math-help

[fair belfry]

ohhhhhh

[past crown]

lmk if that helped

[mystic thunder]

wait lemme try

[fair belfry]

wait i just got it

tysmm

wait nvm

i didnt finish i only solved part of it 💀

[mystic thunder]

💀

[fair belfry]

wait what the

[mystic thunder]

is this right

[fair belfry]

oH

OHHH

ong

bruh..

[mystic thunder]

what

[fair belfry]

i

[mystic thunder]

BRO LCM

[fair belfry]

YEA

im so funny

[mystic thunder]

literally

imwheezinh bro u made my day 😭😭

[fair belfry]

LOL

https://tenor.com/view/only-fans-mario-cursed-gif-22202015

[mystic thunder]

LMFAO

[rigid sinew]

https://tenor.com/view/playboi-carti-carti-playboi-playboy-slatt-gif-16273111

[left knoll]

Umm I don't think this is right...you solved it right upto y=-1,9
But then solve (2x-3)(2x-3)=9 and not -1 as square of any number cannot be negative(unless it is a complex number)

[chilly flower]

anyone can help? the question asks to prove the identity

so like show the right hand side equals to left hand side

[cosmic kestrel]

cos(2a)=cos(a)^2-sin(a)^2
use this for numerator of left part

[chilly flower]

ohhhhh ok i get it now thanks

[high gale]

how is the root of negative 1 = 1?

[mystic thunder]

but isnt root 1 = 1

i was a little confused on that step

[civic tartan]

im currently learning solid gemotry (volumes of prism, cylinder, cone, pyramid and sphere), Im really lost with all of the formulas and equations, could anyone help/tutor me about this?

[left knoll]

Root 1=1 but root 1!=-1
Always remember .... Square of any number is always positive (unless complex number)

[high gale]

root 1 is 1 but root of -1 isnt 1

[left knoll]

Yes u are right it's i

[mystic thunder]

OH MY BAD

thank you for letting me know

I didnt know lol

[fair belfry]

yeh i ended it up getting it thanks

[lavish portal]

does anyone know how to do this

im dying

[swift lake]

is the correct answer (b) cos?

[native mason]

correct answer is A'

[left knoll]

correct ans is b!
Cos(-angle)=cos(angle)
cos is an even function so -ve sign inside doesnt matter

[swift lake]

thanks!!!

[swift lake]

so u meant (b) is a true statement right?

[left knoll]

yes according to me

[swift lake]

yea no makes sense with what @native mason is saying as well

[left knoll]

false statemne tis a
sorry didnt read the question

[swift lake]

becuase we are tryna find the false statement

[swift lake]

nw bro cheers for the reply

[cosmic kestrel]

understand you bro so much

[wise shuttle]

question: how can one set up a solid foundation before taking calculus?

[lavish portal]

oh my god

[ancient prawn]

Algebra and Trig

Refine both and you’ll have a solid foundation for at least calculus 1

Technically pre calculus as well in regards to limits

A lot of calculus 1 doesn’t necessarily have difficult concepts, but rather the implementation/application is where most people fall short

In regards to trig, understand how to evaluate trig functions without using the unit circle, this helps a ton later on

[native mason]

wha :/

[swift lake]

ahaha I said ur answer agreed with the other guys answer

question 4 pls 🙏🏼

[strange frost]

@swift lake
sec(3x-1)=2/root3
3x-1=sec^-1(2/root3)
sec^-1(2/root3) will have 2 values in its domain 0 to 2pi that will be pi/6 and 11pi/6
then form 2 equations

1. 3x-1 = pi/6
   2.3x-1=11pi/6
   then u get the values 🙂

hope it helps 😄

[swift lake]

thanks bro 🙏🏼

[strange frost]

welcome 😄

[swift lake]

i got six values @strange frost does that sound right?

[strange frost]

😳😳

[swift lake]

that’s my working^

[strange frost]

Wow it's good

[swift lake]

does that look right?

[strange frost]

Looks right , i didn't take the 2npi cause it was already on the domain

Do you have the answer ?

[swift lake]

nope ahaha its an assignment ill send the answer to u when i get it

[strange frost]

Well u did it right 👍

[strange frost]

Ok

[swift lake]

appreciate it bro ill add u

[strange frost]

Oki

[hexed scaffold]

Anyone familiar with KNN and K-means numericals in Data Science?

Also Ridge and Lasso

[ancient pine]

can someone help me find the x ?

[left knoll]

x cannot be 3 or 0 otherwise the denominator will be 0, then multiply both side by x*(x-3) then solve from there

[ancient pine]

i tried man

[left knoll]

X=-1???

[ancient pine]

how??:

[left knoll]

yeah it should be 1

-1*

[ancient pine]

explain pls

[mystic thunder]

yes pls

im stuck as well solving haha

[left knoll]

welp the sol is actually quite simple

[ancient pine]

write it down pls

[left knoll]

2/(x*(x-3)) + 1/x = (x+3)/(x-3)
=> 2 + x - 3 = x^2 + 3x
=> x^2 - 2x - 1 = 0

[ancient pine]

wait x^2 and -x^2 is one?

[valid moon]

Guess this is it

Used additional steps cuz no idea why

[left knoll]

oh lol i messed up at step 2

it should be -x^2

[ancient pine]

man

[left knoll]

then multiply both side by -1 and you get x^2 + 2x + 1 = 0

[left knoll]

I approve that's what I did @ancient pine
But in my brain 😂

=> (x+1)(x+1) = 0 and x = -1

[valid moon]

Gud gud but kid needs to understand so ya

[left knoll]

i messed up sign sometimes 💀

[mystic thunder]

u lost me at the second step

[left knoll]

Ya sorry for that

[mystic thunder]

wel third w

[valid moon]

Breh-

[mystic thunder]

what did u do bro

[valid moon]

Uhh the lcm part or beneath it

[mystic thunder]

I started rationalising omg 💀

OH MY GOD

[valid moon]

What kind of drugs-

[mystic thunder]

jeez

how did u lcm

[ancient pine]

thx btw:

[valid moon]

Literally multiple x to 2 and x² -3x to 1

[ancient pine]

@left knoll and u too

[valid moon]

And the denominator will have both of em together

[valid moon]

👍

[mystic thunder]

crazy vro im going back to middle school

thanks though

[valid moon]

Lol

Hold up this place doesn’t have slow mode 😱

[left knoll]

be careful with signs they can give you wrong answer 💀

[mystic thunder]

yeah correct^

[ancient pine]

ok:

[mystic thunder]

ir changes everything 💀

[valid moon]

Literally the most stressful way to lose marks indeed

[left knoll]

TRUE

[valid moon]

And when u misread stuff like 8 and 3

I kinda misread it sometimes

Extra stress

[left knoll]

unless you have good hand writing

yeah

[valid moon]

The question paper

[mystic thunder]

dude same

[left knoll]

oh 💀

[mystic thunder]

I be copying the wrong question

it's crazy

[valid moon]

Calculator lookin handwriting

For numbers

[mystic thunder]

I lost so much marks

[valid moon]

Exactly

The number of times I tried convincing my teacher to gimme at least like 2 marks for getting the right answer for the misunderstood question

[mystic thunder]

SAME

my tution sir was nice enough to do it

but I got scolded like crap

[valid moon]

Such a gud sir Omg

[valid moon]

Wait Wha-

Nvm

How long was the lecture

[left knoll]

do you guys like geometry

[valid moon]

50-50

[mystic thunder]

which lecture

[valid moon]

I’m lazy to construct geometry stuff

[valid moon]

Lecture cuz u copied the wrong thing and asked for marks

[mystic thunder]

well 1 hour

[left knoll]

sometimes it's easy and sometimes its not

[valid moon]

That’s-

Very little indeed

[valid moon]

True true and when I mess up I wanna run away cuz have to redo it all over

[mystic thunder]

it's tution bro

[valid moon]

That’s still a lot breh

[mystic thunder]

one - one and half hour is enough

[valid moon]

I expected 20 min

[mystic thunder]

damn

[valid moon]

Wdym

[mystic thunder]

im saying that tution for 1 or 1 hour 30 mins evedya is enough

[valid moon]

Ohh

Fair enough ya

I meant u getting scolded tho

[mystic thunder]

OH

the whole timw

while he was checking

[valid moon]

How long

Duration

[mystic thunder]

like 30 minz approx

[valid moon]

That’s longer than expected 💀

[mystic thunder]

its ok im used to it

[valid moon]

There’s worse than that- ?

[mystic thunder]

no he doesnt scold very long but the quality 🙏

[valid moon]

Wdym by “quality”

[mystic thunder]

when he scolds he scolds like shit it seems worth 2 hour long

[valid moon]

So it hurts ur ego to the point u wanna say something?

[mystic thunder]

no it doesn

[valid moon]

So wot annoys u then

It’s for science

[left knoll]

🤯

[mystic thunder]

nothing does tbh

[valid moon]

Then how did I annoy u

I don’t remember wot I did

[mystic thunder]

i was kidding

[valid moon]

U-

I give up.

U win.

[mystic thunder]

thank you so much oh my god i need a medal

[valid moon]

On god bro ✊

Ask zoe

[left knoll]

wha

[valid moon]

Kid needs a medal

Guess u gotta find one now

[left knoll]

wat medal, what just happened

[valid moon]

Blame woot ig

But u kinda need to find a medal

[left knoll]

hmm like what kind of medal

[valid moon]

A medal that goes around their neck but doesn’t kill em

Yes

[left knoll]

yes

🏅

[valid moon]

Ggz.

[mystic thunder]

thanks bro

denny cant give me a medal for gods sake

its too heavy for him apparently

[left knoll]

you're welcome

[valid moon]

Nah then how am I holding I phone breh-

[mystic thunder]

medal so good it heavy than mobile

[valid moon]

Then how is ur weak ahh able to wear it

Also we won’t have wrick lady pinging the mods on us for conversing here right

[serene bronze]

anyone has tips to ace my maths exam its 5 days from now help ;-;

[mystic thunder]

vuz im stronk

[valid moon]

Gah damn bro u should honestly carry my Uni bag around for me

If anyone calls me out for child labour just tell em you’re an adult

Fair?

[mystic thunder]

i gotchu

no one will doubt

[valid moon]

Gg ez

[valid moon]

Right the whole height difference finna be invisible fr

I’ll just tell em I’m sick ig

[mystic thunder]

nah they wont doubt

[valid moon]

That’s chill then

Dw theres like 3 books in it and a laptop

The rest are lightweight

[mystic thunder]

ez bro

[valid moon]

Very very strong indeed 💪

U should also carry by basketball and skateboard

[mystic thunder]

ez

[valid moon]

Light work

I agree

[mystic thunder]

but my hands smol

[valid moon]

That’s alr

Wear the bag

Both straps

One hand basketball

One hand skateboard

Or just ride my skateboard along gg ez

[mystic thunder]

wow nice

YES

[left knoll]

can you guys stop

[valid moon]

But why

[mystic thunder]

blame @valid moon

[left knoll]

ok nvm

[valid moon]

Hell nah.

[left knoll]

💀

[valid moon]

Confused af

[mystic thunder]

great

[broken hinge]

what has math helped turned into

[valid moon]

That’s what happens when slow mode doesn’t exist in a channel 😭

[mystic thunder]

he's doing the math about how I can carry 3 of his things and distribute the weight accordinly so I don't fall

physics lowkey

[valid moon]

On god bro imagine being Smort

Ya we should prolly switch channels don’t wanna get warned

[silver pier]

how would i go about solving 3 a and 3b,
note: ques: 2 is the table

[cosmic kestrel]

maybe you would post also question two if it's mentioned

[left knoll]

is n a function

[cosmic kestrel]

looks like some measure on the set or even probability measure but I have to be sure from 2nd problem

[left knoll]

ahhh

[cosmic kestrel]

ok I found that's it's enough for them just to be random measure. Then N(E)=N(A)+N(E/A)=N(B)+N(E/B)=N(A U B) + N((E/A) П (E/B))=N(A П B)+N(A/B)+N(B/A)
And lot of another identities, just use disjointed sets

[left knoll]

ez

[silver pier]

thats the table

my bad, it got cut from the ss

how would i go about solving no.3 in an effective way

[peak comet]

This looks difficult

[left knoll]

anyone have experience with kangaroo maths?

[cosmic kestrel]

one just says if sets disjoint then their total "area" is sum of their "areas". And " area" of empty set has to be 0.

[wise shuttle]

ohh okay thanks 👍

[wooden sky]

Hi, does anyone know how to use RStudio?

I have to make a comparison between postures and characters.

[wooden sky]

here is the document

[wooden sky]

there are 97 lines

thank you for your help

[pale sigil]

What do you want to do with the data?

[wooden sky]

make a comparison between posture and MBTI

[pale sigil]

What a comparison?

Just numbers and stuff like that؟

Or you need diagrams and drawings

My job is related to these things

If you want, send me the csv file of the data

I can help you with Python

It calculates the average and the maximum, the minimum, or any scale you need for comparison, or draws a graph for you

[wooden sky]

I need a diagram, thank you for your help

[pale sigil]

It must be with RStudio?

[wooden sky]

yes with Rstudio if it is possible for you.

[pale sigil]

I am not very familiar with R Studio, but if you are free to calculate with other things, I can help you

[wooden sky]

is it feasible to use excel ?

[pale sigil]

yup

Select all the data and click on the graph option in the insert tab, where you can choose its settings

[wooden sky]

OK, thank you very much

[hexed inlet]

hi

does anyone here can teach me in numerical reasoning ? thank you

[quiet bramble]

how to solve - prove that (sin A + sec A ) ² + ( cosA + cosecA )² = ( 1 + secA cosecA)²

and also how do i get better at maths in less than 2 days

[barren crown]

assuming ur prolly giving 10th boards imo u should watch pw marathon series it started yesterday ull have to catch up a bit but yea or just learn the basics of a chapter and solve pyq and sqp

[plain gazelle]

can someone help me solve this algebra question?

[tacit vine]

Solve the parenthesis first divide by 260 and divide by 100

You always have to solve for parentheses first

[plain gazelle]

i got 0.01664

[plain gazelle]

muchas gracias

[thin nimbus]

does anyone know how to solve this

A water wheel with diameter 3 m is used to measure the approximate speed of the water in a river. If the angular velocity of the wheel is 15

[manic rose]

whats the rest of the question

[thin nimbus]

what is the speed of the river in kilometers per hour

[strange rampart]

velocity of the river= Angular velocity times radius of the wheel

the units of angular velocity should be in rad/s if its rpm or something u must convert it

u will get the answer in m/s

[fleet crest]

I'm solving previous year questions but 15 days prior to when boards started i was informed that from basic maths i have to give standard maths and i couldnt get much time to prepare so any suggestions

[barren crown]

there isnt much diff between basic and standard paper id say the same to follow pw marathon since they have already done the work of collecting the most important questions and pyq

[still plover]

oh ok! which grade are you into if youre comfortable sharing?

[barren crown]

in giving 10th boards too

[grave elbow]

can someone explain to me where i went wrong

idk why its incorrect

[quiet bramble]

oh okayy fot it ,thanks a ton for the help

[quiet bramble]

okay will do that,hopefully i do wellfor the exams

[still plover]

ohh i see.. All the very best!

which stream are you choosing in 11th grade?

[barren crown]

gl to you too

[barren crown]

pcm wbu

[still plover]

oh wow thats cool!

i'll be taking commerce i was looking fot a study buddy are you interested?

for*

[barren crown]

suree

[still plover]

oh i have put up my intro in #study-buddies if youre interested

[willow anvil]

why do they choose

different values for x1 and x2

when x1=x2

[pale sigil]

They should not be equal

[willow anvil]

?

[pale sigil]

It is not a one-to-one function

[strange rampart]

there are two conditions x1=x2 and x1x2=1 they are telling above

in this case x1=2 and x2=1/2 makes it prove that it is not one one since x1 != x2 and it proves the case x1x2=1

so it is not a one one

as x1 is not equal to x2

[left knoll]

Can someone please help me with my math 💀

[astral berry]

is that just another way of saying A is the set of perfect squares

[empty perch]

math was a silly mistake

[shrewd ridge]

I need to verify this identity can someone help

[cosmic kestrel]

can't even read what is in the left part

tgnin#|.

[cosmic kestrel]

divide left part by sin()-1

[cosmic kestrel]

5. cos()=+-√(1-sin()^2)
   if tan<0 and sin>0 then cos<0
   so cos()=-√(1-(5/8)^2)=-(√39)/8
6. if tan>0 and angle is in the 3rd quarter of circle then both sin()<0 and cos()<0. Then use just formula
   1/(1-sin()^2)=1+tg()^2
   so
   sin()=-√(1-1/(1+tg()^2))=-√(1-1/(1+7/9))=-(√7)/4

[left knoll]

Omg thank you

[subtle parcel]

Hi, does anyone here have their major in Stat? hmu

[steep zodiac]

can someone please help with algebra 1?

i have a quiz tomorrow and i barely know what im doing

[young ivy]

too late?

[left knoll]

which grade

[cosmic kestrel]

https://youtu.be/HeKXICfUPac

https://youtube.com/shorts/Z06q_GBnnvg?feature=share

[left knoll]

lol guys

[low thistle]

Does someone have Haese ib Math AA HL textbook and could share it. I would appreciate

[nimble hill]

Yes

I have all

For AA HL

Also the worked solutions

[opaque flax]

Hey I was wondering if anyone could help me with my engineering related problem?

I've been staring at this problem for close to an hour and dont even know where to begin 💀

[cosmic kestrel]

position vector is OD

can't u find it's length and angle?

ODx=OBx+BCx+CDx and the same for y

start with this

[raw lintel]

as @cosmic kestrel stated try to use sin and cos to get the x and y portions of the given vectors

[grizzled lotus]

How to do? a) 0.2 b) 0.5

@echo socket

[barren crown]

apply the probability formula?

favoured outcome/total outcomes

[low thistle]

Thanks for the reply, I already found them🫡

[cosmic kestrel]

read as "students were survived"

[quaint talon]

do you guys know of any program like symbolab that solves double integrals?

[quaint talon]

thks, i'll try

[quartz roost]

🙂

[silver pier]

how would i solve 21

[frigid wave]

I think you have to construct a triangle B-C-O. Since B-D = 2 cm, B-C = 4 cm. And since every corner in an equilateral triangle is 60°, the triangle B-C-O has to have two 30° and one 120° corner. Now using sin or cosine you can find B-O and from that you can get the radius r

[grim crane]

Have u found the answer yet?

[timber patrol]

geometry hits diff tho

[quaint talon]

lol

[cosmic kestrel]

it definitely does the job well

[copper heart]

What is this symbol? Before Pi

[rain scarab]

Hello Iam 15 and I want to get into for most of my life had been scared of maths until started programming so want to learn maths now from zero to end can someone please suggest books or yt channel or anything that helps an idiot with zero knowledge

[sweet karma]

it's the multiplication from I=1 to n

[copper heart]

Ohh i just found out thank

Can you help me with 86

[sweet karma]

oh god i hate probabilties lol i never studied it sorry🥲

[copper heart]

Same😥

[left knoll]

depends on what country you are from and the board you are doing

[rain scarab]

Bangladesh class 10

[brazen plover]

The math sorcerer and Tom rocks maths might help you

[woeful zinc]

i think its b) independent

since its just multiplying the probabilities

can someone help with this:

i swear im missing smth simple

[copper heart]

Yeah i also thaught the same thing... Thanks

[woeful zinc]

np :)

[left knoll]

anyone here good at mechanics

i could rlly use some help and will only take like 15 mins

[rain scarab]

Alright thanks man

[hallow frigate]

Help me guys, Is this division correct?

[cosmic kestrel]

looks like correct

[winter pike]

how do i sketch this

[winter pike]

but if i was to combine them

would i just remove the small cone

[cosmic kestrel]

no remove the rest

[winter pike]

the rest as in..?

[winter pike]

ahok gotcha

ty

i understand the x^2+y^2+z^2<1 part

but im a bit confused abt the other one

[cosmic kestrel]

another one compares height with distance to z axis. So if you are inside cone, you are close enough to satisfy that height is more than distance, if you are outside the cone you don't satisfy inequality

[winter pike]

so would i include the top part thattouches 1

so liek this?

[cosmic kestrel]

yes because it's non-strict inequality

it includes edges

[winter pike]

tysm

so how would ik the parimeter of x and y

[cosmic kestrel]

what is parimeter

[cosmic kestrel]

so you want to find the parameters of intersection line. On this line both inequalities become equalities and are satisfied in the same time. So you have to solve system of equations:
x^2+y^2+z^2=1
z=sqrt(3(x^2+y^2))

the simplest way is to get z from second equation and put in the first

[winter pike]

so x^2+y^2=1/4

so itd be 0.05?

[cosmic kestrel]

It's an equation of circle with radius 1/2

yes

[winter pike]

0.5*

[cosmic kestrel]

yes

[winter pike]

ok thanks

that was really helpful

[cosmic kestrel]

Anybody knows how to compute partial trace?

[ember perch]

Could anyone help me solve this rq please?

[cosmic kestrel]

120 and 76 angles measure the central angles (as if it will be angle SOT, where O is center of circle). Inscribed angle SRT leans on the same arc as our central angle SOT, but inscribed angles are always twice less than central ones if both lean on the same arc (ST in our case). So SRT should be 120/2=60 degrees

[ember perch]

THANK YOU

[fluid saffron]

hey guys

any tips on how i can train myself to answer questions on an add maths test such that i can actually finish on time

[cosmic kestrel]

As an AI language model, I have a few suggestions for you:

1. Practice regularly: The more you practice, the more you'll become familiar with the types of questions asked in Add Maths exams. This familiarity will help you to answer questions more efficiently and quickly.

2. Improve your mental math skills: Try to solve problems mentally instead of relying on pen and paper. Memorize important formulas and tables. This will help you save time during exams.

3. Time yourself: When you practice, always time yourself. This will help you to get a sense of how long you have to complete each question during the exam. You can adjust your pace accordingly.

4. Prioritize questions: Do the easier and quicker questions first. This helps you build momentum and confidence, making it easier to tackle tougher questions that may require more time.

5. Learn to make educated guesses: If you're stuck on a question, don't waste too much time trying to figure it out. Move on to the next question and come back to it later if you have time. You may also be able to use the process of elimination to make an educated guess.

6. Eliminate all possible distractions: Make sure your environment is conducive for studying/learning. Turn off your phone or put it on silent mode to avoid interruptions.

Remember, time management is the key to success in exams.

[fluid saffron]

Thanks, for me the part i feel i definetely need to do more is to practice more

Yesterday i was totally decimated by the add maths exams

i didnt answer two whole questions thus losing 20 marks

the paper was two hours and i already know the solutions to the problems i couldnt answer

[cosmic kestrel]

for similar triangles:
Sadc=(1/4)^2Sabg
Sdec=(1/4)^2Sbeg
So our required
S=Sadec=1/16(Sabg+Sbeg)
for triangles with the same height area will differ in the same ratio as differ their base:
Sadg=Sabc=1/4Sabg
and we also can notice that
Sbeg=Sabc-Sabc-Sdag+Sadec
So we obtain
S=1/16(4Sabc+4Sabc-2Sabc+S)
therefore
15S=6Sabc and S=0.4Sabc

[maiden epoch]

Can someone solve this?

[cosmic kestrel]

use Eighler's formula to get your complex number in the exponent from

let's define some complex number re^{i\phi} and equalise it to your given number -\sqrt(3)/2+i/2. As wee see, we can find r just by finding square of module of our complex number:
$r^2cos(\phi)^2+r^2sin(\phi)^2=r^2=from the other side=(-\sqrt(3)/2)^2+(1/2)^2=1$. So we see that r=1 or -1, but let's use positive one because +1 will behave itself simplier during taking a power compared to -1. Let's now calculate \phi. As we see, if -\sqrt(3)/2+i/2=cos(\phi)+isin(\phi) then sin(\phi)=1/2 (which is possible for 30 and 150 degrees) and cos(\phi)=-\sqrt(3)/2 (which is possible for 150 and -150 degrees) what gives us the exact value of \phi=150 degrees or 5\pi/6 in radians. So your complex number in a exponent form will look like rexp(i\phi)=1exp(150i). What will happen if we put this exponent into a power of 29? Nothing special: exp(150i)^29=exp(29150i)=exp(4350i)=exp(30i) where we substituted 360 degrees 12 times to get adequate angle of 30 degrees. And you can write that exp(30i)=cos(30)+isin(30)=\sqrt(3)/2)+i(1/2)

[winter pike]

hey, same q from yesterday just wanted to make sure the equation was right

like where i put it?

[cosmic kestrel]

bruh wdyw exactly

to find that ring parameters?

[winter pike]

like to show which part of V is z>sqrt 3(x^2+y^2)

and x^2+y^2+z^2<1

[cosmic kestrel]

everything that is inside the sphere satisfy x^2+y^2+z^2<1. Everything that is inside the cone satisfy z>√(3(x^2+y^2))

[winter pike]

so since V is what they both overlap what do i put as the equation of V

[winter pike]

so wht would be the bounds of z

[broken ermine]

you want something like this?

[cosmic kestrel]

there is no "general" equation of V. it can expressed only lile system of 2 equations

[cosmic kestrel]

wdym?

[winter pike]

i solved it nvm

[trail flint]

can anyone help me with multistep rational equations

the lcm rule or whatever, I can't seem to understand

[cosmic kestrel]

I see that 1/(2x-2) can be turned into 0.5/(x-1), so let's put -1/(x-1) to the right side and we will obtain
-2/(x-4)=0.5/(x-1)+1/(x-1)=1.5/(x-1)
finally we can turn over both parts
-(x-4)/2=(x-1)/1.5
then u'll guess how to solve it

[winter pike]

when u interpret the question, which part is gold in the deluxe gizmoid?

[amber lagoon]

what is the simplest?

[trail flint]

That's incredibly helpful

Cheers

[amber lagoon]

Answer for those wondering

[pliant agate]

someone help me with this

i forget dx

[grim shell]

for Q1, I have an answer but it seems too easy to be true considering this is one of the later topics of A level maths, could someone solve it and tell me what they get?

[drifting saddle]

i need help please

[sweet karma]

https://youtu.be/STh0WBY8PaM

[sweet karma]

if you understand french i think he explained it well

[drifting saddle]

oh thanks must be where my friend found it

and yea i understand a bit of baguette

[sweet karma]

you're welcome, interesting integral tho

[cosmic kestrel]

x^3exp(x^2)dx=(1/2)x^2 d(exp(x^2))
so u'll get the integral log(t)dt for t=exp(x^2)

[cosmic kestrel]

force at D doesn't create a moment, force at C creates a clockwise moment 301.7=51 and force at the middle of BC creates counterclockwise moment 250.7=18.5

[hushed jacinth]

help 😭

[maiden epoch]

Why it goes down on 5 points here? What’s the rule?

[pale sigil]

First, the main graph is |x| Draw it, then move it 4 units to the positive x-axis on the x-axis. After that, you must move the graph 5 units down on the y-axis.
Changes on the x-axis are always reversed and changes on the y-axis are always done directly
That is, when x becomes minus 4, it means move the axis by 4 positive units
But when y becomes minus 5, you have to move 5 units to the negative

[grim shell]

Okay epic thanks, exactly what I thought.

[cosmic kestrel]

so 0.04=0.5(1+erf((5-\mu)/(\sigma\sqrt(2)))) so erf((5-\mu)/(\sigma\sqrt(2)))=-0.92
and
0.7=0.5(1+erf((25-\mu)/(\sigma\sqrt(2)))) so erf((25-\mu)/(\sigma\sqrt(2)))=0.4
and they use inverse function but it will not give you precise answer ofc, I am not sure that it's supposed to be solved like that

[winter pike]

so im trying to do 3b
and i was wondering whether the polar coordinates were 0 < θ<2pi 1<r<sqrt 3 and 0 <z< r^2+2rcosθ-4

[rain solstice]

does f( |R) c |R+

[cosmic kestrel]

it's not polar coordinates idk what it is

polar are 2d coordinates, 3d version is called spherical coordinates and they don't include z, they include r and 2 angles

your coordinates are cylinder coordinates

the problem is that the center of paraboloid stays not in (0,0) but in (-1;0)

so I don't think cylinder coordinates are good here, but I am not professional at orientated integration

[maiden epoch]

sorry for the late reply, and thank you for the explanation!

[fickle holly]

Hi guys, I did this. Is it correct? Please check me, thanks

Oh no this chat is dead

[willow anvil]

i have qquestion for interval of convergence
How are we supposed to check it
the endpoints
i get like some absurd number
7root(-1/2) < x < of 7root(1/2)
are endpoints

[stark dune]

yeah log12(n) would be ln(n)/ln(12)

[solar drift]

yup your answer is correct

[mystic thunder]

can someone help me factorize : x^2 - 2√5x + 3?

I cant

[undone ledge]

Does anyone know how to plot these?

[cosmic kestrel]

I cat

[cosmic kestrel]

the first one is the graph of square root, but the beginning of graph is shifted to the point (2,-4)

[cosmic kestrel]

the second one is just the graph of circle of radius 2 which centre is shifted to the point (-1,1)
It can shown the by rewriting your initial equations in the following way:
y=-sqrt(4-(x+1)^2)+1
(y-1)^2=4-(x+1)^2
(x+1)^2+(y-1)^2=2^2

[cosmic kestrel]

let's assume your expression ax^2+bx+c has roots x1 and x2. It means it gets value zero only if x=x1 or x2. Do you know what expression also becomes zero at x=x1 or x2 and is quadratic?
(x-x1)(x-x2).
But as you see, after multiplying these brackets you'll obtain x^2-x(x1+x2)+x1x2=0 where there is no a before x^2. So we have to rewrite this expression as
a(x-x1)(x-x2) to get necessary similarity to ax^2+bx+c
So as you see the only thing you have to do is to find roots of your quadratic expression. In your case:
x12=(2sqrt(5)+-sqrt(20-12))/2; --> x1=sqrt(5)+sqrt(2); x2=sqrt(5)-sqrt(2)
so
a(x-x1)(x-x2)=(x-(sqrt(5)+sqrt(2)))(x+(sqrt(5)-sqrt(2)))

[undone ledge]

ohhhhh i get it now thank youuu

[fair belfry]

hi, pls help with q13 and 14 thanks 🙏

[bronze edge]

Can someone help me? both d and f
The text reads: fixated p =/= 0, n (in) (Naturals) fixated

We CAN'T use L'hopital

[left knoll]

Well use na^n-1?

[bronze edge]

What you mean about that?

[left knoll]

Limit x to a ((x^n-a^n)/(x-a))

That equals na^n-1

D.)1/n * p ^((1/n)-1)
F.) np^n-1

[bronze edge]

But how do I reach that?

[left knoll]

Well that is just given in the question bro

[bronze edge]

Just straight up make the division and that's it?

[left knoll]

Solve d and f the way u solved e....they are all the same

Don't divide...the formula I have given use that ...that is a general identity like sin x/x = 1

[bronze edge]

Ooh ok ok, I see

I didn't know about the formula at first, thanks for showing

Out of curiosity, how do I show the formula? the na^(n-1)

[fair belfry]

pls help 😭

[fair belfry]

wait nvm i got it LOL

[mystic thunder]

why can't I split the middle term

[undone ledge]

Does anyone know how to get the domain of c and d

[stark dune]

for c its real numbers - {-2,+2}

since denominator cannot be zero

for d ig all real numbers

denominator can never be zero in d

[fringe stratus]

Hi ! Does anyone know which estimator is better ? I recall my teacher saying something about the fact that since n goes towards infinity much quicker than sqrt(n) then something, but I'm not sure of how it affects the estimators.

[cosmic kestrel]

wdym

[mystic thunder]

like factorizing using the middle term splitting method

because the quadratic formula hasn't been tot to me yet

[cosmic kestrel]

you'll get the same result IG

[mystic thunder]

but i

[cosmic kestrel]

I just told you the easiest method

[mystic thunder]

cat split the middle term

[mystic thunder]

I've been solving using the hard method my whole life😔

[cosmic kestrel]

as you see it's not always easy like in your example

where you have root

[mystic thunder]

yeah usually when there are roots I can solve but i can't apply this method

thank you for your help though!!

learn something new every day I guess

[cosmic kestrel]

more clarification please

[mystic thunder]

it went right above my head

[fast skiff]

Can someone help me with this problem of calculus of variations? I did the first point, but I'm not even sure about it and I don't know how to solve the other points

[polar galleon]

Kind of forgot how to do this. I'm looking for the value of K

[cosmic kestrel]

it is not even the full text

[left knoll]

find what you have to find

[cosmic kestrel]

e^{k×1 year}=80% --> k=ln(0.8)=-0.22314355131

@polar galleon

[polar galleon]

Thanks heaps!!!

[calm quartz]

Can someone help me understand this. I am having trouble understanding "For a sine wave the value is 0.707 times the peak voltage." Why 0.707 at the sine wave?

[glass matrix]

hi

can someone explain the log rule

[left knoll]

1=ln(3k)
that means
e^1 = k3
thats all that means

[polar galleon]

(Getting stuck on the fractions) Find the derivative of each of the following with respect to x:

[left knoll]

use d/dx of u/v

[polar galleon]

Thanks

[candid moth]

Tokenization error
On line 1 at position 1

2x+1=2
^

[cosmic kestrel]

because if you apply your sine wave to some resistor, you'll spend P=U^2/R of power every second. For calculating all spent energy in a wave period you can use integration:
E_{AC}=\int P(t)dt=\int U(t)^2/R=\int sin^2(t)/Rdt
this is integral over period 2\pi of oscillation is widely known and gives you pi/R value independently from the frequency of your signal, but I made frequency=1 for simplicity.
If you have DC signal U with the same energy spending, you have to equalise integrals:
E_{DC}=\int U^2/Rdt=2\pi U^2/R equalise to E_{AC}=\pi/R
as we see U^2=1/2 so U=1/sqrt(2)=0.707

[minor vault]

hello. im having trouble graphing bode plots. Could someone help me with this question

[late crater]

can someone please help me with this

[strange rampart]

try drawing venn diagram for these sums

here they r asking u to find p(anb)

[late crater]

why does thinking of it as a tree diagram not work

[strange rampart]

p(aub)=0.45,p(b)=0.35,p(a)=0.27 b is blue eyes, a is kid has black hair

just substitute formula p(Aub)=p(a)+p(b)-p(anb)

[strange rampart]

this doesnt even qualify to be a tree diagram q

[late crater]

what would qualify it to be

[strange rampart]

tree diagram can be used for sums like 2 bags x red balls,y balls probability of getting red ball

those type of sums

get it?

[late crater]

what is the diffrence between that and this situation

[strange rampart]

how exactly will u plot tree diagram for this sum? like its not possible

[late crater]

give me a second

[strange rampart]

yeah send me

[late crater]

like ik there is a flaw in using a tree diagram but i dont get what it is

[strange rampart]

so uk the proper way to solve the sum and ur asking me why doesnt tree work ryt?

lemme think

[late crater]

yes

[strange rampart]

these events are dependent on each other

lemme draw and see

[strange rampart]

if ur gonna do it the tree diagram way ur gonna double count stuff that is why its wrong

for eg lets take the first lane u wrote blue eyes prob is 0.27 and black hair is 0.35

so if u simply multiply u wont get it because blue eyes probability is P(Be) which includes in a venn diagram even p(Be n bh)

[late crater]

is this because the overlapping part is counted in both probabilities

[strange rampart]

yup

so for these sums where the events are dpendent on each other just use venn diagram

tree diagram complicates stuff coz u overcount stuff

[late crater]

k got it ty

[strange rampart]

np

[strange rampart]

instead of using u/v u can just divide each term

like (4e^2x/2e^2x -2e^x/2e^2x +1/2e^2x)

which will lead to (2- e^-x + 2e^-2x) which u can differentiate term by term

[cosmic kestrel]

can't u integrate?

[solar goblet]

how do we integrate without a curve formula

[cosmic kestrel]

dont you know the circle formula?

[solar goblet]

i don't think so

[cosmic kestrel]

x^2+y^2=R^2

[cosmic kestrel]

lost 2 somewhere but u'll find

bruh I accidentally used my language there, it's written (change of variables) near x/R=sin(a)

[solar goblet]

oh damn

we didn't even learn the concept of extracting the area this way

thank you so much tho, i'll go through them properly

[strange rampart]

which part do u need help?

line m u can use sum of angles is 180 degree

uk that property right?

yeah start with that

now are u able to solve?

so u shud have got an equation in 2 variables when u did the line l part

the next equation should be (2x+y+30)=(x+y+40)

i forgot the properties name ig it is called corresponding angles

now u will be able to solve with these 2 equations

[tulip charm]

If the ratio of the areas of two similar triangles is 64 : 121, then find the ratio of their corresponding sides.

yo this was a question in my test which i couldnt do

id be glad if anyone would help me

[cosmic kestrel]

imagine if you divide your triangle to infinite amount of squares, covering your triangle, what would happen with those squares if you increase triangle side 2 times? Square's side will also increase two times, so area of each square will increase 4 times, so total area of all squares and triangle as well will increase 4 times. So if you increase side of any figure by x times, area will increase x^2 times and with same logic volume will increase x^3 times.

[cosmic kestrel]

there is also another explanation. As you see from the drawing, increasing each side of triangle n times will make your area increase n^2 times

so if you have n^2=121/64 then each side have to increase by n=square root(121/64 )=11/8

[tulip charm]

thanks man, found this easier

[pseudo stump]

hello, could you please tell me how do I start with this?

a simple idea would be enough

[pale sigil]

a simple idea
4^x = 2^2x
9^y = 3^2y

[pseudo stump]

yeah, thought of that, then 25 = 5^2

[pale sigil]

no no

[pseudo stump]

huh

hold on ima try something more

[pale sigil]

Try to use the upper information to solve the lower

[pseudo stump]

thank you

[pale sigil]

Look for similarities

[pseudo stump]

the 2+3 repeats, but I got no idea what to do next with that info...

[pale sigil]

You have to solve it using logarithm

[pseudo stump]

oooooooh

just thought of that

damn

:> thx anyway

[pale sigil]

(2^x)^2 + (3^y)^2 = 25
(7 - 3^y) + (3^y)^2 = 25
(7 - 3^y) + 9^y = 25
9^y - 3^y = 18
3^y(3^y - 1) = 18
3^y = 3
y = 1

2^x + 3 = 7
2^x = 4
x = 2

x = 2
y = 1

[rain solstice]

how to solve
Arctan(x)+Arctan(3x)=pi/3

[cosmic kestrel]

you can take tan from both sides

but don't forget that you'll get additional solutions because tan(pi/3)=tan(pi+pi/3)

you can easily get rid of them, remembering that arctan is monotone function, so the bigger x (from 2 solutions) will give u bigger arctan(x)+arctan(3x), so to get pi/3 and not 4/3pi u have to use the smaller solution for x

[rain solstice]

i just noticed it thx

[left knoll]

Anyone can help me to understand Probability from CSE 2nd year ?

[cosmic kestrel]

depends on what u ask exactly

[bold atlas]

what is the approach to solve modulus summations problems? like |x-3| + |x+4| = k

[cosmic kestrel]

the main approach is to remove modulus, considering the particular values of x. For example in your case we see, that modulus will behave differently, depending on whether x<>3 and x<>-4.
Let's start from the first assumption that x>=3. Then removing moduluses will give us
(x-3)+(x+4)=k
We changed nothing because moduluses won't do anything with positive numbers inside it anyway. So we will get x=(k-1)/2. If this value>=3 then it's our solution, if it's<3 then it contradicts our initial assumption.
For the second assumption (-4>=x>3) after removing moduluses we will obtain
(3-x)+(x+4)=k and if k=7 as we see, all x in range [-4;3) will satisfy our equation

[trim kayak]

Hello
I am a high school student . I want some tips or advice for Olympiad math competitions,
I love math and I want to start doing Olympiad math so I can increase my chance to get to a good college

[bold atlas]

ah got it, i was just confused if we have to take the -cases approach or any other method was there, i think i just need to trust my instinct haha, THANKYOUU!!!

[hexed ivy]

I can dm you a link for a math olympiad discord server

[trim kayak]

Sure!!

[cosmic kestrel]

is there the same for the physics

[hexed ivy]

There probably is but I'm not in it. Im only in the math olympiad and the chemistry olympiad discords

[cosmic kestrel]

can you ask there

IG math guys can know

[stark dune]

can you share chem one

[hexed ivy]

check dm

[lone adder]

Hi ! I would like to know if someone would be kind enough to help me in maths (more precisely in stats) because I have a lot of gaps on the subject and I have an exam soon, I speak French and English rather well . contact me in dm if you agree, thank you in advance!!

[hazy pond]

YOU DID NOT SOLVE MY PROBLEM I DON'T UNDERSTAND YOU

in the problem it asks you to calculate a and b the derivative

[supple island]

they were trolling, i think that the intention was just asking to translate

[supple island]

ok so, first of all, what's the derivative of f(t)?(leaving A and B unknown)

[hazy pond]

the drift of f(t)

[supple island]

really doesn't seem like f'(t)

[hazy pond]

mistake with another exercise but this is the derivative

[supple island]

this seems more like it, now you just have to compare this with the f'(t) you are given, but you have 1 equation and 2 variables so it's not gonna be doable unless we're able to get more equations.
for example we could see what happens for f'(0) and f'(pi/2)

sorry for the late reply, next time ping me

[rain solstice]

can some1 explain how he did the integral of e

[quick wraith]

integral of e^(ax) = [e^(ax)]/a if u want to check try by differentiating it

[rain solstice]

is it a general rule since i never saw something similar
the only rule about e that i know is
∫f(x)'e^f(x)=[e^f(x)]

[quick wraith]

yeah this is more general form I=integ. Of e^f(x) .dx

I= e^f(x)/f’(x) +C

[rain solstice]

thx u saved me alot of time while i was stuck in it

really appreciate it

[swift lake]

how would you do 2(f)

[quick wraith]

finally put any two different values of s and t as per your wish

[silent escarp]

ANYONE PREPARING FOR JEE ADVANCED??

[cosmic kestrel]

where do you get all those abbreviations

JEE GSCE OSDY

[quasi gorge]

Anybody got any fun tricks for converting large binary numbers (32 bit + 😦 ) into decimal (without a calculator)

[cosmic kestrel]

do you have an exam where you have to work with binary numbers but want to convert them in decimal for simplicity?

[quasi gorge]

yeah and also questions that straight up ask what is 010110101010110101101010101100110101010101101010101100101 in decimal (no joke)

(ok not quite as long but up to 32 bits)

[cosmic kestrel]

is it exact example or there are another numbers? Maybe they are not so arbitrary

[quasi gorge]

No I can give you an exaple hol up

000100110001000100110010

Like man its only a 1:30 exam

[cosmic kestrel]

you can easily convert like 12 bits bcs 2^12 is just 4096, it's not so much to add on the paper

so just try to remember powers of two

and then check methods of fast summarizing

[quasi gorge]

fast summarizing?

lemme go google it

[cosmic kestrel]

there are plenty of such methods

[quasi gorge]

what does it mean?

[cosmic kestrel]

fast addition sorry for my english

[quasi gorge]

No problem

Thankyou I was wondering if there was a faster way but now im convinced its the fastest

thanks to you

@cosmic kestrel where are you from ?

[cosmic kestrel]

i am in Russia currently

[quasi gorge]

Привет

[cosmic kestrel]

ёмаё

[quasi gorge]

🙂

i cant speak russian or Belorussian so 😦

[cosmic kestrel]

Belorussian is almost dead language as I know lol

[quasi gorge]

Interesting how does it differ?

[cosmic kestrel]

Belorussian has a lot of y sounds if you ask about it

[quasi gorge]

Ah ok

спасибо за помощь друг...

(google translate)

[cosmic kestrel]

I hope I really helped a bit

[quasi gorge]

Thanks 🙂

[hazy pond]

He asks me to calculate the drift when he finds the derivative and to match the expressions that he would have to do to find the sum of A and B

help

[swift lake]

god bless u brother

[hazy pond]

thank you

[cosmic kestrel]

https://youtu.be/CPnrs2Yl-rY

[random niche]

In case you're curious about Belarusian and Russian pronunciation differences:
https://www.youtube.com/watch?v=vsBDoJfU_iE

[tawdry bramble]

Hi, anyone here familiar with dimensional analysis? Really confused on this.

[left knoll]

Still need any help?

[tawdry bramble]

Thank you but not really, I want to become a software engineer and I’m trying to brush up on math concepts to help me In college and I did some research and found out that mainly dealt with the medical side of math, thank you for responding though. I will be back lol

[left knoll]

Please do.

Dimensional analysis is a delicacy.

[shrewd ridge]

Does anyone know how to solve this

[cosmic kestrel]

put useful values of x into your expressions and then evaluate them

final check

[fiery pivot]

please help i cant find what the answer to (d) is 🙏

what i have: (sqrt(4+2h)-2) / h

but idk how to single it out so i have only one (h) variable

[cosmic kestrel]

multiply both nominator and denominator by sqrt(4+2h)+2

what will u get?

in the nominator root will disappear, check it

in denominator you can write sqrt(4)+2 instead of sqrt(4+h)+2 because for infinitely small h there is no difference what u divide over

[fiery pivot]

OMG THAT MAKES SO MUCH SENSE

Thank you!!

[fiery pivot]

i didnt think about making it +2

so i kept getting gross numbers

[cosmic kestrel]

did you get 1/2?

[fiery pivot]

i got 2/sqrt(4+2h)-2

im lost again lol

[cosmic kestrel]

if we make h smoll

damn how did you got that

oof

[fiery pivot]

ill send picture

so i multiplied top and bottom like u said

the 4's subtracted out leaving 2h in the numerator

the h's cancled

leaving only 2 in the numerator

[cosmic kestrel]

yeah it's right

so, what's problem?

then they just ask you to make h=0

so u'll get 2/(sqrt(4)+2)=1/2

it's the thing called derivative

[fiery pivot]

ohhh 1/2 for question e

[cosmic kestrel]

yeah

[fiery pivot]

the slope of tan line?

[cosmic kestrel]

it's one of definitions

[fiery pivot]

tyty for the help

[cosmic kestrel]

if you did h=0 in the beginning u would get smth senseless like 0/0, that's why we needed trick with sqrt multiplication

to compare 0 in nominator and in denominator

and then reduce that h=0 from both of them

[shrewd ridge]

Damn are you a math major

That literally made no sense to me my iq is that of a squirrel’s

[cosmic kestrel]

so u dont get what I wrote?

[shrewd ridge]

No

[cosmic kestrel]

in which part

there are two expressions

two functions of x

there are equal

independently of what is x

so I can put any x I want there. For example x=0. I know that sin(0)=tan(0)=0 and sec(0)=cos(0)=1

also I wrote tan(x) as sin(x)/cos(x) and sec(x) as 1/cos(x)

[tawdry bramble]

I’ve done some thinking I’m gonna take you up on that offer, if it’s still on the table.

[left knoll]

No yes of course, do you have any example problems?

[tawdry bramble]

Ik its basic but I kinda need a basic understanding

[left knoll]

Give me a minute.

Can I DM you a video explanation?

[tawdry bramble]

yes pls!

[left knoll]

Thank you!

[grizzled lotus]

How to do a)?

[fiery pivot]

could i have some help on this please?

i plugged it all in to the derivative formula thingy

f(x+h)-f(x)/h

but i cant simplify to only one variable of h

[quasi gorge]

||Im not very good at math (i study computer science) but is m=4/9 and the equation is y=4/9x - 65/27|| Dont trust my answer

[cosmic kestrel]

I see two a) here

[fiery pivot]

help me aslan help me 😭

[fiery pivot]

its not 4/9 😢

[cosmic kestrel]

bro u have so many tools to find derivative

beginning from chatgpt and ending with wolfram alpha and derivative tables in google images

so u can just get answer that derivative is -4/x^2 from there

but even if you want honestly to calculate it what's the problem

f'=(4/(x+h)-4/x)/h=obviously we need common denominator=(4x-4(x+h))/((x+h)xh)=-4/((x+h)x) which is approximately -4/x^2 for h=0

just put necessary x=-3 there

u haven't even tried to google bro

[fiery pivot]

i would if i knew what exactly im supposed to google...

[cosmic kestrel]

derivative of 1/x function

[fiery pivot]

ohhhh

[cosmic kestrel]

or "table of derivatives"

there are the most popular ones already calculated

[fiery pivot]

okok this helps thank you aslan

[ashen eagle]

Check out this YouTube channel.
Hope you find it interesting 🧐
https://youtu.be/Kss13U-hvPk

[swift lake]

how would you do 2(f)

[glossy rover]

if you're doing statistics/financial math i can help

[thin nimbus]

Frank has a choice of three jobs. He wants to work 4 hours a day.

Job A pays $11.50 an hour
Job B starts at $10.00 an hour and increases by 5% each hour
Job C starts at $10.00 an hour and increases by $0.25 each hour

which one makes the most money

im thinkin A

[cosmic kestrel]

bro...

[thin nimbus]

am i wrong

10

i chose a assuming the number of hours they work resets each day

im pretty sure my answer works

[glossy rover]

you are right

[hasty wyvern]

isn't the number of hours 4?

[flint owl]

Could any one give a calculus practice sheet😐

[left knoll]

Can anyone solve this with calculations? Polynomials

1. Divide the polynomial by the binomial
   (x³-x²-5x+6):(x-2)
2. Solve the equation
   (x³-x²-x-2):(x-2)
3. Solve the inequality
   (4x³-4x²-x+1):(x-1)
4. Solve the inequality
   x ³ - 7x² - 3x + 21 : (x - 7)

[left knoll]

heyy can someone pls help, the question is to calculate f(x)'s sign so we have to calculate its derivation

i did it but how can i know if the result is positive or negative

like 2exp is always positive, same goes for x²-x+1

but the -1 is the main issue

we need to know if 2exp(x²-x+1) is > 1 or not

[zinc frigate]

for what values

what’s your domain

[left knoll]

R+

heres the function

i said its R+ since theres x in the denominator (idk how its called in english sorry sjfjdj)

OH MB NOT R+ R*

[zinc frigate]

e can never be negative

wait

did you take the derivative properly

[left knoll]

yess thats true but we dont know if its > 1

im sure that its correct but idkk i dont have the solution to verify

but i did it like 3 times and its always the same derivative

[zinc frigate]

derivative seems fine

so you want to know if it’s positive on the entire domain?

[left knoll]

yepp

so that i can calculte its sign after

[zinc frigate]

what do you mean by calculate it’s sign?

[left knoll]

know when the function is positive and when it is negative

[zinc frigate]

ohhh

do you know how to find the asymptote?

[left knoll]

like in this exemple

yess kinda

but to calculate the limits we first have to find the borns

[zinc frigate]

do you know how to find the critical points?

[left knoll]

nop :/

[zinc frigate]

what were you doing in this example?

what does the derivative give us?

[left knoll]

2(x-1) exp x²-2x

so the sign depends on x-1

[zinc frigate]

no, you found the critical point i.e. where the derivative is 0

[left knoll]

yes thats it

[zinc frigate]

now

what did you do after that

with the number line

[left knoll]

i said that in ]-infinity,1] the function is negative

and in [1,+infinity[ it is positive

i calculated the limits and images

[zinc frigate]

infinity side domain is never inclusive

it can be (-infinity, 1] but not [-infinity, 1]

[left knoll]

yess thats what i did

I wrote ]

[zinc frigate]

[] don’t work with infinity

only ()

[left knoll]

oh school never teached us this

[zinc frigate]

now, you checked the points before and after the critical point to see if the function was decreasing or increasing

[left knoll]

exactly

[zinc frigate]

yes just keep that in mind, infinity isn’t included in the domain, the function goes up to infinity but is never equal to infinity

[left knoll]

okayyy

[zinc frigate]

now do this for your original function

set the derivative to 0 and solve for x

[left knoll]

thats the problem i cant find when the derivative equals 0

[zinc frigate]

can you find values for which the derivative does not exist?

[left knoll]

the equation is complicated

mhh wait ill try

no i cant

[zinc frigate]

look at your derivative

what can’t happen in the denominator

[left knoll]

ahh yes i completly forgot the denominator

it cant be 0

[zinc frigate]

x^2 - x + 1 = 0

can you solve this?

[left knoll]

nop

the delta is negative

since the domain is R* theres no solution

[lunar mural]

It’s just one right?

[left knoll]

can i get some integration help

if there is anyone here who is particularly confident

[cosmic kestrel]

yeah chatgpt can

[wintry olive]

Hey guys

I need some help with multivariable calculus

[left knoll]

Can someone help me solve this

[timid delta]

T.F = g(s)/(1+g(s)) ( as feedback is unity)

response = t.f/s

then take laplace inverse

either using partial fraction or convultion

[left knoll]

I am kinda stuck here

@left knoll i made kinda

[left knoll]

Isn't this for closed loop ?

[vernal comet]

wait what operation was made from the 1st to 2nd?

where'd that 9^n go

[supple island]

it became 1/3^2n

[cloud needle]

Can I post any math question I have here

[peak comet]

As long as you are not letting people do all the work for you and or just answer any questions or problems for tests/exams

[vernal comet]

I think I get how this works, but how do we know directly from the example to do this trig identity for the solution? Nothing else is really given

[weak rivet]

If z1= -4+6i and z2= 2*1/5+2i verify conjugate z1-z2 = conjugate z1 - conjugate z2

help 😭

[cosmic kestrel]

do you know how to subtract complex numbers?

[weak rivet]

yes

i kinda alr solved it... But tysm for replying

[drowsy matrix]

Hello guys, can u help me pls ?🥺

I have no idea how can I convert and solve this

[cosmic kestrel]

obvious change of variable t=sqrt(x-2)

[left knoll]

I had a question its kinda based on chemistry but has a lot to do with math as well

Q1. Someone gifter me 1 mol rupees ( currency ). Where according to avogadros number 1 mol is 6.022 * 10 raised to 23. I spend 100,000 rupees per second. How many Years can i spent this amount of money for. Compare this year to the relative age of the earth.

Its hella confusing a quick answer would be very helpful. Also uploaded on science channed as its kina revolving around maths as well Thank you.

for more context this is earths age in numbers 4534000000

I got some ridiculous answer and i believe its wrong its (115.50 * 10 raised to 4 times current age of earth is the amount of time i will be the amount of time i will be able to spend the money for)

[atomic gazelle]

ah shit i didnt take chem sorry

[left knoll]

bro its just one number the constant rest is maths but thank you for reading the question giving your time

[atomic gazelle]

but whats a mol

[left knoll]

its like the number of atoms in 12 grams of 12 carbon ( isotope of carbon )

the number is 6.022 * 10 raised to 23 atoms

[atomic gazelle]

what does that have to do with spending money 😭

[left knoll]

its also called avagadros number or in some books avagadros constant

[atomic gazelle]

sorry i got u helping me instead

[left knoll]

no sir it helped me revise thank you

[left knoll]

donno got this question from coaching like a brain teaser and gotta do them to make brain faster