#unable to get 0 for all alphabets that occur once only

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rigid moat
azure wharfBOT
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tropic plank
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How do you need help?

rigid moat
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hi, Anurg

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i can't get the return value as 0 when i have String = a b c d e meaning the character only appeared once

tropic plank
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With spaces?

rigid moat
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no space

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//"abcde" -> 0 # no characters repeats more than once

tropic plank
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And can you explain your logic

rigid moat
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i use a hashmap to store the key value

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if the character appear once only, it will but put character and 1

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otherwise, the 1 will be added with another same character that appeared

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after the storing, I then iterate over the hashmpa

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an then if the character is only once thru out and the size is the same as the string size, so the return value should be 0

tropic plank
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"Size is same as string size" where

rigid moat
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yes, should be same as string size

tropic plank
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But you only have to count how many letters occur multiple times

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Why would it have to be equal to string size

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And isn't yout total 0

rigid moat
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the total will change accordingly

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because some String has multiple same characters

tropic plank
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Map.size() != string.size()

rigid moat
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oh ok. let me review

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still, i can't get it right after changing the size to String size

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which is Character array length

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@tropic plank hope you can give me some hints

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it is late so i think i better go sleep now

tropic plank
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Same