math-help

[gritty palm]

I REALIZED MY DUMB MISTAKE

OML

i forgot the freaking - in the quadratic formula 🤦

[dire aurora]

silly mistake?

[gritty palm]

yeh TvT

thanks lol

[dire aurora]

i dont think u need the quadratic formula for that one right

[gritty palm]

ik but im dumb TvT

[gritty palm]

wait i do tho, to solve for x

anyways, i finally solved 1 thanks to u TvT <3

now number 4... TvT

[dire aurora]

ill show u my working in a min

[gritty palm]

oh that would be useful,thx

[gritty palm]

oh i see ok thx

bruhhhhh much simpler than what i did lmfao

[dire aurora]

let me ask u, if instead of C(x) = 0.01x^3-10x+150

[gritty palm]

ok for 4 im assuming i start of with R-C

[dire aurora]

C(x) = - 0.01x^3-10x+150

notice the negative

[gritty palm]

huhhh

[dire aurora]

how would that change things

[gritty palm]

there is no negative in the problem tho?

is it cause its a cost

so u lose money hence the negative sign?

[dire aurora]

the shape of cubic would change

[gritty palm]

righttt

[dire aurora]

so the min t.p would be in the negative side, in many cases

[gritty palm]

so it would be the graph on the right in ur notes page?

[dire aurora]

and the max will be in the positive side

yes

[gritty palm]

ok

[dire aurora]

if u did the same thing we did just then

ud be wrong

[gritty palm]

right ok

[dire aurora]

because u would have the max t.p no the min t.p (assumming the function still has 2 turning points)

so u need to think because u use calculus

otherwise ur just guess essentially

[gritty palm]

okkkk

[dire aurora]

u can also test for min and max t.p

in ur two solutions

[gritty palm]

so i did whwat we did in question 1 for both equations?

[dire aurora]

4a is the same as we did before

because this is a postive cubic function

[gritty palm]

right

ok

[dire aurora]

assumming theres two turning points, we want the min t.p

im not sure if ur teacher will deduct a mark if u dont test the solutions for max or min t.p

u have to make sure

[gritty palm]

ok

lemme calculate rlly quick

gimme a sec

wait but r'(x) equals 35

what do i do with that?

[dire aurora]

if u want to test if a solution to the first derivative is a local max or min., you can simply substitute the solution into the original function and see which is the higher and the lower one

in terms of y or C(x) in this case

or

the cool way to do it is to find the second derivative

and then sub a solution where x is a turning point into the second derivative

and if the result is positive

i think i means its concave down

therefore max t.p

and if its negative

the t.p is min

because the nearby values make a concave up arc

can u check if im correct by looking at ur drawings yesterday please?

[gritty palm]

hmmmm, i dont think i quite get what ur saying, sorry TvT

[dire aurora]

so when u solve the first derivative in this case u get two answers right?

[gritty palm]

yes

[dire aurora]

or the last question

that means there are 2 turning points

[gritty palm]

yeh

ohhh ok

[dire aurora]

even if u are very good with understanding cubic functions, it can be very hard to tell which solutions give the max t.p and which solution gives the negative t.p

[gritty palm]

i was just not understanding the part where u talked about the third derivative ;-;

[dire aurora]

thats why it may be neccessary (even in an exam) to test which t.p ur solution give

[dire aurora]

did i say third?

second haha

[gritty palm]

i meant second haha

oops

[dire aurora]

third derivative is all 0

[gritty palm]

ok

[dire aurora]

u should test the solutions of the first derivative to see it give a min or a max t.p

best way to do that is using the second derivative

imo

[gritty palm]

ah i see

[gritty palm]

ohhhh i seeeee

thanks so much omg

[dire aurora]

please verify these results by looking at the sketches u made yesterday

[dire aurora]

in this case u want to test to know if ur t.p is the local minimum (minimum t.p). if it isnt, then logically this solution is not the answer to the questions how much goods x should be made at the lowest cost C(x)

let me know if u need help with question 4

[grave elbow]

tysm i got it

[gritty palm]

thanks so muchhhh

i think i can do it from here, thx :)

[dire aurora]

part b looks like a simultaneous equation i think

c is asking u to articulate u know what the heck happened

i.e why was ur method is part b correct dependent upon how part a's method was correct

[dire aurora]

tbh i dont know the answer to part a

part b is ok

if cost cant be negative then c(x) is a discontinuous function

that makes little sense to me

maybe theres a typo and the constant should be 4000?

idk

please tell me the answer to part a

[gritty palm]

this is the answer sheet

[dire aurora]

lol its a poor question

c(x) is negative at x = 272

c(x) is cost

cost cant be negative

by definition

[gritty palm]

there r many typos in this textbook 😭

it’s a rlly shit textbook

😭

thx for helping tho lol

u were very helpful

[dire aurora]

if u can understand why the writer made an inaccuracy then ur fine

[gritty palm]

thanksss <3333

[gritty palm]

yeh, thx :)))

[dire aurora]

if this was a test then u would have found x = 272... by testing the second derivative

and found it is the min t.p

then, u sub x=272 into c(x)

and u see that its negative

and then u note that

idk

smth is wrong

u should write, since cost c(x) cant be negative, c(x) is a discontinuous function and undefined at x = 272

part b is fine

profit = revenue - cost

so u do r(x) - c(x)

and solve for x

i think

the answer is still 563

i think the textbook is just bonkers tbh

like really bad if im not mistaken

[raven galleon]

Would the education variable be an ordinal or scale?

there are no set values (just number of years)

[left knoll]

I don't understand where did 1/4 came from

[left knoll]

cos60 =1/2

[left knoll]

1/4*

[left knoll]

u sure?

Did they multiple whole equation? if say why is cos80 outside

[left knoll]

I meant where did 1/4 came from

my bad

1/2= 2/4 = 2 * 1/4

i think he wants to reach this form

so he made 1/2 = 2/4

i didn't solve the whole question so i don't know well

[left knoll]

Interesting question

You just use the formula over and over again to get to the solution

2cos90cos10* instead of 2cos100cos90

@left knoll yo tysm but my dumb brain still can't understand I have to cram whole trigonometry and other 4 chapters because i procastinated

[left knoll]

totally understand your pain

[left knoll]

What should I do

I don't want to fail :(

do your best and whatever will happen isn't a problem
it's not the end of world if u fail. just learn from mistakes and don't procrastinate anymore

going to the exam with 30% studying better than you going with 0% because you were afraid of failing or because you thought you would not be able to pass

like i said just do ur best in this moment

[silk patio]

Can some help me😭

But yeah do you’re best you got this

🙂

[left knoll]

I will try(hopefully)

[left knoll]

bruh I need 28/70 means 40% i have past papers even if i did all sums i know perfectly it still only adds up to like 15 :(

@left knoll Thank you <333

[left knoll]

Do not count like that
God only knows 😂

yup am gonna definitely fail will try nevertheless

[left knoll]

np bro
I had some times that I thought it was impossible to succeed but it was a miracle and I succeed so don't give up

[left knoll]

yeah better than not trying

[left knoll]

bruh just use photomath

its free

and explains the steps

[ebon sage]

hi everyone, I'm trying to use geogebra commands but it doesn't work. do u have any idea?

[silk patio]

Thank you

🙂

[forest tapir]

i don't think i remember😕

[fierce slate]

is the math help chat also for accounting???

[left knoll]

can someone explain?

[acoustic forge]

https://www.msipg.com/trigonometry-formula/

just use these formulas

[left knoll]

oh it was identify i thought they simplified or something

[acoustic forge]

They simplified it but they used this, not the usual fraction simplification(you get what I mean)

[left knoll]

yup got it

[acoustic forge]

Yes

[wispy wind]

Can someone help question b?

[shadow wasp]

what is the proportion method

[ruby holly]

Use proportions of side lengths

Or of whatever related quantities

[left knoll]

can anyone teach me this

[ebon sage]

Hi everyone, is there anyone who's studying calculus 1 and 2? I'm searching for a study buddy so we can exchange exercise...

[shadow wasp]

Do I just multiply, the 7/8 and 1/2 of the inches is confusing me

[stone locust]

Can anyone help me with this¿

[ember garnet]

it's ( 7 + (1/12)*(11 + 1/2) ) x ( 28 + (1/12)*(3 + 7/8) ) square feet

[left knoll]

help anyone? please

[dire aurora]

My attempt. With trig questions like these with bearings its a great habit to immediately look for information based on the 3 pairs of parallel lines pointing north. Whenever two parallel lines are intersected by another straight line thats is where u have insight and you should spot them easier with practise.

Can somebody tell me if two rectangular hyperbolas intersect if there have the same sign but different scale factor? i.e does y= 3/x and 1/x intersect? If so, how might i find the intersection points?

[ember garnet]

If two functions f(x) and g(x) intersect, that means they have the same value at the point of intersection, which means there is a solution to the equation f(x) = g(x). So try to solve 3/x = 1/x

[dire aurora]

limx->0 is the answer?

so theres no intersection point?

does that make sense logically too?

as y f(x) and g(x) increase at the same height they are ever closer yet never intersecting?

[ember garnet]

Yeah the only solution is 0 but they diverge at that point so they don't intersect

[dire aurora]

ok thanks for ur explanation and your answer 🙂

[ember garnet]

np

[mellow latch]

can someone help me

it's in german but i think you will still understand it

i have to find the volume of the right cylinder

[clever talon]

Volume = pi×r²h

I don't understand the full thing

[mellow latch]

The blue cylinder has a volume of 144cm^3. Give the volume of the purple cylinder with the same height and a quarter of the radius of the base.

Is that even english idk I trust google translator

[clever talon]

Vol is Directly proportional to square of radius

So if radius becomes 1/4th then volume becomes 1/16th

So I guess 9

What's the answer?

[mellow latch]

9 was correct thank you

[clever talon]

Np

[dark sparrow]

Holaa!

Alguien que hable español

[undone ledge]

Hi could someone give me a hand with this :))

[undone ledge]

Nvm I got it :))

[left knoll]

Ah. Solved it anyway

[undone ledge]

Still helpful I’ll go through ur notes thank you!

[plain gazelle]

algebra? looks similar to what i’m doing today

[silk patio]

Can someone help me ? With this

[left knoll]

Do u know pythagorean theorem?

[dire aurora]

Can someone please show me the working to get tanx . -tan(pi/2-x) = -1 ? I have no idea

I just know its true and verified on graphing software

I can get it like this but i want to know if there is a purely algebraic way to simplify tanx . -tan(90-x) into -1.

[lost flare]

TIPS for SAT?

[worldly spoke]

Do you know tan(90-x) = cot(x)

[dire aurora]

no. not yet.

i dont know why tan(90-x) is cot x but i see tan x times -cot x is sinx/cosx times -cosx/sinx =-1 now, thanks to you

i think i know why tan (90-x) is cotx actually

its the complimentary angle

[worldly spoke]

Yes

You are right

[dire aurora]

so tan of 90-x is x/y on the unit circle

[worldly spoke]

Yes accorindg to what you draw above

[pulsar jewel]

Anyone familiar with lie algebra and its application in yang mills SU(N) guage theory?

[worldly spoke]

Yes , thats correct

[dire aurora]

ok, thanks for telling me about the cotx identity! that should tie it all together for me.

[worldly spoke]

Np

[copper heart]

does a empty set consider a proper subset of a set 🙃

[left knoll]

These questions were a pain for me

[left knoll]

Yes empty set is subset of every set

[lusty narwhal]

hi, do you guys have any tips on how to learn math fast? like im ass at math im like at a 4th grade level and by june i gotta know pretty much all thats there to learn between 1st and 8th grade (both geometry & algebra) cus i have a very important exam thats basically gonna determinate the highschool that ill go to for the next 4 years and i need at least a 90% on that exam

let me know if you need additional info on the situation that im in

[ebon sage]

Hi everyone, I have to prove that this function is continuous but I cannot use limit or polar coordinates. I have to prove that the distance between f(X) and f(x0) is 0 when the limit of the distance X - X0 approaches the zero

In this case this is the distance: (x^2 + y^2)^(1/2)

So you have to prove that: 0 < |(xy)/(x^2 + y^2)(1/2)| < (x^2 + y^2)^(1/2). and then lim (x^2 + y^2)^(1/2) = 0 as x --> 0, so |(xy)/(x^2 + y^2)(1/2)| is zero, therefore f(x,y) is continuous

[silk patio]

Kinda forgot 😭

[rotund vessel]

https://en.wikipedia.org/wiki/Pythagorean_theorem

[left knoll]

https://www.youtube.com/watch?v=AA6RfgP-AHU&ab_channel=KhanAcademy

and don't forget the sum of the angles of a triangle = 180

[silk patio]

Thank u am

Sm*

[dire aurora]

My advice would be to have a day-to-day system where you are able to spend your free time anyway you see fit and are free from addictions and distractions. A plan like this will require a lot of work, thinking and self-awareness, but if you are able to study 3 or more hours every day until June with proper math guidance and real patience there is no goal that is too far fetched for you. Get a good textbook and use khan academy or similarly talented teachers online to learn each topic and investigate every single concept you encounter. First you will need to do a lot of thinking to yourself and figure out what is important to you. If you realise that working hard towards your dream(s) will provide more meaning and fulfilment and improvement to your life than you can possibly comprehend at first then the next step is to progressively abandon the habits that stop you from acting freely toward any such goals. As you understand more and more over time exactly how much more meaningful and rewarding your dreams are as well as why it is necessary to not become mediocre then hopefully things will start falling into place and you start to form solid habits that align toward your health and improvement. You will pick up tools too keep you accountable and routines that you can keep a record of each day. All in all I am just trying my best to give you my honest opinion of how i think someone achieve their goal no matter how immense they may be. Its a personal journey of progress and its very complex and not easy to achieve, but as you learn more as you go you will improve as you go as you will be able to adopt an increasingly comprehensive plan for your self that includes a day-to-day regime of how you can achieve your giant goals by achieving each and every tiny goal that you set after conscious measurement and consideration.

[dire aurora]

Oh and no. We don’t have any tips to “learn maths fast” if you know what i mean. Thats not what you actually want for yourself. I hope what i said above made sense and i wish the best of luck for you

[obsidian forge]

Hey all, could someone help me understand what the formula this question is asking for? I'm not understanding how the input and output relates to the initial rates given? I think there's algebraic formula in here somewhere?

[left knoll]

I can't understand ur question but the code should be something like this

[obsidian forge]

Ah I see, so what I was initially thinking was to do an algebraic formula because this is for my Intro To Programming class and we're using Python thru-out this class. We just learned variables/operations in Python and I'd assumed it would be some kind of math formula that we have to show within the IDE. Thanks for your help! I'll keep looking over what you wrote and try to replicate it so I can further understand it

[left knoll]

Not a problem . If u found an algebraic formula to solve the problem please tell me.

[obsidian forge]

@left knoll Will do!

[left knoll]

are you sure this is continuous?
im like pretty sure this is not continuous at (0,0)

[fair belfry]

hi can someone pls help me with the first 2 questions i completely forgot how to do it 😅

[clear condor]

if cos^-1 (0) is equal to 90 degrees because at 90 degrees cosine equals 0, why isn't it also equal to 270, since at 270 it is also equal to 0

[left knoll]

when you say cos ^ -1 you are implicitly implying it's the invertible function of cos. but that is simply not true for all R (real numbers)
first, cos^ -1 is defined on [-1,1]
when we say cos^-1 we mean the invertible function
an invertible function is first and foremost a function, and for all numbers in it's domain (which is the interval [-1,1]) it should be well defined (it should define a single value for every x). in the case you're describing cos^-1 is not a function because cos^-1 assigns two different values to 0. therefore, in order for it to be function we should restrict it's range to intervals of the length pi. and in the case of cos^-1 [0,pi] is used (it's just defined like that, if you wish to use other ranges it's not "cos^-1" "anymore"). that's because when we ask what is cos^-1(1/2) we are really asking.. what's the smallest angle x for which cosx=1/2.
i didnt give a super formal explanation, but i hope it helps

[formal forge]

can someone please show me how to do this conversion (step by step using the whole table thing)
Convert 45 kg cm / hr^2 to Newtons

[cosmic elm]

what is this problem called so i can khan acadamey it 😓

[odd fog]

https://www.khanacademy.org/math/algebra/x2f8bb11595b61c86:quadratics-multiplying-factoring/x2f8bb11595b61c86:factor-quadratics-intro/v/factoring-quadratic-expressions

https://www.khanacademy.org/test-prep/sat/x0a8c2e5f:untitled-652/x0a8c2e5f:passport-to-advanced-math-lessons-by-skill/a/gtp--sat-math--article--solving-quadratic-equations--lesson

[odd fog]

Those should get you up to speed in no time :)

[ebon sage]

I'm not sure but I should prove it with the distance. Idk if you know that definition

[left knoll]

oh actually it's my bad i didn't see the sqrt there

this might help
https://math.stackexchange.com/questions/572098/show-continuity-of-fracxy-sqrtx2y2

[left knoll]

math exchange is usually a good source

[ebon sage]

Thank you

[tiny sphinx]

it will be a great help if you anyone could solve this

[left knoll]

Is it algebra?

[ebon sage]

I've never seen something like this in C.
= is the assignment operator

[left knoll]

If you mean C as in the coding language… wouldn’t this be a compilation error?
But this is the math help channel so maybe that’s not what that means idk? Regardless I’m curious about what this is lol

So like if someone knows what this is can you tell us 🙏

[tiny sphinx]

no its evaluation problem in C language

[tiny sphinx]

exactly, it does not make any sense to me

[tiny sphinx]

yes in coding only, its supposed to be related to operators precedence and associativity

[left knoll]

oh ok. I'm kinda sure 100% there is nothing like this in programming

[ember garnet]

maybe the second equal sign should be a double equal sign instead? Then it would make sense

[left knoll]

That would make sense

[maiden wasp]

yeah the double equal sign is what's used in c

i think this problem's meant to show how c doesn't have a strict "boolean" type

booleans are represented by integers basically

so even though subtracting a number by true/false makes zero sense to us it technically works in c (iirc, true is equivalent to any positive nonzero number)

[maiden wasp]

just tested (sorry for ping)

#include <stdio.h>

int main(int argc, char *argv[]){
  printf("%d\n", (4 + 5) - (4 == 5));
  return 0;
}

9 is printed on screen

oh hm

right if (5 == 5) is put in, it comes back with 8

so true -> 1, false -> 0

when it comes to equality checks

what's it going chat i (believe i) failed my calc quiz on integration by parts and trig identities substitution

[floral lake]

Hey guys, need help here with java in eclipse ide. First time learning, I'm not sure if im doing this right. Some help would be really appreciated thank you!

[rustic shuttle]

There are a few problems there

From what i understand from the question, time 2 should be later than time 1, your code suggests the opposite

Also the "min1>min2+45" doesnt account for time in between hours, such as 14:30 and 15:20 (50 minutes = True) which in your code would not pass

I'm only focusing on the logic because idk the coding language so well

[left knoll]

ouch noo i hope it's not too bad

[maiden wasp]

hope i still get some partial, it was a very short quiz
one nice thing at least is that we get a couple of our quiz scores dropped through the semester, so provided i can understand that topic going forward, it’ll be alright
just had a bit of a shaky start this semester since there was a lot i didn’t fully grasp during the latter part of calc 1, so that’s been taking some time to catch up on, like u sub, i sorta understand it but it hasn’t clicked in the way that i’d hoped, and i’m still a little lost without the formulas
just a little worried that i can’t keep to pace since we also have graded homework this semester, albeit on completion
the grade drops are a nice buffer so i’m remaining optimistic, as long as i keep filling in the gaps

it’ll be alright i’m sure, pardon my ramble

[left knoll]

Oh I can’t stress enough how much I hate the technical part of calculus lol
None of it is easy I feel you 🥲
But at the end of the day that’s what I really need to do since I’m not a math major
I just finished my calc 2 course and it doesn’t get any easier but you learn to push through it 🥲
Thank god my course isn’t too technical
It’ll be alright though just keep at it

I’ve gotten some pretty bad grades (like really bad) in math in the last semester on my midterms
They aren’t always a good indicator of how things will go moving forward
I learned from my mistakes and improved and got higher grades than I expected… there’s always hope

You got this!

[maiden wasp]

thank you @left knoll!! it means a lot

[willow sage]

guys what is the right way to find the Highest Common Factor (HCF / GCD) of two integers?

there's so many ways and it's confusing me now

[left knoll]

generally i think you'd want to use the Euclidean algorithm since it's an efficient way to do it

the euclidean algorithm

at least as long as the two integers we're talking about arent two consecutive terms of the Fibonacci sequence

[mystic thunder]

do you still need help?

[tacit coral]

https://matematikdelisi.com/Orta/Sinif8/Hesaplama/images/EBOB-hesaplama.png

EBOB means HCF

you just divide the integers sequentially 2,3,4,..,etc.

[willow sage]

wow this is realyl insane, thanks

[indigo flint]

ser

[fair belfry]

yes pls 🙏

[mystic thunder]

for the first qs, u need to split the middle term (it's a method for factorizing)
u need to split it in such a way that when u add/subtract the numbers it's the middle number, and when u multiply it you get the product of the first and the third term
like-->
6p^2 - 9pq+4pq - 6q^2
(-9pq+4pq= -5pq, i.e the middle term) and
-9*4=-36 (product of the first and third term
Now, after splittiing the term, u have to find common
6p^2 - 9pq+4pq -6q^2
3p(2p-3q) + 2q(2p-3q)
=> (3p+2q)(2p-3q)

and in the second one, we have to use an identity, we can write the above question as
(a)^2 - (12)^2
as we can see, the identity x^2 - y^2 = (x+y)(x-y)
here x corresponds to "a" and y corresponds to "12"
==> (a+12)(a-12)

there you go

[fair belfry]

ohhh ic ty!

[vital flax]

hello, if anyone here has good experience in mathematical logic, I have one question that I asked in my Uni's discord but no one responded there at all lol. If I have a formula or a set of clauses, let's say { p(x), p(f(x)) } with p a predicate, and I apply a substitution onto it like [x/y], would the x inside the function call also be exchanged or will it be unchanged? I'd argue it would change as well

[snow dock]

dumn question but is it possible to go for 40 to 80-100 in math with 3 months in exams

from*

[left knoll]

When applying a substitution such as [x/y] to a formula or set of clauses, the variable x will be replaced by the variable y throughout the entire formula or set of clauses. This includes inside function calls. So in the case you provided, the x inside the function call of f(x) would also be replaced by y, resulting in the clause p(f(y))

[vital flax]

Thank you! staying on the topic of substitution to clean a FOL formula. I've followed the various exercises and solutions by my prof and his assistants. Let's say in a exercise involving converting a given FOL formula into it's prenex and/or skolar form, and the formula F looks like this:

Vy: (p(x,y) ^ Ex: q(x))

They would first notice that x is both bound and unbound, and according to both wikipedia and the slides, the x in the subformula Ex: q(x) must be renamed to a var that's not yet existing like lets say z, so the formula F becomes F' := Vy: (p(x,y) ^ Ez: q(z)), but I have also seen them substitute the free instance of an x in videos or the solution to the mock exam as well instead, so:

Vy: (p(z,y) ^ Ex: q(x))

Which version is valid? are both valid? because for me both seem valid, because we're trying to resolve this naming conflict by changing either one of these to something else and both achieve that that the cut between both free and bound variables is empty.

in said mock exam solution this was given:

and this is the cleaned version

[left knoll]

Both versions are valid ways to resolve the naming conflict between the free and bound occurrences of the variable x. In the first version, you rename the free occurrence of x to a new variable z, which ensures that all free variables are distinct from all bound variables. In the second version, you rename the bound occurrence of x to a new variable z, which also ensures that all free variables are distinct from all bound variables.

it is important to be careful when renaming variables to avoid introducing new errors or ambiguities into the formula, and to always check that the renaming preserves the meaning of the formula.

[vital flax]

🙏

Thank you so very much!

[left knoll]

any time

[ebon sage]

Hi, I have a problem with contour lines. If I have f(x,y)=(x^1/2 + y^1/2)^2 and if I search for the contour line for z=1=f(x,y) I find: y = (1-x^1/2)^2 but using geogebra I obtain the same curve from x=0 to x=1 but then it's different and I don't understand why

in yellow the contour line. in red the function of the contour line that I found. In x from 0 to 1 it's the same

[fluid saffron]

Im not sure what to do, please help

[spark fern]

The equation you have provided, f(x,y)=(x^1/2 + y^1/2)^2, represents a surface in three-dimensional space, with x, y, and z as the coordinates. To find the contour line for a specific value of z, you need to solve for x and y when the value of z is fixed.

In this case, the contour line for z=1 is given by y = (1-x^1/2)^2. This line represents the set of points (x,y) on the surface for which the value of z is equal to 1.

The difference between the curve you obtained from the equation and the one from Geogebra may be due to the range of x values being used. The equation y = (1-x^1/2)^2 only holds for values of x between 0 and 1. If Geogebra is plotting the curve for a range of x values outside of this interval, the shape of the curve may be different.

It is also possible that there is an error in either the equation or the way it was implemented in Geogebra. It may be helpful to double-check both the equation and the input in Geogebra to make sure they are correct.

[severe crane]

does anyone know how to rotate text on geogebra?

[ebon sage]

Thank you for the answer.
But, the contour line is raised to the second so x can assume any value, so the range is not from 0 to 1.

Not any value but x≥0

[sage cobalt]

Hi everyone! could someone be so kind to help me with this? I have been stuck on this qn for 2 hours now.........

[silk sandal]

Here you go

this is for b)

You can get c) from there

[neat dome]

Hi
I know that the area of the parallelogram is 100 cm² and the AC diagonal intersects the BE height in the point O.
BO/OE=5/3
I need to know the area of BEDC.
I think that the solving has something to do with AOE and COB triangles but I'm lost.
Please help.

[left knoll]

Isn't it the difference of two squares?

[jade creek]

did u solve yet?

[left knoll]

What??

[full sorrel]

hey

how'd you solve this?

[jade creek]

greatOR

[rotund vessel]

just square it and find the two roots

the answer will turn out to be some kind of interval

[dire aurora]

when u look at the solution you may not understand it anyway. please check PM shortly for some youtube videos that you should watch

[dire aurora]

Why doesn't null factor law apply to solving inequalities of a quadratic?

only using vertex form and taking absolute values works but not (x+a)(x+b)>0 x>-a or x>-b

I understand why its a wrong result

but I don't know the reasoning behind why the algebra doesn't work correctly that way when it does with equations

[jade creek]

because ones a rule for equations and another is a rule for inequalities?

[fluid saffron]

can someone pls help

[left knoll]

not sure tbh

[whole wren]

Sure enough ChatGPT is handy, but wouldn't it be even more handy to learn to find the answer by yourself so you get a better understanding of it ?
Maybe I'm oldschool, who knows

[fluid saffron]

i dont really get it either, but thanks for going out of your way to take the time to ask the AI

i was doing revision so ill see if i can ask for an explanation at school

[left knoll]

lol, idc to understand the answer cuz it's not my question

not old school i totally agree with u

[fair belfry]

yea, revise the syllable/subtopics taught and study the ones you dont know and keep practicing questions from each subtopic until youre familiar ig, i actually have no right to say this bc my math tests are usually in the 70% 💀

[grizzled lotus]

Does anyone knows where they get that log 25?

[whole wren]

there are 25 patients

[left knoll]

hello, i am struggling with 8a. any help appreciated!!

[fluid saffron]

hi can i get help with this

[fallen flower]

This seems like kind of a silly problem, but if try to find the factors of of a trinomial it doesn't seem to yield the exact answer. The answer was either (x + a)(x + b) or (x + b)(x + a), are both correct or is there only one singular answer?

When I take the factors of the third term it could either be (a × b) or (b × a) if it is a positive term

In example is x^2 + 10x + 16 factored (x + 2)(x + 8) or is it (x + 8) (x + 2)?

[whole wren]

Lemme grab a pen and paper pal

[fallen flower]

Yeah it just seems so simple and yet I'm not grasping it

[whole wren]

Sorry for the time, I checked, and it is (x+8)(x+2)

[fallen flower]

What is the exact process to that answer though?

Just so I don't make the same mistake on future equations

[quartz silo]

both answer is correct. doesn't matter the order in this problem

[fallen flower]

Okay thats what I was thinking, either way it achieves the same answer

[quartz silo]

yeah

[fallen flower]

Could it also be (x+2) (x+8) since it is commutative?

[whole wren]

Using the difference of squares:

x² + 10x + 16 can be written as (x + a)² + b, where a = 8 and b = 16 - 64 = -48

Factor the expression (x + 8)² - 48, using the difference of squares formula (a - b)(a + b)

The result is (x + 8)(x + 8 - 6) = (x + 8)(x + 2).

I don't know if that makes sense to you though, I nearly fell asleep on my phone here so I'll go now

[fallen flower]

Are both answers correct or does it have to be just one?

[whole wren]

If you want it to be precisely according to the formula, (x+8)(x+2), but otherwise (x+2)(x+8) also works

Neither can be wrong as long as you got it right

[quartz silo]

did you already complete this?

[ember garnet]

you can find one solution by observation if you set both sides equal to zero

[fluid saffron]

one of the solution(s) is 2/3?

how can i find another if theres another?

thanks btw wouldnt have guessed that

[cosmic elm]

how to solve

[cosmic elm]

i see thank u

[left knoll]

not yet!

[oblique solar]

did you got α and θ in terms of arctan?

[oblique solar]

you got the answer?

[left knoll]

no, i’m still struggling with applying all of this

[cunning fern]

i got the answes but they are in terms of arctan or tan-¹

[left knoll]

if you’ve got it written down somewhere i’d love to look over it

[cunning fern]

yes 2 min please

I'm in middle of something

[left knoll]

ofc it’s not pressing at all please take your time

[cunning fern]

if you do not understand something, please let me know

[left knoll]

thank you so much this is so helpful 🥹🥹

[cunning fern]

glad I was able to help

[left knoll]

CS students: how proof-based are your math courses? And when did you have to take them? (Say linear algebra and calculus 1+2 and or vector analysis, maybe discrete math if you take that? and so on)
Just curious about how it is elsewhere bc I took my proof-based math courses in the first semester + second semester and heard that some don’t take them till a bit later but idk how true that is

[peak comet]

Anyone got some good algebra books? Some pretty basic ones, i wanna get better at the fundamentals

[cunning fern]

Hall and Knight is very good

even though it's not very basic

[ember garnet]

i graphed it and there is another solution at 5 point something iirc. However I have no idea how you can solve it analytically, it's not a conventional equation and even online equation solvers won't give you a step by step answer (at least the ones that are free)

[peak comet]

I’ll give it a go

[cunning fern]

got till here but I have no idea how to go further

[ember garnet]

yeah you can also write this way which resembles a quadratic but instead of degree two it is degree 1.29... :p

[cunning fern]

ah that's another way to write it

thanks, learnt something new

[cunning fern]

can anyone help with summing this expression to infinity

:>

[left knoll]

doesn't this diverge?

[cunning fern]

yes it should

[left knoll]

why would you want to sum it

maybe i misunderstood your question?

[cunning fern]

it was a calc question

i ended up with this

[left knoll]

oh so you should check whether it's divergent or convergent and if it's convergent you want to sum it?

[cunning fern]

this was the question

[cunning fern]

it's probably convergent because the numbers are getting smaller and smaller

[left knoll]

i wouldn't say that's enough of a reason for it to converge
like as you already might know 1/n also follows that pattern but the infinite sum is not convergent

you'd have to prove it

intuitively i'd say that it "looks" like 1/n

[left knoll]

as in the sequence here

[cunning fern]

yes

[cunning fern]

it kinda does, but it's like 1/4n

[left knoll]

yea but a 4 doesnt matter in infinity

you can use the comparison test probably

and play around with it

[cunning fern]

please elaborate

[left knoll]

how far are you into calculus might i ask

[cunning fern]

i am in high achool

[left knoll]

ooh

[cunning fern]

last year of high school to be precise

[left knoll]

umm do you know anything about convergence tests of infinite sums?

[cunning fern]

honestly I don't know much

i stumbled from this question from a social media post

and I thought I'll be able to solve it using telescoping method

as taught to us in sequence and series

[left knoll]

okok there are plenty of sources online i'll link a wiki page if you want to check it out https://en.wikipedia.org/wiki/Convergence_tests

[cunning fern]

i have no idea :(

[cunning fern]

thank you for helping, appreciate it

[left knoll]

is this a power series i cant see it too well

[cunning fern]

wait I'll send a better picture

[left knoll]

I think it’s a power series aka a Taylor series
Idk if there’s an easier way but typically what you’d want to do is you’d want to find the function whose Taylor series is that and then that limit would be easier cuz you’d have a more concrete function… usually you’d try to find that function through playing around with the power series and seeing which already known Taylor series it looks like
Then again you can still try to play around with the expression and find an easier way to do it I’m not sure

of course assuming I’m assuming so many things here about the convergence radius

But yea
Does anyone else have any input on it?

[cunning fern]

I am sorry but I am not able to understand anything of this :'). Thanks a lot for your time tho

[left knoll]

Ouch I’m sorry 😭

Where did you get this from

Like the problem

You’ll learn all of this in calculus 2 🙏

[cunning fern]

black pen red pen ig

[left knoll]

Ooh

Yea there’s a lot of calculus 2 involved here

[cunning fern]

he has a solution video too, but that one is very different from the question I posted

[cunning fern]

like the question he posted on ug

ig*

[left knoll]

Ooh

[cunning fern]

and then solved on yt was different

[left knoll]

How did he solve it

[cunning fern]

that question was different

that question was different

in that question

[left knoll]

Oh okok

[cunning fern]

he double differentiated the expression inside

and was left with x^ 4n+2 / 4n + 2 which he said becomes tanh-1

[left knoll]

Yea then he probably used Taylor series as well

[cunning fern]

Can you provide me a source to read about these power series

[left knoll]

of course
Wikipedia has everything and you can also use khan academy
i'd honestly recommend studying cacl 1 and all before you jump to this (calc 2)
then again calc 1 and 2 is different depending on where you're getting your education haha
but here: https://en.wikipedia.org/wiki/Power_series
https://www.khanacademy.org/math/ap-calculus-bc/bc-series-new/bc-10-13/v/power-series-radius-interval-convergence

[left knoll]

also pretty cool that you do all of this already and are exploring things
wish i had done more exploring back in the day lol

[cunning fern]

:)

[cunning fern]

Are things like expansion of log(1+x), a^x also Taylor series

(haven't seen the links, i am in forest and chrome is disabled :/)

[cyan tartan]

Can u guys help me prove the 2nd and 3rd part

property of ellipse

[fluid saffron]

[left knoll]

Yes

[fluid saffron]

hmm i dont know lol cant really follow

[fluid saffron]

nope, the only answer i have is 2/3 but cant find the other

[cunning fern]

what is your grade, if you don't mind me asking

[fluid saffron]

im in highschool last year (its called form five in botswana)

[cunning fern]

ah same

[fluid saffron]

thanks for the help you offered, ill see what i can do

[cunning fern]

:)

[flint urchin]

(ignore the red marks)

is it wrong to square both sides and then prove that the squared LHS is equal to squared RHS?

[cunning fern]

1 ≠ -1 but if you square them, you'll get same result

so it isn't the best way

[flint urchin]

Hmm

[cunning fern]

do you know about square root being always in |mod|

[flint urchin]

No..

[cunning fern]

oh

square root of X² is |X|

not just X

I think I am complicating it

ignore it

[flint urchin]

Does the || mean +-?

[cunning fern]

the || means that no matter what is inside, the result will be always ≥ 0

so you proved that X² = Y²

but that does not prove X = Y

because after taking roots, it will give |X| = |Y|

which means X = ± Y

[flint urchin]

Ok Ty

[cunning fern]

How is log0/log0 a ∞/∞ form

Can someone explain

[remote linden]

log(0) -> -∞, so log(0)/log(0) = -∞/-∞ = ∞/∞

[peak comet]

Got myself a math book

Finna self study

[cunning fern]

Oh yehhhh

Thanks a lot! :)

[shadow wasp]

How do I add area I got the area of two rectangle 270 and 288 and got 558. Is this right. I just added both

[whole wren]

That's correct

[shadow wasp]

thx

[whole wren]

np

[nimble wedge]

Does anyone know this, I can't find a solution to this expression. I need to find x1 and x2 but I can't figure out where the error is

[cunning fern]

there is only x in the expression

x1 and x2?

[nimble wedge]

so I need to extract x1 and x2 from all that via the quadratic equation

but no matter how I tried to get it, it was impossible to get it

[cunning fern]

oh you mean the roots

[nimble wedge]

something like that

with us, it is an equivalent equation, so through it I finally get a quadratic equation and only then do I get x1 and x2

but I think that this task is impossible to solve if it doesn't exist, so I wanted to check with you people

[cunning fern]

Let me see if I can simplify it

might I ask your grade

so that I get some idea

[nimble wedge]

okay, if you manage to solve it somehow, although I tried to do it on the easy and on the thesis, but nothing, and I only know that somehow the solution should be 1 and 2

[cunning fern]

is the left hand side multiplied?

because I assume it is

[nimble wedge]

the left side is subtracted and the right side is multiplied

[cunning fern]

1 and 2 are not the solution then

[nimble wedge]

I don't know, that's what it says in the solution book, and now I don't know if they made a mistake about the task or about the solution. but I think this task is impossible to solve

[nimble wedge]

Did you get something?

[whole wren]

2^(x^2)^(-3) is 0.01 if we assume its x is 1, no ?
(sorry, not trying to intrude just to understand as well)

[cunning fern]

isn't it like 2^ x² - 3

which gives the answer 1/4 when x = 1

[nimble wedge]

well, like me, I only know that x1 should be 1, and x2 should be 2. but that's before I get the quadratic equation

[cunning fern]

no need to be sorry, I am sorry if that came out as rude

[nimble wedge]

it's ok you don't have to apologize trust me i'm confused about the task too

[cunning fern]

that means the LHS is not substracted

instead it multiplied

LHS = (-1)^-2 . (2)^-2. (5)^-2

which is 0.01

same as RHS when we put x = 1

yes it's definitely multiplied

@nimble wedge @whole wren

[whole wren]

may i ask where the (-1)^x²-3 comes from ?
i'm assuming it's the (-) sign

[nimble wedge]

that's what I wanted to ask

[cunning fern]

(-5) = (-1).(5)
(a.b)^m = a^m.b^m

[cunning fern]

this is correct for x = 1

but for x = 2, it is not

because the power of (-1) will be odd i.e 1

which will make the left hand side negative of the right hand side

[whole wren]

that makes so much more sense now

Thanks

[cunning fern]

I think there is only one solution i.e 1

x = 2 doesn't satisfies

solution mistake maybe

[nimble wedge]

now I understand how you did it and I see what now. thank you very much for the result and the solution 😁😁

[last saffron]

Hey, does anyone know why this is being put into log?

(T1/2)

[left knoll]

If I understood you correctly, generally speaking when you have a variable you as an exponent and you’d want to isolate it you’d use log because it’s the inverse function of the exponential function a^x, (a is a given number)
And from what I can see they are trying to find what T_(1/2) so that’s why they did that

@last saffron
Otherwise tell me if I misunderstood you

[last saffron]

You're absolutely right, thank you very much!

[severe crane]

can anyone explain why eulers number is used to model functions

[whole wren]

because it is exponential

[severe crane]

why is it used over other constants in exponential functions?

[left knoll]

it's literally just found almost everywhere. and perfectly describes different phenomena in different fields (finance and so on). which is why it's used over other constants

[left knoll]

Hello, someone wanna some math books links for free?

[severe crane]

i need to provide an explanation in a portion of my paper, would you be willing to read a paragraph and let me know if it makes sense?

[lyric delta]

hi, can anyone recommend me exercises? most of the time i understand how to solve a question but still ended up being wrong because i wasnt careful on very very basic and easy operation. i tried being more careful but things still got out of my sight. thanks in advance

[left knoll]

I’m not that well-versed in this I just know that fact

[cunning fern]

exercises on?

I mean like algebra, geometry, calculas

[finite lodge]

Q. Find the number of co prime divisors of the number 2^5 × 3⁴ × 5⁷ × 7²

[undone ledge]

Can someone help me on question 12?

[cunning fern]

do you know about fundamental principle of multiplication?

[undone ledge]

Nope

Should I look into it?

[cunning fern]

it's a very basic principle

when you have to do two simultaneous operation, you multiply both of them

like there are two tasks A and B

[undone ledge]

Ohhh wait I know it

[cunning fern]

A can be done in 3 ways and B in 4 ways

if you are going to do A and B simultaneously, it'll be 3.4 = 12 ways

simple as that

so you can break the problem into two parts

[undone ledge]

So that equation I have can be done in 8 ways

But I need to find the number of ways for females

[cunning fern]

I'll solve b part for you

So we need 1 female players in the team of two players. Now we have two choices, either take the female player from the team A, or take the female player from team B.
If we take female player from one team, it's a necessity that we take a male player from other team.
The required probability will be :- 3/4 x 1/2 + 1/4 x 1/2

Is the answer 1/2 for part b @undone ledge

[cunning fern]

Is this from permutations and combinations?

I learnt something like this last year but can't recall

[undone ledge]

Yep it is

[undone ledge]

I’m going to work it out going over what you just said it’s making more sense now thank you :))

[cunning fern]

720?

[solid anvil]

I need help

Please solve this inequality

The answer is c

But I don't get how

Ohh

Wait

I get it

😄

[grizzled lotus]

How do I find mean using scores ?

[cunning fern]

I am not able to understand why the right hand limits doesn't exist at x = 1

This is the solution

but I can't understand what does "oscillating" mean here

[pliant agate]

its b not c

[cunning fern]

c is correct!

[sweet karma]

when X → 1+ lim 1/1-x= + infinit , and when x→ +infinit lim cos does not exist

[pliant agate]

can you explain it to me please

[cunning fern]

multiply the equation by -1

that'll change the sign of inequality

-4 ≤ 3x - 2 ≤ -1

add two to each side and then divide the whole equation by 3

which'll give -2/3 ≤ x ≤ 1/3 @pliant agate

[cunning fern]

can you explain please, I do not understand

[lament wren]

Anyone knows what chapters do i study before complex numbers (11th grade India)

[cunning fern]

it doesn't have a lot of pre-requisite

before the algebra part, study trigonometry

[lament wren]

it does when you see questions

[cunning fern]

and before the geometry part, study circles and straight lines

[lament wren]

yeessss needed thet

[cunning fern]

well, if you'd do jee advanced question, they'll require more than one concept

[lament wren]

yea

ik

thenks

[sweet karma]

kinda hard to explain in english since i know math in french

[cunning fern]

will it work with google translate?

[sweet karma]

basically all i did is calcultale the lim of 1/1-x =+ ∞ ( and then u use the lim GoF rule) then lim cosx when x→+∞ does not exist , you can see it in this graph

https://socratic.org/questions/what-is-the-limit-as-x-approaches-infinity-of-cosx#158473

here is a better explanation than the graph lol

[cunning fern]

Thank you very much for help!!! I'll look into this

:)

[compact fable]

Hope it helps❤️

[cunning fern]

write down all the formulas somewhere and then memorise it and solve a lot of question after that

you'll get used to it

oh

you know the DI table method?

you can use that in place of integration by parts

and it's easy to learn

they are both very similar

when you solve question, do you need to show the full procedure?

nah that's not the case I assure you

maths and physics don't really require frequent revision

ah for written you'll have to go with the parts one, no choice for you

also I think you are having difficulty in those sinx, cosx problems

[cunning fern]

where you gotta do the steps again and again

nah I am not taking stats

trig problems in by parts are hard

maybe you should do like 5 question on that concept daily for a week atleast

[pliant agate]

oohhh thanks maan

[unborn igloo]

anyone have a video or can explain how people came up with the addition and subtraction identities in trig

i understnad thing more when i see where they came from

and i couldnt find any yt videos

[left knoll]

search up Ptolemy's theorem for the sine addition formula explanation

[sweet karma]

https://youtu.be/WNyAreYIbU4

if you studied complex numbers, you'll remember them easily

[solemn estuary]

can anyone help me with solving my math homework

i keep having trouble finding the point A

[cunning fern]

can you translate what's written in arabic

[solemn estuary]

kk

we need to find the equation of AB and the equation of AC

we are givin that both AC and AB touch the circle

[cunning fern]

they are tangent

[solemn estuary]

idk much english

[cunning fern]

tangent means a line which touches at only one point

[solemn estuary]

and we are givin that B = (-2 , 1) C = (10,-5) and M = (3,-4)

[cunning fern]

I learnt this last year

let me check my notes

[cunning fern]

the equation of a tangent is

xx1 + yy1 + g ( x + x1 ) + f ( y + y1 ) + c

where x1 and y1 are the points where the line ( tangent ) intersects the circle, in this case B ( -2, 1 ) and C ( 10 , - 5 )

g is the negative of x coordinate of centre of circle

f is negative of y coordinate of circle

c is the constant in the circle's equation, which you'll get when you will write the equation of circle

@solemn estuary

[solemn estuary]

kk

[ebon sage]

Sometime math seems like Arabic lol, jk

[ebon sage]

De l'hopital
Lim X --> inf {(1/X)/1 } = 0

[cunning fern]

n is tending to?

[oak sphinx]

n tending to N

[sweet karma]

i think + infinit

[fading sonnet]

Guys i might need sum help with this one.

Question 8

[fading sonnet]

Here's how i did it

Yeah i also found out i can use Laplace

[whole wren]

So you solved it ?
Also correct me if I'm wrong but these are vectors right ?

[fading sonnet]

Yes i did, i just had to prove that the determinant of that matrice is equal to (a-b)³, there no vectors.

[jade drum]

Sine takes value between -1 and +1 when we solve in the second case the argument of sine inverse it comes out to be somewhere above 2 which isn't possible hense an error

While in the ist case it comes under 1 that's why no error

[silk patio]

You have the same calculator

[trim slate]

i have no specific math problem i need help on, but i'm just curious on how to go about studying math. since i'm in precalc i know to memorize limits, derivatives and equations but i feel like i'm missing something/i still end up forgetting stuff when i get test papers handed to me

[pallid bear]

Can someone help me do my math homework?

I am super behind and I’m trying to get tutored to get caught up but it’s difficult

[silk patio]

I feel you

[quartz silo]

which number?

[quartz silo]

here's #1 and #4 to get you started

[obsidian carbon]

Anyone down to help with some trig?

[cunning fern]

send question

[obsidian carbon]

Ah I got it figured out, thanks though mate!

[jade drum]

You asking me

[left knoll]

hey guys does anyone have a counterexample for 2
we're given a function sequence f_n which is bounded for all n in N and x in I, I=[1,inf) and it's (the function sequence) uniformly convergent to a function f
and 2 says if the the improper integral of f_n on 1 to inf is convergent for all n in N then the improper integral of f on 1 to inf is convergent and is equal to that limit
all of the examples im able to come up with wind up being convergent to 0 and that's why im struggling

thanks in advancee

[winter grail]

if I remember correctly fn should also be approximated by a staircase function for 2 to work

[left knoll]

i'll look into it thanks a lot!

[trim slate]

if anybody has strategies that they used for calc + general ideas for practicing math that would be helpful (i forget everything for my tests)

[trim slate]

ty!

[red comet]

Also I put the side length as the angle on accident soo oops

[rain plinth]

if triangle YZX correlates with XZW then shouldn't XY correlate with XW? If so then option B should be right too.

(key says option A is correct)

[cunning fern]

no YZX is not similar to XZW

wait it is

mb

yeah, B should be correct too

[rain plinth]

ikrrr but key says only A is correct
im losing my mind here

this book is rarely wrong so i think we might be missing something

[cunning fern]

are multiple answers correct?

if its single correct mcq then A is more appropriate

[rain plinth]

why so

[cunning fern]

because first we got YZ/XZ = 1/k, then we got XY/XW = YZ/XZ so maybe thatswhy

[cunning fern]

Hi, needed help with this prblem

[sonic remnant]

damn

i used to know this back in high school

now i don't 😭

[obtuse mural]

i'm trying to solve it

i divided the problem in 2 parts, solved the second one (i think it's right)

i will try the first part now

I'm not taking into account the constants, bc we can just group them at the end

[obtuse mural]

i have no idea how to do this, sorry

[ember garnet]

Use https://www.integral-calculator.com/

[left knoll]

Idk why but I smell long division

[sonic remnant]

really? O.o

[cunning fern]

no problem mate, thanks for help

[cunning fern]

damn, didnt knew something like this existed

[cunning fern]

yeah , kinda long division and then breaking the denominator into x(1 + xlnx)

[cunning fern]

haha no worries

[silk patio]

Can some help me

[turbid edge]

use sin cos tan cot

example 1
sin60* = y/10

=> y = 5 multiple square root of 3 (i can't type it, doesn't see any square root symbol)

similar to another, it's easy

[warped grove]

Could someone walk me through how I substitute the 5/root(2) for terms of theta. The answer is pi/4 and I can integrate it but I don't know how to get my X in terms of theta.

[clear hearth]

if you want the 5/sqrt2 in theta, just plug it into arcsin(x/5) = theta equation

[warped grove]

Thank you

[neat nova]

@obtuse mural

[grizzled lotus]

What’s the difference between PVIFA and PMT

[grizzled lotus]

anyone got discounted cash flow analytics questions and answers? i cant seems to do any practice T_T

[acoustic forge]

I've done the "A" part right but can't understand how to do the "B" part as my answer doesn't match it

This is from Edexcel Core Math C2 A level math and the topic is "Radian measures and its applications"

These are the answers

[raven cypress]

i think for part b we differentiate

i'll try to do it

hold on

is it okay if we turn the sin into a (1-cos) here or is it invalid?

[raven cypress]

part i, we differentiate 50r-r^2 into 50-2r
equation will become 0=50-2r, which gives r as 25

to show A as a maximum just differentiate the equation of the area given, which will give you -2 (when the answer is negative the point is a maximum)

wait the ms is confusing

but for the second part it's substituting the value of r into the perimeter ewuation

giving you the angle as 2 radians

[raven cypress]

nvm i understood it wrong

for the last part substitute the value of r into the area equation given

[undone ledge]

Question 4

Would I use the addition rule?

[grizzled lotus]

How to do 5.11

[cedar ermine]

Hey , you need solution of this ?

[gray echo]

Does $1,0759.50 mean 1,0759 x 50 = $53,795 ? And this is the amount of money u get after 10 years ?

[silent pendant]

Hi, I would like some help on this question please. As I arrived at the end of my answer I ended up with sin inverse 3/5 which doesn't give a definite value so I am confused whether I did get the correct answer or not

[undone ledge]

Yeah ><

[cedar ermine]

Thanks me later : )

[cedar ermine]

I actually added an extra step to get more values

@forest iris Guys, If you need any help regarding any solution or something else related to maths , you can dm me for your problems

[undone ledge]

Thanks :DDD

[obtuse mural]

really smart solution!!

[silent pendant]

Hey Shot cool, I believe your method for finding p(x) was incorrect. Here is what I believe is the correct way of finding out the pr(X)

[novel pumice]

i'm kinda stuck with both a and b 🙏

[weak lotus]

what topic are you learning?

like what kind of math

i would think like this:

(a)
you know the price for 10m --> 7500
you know the price for 20m --> 9300
the difference in depth is 10m, so for an extra 10m you pay 9300-7500 = 1800
so if you need to know how much it is for 100m i would do the price for 10m = 7500 + 9(1800) since its givin that its a constant price for every subsequent extra depth of 10m

[copper heart]

Can some one help me with this

[silent pendant]

if not for the m!=0 condition it couldve been equivalence (as condition for symmetric wouldve been met) but since it exists this will be symmetric and transitive only

[copper heart]

I think it would be equivalence as you mentioned 2 already ... We have m!=0 but n can be able to 0 (n=0) .. hence we can say a-a = 0 where m!=0 ... Correct me if am wrong

[silent pendant]

n is mentioned a positive integer and I think 0 isn't included in it, otherwise it will be equivalence only

[copper heart]

Isn't positive integers are same as whole numbers

[copper heart]

Okay thanks 👍

Then what could be the solution since answers can't be multiples 🙃

[silver pier]

5b, is my answer accurate?

[silent pendant]

You have to mention FR=EP (perpendicular from centre bisects the chord)

And then prove them congruent cuz RHS

[silver pier]

i see

[left knoll]

** rth term from beginning is (n−r+2)th term from end.** but how ?? (I read this line in BINOMIAL THEOREM)

[cunning fern]

gotta be (c) then i think because its not reflexive as a - a = 0 and neither n nor m are 0

[vague dagger]

guys i need help on something

what does this mean

[fallen galleon]

i think it means

it is closer to the origin

by half of the other one?

sorry for the sloppy line

i ws using a trackpad

@vague dagger

but im not 100% sure that is what it means

[fallen galleon]

also if you do end up using my answer

there should be another perpendicular line at positive 2.5

that is perpendicular to the line

since i only gave 1 solution

[languid compass]

Can someone please help me with this problem

[fallen galleon]

do you know how to do volume of revolution

im a bit rusty with the integrals

but i can explain what the problem wants

so given this graph of all the lines

they want you to rotate where the area from quadrant 1 (upper right) around the line x=-3

since it is a vertical rotation around the y axis it will be an integral with dy

[languid compass]

Thank you, I think I'm supposed to use the disk method, I was just a bit confused on how the process would change with having 3 functions instead of 2, and with me only having to find the volume in the first quadrant

[fallen galleon]

if you are finding the volume of whatever is in the first quadrant

you will be using the range

with respects to whatever is in the first quadrant

actually

i dont want to misinform you because it has been years since i have done calculus

so

i would just watch this

https://youtu.be/jxf7XqvZWWg

[languid compass]

Ok gotcha thank you, I appreciate the help

[fallen galleon]

yeah sorry I couldnt be of more help

[languid compass]

No worries! Still appreciate it nonetheless, I'll check out the video

[tidal creek]

does anybody know how to simplify this question

[eager palm]

I think the only thing you can do is to get rid of the brackets but that wouldn't be simplifying it

[eager palm]

can someone explain how to get that ax²+bx+c type of function with the function on the left?

[tidal creek]

thx

[left ether]

ofc

[left ether]

is the function on the right any type of hint or smth or it has to be totally ignored

[eager palm]

the funtion on the right is the solution you get by changing the left side. but idk how

[left ether]

ohh

lemme try

[left ether]

idk what i did LMFAO
i hope its correct

[left knoll]

"Prove that if a plane is perpendicular to two secant planes, then it is perpendicular to the intersection of these planes"

pls help

[eager palm]

makes sense, thanks

[left ether]

no problem

[vernal comet]

Been trying to solve this for a little. I don't think squeeze theorem works but I can't get the term stuck in the cos out

pls help 😩

[blissful swan]

Can anyone help me to solve this?

[fluid saffron]

Hi have i done this correctly?

[blissful swan]

thanks dude!!

[edgy sun]

im looking at this problem and idk where to begin

[thick pine]

Is anybody familiar with Gauss' and Stokes' Theorems in differential geometry?

[long terrace]

In the context of Vector Analysis from the book of Apostol, yes, but I don't know in differential geometry

[long terrace]

Is this Chat only for math help in High School or are university maths also welcomed?

[thick pine]

This is the exercise task

[left knoll]

Hii, but can't we directly substitute the limits in this case? Wouldn't the resulting answer be 1?

[vernal comet]

I got it-- took the conjugate. Forgot it was a thing x) Thanks though

[left knoll]

Np :)
But why take the conjugate though?

[proper cosmos]

hey
can someone please explain me in the simplest way why its true?

[stark dune]

take 2^(x-2) common

you'll be left with 2^2-1 which is 3

[proper cosmos]

how can i take 2^(x-2) common if its the biggest among the two?
(thanks for the reply)

[stark dune]

2^x is bigger lol it can be broken down to 2^(x-2 +2)

[proper cosmos]

oh hahah yeah right sorry

thanks guys

[spice flare]

the integral of cos x = sinx , then sub in the value of 2pi into the sinx and minus that from the sin of 0

[trim kayak]

i need help in inequation 2

why cant i find the solutions even i am doing the right steps

[edgy sun]

wdym?

im pretty confused

like they give us 3 integrals

[trim kayak]

Guys I found the answer

[left ether]

goodjob

[edgy sun]

how would i start this problem

[fluid saffron]

I need help

[edgy sun]

i did integration by parts once but im not sure where to go from there

[fair belfry]

hey guys this is apparently wrong but im not sure where pls help 🙏

[edgy sun]

u can simplify 2x^2-2x-24 =0 as x^2-x-12 = 0

and then factor it as (x-4)(x+3) = 0

which is 4,-3

[fair belfry]

ohhh right tysm

[sick egret]

might wanna double check the values, but this is how you do integration by parts

[thin solar]

ok so

this is like

really basic

but

i dont get it

[thick pine]

Q7 or Q8?

[thin solar]

8 please

[thick pine]

So 10 <= a <= 100, so it could be a=28 or a=79

Standard form means only one digit before the dot

So 4 in standard notation would be 4 * 10^0, 455 in standard notation would be 4.55 * 10^2

[thin solar]

ohhh

the wording of the question threw me off

thank youu

[thick pine]

No problem 🙂

[left ether]

how is a cubic equation solved? the book I'm using didn't give me a solution to this n straight forward gave me the answer "0.25", I end up getting to 16x^3-4x^2+4x-1=0 but idk what to do next and how to get to the "0.25" answer

i searched up abt how to solve a cubic equation but it looked really complicated, can anyone explain it to me in a less complicated way? I'm a science major n this is my first time coming across something like this n we don't really get straight forward questions from this topic, but today i came across this two times in chemistry n since im not a math major the books aren't helping at all 💀

[dreamy oasis]

Well
Here is the solution
16x³-4x²+4x-1=0
U can regroup this with 4x²
4x²(4x-1) + 4x-1
And then u can again regroup this
4x-1 (4x²+1) =0
Then u can find the solution easily.
Hopefully this helps.

[left ether]

OH MY GOD 😭
i was literally sitting there for an hour n i couldn't think of a solution this was way too good and easy tysm

i feel dumb as hell ngl

if it wasn't possible for the equation to be regrouped n stuff, how is it solved?

[dreamy oasis]

You're welcome

We have cube expansion
(a-b)³= a³-3a²b+3ab²-b³
(a+b)³=a³+3a²b+3ab²+b³
If the equations fits these formula we can use these formula.

Sometimes equations can also be solved by factoring.
But I don't have a very good knowledge of math, so maybe there are other ways, I don't know.

[left ether]

oh alright, tysm!

[karmic crest]

someone have some tips for me?

I am learning second degree equation

Delta, Bhaskara, etc

[rain solstice]

dont worry from then to university it will get way easier in factorisation

like taylor formula i dont know if you study it in your country but you can look for it

[rain solstice]

he can also do this (a-b)³=(a-b)(a-b)²

it make it waaaay easier

[plain pendant]

wasup guys

someone can help me?

[left ether]

is the 2x= 2-5y the answer for the thing u wrote at top?

cause the first one seems to have a problem, since the (x-y) are the same they can be removed, but then there won't be any answer

[plain pendant]

noo,This is a system

i dont know the name this problem in english

[left ether]

hmm

[glass crater]

bottom line looks like linear equation for a graph

[left ether]

yeah but what's the one on the top

[plain pendant]

x-y/5 = x-y/2

[left ether]

ohh so the 2 and 5 r under y? not the whole (x-y) thing?

[plain pendant]

yeah

[glass crater]

ooo

[left ether]

nah again it'll be false

[plain pendant]

Is my handwriting that bad?

[left ether]

no no it's not about the handwriting