it works that's good !
I just used the linearity of integrals : integral of (f+g) = integral of f + integral of g

[pastel pecan]

for distance you need to take absolute of the velocity function we got
I don't know how to do that

@candid rivet

[crimson heart]

is that AS level stuff?

[candid rivet]

I dont know what AS is (I'm french) but it's a pretty basic property about integrals

[crimson heart]

yes u got it right

sorry but i dont understand where u got 1 and 4 from

[pastel pecan]

equating the final

t-1
t-4

[crimson heart]

wait where did u get these numvbers from

[crimson heart]

because i get u have to differentiate

[candid rivet]

me neither 😂
Is it like the integral of |x(t)| ?

[pastel pecan]

yeah I differentiated it

[crimson heart]

yh but wait lemme send what i gopt when i did that

[pastel pecan]

wait Ill verify the above

[candid rivet]

i'm really not sure haha

[rain canyon]

I’m not sure what to do from here

[crimson heart]

like how do i get t = 1 and t = 4 form this eqwuation

oh for b this is the answer

[candid rivet]

if that can help

[weak lotus]

b is probably integration

[pastel pecan]

factorize it

[crimson heart]

suprisingly not

[crimson heart]

i thought so as well

i thin u could use integration

[weak lotus]

oh damn it isnt?

[crimson heart]

i think u can use integration if velocity was ur y axis

[pastel pecan]

oh hey gillies

[pastel pecan]

it is

[weak lotus]

hey bo

[pastel pecan]

but you need to find absolute of a function before integrating it

how do you get absolute of an function

[pastel pecan]

this is way sus

[weak lotus]

fuck i would do a line integral hahaha

over some scalar field f(x,y)

[pastel pecan]

from bro to boo

gay

[weak lotus]

to roasted for this

[rain canyon]

I’m not sure but I ended up with this

[crimson heart]

but ik this is wrong

i think my brain is cooked

[weak lotus]

https://tenor.com/view/shut-up-cat-monch-cat-monch-spinfal-gif-19376414

[pastel pecan]

i want to avoid your teeths

why are there two tenz

[crimson heart]

@pastel pecan this is the answer

for b

[crimson heart]

tenz2.0 is my ipad

so i can send my working

[pastel pecan]

how did you do it

[crimson heart]

do what?

[pastel pecan]

.

[crimson heart]

i ended up with this quadratic but i didnt get the answers t = 1 and t = 4

[pastel pecan]

yeah factorize the function inside the brackets too

or throw in quadratic formula

[crimson heart]

i did and ended up w this

[pastel pecan]

https://tenor.com/view/what-huh-monkey-shocked-mouth-open-gif-16459002

[crimson heart]

5.7 and -0.7

[pastel pecan]

haiyaaaaaaa

why is your constant value -ve

[pastel pecan]

here as well

[crimson heart]

aah

im so cooked

thanks bro

[wet lark]

Can you find the part about the values ​​that k can take? I can find the another part (I mean k= -2 part )

[left knoll]

What

Wdym

[wet lark]

I found k ≠ -1

[wet lark]

I mean , can you find what must be k if this matrix is invertible

😕

[left knoll]

Ok

Baby steps

What does it mean for it to be invertible?

For a matrix to be invertible, this means there is another hypothetical matrix that, when multiplied with the first one, results in the identity matrix

[wet lark]

yes

[left knoll]

Lets call that matrix that is shown "A"

And the hypothetical matrix "B"

Terms of A and B will be such that by multiplying them knowing their results (0 or 1, cuz identity matrix) you will have a bunch of simple equations

Just work them out until you draft the value of k

[wet lark]

ohhhhhh

okay

I got it now

thank youuu

[raven galleon]

can someone interpret this or link what kind of stats this is finding? "OR = 1.41 [1.23–1.62, 95% CI"

[wet lark]

can you solve it if you have time ?

[left knoll]

Not today, no

But throw it to chatgpt

[wet lark]

It is giving errors

[left knoll]

Hold on

Mode: Advanced Problem-Solving

For a matrix to be invertible, its determinant must not be zero. Let's first calculate the determinant of the given matrix to find the value of ( k ) for which the matrix is invertible. Once we have ( k ), we'll calculate the inverse of the matrix when ( k = -2 ).

I'll run the Python code to determine the determinant and then calculate the inverse if possible. Let's begin.

The determinant of the given matrix is ( 2k + 2 ). For the matrix to be invertible, this determinant should not be zero. Solving ( 2k + 2 = 0 ), we find that ( k ) must not be equal to ( -1 ) for the matrix to be invertible.

Given ( k = -2 ), which is not equal to ( -1 ), the matrix is indeed invertible. Here's the inverse of the matrix when ( k = -2 ):

[ \begin{bmatrix}
-1 & 1 & -3 & -3 \
-2 & 1 & -1 & -1 \
-\frac{1}{2} & 0 & -1 & -\frac{1}{2} \
-\frac{1}{2} & 0 & 0 & \frac{1}{2} \
\end{bmatrix} ]

Now you know both the condition for ( k ) to make the matrix invertible and its inverse when ( k = -2 ).

Ill print the matrix lol

See if it works

@wet lark

[wet lark]

...

Is it the solve ?

just this

not equal to -1 ?

I thought we have to find an interval

[wet lark]

thank you so sooo much

🫶

[candid rivet]

Well just so you know, actually almost every matrix is invertible (take random numbers and you'll almost everytime get one that is invertible)(the reason being that you need to have the determinant differant than 0, which is really likely)
So the solution being interval would be very surprising

[wet lark]

ohh thank you , I didnt know that.

[remote terrace]

Can someone help me solve question number 11 and 13 please 🙏

[left knoll]

11: a pyramid has everything to do with triangles. Draw the pyramid as described and try to make sense of the triangles that compose it

That goes for 13 too

Cilinders, pyramids, cubes etc. Its all about decomposing the 3d object into triangles and squares

[remote terrace]

I tried it yet not sure about answer

[left knoll]

Describe what you did

[remote terrace]

Q 11

Q 13

[pulsar pawn]

Anyone know how to do this question?

Solving for x

[pastel pecan]

Take log

[pastel pecan]

.

[pulsar pawn]

Thx so much

Really helps

[pastel pecan]

profile changed from brown guy to anime girl

[pulsar pawn]

mb bro

[pastel pecan]

no prob Id smash both

[pulsar pawn]

hell yeah

[pulsar pawn]

Same

[left knoll]

Wth is wrong with people

[acoustic crag]

Its not easier to pose x = exp(x) ?

*ln btw

[acoustic crag]

Mb you did the same thing with u didnt see

Love u anyways

[vague prairie]

anyone good at graph theory proofs?

i got a discrete exam comming up :*) need sum help

[pulsar pawn]

.

anyone know how to do this?

[weak lotus]

and what do you need?

like find the roots? or

[pulsar pawn]

Derivative

Using either Chain, Product, or Quotient rule

[left knoll]

excuse my handwriting

[pulsar pawn]

how did u get x to power 4?

[pulsar pawn]

thanks

[left knoll]

(5x^2)^2 in the Quotient rule

[left knoll]

yw

[pulsar pawn]

ah I see

[weak lotus]

next time put it into the question lol

did not know what i had to do

[pulsar pawn]

Mb Bro

(┬┬﹏┬┬)

[pulsar pawn]

Can anyone help me find out what's going on in this product rule derivative question?

I don't know what's going on in the last two steps of working out

[left knoll]

took x (x+1)^4 as a common factor

[pulsar pawn]

Are there any methods of doing this?

Other than looking at every single term individually?

[left knoll]

If u did reach here u aint wrong but to make the solution more simplified ( iam not sure if it's the correct word ) u could take the least common factor which was the (x)
And the (x+1)⁴

[pulsar pawn]

Ah, I see

Ty so much

[left knoll]

Yw

[left knoll]

U do understand how to solve the homogeneous differential equations in general ?

So what step didnt u get ?

[left knoll]

Not saying it easy but bec i was gonna explainn the whole homogeneous and tho u maybe didnt get something

Nah u r good tbh
Keep it up 🔥

[weak lotus]

i would also recommand getting into taylor series and taylor analysis, which are both techniques to solve DEQ's

and if you have insane amount of time

get to greens functions

mine works

np

you can print it? lol

second hand college book stores are a wonderful option to

first hand are to expensive imo

[left knoll]

Was gonna mention u fr

[maiden helm]

i need help learning how to solve 8), i have the answers for 8 but i dont understand it at all

[left knoll]

thats de morgan theory

wait

[maiden helm]

yes

im confused when it comes to the proof

are you ok with hoping on vc so i can screenshare?

[left knoll]

ig u could prove it algebraically , and in truth table too
or there is another way to prove ?

[left knoll]

ok

[maiden helm]

which server vc do you prefer?

[left knoll]

Is there any short ways to solve nearly 1000 problems in 5 hour?

[left knoll]

any , lets go to study room 24

[maiden helm]

oh, im deafened

can i add you and call instead?

[left knoll]

for sure

[left knoll]

What kind of problems ?

[left knoll]

Thats less than 20 seconds per problem

Unless you've got a first grade sheet of 2 + 2 and 7 + 5 problems, Id say just bite the bullet and flop it

You could maybe also use chatgpt, but if it is a test that would be unfair

[ember notch]

How do you even get into that situation

[left knoll]

Please help if you have some time!!

[dire aurora]

Can someone please show me the connection between these two problems? I am trying to understand why the word 'hence' is used and how the working for part (a) should help with part (b).

[vagrant gale]

One message removed from a suspended account.

[dire aurora]

I know how to do a) and I know how to do b). the methods are different from eachother. How are they related?

for a) its -8 + 6i = w^2 and w is complex due to FTA and so you have -8 + 6i = (a+bi)^2 and you solve simulataneously

for b) you can factor, complete the square (twice, really) or use quadratic formula, but none of these has something to do with the method used for a)

[acoustic crag]

hey

somoene can resolve this ?

to see if we got the same result

ty already

[woeful creek]

hi im stuck on this question. the second image shows the worked solution but i don't get their approach like the use of the derivative and where the 2x even came from and how its relevant to solve the integral? im so lost i dont get the approach at all. someone who could explain this to me please? 🙏

[whole oak]

its using subsitution method

to get the integral

where t = (1+x^2)^-1

[outer pond]

have you studied the substitution method to solve integrals, if you have then you can understand it easily but if you dont get it you can see my solution maybe its more easy to understand idk and for the 2x, it comes from the chain rule of differentiation i.e. [d fog(x)/dx= f'(g(x)) * g'(x) ]

[dire aurora]

Can someone please show me the connection between these two problems? I am trying to understand why the word 'hence' is used and how the working for part (a) should help with part (b).

[acoustic crag]

I dont really get where there is a connection actually it seems that you can do a without b and b without a ...

[soft kernel]

@dire aurorai mean...z is usually the complex number and the square root from a is also a complex number...so maybe that z is the solution of A

ill try n solve wait

[soft kernel]

it isnt working

[acoustic crag]

I check and you can't do b actually

so you really need a

I'll check this again later

[dire aurora]

You can do b; its just a bit hard. Just don’t see the connection

[dire aurora]

A was pretty easy, yeah. Just don’t see how it can help with B

[acoustic crag]

How you doing for b without a ?

[dire aurora]

Quadratic formula or completing the square

Completing the square is bit tricky; you basically have to construct a second square binomial

[acoustic crag]

I don't think it was what this ex was meant for

[dire aurora]

Yeah, seems like you were supposed to do it with a), and the coeffiecient (1-z) seems to be a pattern to exploit

But i have no clue how

[acoustic crag]

What did you find as a sqrt for a @dire aurora

[woeful creek]

thank you so much!! it makes a lot more sense now. i wasnt sure of how to apply the substitution method before but i see it now. i really appreciate it thank you 🙏

[woeful creek]

thank you🙏

[left knoll]

Can someone help me out to solve this? I've been cracking my head opened

You have two wells which give the following analyzes for water samples:

Well No. 1: Has 132 sodium mg/l and 146 mg/l. This well yields 13 cubic meters/day.

Well No. 2: Has 133 sodium mg/l and 144 mg/l. This well provides a capacity of 12 cubic meters per day.

How much of that well water can you use in a reservoir that holds 40 cubic meters where 67 cubic meters of clean water will be mixed in order not to exceed the limit for human health, which is 100mg/l?

[deep edge]

Good day everyone, I have a question about probability, I am just so confused here. In conditional probability, how will you know what you'll put on the numerator and denominator?

[candid rivet]

Are you talking about the "probability of A knowing B" ?
If yes then I just remember that it is P(A∩B) on the numerator, and "knowing B" is the thing that makes this probability special, so i know I have to divide by P(B) (and not P(A))

[acoustic crag]

You forgot to divide by 2 I guess ? I find that delta is equal to 0

There is a two before the y''

[candid rivet]

oh sorry I didn't see the 2 😵

so it is (X+3)^2 (so delta=0 yes) and solutions are in the form

x(t)=(A+Bt)exp(-3t)

and you should find A=1, B=4, so :

x(t)=(4t+1)exp(-3t)

[acoustic crag]

thats what I found

[acoustic crag]

Ty hehe

[candid rivet]

niceee

[soft kernel]

hope this helps!!

[left knoll]

using bodmas shouldnt you multiply first?
why did he add the r first and not times the P by 3 first?

if its a triangle aint it 1/2 base x height

[wild gull]

you're just changing the subject of the formula, not carrying out operations

bodmas will not apply here

2 ways to look at this

if you do it intuitively, you see the acceleration increases at a steady rate. Acceleration is the slope of a v-t graph, leading to a curve in its case. As acceleration increases, the velocity between now and the next second will have a greater difference than between that of the last second and now.

the s-t graph will more or less be the same. velocity is increasing faster and faster with each time step, meaning s-t will be a curve

in reality, the curves will be different
i'm guessing s-t's will be steeper becuase s changes even more relative to acceleration

2nd way is to pop it into a graphing calculator.

(for the first 5 seconds) integrating to get a formula for v will give 3t^2
integrating v's formula to get one for s, t^3

(oh dear I ignored constants)

if you had more info you could determine the constants, but, just to have a rough idea:

[soft kernel]

just integrate

youll get an eqn substitute the t values...see how the graph changes

then the obtained eqn after integrating,integrate again to get p-t

here p stands for position

[old moat]

Can someone please help me with part b?

[autumn brook]

First calculate the slope at C, then find the point on the x-axis, calculate the triangle between C, the point on the x-axis and the point on the x-axis below C. Then integrate from the point where the curve hits the x axis till point C

[old moat]

tysm for ur help

[cyan ingot]

Yo chat how can I salve this

A store stocked 150 cans of popcorn for a weekend sale.
That weekend, 72 of the cans sold. What percent of the cans of popcorn stocked were sold that weekend?
A. 2%
В.
5%
C. 48%
D. 72%

[wild gull]

you wanna do a lil 72 ÷ 150

then multiply that by 100

[mental moth]

some1 help prove this trig identity

[mental moth]

yooo tysm man

[left knoll]

guys help, im stupid

[acoustic crag]

Aya bro the handwriting I can't send the question pls

[acoustic crag]

No offense btw I think mine is worse I can't even read what I write

[left knoll]

I need to find cos2a if sina=0.75

and 0<a<90

[polar glade]

cos2x=1-2sin^2(x )
sinx= 3/4, sin^2(x)=9/16
cos2x=1-2.9/16
= -1/8= -0.125

[left knoll]

ty bro🩷

[left knoll]

@candid rivet just very random but im doing something random . i dont know weather you'd like to partake. its a maths paper that we get for gcse its a grade 9 aswell. i just want to see what mark youd get seeing that your good at maths. its just for fun you dont have to do it if you dont want to

[candid rivet]

humm ok maybe why not if it's not too long !

[left knoll]

do u want non calculator or calulator

acc its probably going to be too easy ,ill send you a sample question

@candid rivet

[candid rivet]

sorry what does "acc" means ?

no calculator if possible please

[candid rivet]

looks doable

[left knoll]

sorry for that it means actually

i think this question is the one at the end of the paper meaning it will always be hard

[mental moth]

does anyone know a good like video series on precalculus probability. im taking a summer course on precalc so i can do calc next year, but the school's course has a probability unit and my online course doesnt

[candid rivet]

oh ok thx

yes might be a bit easy, is grade 9 last year of high school ?

[left knoll]

no basically that is like a grade determining test results

our score

[candid rivet]

ohh okay cool

[weak lotus]

organic chem tutor, khan academy, 3blue1brown

[median venture]

maths/chemistry (binomial distribution) . not sure why but i can't figure out how to answer this, using the formula i was taught: x^N * N!/n!(N-n)! gives a math error

[candid rivet]

the right formula is :

p_k = n!/k!(n-k)! * p^k * (1-p)^(n-k)

where p is the probability of "success", n is the number of molecules

Here, you have n=100, p=1-p=1/2

[median venture]

thank you

[random atlas]

💀💀

Help

[candid rivet]

It's called Fresnel Integral, it is really hard and pretty advanced to calculate

If you really want I can send you a proof in french

but the main idea is to work with complex integrals, and find a differential equation, and at the end you have to prove that a certain function is continuous at 0 which is pretty hard to prove

if you just want the value it's sqrt(2 pi)/4

[random atlas]

Sqrt(pi/8)

Some really good student in our class did it

He used function named lapace or smth then everything came to a double integral then he applied the taylor series

From there he got this

[random atlas]

Yea i would really appreciate that

[candid rivet]

there you go

[random atlas]

Thanks

If you got any good resource on vectors, matrices and determinant, please share that too

A single pdf would also help

[candid rivet]

sorry i don't have any of this
If someone knows please share !

[fast heath]

friend sent me this does anyone know how to solve it?

[median venture]

How would I approach this?

[versed sapphire]

hello any help with this equation for X being a rational number find X:
1 + X = 2

[barren vine]

im sure you can try and find by yourself

just put X on a side and all the numbers on another side

[versed sapphire]

well the only thing u can add to one to get two is another one but does that mean X = 1 ? if so why the equation is not X+ X = 2

[random atlas]

Oh okay no prob

[acoustic crag]

mmmh well it is actually X is what you want to find so its gonna verify the equation in our case X = 1

[acoustic crag]

What you can do (I think its better btw) its that to find X you put the 1 in the other side so it become negative the goal is to isolate the x : X = 2 - 1

[acoustic crag]

Think of b as K and derivate the rest (r)

[acoustic crag]

@wet creek spam

[wet creek]

thanks!

[hushed flax]

is there a statistics related channel?

[dire aurora]

Can someone please show me the connection between these two problems? I am trying to understand why the word 'hence' is used and how the working for part (a) should help with part (b).

I know how to do a) and I know how to do b). the methods are different from eachother. How are they related?
for a) its -8 + 6i = w^2 and w is complex due to FTA and so you have -8 + 6i = (a+bi)^2 and you solve simulataneously
for b) you can factor, complete the square or use quadratic formula, but none of these has something to do with the method used for a)

[void gull]

i believe its because when using the quadratic formula, the discriminant probably evaluates to be -8 + 6i, and since the formula requires you to find the square root of the formula, you can use your part a answer in part b

[dire aurora]

thank you so much. I wasted so much time on this question. that thought did occur to me but I kept maybe the same algebra mistake and didnt notice the discriminate is -8 + 6i

[mental moth]

i am considering getting really serious into competition math. i am a sophmore in hs and the math team starts up again in late october/early november. what books should i buy, or videos i should watch, or resources i should use to succeed

[candid rivet]

not sur if the question is to calculate the area of the rectangle, but i guess it is since it works

[left knoll]

Anyone that can help me with this? I don't understand the regularization method im used to standard L1/L2 Norms

(Halo stands for human aware loss function but thats not relevant to my question, the SLiC algorithm doesnt have to do anything with it)

[left knoll]

can someone please explain the solution

[left knoll]

i can in a call if u want

sure

[left knoll]

come study room 20

chill room

im here

can u talk or

yes

1 sec

[left knoll]

why is this squared rooted? is it because we're doing the reverse?

[candid rivet]

the fact that the images are mathematically similar means that their width and height are proportional

[quartz dune]

Hi guys can u help me?

[scenic notch]

can anybody help me with part e of this question? Your meant to turn a 3x3 matrix into a 4x4 but i dont get why or how?

[scenic notch]

nvm i got it

[candid rivet]

what are you supposed to do ?

[quartz dune]

determine the order of the element in the body K

[candid rivet]

Is the order the minimum integer k such that a^k=1 ?

If yes I've calculated a^k for k up to 10 and still not

[quartz dune]

Like this

[coral hornet]

Guys, I'm really stuck with this math problem, and when looking at the answer I just dont understand how that can be the answer? can someone explain?

And this is the correct solution shown in the book

Why does 4 change place?

[ember garnet]

it's just using the commutative property, the result will be the same either way

[sacred marsh]

I don't get what you mean

There is a 4 in the denominator and the numerator in both LHS and RHS

[coral hornet]

omg thank you sooo much I was overthinking it too much I guess. Thank you !!!

[ember garnet]

you're welcome :)

[pastel helm]

Anyone have. Elements of Partial Differential Equations-Ian N Sneddon solution manual?

Solution of the 4th question, anyone?

[short zinc]

Can anyone help me with this idk how to do

[modern lotus]

Is this good ? The teacher doesn’t give us the answers

[left knoll]

What is Sum(fx)?

Most of this looks illegal but maybe I just dont understand it yet

[modern lotus]

It’s in French sorry

But it weight + air resistance

[left knoll]

Ye its all good ill translate it with gpt 4

When I get home

It looks like you broke this [rule] (https://math.stackexchange.com/questions/1525791/differential-equations-how-does-separation-of-variables-really-work) to me (not saying you are wrong, but maybe you are gay)

Ill take a look at it when I get home

Looks interesting

Some dx/dy shenanigans

[modern lotus]

Gay?!

[acoustic crag]

T'utilise la seconde loi de Newton

et ensuite tu pars du principe que l'acceleration c'est une derivé de vitesse sur temps

et t'obtiens ton equation differentielle en rearangeant les thermes

et pour la resoudre c'est une equa diff de premier ordre avec second membre donc t'applique tes formules

I'm sorry tho but i'm french so I think its better to explain in french

[modern lotus]

T’en fait pas merci beaucoup pour l’explication

La prof a enfin répondu à mon message après 8 heure et elle m’a dit que la seule erreur était m’as référence

[tiny isle]

C'est une leçon du 2eme année bac ou de la 1ère ?

[weak lotus]

is thats second semester first year that would be kinda wild ngl

[tiny isle]

Yeah frr

[weak lotus]

normally gets given in the first semester under the course "general mechanics"'

[tiny isle]

We had in the first Semester of the 1st year Under the course Epp

But it defenitely didn't have that dv and dt

It was Epp=mgz+c ig

[acoustic crag]

@tiny isle and @weak lotus its a lesson from first year

Second semester

[tiny isle]

1 bac?

Quelle filière ?

[acoustic crag]

premiere année post bac licence de physique chimie

[acoustic crag]

T'as pas ca en trmnl lol

[acoustic crag]

Ou prepa MPSI et PCSI

[tiny isle]

Oooh thank god, i got scared

[acoustic crag]

No no lol np physics in last year of school is way easier even tho you have to work cuz the BAC is not that easy

[tiny isle]

Yeah but it actually depends on the "filière"

[acoustic crag]

If you have physics in term it only can be a speciality

[acoustic crag]

You cannot have physic like that you choose it there is no "filliere" anymore here its more American , you choose your speciality

[tiny isle]

Yoooo, that's great

I hope they would do the same thing here

[acoustic crag]

Where do u live ?

[tiny isle]

Morocco

[modern lotus]

Cegep , un système bizarre qu’on a juste au Québec

C’est avant le bac

[tiny isle]

C'est fou

[modern lotus]

Je devrai commencer l’uni l’année prochaine mais j’ai aussi une année préparatoire avant le bac

[modern lotus]

Nice, my native country

[tiny isle]

No way

[modern lotus]

Yes way

[tiny isle]

Hhhhhh

[tiny isle]

Were u there since childhood

Or went for studying?

[modern lotus]

Spent 2 years when I was one and lots of summers there, born in Canada but my parents are both Moroccan

[tiny isle]

Have u ever thought abt coming here?

[modern lotus]

Maybe after I get diploma

[prime zephyr]

Hey, I'm not sure whether this is the right place for programming questions but: I need to implement the secant method to approximate the root of a function. One of the given functions is f(x)=tanh(x) with initial values x1=-1 and x2=3. This leads to the output NaN because of the asymptotes of tanh. I asked the tutor for help and he told me that if I make the method return an error message for f(x1)*f(x2)>0, all cases with asymptotes should be solved. As you may guess, that didn't work. I asked chat gtp, which implemented an if statement leading to the root becoming infinity. I am at my wits end and could use some help. Here is my code:

double secant(double x1, double x2, double (*func)(double), int &schritt, const double tol )
{
double xn; // Variable für die lineare Approximation
schritt = 0; // Schrittzähler für Konvergenzgeschwindigkeit
//triviale Lösung
if ( func(x1) == 0 ||func(x2)==0)
{
std::cout<<"0";
}
//checken ob f(x1)*f(x1)>0 => return 0
if (func(x1)*func(x2)>0)
{
std::cout<<"Bedingung nicht erfüllt\n";
}
do
{
// Berechne neuen Wert für die lineare Approximation
xn = x2 - func(x2) * (x2 - x1) / (func(x2) - func(x1));

    x1 = x2; // für die nächste Iteration: x2 -> x1
    x2 = xn; // xn -> x2
    schritt++; // Inkrementiere
} while (std::fabs(x2 - x1) > tol); // Iteration wiederhohlen bis gewünschte Genauigkeit erreicht wird

return xn; // Ergebnis

}

Here is the code from chat gpt:

double secant(double x1, double x2, double (*func)(double), int &schritt, const double tol)
{
double xn; // Variable for the linear approximation
schritt = 0; // Step counter for convergence speed

do
{
    // Calculate the new value for the linear approximation
    xn = x2 - func(x2) * (x2 - x1) / (func(x2) - func(x1));

    // Check for NaN or extremely large values
    if (std::isnan(xn) || std::fabs(xn) > 1e10)
    {
        // Adjust interval away from asymptotes
        double mit = 0.5 * (x1 + x2);
        if (func(mit) * func(x1) < 0)
            x2 = mit;
        else
            x1 = mit;
    }
    else
    {
        x1 = x2; // Update for the next iteration: x2 -> x1
        x2 = xn; // Update for the next iteration: xn -> x2
    }

    schritt++; // Increment step counter
} while (std::fabs(x2 - x1) > tol); // Repeat iteration until desired accuracy is achieved

return xn; // Result

}

[modern lotus]

Maybe #tech-related-help

[royal valve]

Can someone help me solve this problem? I have an exam next week 🥲

Solve the equation f(2x)-3=0
If f(x)= 2x^3-9x^2+3x+17

[eternal quartz]

can i ask physics question in here?

i cant find a chatroom gor that

[weak lotus]

science help?

what do you need help with

[weak lotus]

fill in 2x for all x and subtract 3 at the end

2.(2x)^3 - 9.(2x)^2 + 3.(2x) + 7 (-3)

[royal valve]

THANKS

[south void]

Yo can someone help me with this?
for the one on the left you have to mark the edges so that you can see the groundfloor.
for the one on the right you have to mark the edges so that you can see

[silver coral]

do u have tips on how to memorize the calderwood equation?

[slender temple]

https://cdn.discordapp.com/attachments/1033736632538501121/1237502111957127362/image.png?ex=663be127&is=663a8fa7&hm=d7be640302cffb3c59b5d20e728467d32347a83fc4b5aa2eb5af13c7435832b7&

how did the -x appear?

[wispy pendant]

It s an error

There is no minus

Oh no

It s because you re in - infinite that’s why

[slender temple]

do u mind if u could explain the process of getting to -x?

[wispy pendant]

Ok let me ask you a question

Do you know wether or not the value of this expression after the square ?

We’ll limit go to minus infinite

So it seems that without square the value is minus x

But if you had for example

X got to plus infinite

So it s positive for a given x

Any x

Because it s positive

[grizzled dust]

for this question to get x would just isolate the x and plug the y values get to the x values then using the first deriv u can solve to get the slope?

[glossy garnet]

its been awhile since ive done these but iirc y = mx + b and m is ur slope

I think there is an equiv for that with higher order stuff

[mystic thunder]

how

[drifting umbra]

yes tht is correct

ull get 1/2

[mystic thunder]

thank you so much

[grizzled dust]

would b be the correct answer for this
i got 4cos2x but it wasnt in friction form

i didnt get the 1/x

[untold comet]

Is anyone familar with law of sines and law of cosines

[drifting umbra]

what is the question?

find the derivative?

[grizzled dust]

i found the answer already

@drifting umbra

[cunning spear]

Does anybody know where I can find an IB MYP math study sheet or something like that??

[ancient pike]

no coding help guys 😂

[left surge]

I would like to hear what your experience with the Accuplacer was like.

[brittle sleet]

There should be fr

[ancient pike]

yes i agree

[remote terrace]

How can i find the radius of the sector???

[terse meadow]

AB = GF + FD +DE
So FD = AB -GF-DE
And FD is the diameter so you need to divide FD by 2 to have the radius

[remote terrace]

Thank you 😃

[wary bison]

If f(x) is the yellow like and the tangent of f(x) is the green line . Then what is the area which is surrounded by f(x) tangent of f(x) and the X axis ?

Like respective to the shape I can calculate the integral I just don't know which one is it

My assumption is that I integrate from the common point of tangent and X axis and the common point of tangent and f(x) is that correct?

[brittle sleet]

DE or DC?

[terse meadow]

Thanks for the correction it's DC

[terse meadow]

I have made a mistake it's not DE it's DC, sorry you can thanks @brittle sleet he find the mistake he is a hero

[brittle sleet]

Hardly haha

[waxen granite]

how do we find out an integral of a square function using a right riemman sum?
for example how do we find the integral of (f(x))^2 dx with a table of
x f(x)
1 3
3 7
5 11
7 17
using a right riemann sum with 3 equal subintervals

[remote terrace]

Thank You for finding the mistake 😄

[glass matrix]

Someone please help 🙏

[weak lotus]

taylor expansion

find the taylor expansion of sint(t^3) plug it into the integral

and since you will get coefficients who only depend on t, if you fill in 0, you will get 0, so therefore, only plug in x and you have it

[weak lotus]

you do this by finding the taylor expansion of sin(x)
but x = t^3
so everywhere there is an x in the formula, you fill in t^3 and expand further

[silk abyss]

anbody could tell me why 1 is wrong. I think it might due to being an assumption?

the correct ans is C

[limpid crane]

even the derivative is inc and positive

[fierce spindle]

Hey guys, I've got a concept doubt about the parameters of the plane equation. Since I've started studying analytical geometry, I've noticed that the parameter "t" in the equation of the line means (I don't really know, this observation might have errors) what place am I on the line (and the interval 0 <= t <= 1, on the vector).

Look at this picture:

.

But then I started learning about the plane equation. It has two parameters, t and h. Anybody could tell me what of these parameters (t, h) means in the plane parametric equation?

[deft apex]

Does anyone know about any sources/books that talks about One Relator Groups?

[rain solstice]

am i dumb this looks so easy but in reality 💀

[tame coral]

When is it permissible to exchange the derivative and the limit of a function from $\mathbb{R}$ to a Banach space?
In the scenario where we compute $\frac{d}{dt} e^{tT}$, with $t$ belonging to $\mathbb{R}$ and $T$ belonging to $L(X)$, where $X$ is a Banach space.

[candid rivet]

No this looks hard imo xD
I don't know how to solve it, but you have to show that ti+tj > tk for all i,j,k

and the big product is greater than n^2 by cauchy schwarz inequality

but good luck lol

[candid rivet]

do people actually click on this ?

[pulsar jacinth]

Hi, please help. It's in spanish but here's the translation: The temperature T at each point (x;y;z) of a rectangular box is given by T(x;y;z)=500 / (x^2 + y^2 + z^2) , in which x,y and z are in meters. Determine the rate of change of the temperature T at (3;4;0) in direction to the point (3;7;4).

[stiff skiff]

cos 45 divided by sec 30 + cosec 30

help

[silent pulsar]

if i understood correctly its ΔT(l) =(500/(3^2+7^2+4^2)-500/(3^2+4^2)) / sqrt(3^2+4^2)

so (500/74-500/25)/5 = (6.75675675676-20)/5 = -2.64864864865 Celsium per meter(in that direction)

[acoustic crag]

Sec ?

[silent pulsar]

cos(45)*(1/cos(30))+1/sin(30)= sqrt(2)/2 multiply 2/sqrt(3)+1/(1/2)=
sqrt(2/3)+2

[weak lotus]

secans

[kind sky]

why cant i post images on this channel

[edgy leaf]

can someone help me with mathematical logic, please?
"demonstrate through the resolution method"

[noble shoal]

hey that's associative law

[alpine marsh]

PLWASE I NEED HELP

MY EXAM IS TOMOrrow

Can someone help me

Different job of exponential and logarithmic functions

Plz if ur good at math

Text me

Bc I can’t send the question here

[mystic thunder]

plsplspls help me w this question

the answer is 2 btw

[heavy blaze]

300000000

[heavy blaze]

innit??

[mystic thunder]

noop

it's okay though I got it

[heavy blaze]

can u tell me how did u solve it

[mystic thunder]

sure

[next vigil]

4

[mystic thunder]

man

the answer key says 2 I think the answer key is wrong

[mystic thunder]

bro used paint 😭😭😭

alr thank u

somuch

[cosmic kestrel]

I can help you)

[alpine marsh]

Thanks but I did my exam alr

[eager shore]

hi , so i have a question i hope sm1 would helpme .

[cosmic kestrel]

ask your question

[prime solar]

Does anybody here have mathematical statistics?

[eager shore]

oh i asked my teacher about it today , THANK YOU

[grand holly]

Hello there,
anyone here a specialist for mathematical induction? I got some mathematical induction problems troubling me.
Any kind of help appreciated.

[cosmic kestrel]

clarify your question please

[weak lotus]

those kinds of questions are mostly reproduction

and

1. use some insight, i mean mathematical tricks, short cuts
2. just calculate left and right hand side to proof its true

[grand holly]

This is the problem that am working with, i got this far so far and i don't know where am I making a mistake.
thank you for the help

[weak lotus]

im not a mathematician so there might be some wrong mathematical build up

like not the official rules for induction

but the core is there

[grand holly]

OH I SEE, thank you very much, you seem more like a mathematician than me, so thank you very much once more

[weak lotus]

Your very welcome

[left knoll]

how to know when to multiply and when to add in combination

[cosmic kestrel]

do you have an example?

[left knoll]

yeah sure wait

[left knoll]

https://www.teachoo.com/2400/609/Example-19---What-is-number-of-ways-of-choosing-4-cards-from/category/Examples/

This is the question in the 1st part of the course we are adding the combinations whereas in the 2nd part of the ques we are multiply it also in 5th part we are multiplying it why?